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Chemistry 102 ______________________________________________________________________________ EXPERIMENT 1 REACTION RATE, RATE LAW, AND ACTIVATION ENERGY THE IODINE “CLOCK” REACTION 2015 www./proffenyes.com 13 NAME: ______________________ Date: _____________ Partner: ______________________ 67/67 PART I: DETERMINATION OF THE RATE LAW 1. Initial Concentrations of Reactants For each kinetic run, calculate the initial concentration of the reactants: [I - ] and [S2O8 2- ]. These calculations should be done prior to performing the experiment! Since the reaction takes place in a total volume of 50.00 mL, this volume must be taken into account in calculating the initial concentration of the two reactants. For example, in Run 1, since the 20.00 mL of 0.200 M KI added reacts in a total volume of 50.00 mL, the initial concentration of [I - ]0 can be calculated as follows: 20.00 mL [I - ]0 = 0.200 M KI = 0.0800 M KI 50.00 mL Similarly, in Run 1, the initial concentration of [S2O8 2- ]0 is calculated as follows: 20.00 mL [S2O8 2- ]0 = 0.100 M (NH 4 ) 2 S 2 O 8 = 0.0400 M (NH 4 ) 2 S 2 O 8 50.00 mL On the next page, carry out similar calculations for all other initial values of the two reactants and complete the appropriate columns in DATA TABLE III. You are required to: Show all your calculations Include units in your calculations, and Express all measured quantities (including your answer) in the appropriate number of significant figures.
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Page 1: 67/67 PART I DETERMINATION OF THE RATE LAW [I [S O ...proffenyes.weebly.com/uploads/2/5/2/3/25237319/experiment_1... · 67/67 PART I: DETERMINATION OF THE RATE ... the known values

Chemistry 102

______________________________________________________________________________

EXPERIMENT 1

REACTION RATE, RATE LAW, AND ACTIVATION ENERGY

THE IODINE “CLOCK” REACTION

2015 www./proffenyes.com 13

NAME: ______________________ Date: _____________ Partner: ______________________

67/67 PART I: DETERMINATION OF THE RATE LAW

1. Initial Concentrations of Reactants

For each kinetic run, calculate the initial concentration of the reactants:

[I-] and [S2O82-].

These calculations should be done prior to performing the

experiment! Since the reaction takes place in a total volume of 50.00 mL, this volume must be

taken into account in calculating the initial concentration of the two reactants.

For example, in Run 1, since the 20.00 mL of 0.200 M KI added reacts in a total

volume of 50.00 mL, the initial concentration of [I-]0 can be calculated as follows:

20.00 mL

[I-]0 = 0.200 M KI = 0.0800 M KI

50.00 mL

Similarly, in Run 1, the initial concentration of [S2O82-]0 is calculated as follows:

20.00 mL

[S2O82-]0 = 0.100 M (NH4)2S2O8 = 0.0400 M (NH4)2S2O8

50.00 mL

On the next page, carry out similar calculations for all other initial values of the

two reactants and complete the appropriate columns in DATA TABLE III.

You are required to:

Show all your calculations

Include units in your calculations, and

Express all measured quantities (including your answer) in the appropriate number of significant figures.

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Chemistry 102

______________________________________________________________________________

EXPERIMENT 1

REACTION RATE, RATE LAW, AND ACTIVATION ENERGY

THE IODINE “CLOCK” REACTION

2015 www./proffenyes.com 14

DATA TABLE I

[I-]0 [S2O82-]0

Run 1

20.00 mL

0.200 M = 0.0800 M

50.00 mL

20.00 mL

0.100 M = 0.0400 M

50.00 mL

Run 2

10.00 mL

0.200 M = 0.0400 M

50.00 mL

Same as in Run 1

Run 3

Same as in Run 1

10.00 mL

0.100 M = 0.0200 M

50.00 mL

Run 4

Same as in Run 1

5.00 mL

0.100 M = 0.0100 M

50.00 mL

(10)

2 . Reaction Rates

In order to determine the Reaction Rates, the following quantities must be known:

Initial concentration of [S2O32-] added and completely used up (see below)

Concentration of [I2] produced, at the time the deep blue color (tcolor) appears.

(see below); Enter this value in the Data Table I on the next page.

The time in seconds when the deep blue color (tcolor) appears for each Reaction

Run (determined experimentally). Enter these data in DATA TABLE III.

DATA TABLE II

[S2O32-]added

[S2O32-]

[I2]produced =

2

All Runs

10.00 mL

0.00500 M = 0.00100 M

50.00 mL

0.00100 M

= 0.000500 M

2

(2)

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Chemistry 102

______________________________________________________________________________

EXPERIMENT 1

REACTION RATE, RATE LAW, AND ACTIVATION ENERGY

THE IODINE “CLOCK” REACTION

2015 www./proffenyes.com 15

DATA TABLE III

Initial Concentrations and corresponding Reaction Rates

RATE*: Express Rate as (A x 10-6) throughout the entire experiment

Run

Nr.

Temp.

(0C)

(Room

Temp)

[I-]0

(M)

[S2O82-]0

(M)

TIME

(tcolor)

(s)

RATE

Expressed as A x 10-6

[I2]produced

tcolor

(M . s-1)

1 23 0.0800 M

0.0400 M

41.0 12.2 x 10 - 6

2 23 0.0400 M

0.0400 M

79.0 6.33 x 10 - 6

3 23 0.0800 M

0.0200 M

84.0 5.95 x 10 - 6

4 23 0.0800 M

0.0100 M

168.0 2.98 x 10 - 6

(8)

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Chemistry 102

______________________________________________________________________________

EXPERIMENT 1

REACTION RATE, RATE LAW, AND ACTIVATION ENERGY

THE IODINE “CLOCK” REACTION

2015 www./proffenyes.com 16

3. Reaction Orders

The general formula for the Rate Law for the reaction studied is:

Rate1 = k [I-]m [S2O82-]n

Rate2 = k [I-]m [S2O82-]n

When performing your calculations you are required to:

Show all calculations neatly, in a well-organized manner and in detail (follow the format of the example shown on page 4 or the sample calculation

presented in your textbook (page 605)

Round off your answer to an integer.

a. Reaction Order with respect to [I-]

From Run 1 and Run 2

Rate 1 12.2 x 10 – 6 M . s-1 k [0.0800 M]m [0.0800]n = =

Rate 2 6.33 x 10 - 6 M . s-1 k [0.0400 M]m [0.0800]n

1.93 = 2.00m

log 1.93

log 1.93 = log (2.00m) log 1.93 = m log 2.00 m = = 0.950

log 2.00

(4)

Value of “m” rounded off to an integer = 1

b. Reaction Order with respect to [S2O82-]

From Run 3 and Run 4

Rate 3 5.95 x 10 – 6 M . s-1 k [0.0800 M]m [0.0200]n = =

Rate 4 2.98 x 10 - 6 M . s-1 k [0.0800 M]m [0.0100]n

2.00 = 2.00n

log 2.00

log 2.00 = log (2.00m) log 2.00 = m log 2.00 n = = 1.000

log 2.00

(4)

Value of “n” rounded off to an integer = 1

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Chemistry 102

______________________________________________________________________________

EXPERIMENT 1

REACTION RATE, RATE LAW, AND ACTIVATION ENERGY

THE IODINE “CLOCK” REACTION

2015 www./proffenyes.com 17

k1 =

4. Rate Constant “k” at Room Temperature

The Rate Constant, “k” can be calculated by substituting the known values of reactant

concentrations, the reaction orders and the corresponding reaction rates in the formula

of the Rate Law. Refer to the example on page 5.

(1) Write the equation for the Rate Law: Rate = k [I- ] [S2 O2- ]

DATA TABLE IV

Calculate “k” for Reactions 1 through 6. Show your calculations and include units!

Run 1

[ I- ] = 0.0800 M [S2 O2- ] = 0.0400 M

Rate1 = 12.2 x 10 – 6 M . s-1

12.2 x 10 – 6 M . s-1

k =

[0.0800 M] [0.0400 M]

k1 = 3.81 x 10-3 M-1 . s-1

Run 2

[ I- ] = 0.0400 M [S2 O2- ] = 0.0400 M

Rate1 = 6.33 x 10 – 6 M . s-1

6.33 x 10 – 6 M . s-1

k =

[0.0400 M] [0.0400 M]

k2 = 3.96 x 10-3 M-1 . s-1

Run 3

[ I- ] = 0.0800 M [S2 O2- ] = 0.0200 M

Rate1 = 5.95 x 10 – 6 M . s-1

5.95 x 10 – 6 M . s-1

k =

[0.0800 M] [0.0200 M]

k3 = 3.72 x 10-3 M-1 . s-1

Run 4

[ I- ] = 0.0800 M [S2 O2- ] = 0.0100 M

Rate1 = 2.98 x 10 – 6 M . s-1

2.98 x 10 – 6 M . s-1

k =

[0.0800 M] [0.0100 M]

k4 = 3.72 x 10-3 M-1 . s-1

(8)

(2) DATA TABLE V

Units Summary of Rate Constants “k” for Reaction Runs at Room Temperature

Run Nr. 1 2 3 4

k

(M-1 . s-1) 3.81 x 10-3 3.96 x 10-3 3.72 x 10-3 3.72 x 10-3

k (Average)

(M-1 . s-1 )

3.80 x 10-3

Write the complete form of the Rate Law:

Include the formulas of both Reactants. Do not include numerical values

Include the respective Reaction Orders for both Reactants

Include the experimentally determined numerical value of “k”, expressed in the correct units.

(2)

13 RATE = 3.80 x 10-3 M-1 . s-1 [I- ] [S2 O2-]

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Chemistry 102

______________________________________________________________________________

EXPERIMENT 1

REACTION RATE, RATE LAW, AND ACTIVATION ENERGY

THE IODINE “CLOCK” REACTION

2015 www./proffenyes.com 18

PART II: THE EFFECT OF TEMPERATURE ON REACTION RATE

To determine the quantitative relationship between Reaction Rate and Temperature you will

be plotting an Arrhenius Plot (ln k versus 1/T) to determine the following Kinetic Parameters:

1. The Activation Energy (Ea)

2. The ratio by which the reaction rate increases when the temperature is increased by 100C

(arbitrarily chosen from 200C to 300C)

1. Determination of the Activation Energy, Ea

Summarize your experimental data for the Reactions Runs with the same concentration of

all reactants (as used in Reaction Run # 1), but run at different temperatures. In this

manner, the corresponding reaction rates for these runs will be affected by temperature

only.

DATA TABLE VI

Run

Nr.

Temp.

Range

Initial

Temperature

of

Reactants

(0C)

Final

Temperature

Of

Reaction

Mixture

(0C)

Average

Temperature

of

Reaction

Mixture

(0C)

Time

(tcolor)

(s)

RATE

[I2]produced

tcolor

(M . s-1)

5 About

00C 4 249 2.01 x 10-6

6 About

100C 11 112 4.46 x 10-6

1 Room

Temp. 23

41.0 12.2 x 10-6

7 About

400C 41 16.0 4.2 x 10-6

(4) Calculate the Rate Constants for Runs 5, 6 & 7 from the respective initial concentrations

of reactants and the corresponding reaction rates.

(8) (Calculation do not need to be shown)

Run

Nr.

Recorded

Average

Temp.

(K)

[I-]0

(M)

[S2O82-]0

(M)

RATE

(M . s-1)

Rate Constant

k

(M-1 . s-1)

(Expressed as A x 10-3)

5 About

00C 277 0.0800 0.0400 2.01 x 10-6 0.628 x 10-3

6 About

100C 284 0.0800 0.0400 4.46 x 10-6 1.39 x 10-3

1 Room

Temp 296 0.0800 0.0400 12.2 x 10-6 Calculated Average

3.80 x 10-3

7 About

400C 314 0.0800 0.0400 31.2 x 10-6 9.75 x 10-3

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Chemistry 102

______________________________________________________________________________

EXPERIMENT 1

REACTION RATE, RATE LAW, AND ACTIVATION ENERGY

THE IODINE “CLOCK” REACTION

2015 www./proffenyes.com 19

Calculate and collect the data that will be used for plotting ln k versus 1/T (The

Arrhenius Plot)

DATA TABLE VIII

(Calculations do not need to be shown)

Run

Nr.

1

T

(K-1)

ln k

5 About

00C 3.61 x 10-3 -7.373

6 About

100C 3.52 x 10-3 - 6.578

1 Room

Temp 3.38 x 10-3 - 5.573

7 About

400C 3.18 x 10-3 - 4.630

(4)

Plot a graph of ln k vs. 1/T

A sample graph is attached to your Report Form. Please follow the format, scale, data

reporting style and all the other details included in the sample graph.

Calculate the slope of the graph and show all the calculations on the graph.

Calculate the Activation Energy (Ea) from the slope of the graph

Please show calculations and include units.

J

Slope: - 6.5 x 103 K Recall: R = 8.314

mol . K

Ea J

Slope = - - Ea = (Slope) x (R) - Ea = (- 6.5 x 103 K ) (8.314 )

R mol . K

1 kJ

Ea = 5.4 x 104 J/mol x = 54 kJ/mol

103 J

Ea = 5.4 x 104 J/mol Ea = 54 kJ/mol

(4)

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Chemistry 102

______________________________________________________________________________

EXPERIMENT 1

REACTION RATE, RATE LAW, AND ACTIVATION ENERGY

THE IODINE “CLOCK” REACTION

2015 www./proffenyes.com 20

2. Determination of the effect of 100C temperature increase on Reaction Rate

Collect your data:

t1 = 200C T1 = 293 K 1/T1 = 3.41 x 10-3 K-1

t2 = 300C T2 = 303 K 1/T2 = 3.30 x 10-3 K-1

Read the corresponding Values for ln k1 and ln k2 from your Arrhenius plot

Indicate these values and the source of these readings on your graph

(as shown on Figure 2, page 8)

ln k1 = - 5.95 ln k2 = - 5.25

Follow the guidelines given below Figure 2 (page 8) to calculates the ratio between

the Reaction Rate at 300C and the Reaction Rate at 200C

Show all your calculations neatly, in a well-organized manner and in detail.

Include units in your calculations Round off your answer to the nearest integer.

k1 = anti ln (- 5.95) = 2.6 x 10-3 M-1 . s-1

k2 = anti ln (- 5.25) = 5.2 x 10-3 M-1 . s-1

Rate2 (300C) k2 [[I-] [S2O82-] 5.2 x 10-3 M-1.s-1 [0.0800 M][0.0400 M]

= = = 2.0 = 2

Rate1 (200C) k1 [[I-] [S2O82-] 2.6 x 10-3 M-1.s-1 [0.0800 M][0.0400 M]

(4)

State your conclusion:

(2) A temperature increase of 100C approximately doubled the reaction rate.

6

Bibliography:

1. Nivaldo J. Tro, “Chemistry: A Molecular Approach”, Third Edition

2. R.A.D. Wentworth “Experiments in General Chemistry”, Sixth Edition

3. James M. Postma & all, “Chemistry in the Laboratory”, Seventh Edition

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Spring 2015

1

Experiment # 1 – The Iodine “Clock” Reaction

Post-Lab Quiz 21/21

Name: ________________________________

Instructions:

1. You may consult your Laboratory Notebook.

2. You may NOT consult any other materials (report forms, syllabus, notes, etc.)

3. Please show all your calculations clearly and neatly in the spaces provided.

No credit is earned by unsupported answers.

4. All numerical answers should be given in in the appropriate units and to the proper number of

significant figures.

1. Write a balanced Net Ionic Equation representing the reaction whose rate is being analyzed. Include

state designations.

Underneath each species involved in the reaction, indicate its name:

(2) NET IONIC EQUATION: 2 I- (aq) + S2O82-(aq) I2(aq) + 2SO4

2-(aq)

(1) NAMES: iodide ion persulfate ion iodine sulfate ion

2. What is the purpose of adding Na2S2O3 (S2O32-) to the reaction mixture?

(2) In order to measure the rate of formation of Iodine (I2), the reaction in which the I2 is formed

(see above) is coupled with a much faster reaction that consumes most of the I2

I2 + 2S2O32- 2I- + S4O6

2- (Reaction 2)

Reaction 2 immediately consumes the I2 generated in the first reaction until all of the S2O32-

(thiosulfate) is used up. When the S2O32- (thiosulfate) is consumed, I2 builds up and reacts with

starch to form the the deep blue Starch-Iodine complex.

The appearance of the deep-blue complex tells us that at this point in time (tcolor)

sufficient I2 has been produced to use up all of the S2O32- (thiosulfate) ion

originally added.

3. Write a net ionic equation that illustrates the chemical reaction in which the

S2O32- (thiosulfate) ion is involved. Include State designations.

(2) I2(aq) + 2S2O32-

(aq) 2I-(aq) + S4O6

2-(aq)

(Reaction 2)

(1) 4. Is the S2O32- ion a reactant in the reaction whose rate is being analyzed? NO

5. What is the numerical relationship between:

The concentration of the [I2) produced

and

The concentration of the [S2O32-] originally added and used up

at the time the blue color appears (tcolor)

Hint: Consider the stoichiometry (mole ratio) of the equation in 2. (b) above.

[S2O32-] originally added and used up

(2) [I2] produced =

10 2

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Spring 2015

2

6. The following experimental data are available:

20.00 mL of 0.200 M KI are mixed with 10.00 mL of 0.00500 M Na2S2O3 in a 250 mL reaction flask. A

few drops of soluble starch are added to this mixture.

5.00 mL of 0.100 M (NH4)2S2O8 are mixed with 15.0 mL of 0.100 (NH4)2SO4 in a

50 mL reaction flask.

When the contents of the two flasks are mixed a deep blue color forms after 78.2 seconds.

(a) Write the chemical formula of Reactant 1 in Ionic Form: I-

Calculate the molarity of Reactant 1 after mixing the contents of the two flasks. Show

calculations and include units.

(2) 20.00 mL

[I-] = 0.200 M x = 0.0800 M

50.00 mL

(b) Write the chemical formula of Reactant 2 in Ionic Form: S2O82-

Calculate the molarity of Reactant 2 after mixing the contents of the two flasks. Show

calculations and include units.

(2) 5.00 mL

[ S2O82-] = 0.100 M x = 0.0100 M

50.00 mL

(c) Calculate the molarity of Na2S2O3 added after mixing the contents of the two flasks.

Show calculations and include units.

(2) 10.00 mL

[ S2O32-] = 0.00500 M x = 0.00100 M

50.00 mL

(d) Calculate the concentration of the [I2] produced at the time the blue color

appears

0.00100 M

(1) [I2] produced = = 0.000500 M

2

(e) Calculate the Rate of Reaction based on your data above, and express it in the proper units.

0.000500 M

(1) Rate = = 6.39 x10 -6 M/s

78.2 s

(f) Calculate the Rate Constant, k, based on your data above and express it in the proper units.

Assume that the reaction is of the first order with respect to both reactants.

(3) Rate 6.39 x10 -6 M/s

k = = = 7.99 x 10-3 M-1 s-1

[I-] [S2O82-] (0.0800 M) (0.0100 M

11