06/13/22 1 Solid State Physics 2. X-ray Diffraction
Dec 17, 2015
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Solid State Physics
2. X-ray Diffraction
Diffraction
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Diffraction
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1 2 3sin , , , ...m
mW
Diffraction
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Diffraction using Light
http://physics.kenyon.edu/coolphys/FranklinMiller/protected/Diffdouble.html
One Slit
Two Slits
Diffraction Grating
d
m sin
Diffraction
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The diffraction pattern formed by an opaque disk consists of a small bright spot in the center of the dark shadow, circular bright fringes within the shadow, and concentric bright and dark fringes surrounding the shadow.
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Diffraction for CrystalsPhotonsElectronsNeutrons
Diffraction techniques exploit the scattering of radiation from large numbers of sites. We will concentrate on scattering from atoms, groups of atoms and molecules, mainly in crystals.
There are various diffraction techniques currently employed which result in diffraction patterns. These patterns are records of the diffracted beams produced.
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What is This Diffraction?
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Bragg Law
nd sin2
William Lawrence
Bragg1980 - 1971
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Mo 0.07 nmCu 0.15 nmCo 0.18 nmCr 0.23 nm
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Monochromatic Radiation
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Diffractometer
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Nuts and Bolts
The Bragg law gives us something easy to use,To determine the relationship between diffractionAngle and planar spacing (which we already knowIs related to the Miller indices).
But…We need a deeper analysis to determine theScattering intensity from a basis of atoms.
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Reciprocal Lattices Simple Cubic Lattice
1 2 3ˆ ˆ ˆa x a y a za a a
1 2 32 2 2
ˆ ˆ ˆx y z
******************************************G G G
a a a
The reciprocal lattice is itself a simple cubic lattice with lattice constant 2/a.
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BCC Lattice1 1
1 22 2
13 2
ˆ ˆ ˆ ˆ ˆ ˆa ( x y z) a (x y z)
ˆ ˆ ˆ a (x y z)
a a
a
1 2 32 2 2
ˆ ˆ ˆ ˆ ˆ ˆy z x z x y
******************************************G G G
a a a
The reciprocal lattice is represented by the primitive vectors of an FCC lattice.
Reciprocal Lattices
310 1 2 3 2a a a a
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FCC Lattice
1 11 22 2
13 2
ˆ ˆ ˆ ˆ ˆ ˆ( x y z) (x y z)
ˆ ˆ ˆ (x y z)
****************************
**************G a G a
G a
1 2 3
2 2 2ˆ ˆ ˆ ˆ ˆ ˆa y z a x z a x y
a a a
The reciprocal lattice is represented by the primitive vectors of an BCC lattice.
Reciprocal Lattices
30 1 2 3a a a a
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Drawing Brillouin ZonesWigner–Seitz cell
The BZ is the fundamental unit cell in the space defined by reciprocal lattice vectors.
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Drawing Brillouin Zones
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Back to Diffraction
Diffraction is related to the electron density.Therefore, we have a...
The set of reciprocal lattice vectors determines the possible x-ray reflections.
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The difference in path length of the of the incident wave at the points O and r is sinrThe difference in phase angle is rk
sin2
r
For the diffracted wave, the phase difference is k r ****************************
So, the total difference in phase angle is r)kk(
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Diffraction Conditions Since the amplitude of the wave scattered
from a volume element is proportional to the local electron density, the total amplitude in the direction k is
dVen
dVenf
i
i
r )k(
r kk
)r(
)r(
kkk
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Diffraction Conditions When we introduce the Fourier
components for the electron density as before, we get
( k) r i ss
s
f n e dV
ks Constructive
Interference
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Diffraction Conditions
kkk
k ks
ks
nd sin2
2 2
2
(k )
or 2 k
s k
s s
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r
cell ( r ) i s
sF N n e dV NS
Diffraction Conditions For a crystal of N cells, we can write down
)rr()r(1
j
s
jjnn
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r
cell j
r
( r r )
( )j
i s
s jj
i s i s
jj
S n e dV
e n e dV
Diffraction Conditions The structure factor can now be written as
integrals over s atoms of a cell.
( )
i s
j jf n e dV
Atomic formfactor
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Diffraction Conditions Let
Then, for an given h k l reflection
1 2 3a a aj j j jr x y z
1 2 3 1 2 3r ( a a a ) ( a a a )j j j j
j j j
s h k l x y z
hx ky lz
2 j j ji hx ky lz
s jj
S f e
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Diffraction Conditions For a BCC lattice, the basis has identical
atoms at and
The structure factor for this basis is
S is zero when the exponential is i × (odd integer) and S = 2f when h + k + l is even.
So, the diffraction pattern will not contain lines for (100), (300), (111), or (221).
)0,0,0(),,( 111 zyx ),,(),,( 21
21
21
222 zyx
)1( 2 lkhiG efS
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Diffraction Conditions For an FCC lattice, the basis has identical
atoms at
The structure factor for this basis is
S = 4f when hkl are all even or all odd. S = 0 when one of hkl is either even or
odd.
0 and ,0 ,0 ,000 21
21
21
21
21
21
)1( khilhilkiG eeefS
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Structure Determination
222
lkh
ad
Simple
Cubic
2222
2
4sin lkh
a
When combined with the Bragg law:
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(degrees) sin2 ratios hkl
11.44 0.0394 1 100
16.28 0.0786 2 110
20.13 0.1184 3 111
23.38 0.1575 4 200
26.33 0.1967 5 210
29.07 0.2361 6 211
34.14 0.3151 8 220
36.53 0.3543 9 300, 221
38.88 0.3940 10 310
X-ray powder pattern determined using Cu K radiation, = 1.542 Å
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Structure Determination (310)
angstroms 88.3
104
)5420.1(3940.0
4sin
2
2
2222
2
aa
lkha
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