5: 1 of 30 COPYRIGHT © AREMA 2012 Module 5:Tractive Effort
Dec 18, 2015
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Module 5:Tractive EffortModule 5:Tractive Effort
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Module Objectives
• Learn About Tractive Effort (the Amount of Force at the Wheels Available for Moving a Train)
• Understand the Effects of Combining Steep Grades and Horizontal Curvature
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Energy UtilizationThe two primary aspects of transportation energy efficiency:
– Resistance – How much work is required to move something
– Energy Efficiency – How well energy is converted into useful work
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Train Resistance
Resistance is typically measuredin “pounds per ton” (in U.S.)
Friction
• For our purposes, Resistance is the combination of forces that work against a train’s movement.
• Early measurement of railcar resistance simply involved piling on weight, w, and determining how much was needed to make the car move.
• If the weight, w, is great enough to overcome the static friction, the car will start to move.
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Trains VS. Trucks• Trains require less energy to move than trucks because of smaller resistive forces:
• Lower friction factor (0.18)– Smaller contact area
– Steel wheels on steel rails
– Rubber tires on pavement
• Less wind resistance per pound of load
• Size of contact area?
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Horsepower Tractive EffortHorsepower Tractive Effort• Tractive Effort
– The point of contact between the wheel and the rail is where the torque of the motor is converted to a force that is called tractive effort.
Power to auxiliaries(cooling fans,motor blowers,locomotive controls, airBrake compressor, etc)
Loss in generator (orAlternator/ rectifier)Converting crankshaftPower to electricity
Traction motor lossesGear friction
Power to move, lift,& accelerate weight oflocomotive itself(varies with speed, grade,Curvature, loco/ trainWeight ratio)
)(308
lb-fV
HPTE
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Traction ForcesTraction Forces
W
TE
WTEmax x
=AdhesionW = Weight on Drivers
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AdhesionAdhesion Adhesion
– Percentage of a locomotive’s weight on its driving wheels, converted into tractive effort.• DC locomotives can achieve a
maximum peak of 30 % adhesion on dry rail.
• Through advanced control, AC locomotives can achieve up to 40 % adhesion in many weather conditions.
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Factors Affecting AdhesionFactors Affecting AdhesionWheel/Rail Contact Factors• Wheel-Rail materials• Hertzian (Rolling Wheel)
Stresses• Rail Metal Creep
(Longitudinal Movement)
Track factors• Rail surface condition• Rail profile irregularities• Curvature of track
Vehicle factors• Mechanical
– Loco weight and axle weight distribution
– Weight transfer– Speed– Wheel size variation
• Electrical– Torque control method– Traction motor
characteristics– Power circuit
configuration– Slip-slide control
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Train ResistanceTrain Resistance
• Two Elements:– Rolling Resistance (On Level Tangent Track)
• Friction related• Journal, wheel, track quality, track modulus• Aerodynamics of equipment
– Grade & Curve Resistance• Track Profile & Alignment related• Change in potential energy head
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Rolling ResistanceRolling ResistanceRolling ResistanceRolling Resistance• Rolling Resistance
– The resistance for train movement on straight and level track can be determined by W. J. Davis formula:
R=A+BV+CV²Where
R= Train rolling resistanceA= Rolling resistance component independent of train speedB= Train resistance dependant on speedC= Drag coefficient based on the shape of the front of the train and other features affecting air turbulanceV= Train speed
– The Train resistance on level tangent track is the sum of locomotive and train resistances.
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Freight Train Speed V Resistance
At low speeds, journal resistance dominates, as speed increases air resistance is increasingly most important
Res
ista
nce
(lbs.
/ton)
Speed (mph)10 20 30 40 50 60 70 80 90 100
0
1
2
3
4
5
6
7
8
"Journal" Resistance (A)
"Flange" Resistance (BV)
Air Resistance (CV2)
CV2
BV
A
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Davis Equation Modifications• The Davis Equation has been substantially updated to reflect
modern developments, but its basic form is the same.
• Ro = 1.5 + 18N/W + 0.03V + CaV2/10,000W (CN Equation 1990)
where:
Ro = resistance in lbs. per ton
N = Number of Axles
W = Total Weight in Tons of Locomotive or Cars
V = Velocity of Train (MPH)
a = Cross-sectional Area of Vehicle in ft2
C = Canadian National Streamlining Coefficient
– See AREMA Manual for Railway Engineering Chapter 16 - 2.1.3 for latest version of formula
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Resistance Versus Speed
0
10,000
20,000
30,000
40,000
50,000
60,000
0 10 20 30 40 50 60 70 80
Re
sist
ance
(lb
s.)
Speed (mph)
10,000 Ton Train
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Grade Resistance
1% Grade = Approximately 20 lbf / ton
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Curve Resistance
10 = 0.8 lbf / ton
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Compensated Grade
Gc = G + Dc * 0.04
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Typical Freight Consist
Typical modern freight consist
6000 horsepower,212 tons
100 cars x 143 tons each = 14,300 tons
Typical modern locomotive
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Speed/Tractive Effort Curve
0
20,000
40,000
60,000
80,000
100,000
120,000
140,000
160,000
180,000
0 10 20 30 40 50 60 70 80
Tra
ctiv
e E
ffort
(lb
s.)
Speed (mph)
At low speed, tractive effort is limited by adhesion, not power
Modern Locomotive - Level Grade
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0
20,000
40,000
60,000
80,000
100,000
120,000
140,000
160,000
180,000
0 10 20 30 40 50 60 70 80
Tra
ctiv
e E
ffort
(lb
s.)
Speed (mph)
Tractive force = resistance @ 35,000 lbs.
Modern Locomotive - Level Grade
Maximum Possible Train Speed?
At low speed, tractive effort is limited by adhesion, not power
Train Resistance
About 58 mph. This is referred to as the “balancing speed, why?
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0
20,000
40,000
60,000
80,000
100,000
120,000
140,000
160,000
180,000
0 10 20 30 40 50 60 70 80
Tra
ctiv
e E
ffort
(lb
s.)
Speed (mph)
• Available acceleration declines as speed increases• At balanced speed it is zero.• So, the rate of acceleration declines with speed.
Q: How much force is available for acceleration at 15 mph?
Q: How much force is available for acceleration at 35 mph?
A: 135,000 - 15,000 = 120,000 lbs.
A: 59,000 - 21,000 = 38,000 lbs.
Resistance V Acceleration
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Capability of “multiple unit” control makes this possible
0
50,000
100,000
150,000
200,000
250,000
300,000
350,000
0 10 20 30 40 50 60 70 80
Tra
ctiv
e E
ffort
(lb
s.)
Speed (mph)
What If We Need More PowerT
ract
ive
Effo
rt (
lbs.
)
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Freight Time/Speed Graph
This curve depicts a single locomotive.How will the curve change if a second locomotive is added?
0
10
20
30
40
50
60
70
0 500 1000 1500 2000 2500 3000
Spe
ed (
mph
)
Time (seconds)
About 900 seconds = 15 minutes
How long will it take for this train to reach 40 mph?
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Time/Speed Graph
0
10
20
30
40
50
60
70
0 500 1000 1500 2000 2500 3000
Spe
ed (
mph
)
Time (seconds)
Now how long will it take to reach 40 mph?
About 300 seconds≈ 5 minutesS
pee
d (
MP
H)
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Freight Distance/Speed Graph
0
10
20
30
40
50
60
70
0
50,0
00
100,
000
150,
000
200,
000
250,
000
300,
000
350,
000
400,
000
Sp
ee
d (
mp
h)
Distance (feet)
How many miles until this train reaches 40 mph?
Velocity Profile h (ft) = 0.03 V2
About 75,000 feet ≈ 14 miles
Sp
eed
(M
PH
)
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2 Unit Distance/Speed Graph
0
10
20
30
40
50
60
70
0
50,0
00
100,
000
150,
000
200,
000
250,
000
300,
000
350,
000
400,
000
Sp
ee
d (
mp
h)
Distance (feet)
With 2 locomotives, only about 25,000 feet ≈ 5 miles
Sp
eed
(M
PH
)
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Horsepower:Trailing Tonnage• Long-distance train with
few stops along the way.– Low horsepower:trailing ton
ratio. 12,000 hp: 14,300 tons = 0.83 hp:ton
– Typical of many freight trains
• High-speed train with frequent stops and starts.– High horsepower:trailing ton
ratio may be as high as2 to 4 hp:ton
– Typical of intermodal trainsand may be even higher for passenger trains
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Stopping the Train
• Safety is the most important consideration!
• Adhesion Limits Braking Ability.
• Stopping Train Vs. Motor Vehicle.
6,000’
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Stopping Distance V Speed
0
10
20
30
40
50
60
70
0 1,000 2,000 3,000 4,000 5,000 6,000 7,000 8,000
Spe
ed (
mph
)
Distance (feet)
Stopping a train can often take a mile or more
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QUESTIONS?Authors:
Joseph E. Riley, P.E.
Federal Railroad Administration
(202) 493-6357
Paul Li
UMA Engineering
(780) 486-7914
Revisions:
Robert Kimicata, P.E.
Kimicata Rail Consulting
(847) 394-4105
John G. Green, Ph.D., P.E.
CH2M Hill, inc.
(213) 348-5030