8. Gravity 1. Toward a Law of Gravity 2. Universal Gravitation 3. Orbital Motion 4. Gravitational Energy 5. The Gravitational Field
Dec 28, 2015
8. Gravity
1. Toward a Law of Gravity
2. Universal Gravitation
3. Orbital Motion
4. Gravitational Energy
5. The Gravitational Field
This TV dish points at a satellite in a fixed position in the sky.
How does the satellite manage to stay at that position?
period = 24 h
Ptolemaic (Geo-Centric) System
epicycle equant
deferent
swf
8.1. Toward a Law of Gravity
1543: Copernicus – Helio-centric theory.
1593: Tycho Brahe – Planetary obs.
1592-1610: Galileo – Jupiter’s moons,
sunspots, phases of Venus.
1609-19: Kepler’s Laws
1687: Newton – Universal gravitation.
Phases of Venus:Size would be constant in a geocentric system.
Kepler’s Laws
d Aconst
dt
2 3T a
Explains retrograde motion
Mathematica
8.2. Universal Gravitation
Newton’s law of universal gravitation:
1 212 122
ˆm m
Gr
F rm1 & m2 are 2 point masses.
r12 = position vector from 1 to 2.
F12 = force of 1 on 2.
G = Constant of universal gravitation
= 6.67 1011 N m2 / kg2 .
Law also applies to spherical masses.
m1
m2
r12
F12
Example 8.1. Acceleration of Gravity
Use the law of gravitation to find the acceleration of gravity
(a) at Earth’s surface.
(b) at the 380-km altitude of the International Space Station.
(c) on the surface of Mars.
2Em m
F m g Gr
2Emg Gr
(a)
24
11 2 226
5.97 106.67 10 /
6.37 10
kgg N m kg
m
29.81 /m s
(b)
24
11 2 226 3
5.97 106.67 10 /
6.37 10 380 10
kgg N m kg
m m
28.74 /m s
(c)
24
11 2 226
0.642 106.67 10 /
3.38 10
kgg N m kg
m
23.7 /m s
see App.E
TACTICS 8.1. Understanding “Inverse Square”
Given Moon’s orbital period T & distance R from Earth,
Newton calculated its orbital speed v and hence acceleration a = v2 / R.
He found a ~ g / 3600.
Moon-Earth distance is about 60 times Earth’s radius.
Cavendish Experiment: Weighing the Earth
2E
E
Mg G
R
ME can be calculated if g, G, & RE are known.
Cavendish: G determined using two 5 cm & two 30 cm diameter lead spheres.
Gravity is weakest & long ranged
always attractive
dominates at large range.
EM is strong & long ranged,
can be attractive & repulsive
cancelled out in neutral
objects.
Weak & strong forces: very short-range.
8.3. Orbital Motion
Orbital motion: Motion of object due to gravity from another larger body.
E.g. Sun orbits the center of our galaxy with a period of ~200 million yrs.
Newton’s “thought experiment”
2
2
M m vG m
r r
G Mv
r
Condition for circular orbit
Speed for circular orbit
2 rT
v
Orbital period
3
2r
G M
Kepler’s 3rd law
g = 0
orbit projectiles
Example 8.2. The Space Station
The ISS is in a circular orbit at an altitude of 380 km.
What are its orbital speed & period?
G Mv
r
3
2r
TG M
Orbital speed: 11 2 2 24
6 3
6.67 10 / 5.97 10
6.37 10 380 10
Nm kg kg
m m
7.7 /km s
Orbital period:
36 3
11 2 2 24
6.37 10 380 102 3.1416
6.67 10 / 5.97 10
m m
Nm kg kg
35.5 10 s 90 min
Near-Earth orbit T ~ 90 min.
Moon orbit T ~ 27 d.
Geosynchronous orbit T = 24 h.
Example 8.3. Geosynchronous Orbit
What altitude is required for geosynchronous orbits?
3
2r
TG M
2/3
1/3
2
Tr G M
2/3
1/311 2 2 2424 3600
6.67 10 / 5.97 102 3.1416
sNm kg kg
74.22 10 m
Altitude = r RE7 64.22 10 6.37 10m m 635.80 10 m 35,800 km
Earth circumference = 62 6.37 10 m 40,000 km
Earth not perfect sphere orbital correction required every few weeks.
Elliptical Orbits
Orbits of most known comets, are highly elliptical.
Perihelion: closest point to sun.
Aphelion: furthest point from sun.
Projectile trajectory is parabolic only if curvature of Earth is neglected.
ellipse
Open Orbits
Closed(circle)
Closed(ellipse)
Open(hyperbola)
Borderline(parabola)
Mathematica
8.4. Gravitational Energy
How much energy is required to boost a satellite to geosynchronous orbit?
2
112 dU
r
rF r
2
112 2
r
r
M mU G dr
r
1 2
1 1G M m
r r
U12 depends only on radial positions.U = 0 on this path
… so U12 is the same as if we start here.
Example 8.4. Steps to the Moon
Materials to construct an 11,000-kg lunar observatory are boosted from Earth to geosyn orbit.
There they are assembled & launched to the Moon, 385,000 km from Earth.
Compare the work done against Earth’s gravity on the 2 legs of the trip.
121 2
1 1EW U G M m
r r
1st leg: 11 2 2 246 7
1 16.67 10 / 5.97 10 11,000
6.37 10 4.22 10W Nm kg kg kg
m m
11 2 2 247 8
1 16.67 10 / 5.97 10 11,000
4.22 10 3.85 10W Nm kg kg kg
m m
115.8 10 J
2nd leg:
109.2 10 J
Zero of Potential Energy
G M mU r
r
121 2
1 1U G M m
r r
0U Gravitational potential energy
E > 0, open orbitOpen
ClosedE < 0, closed orbit
Bounded motion Turning point
Example 8.5. Blast Off !
A rocket launched vertically at 3.1 km/s.
How high does it go?
E K U
20
1
2 E
G M mE m v
R Initial state:
G M mE
rFinal state:
Energy conservation:21
2 E
G Mr
G Mv
R
2
1
12 E
vG M R
12
611 2 2 24
3.1 / 1
6.37 102 6.67 10 / 5.97 10
m sr
mNm kg kg
6.90Mm
Altitude = r RE6 66.90 10 6.37 10m m 530 km
Escape Velocity
Body with E 0 can escape to
210
2 E
G M mm v
R
2
escE
G Mv
R
11 2 2 24
6
2 6.67 10 / 5.97 10
6.37 10esc
Nm kg kgv
m
11.2 /km s
Escape velocity
40,300 /km h
Moon trips have v < vesc .
Open
Closed
Energy in Circular Orbits
Circular orbits:2 G Mv a r
r 21
2K m v
2
G M m
r
G M mU
r
2
G M mE K U
r
K 1
2U 0
Higher K or v Lower E & orbit (r) .
0
E
UK
K
Conceptual Example 8.1. Space Maneuvers
Astronauts heading for the International Space Station find themselves in the right circular orbit, but well behind the station.
How should they maneuver to catch up?
1. Fire rocket backward to decrease energy & drop to lower, & faster orbit.
2. Fire to circularize orbit.3. After catching up with the
station, fire to boost to up to its level.
4. Fire to circularize orbit.
Mathematica
energy
0
UG
Altitude
0
E = K+U = U / 2
U
E = K+U < E ( K < K )
h
E = K+U = U / 2
U < U
K K > K
h < h
G M mU
h 1
2 2
G M mK E U
h
GOT IT? 8.3.
Spacecrafts A & B are in circular orbits about Earth, with B at higher altitude.
Which of the statements are true?
(a) B has greater energy.
(b) B is moving faster.
(c) B takes longer to complete an orbit.
(d) B has greater potential energy.
(e) a larger proportion of B’s energy is potential energy.
8.5. The Gravitational Field
Two descriptions of gravity:
1.body attracts another body (action-at-a-distance)
2.Body creates gravitational field.
Field acts on another body.
Near Earth: ˆgg j
2ˆ
G M
rg rLarge scale:
29.8 /g m s
/N kg
Action-at-a-distance instantaneous messages
Field theory finite propagation of information
Only field theory agrees with relativity.
near earth
in spaceGreat advantage of the field approach:No need to know how the field is produced.
Moon’s tidal (differential) force field near Earth
Moon’s tidal (differential) force field at Earth’s surface
E F r f r f r
Mathematica
Application: Tide
Two tidal bulges
Sun + Moon tides with varying strength.
Tidal forces cause internal heating of Jupiter’s moons.
They also contribute to formation of planetary rings.