• 1. SS &os Progs 1a %{ #include int sc=0,lc=0,wc=0,cc=0; %} %% [^ t n]+ {wc++;cc+=yyleng;} n {lc++;} " " {sc++;} .; %% yywrap() { return 1; } main() { yyin=fopen("nag.txt","r"); yylex(); fclose(yyin); printf("character count=%dn",cc); printf("word count=%dn",wc); printf("space count=%dn",sc); printf("line count=%dn",lc); } ============================output================================== nag.txt ------nagarjun atria coll 5th sem lex lab student ------------------------------------------------------------------yadavakings@ubuntu:~$ vi 1a.l yadavakings@ubuntu:~$ lex 1a.l yadavakings@ubuntu:~$ cc lex.yy.c yadavakings@ubuntu:~$ ./a.out character count=36 word count=8 space count=3 line count=51b. Nagarjun.E, Atria institute of echnology,Ananadnagar-24Page 24

2. %{ #include int flag=0,n=0,cmt=0; %} %% "//".* {cmt++;} "/*".*"*/" {cmt++;} "/*".* {flag=1;n++;} "n" {if (flag==1)n++;else echo;} .*"*/"{if(flag==1) {cmt+=n;flag=0;n=0;}} . {if (flag==0)ECHO;} %% yywrap() { return 1; } main() { yyin=fopen("nag.c","r"); yyout=fopen("out.txt","w"); yylex(); fclose(yyin); fclose(yyout); printf("number of comment lines= %d",cmt); } =============================output========================================== ========== nag.c ---#include //nagarjun /*atria collstudent*/ /*5th sem*/ int a,b,c; a=b+c; -------------------------------------------------------------------------yadavakings@ubuntu:~$ vi 1b.l yadavakings@ubuntu:~$ lex 1b.l yadavakings@ubuntu:~$ cc lex.yy.c yadavakings@ubuntu:~$ ./a.out number of comment lines= 3 out.txt ------#include int a,b,c; a=b+c;2a. Nagarjun.E, Atria institute of echnology,Ananadnagar-24Page 24 3. %{#include int id=0,op=0,bc=0,i=0,j=0,x,flag=0; char opa[10]; int ida[10];%} %% "(" {bc++;flag=1;} ")" {if(flag==1) {bc--;flag=0;} else bc--;} "+"|"-"|"*"|"/" {op++;opa[i++]=*yytext;} [0-9]+ {id++;ida[j++]=atoi(yytext);} . ; %% yywrap() { return 1; } main() { printf("enter the expression"); yylex(); if((flag!=0)||(bcfile2 if cmp file1 file2 then echo "common permissions" else echo "different permissions" echo "$1 permissions" cat file1 echo "$2 permissions"Nagarjun.E, Atria institute of echnology,Ananadnagar-24Page 24 13. cat file2 fi ================================output============================== yadavakings@ubuntu:~$ vi 8a.sh yadavakings@ubuntu:~$ sh 8a.sh common permissions yadavakings@ubuntu:~$ chmod 222 file2 yadavakings@ubuntu:~$ sh 8a.sh cmp: file2: Permission denied different permissions permissions total 100 -rwx------rw-------rwx------rw-------rw-r--r--rw-r--r--rw-------rw-r--r--rw-r--r--rw-r--r--rw-------rw-------rwxr-xr-x drwxr-xr-x drwxr-xr-x -rw-r--r--rwxrwxrwx --w--w--wdrwxr-xr-x -rw-r--r--rw-r--r--rw-r--r-drwxr-xr-x drwxr-xr-x drwxr-xr-x drwxr-xr-x permissions cat: file2: Permission denied8b. #include #include #include #include int main() { char *cmd = "vi 8b.txt"; char *fname = "8b.txt";Nagarjun.E, Atria institute of echnology,Ananadnagar-24Page 24 14. char *s1 = "ABCDEFGHIJKLMNOP"; char *s2 = "abcdefghijklmnop"; int fd; fd = creat(fname, s.IREAD | s.IWRITE); if(fd==-1) { printf("error in file"); exit(1); } if(write(fd,s1,16)!=16) printf("error"); lseek(fd,48,SEEK_SET); if(write(fd,s2,16)!=16) { printf("error"); } printf("contents of the file aren"); system(cmd); } ====================================output=================================== ===== yadavakings@ubuntu:~$ vi 8b.c yadavakings@ubuntu:~$ cc 8b.c 8b.c: In function main: 8b.c:12: error: s undeclared (first use in this function) 8b.c:12: error: (Each undeclared identifier is reported only once 8b.c:12: error: for each function it appears in.) sorry no output for this..... check and text me....!9a. for i do { echo "echo $i" echo "cat>$iout.sh yadavakings@ubuntu:~$ cat out.sh echo 1.txt cat>1.txt2.txt1.txt2.txt #include #include #include int main() { pid_t ppid,mpid,pid,status=0; pid=fork(); if(pid10 p2->10 p3->10 p4->5 p5->10 p1->5 p2->10 p3->10 p5->10 p2->5Nagarjun.E, Atria institute of echnology,Ananadnagar-24Page 24 18. p3->10 total estimated time10.sjrf #include struct proc { int id, arrival,burst,rem,wait,finish,turnaround; float ratio; } process[10]; struct proc temp; int no; int chkprocess(int); int nextprocess(); void srtf(int); main() { int n; printf("nn enter the number of the processes");Nagarjun.E, Atria institute of echnology,Ananadnagar-24Page 24 19. scanf("%d",&n); srtf(n); } int chkprocess(int s) { int i; for(i=1;i