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Jun 01, 2018

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    AS-evel !aths"!echanics #for Edexcel

    M2.4 Work and

    Energy

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    $onte

    nts

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    %nerg&

    %nerg&

    'or(

    $onservation of energ&

    'or(-energ& and dissipative forces

    Power

    %)amination-st&le *uestions

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    !echanical energ&

    Energy is measured in+oulesor (ilo+oules, reresented

    !y " or k".

    !echanical energ&is energy t#at a arti$%e #as due to

    eit#er its motion or its osition.

    Energy e&ists in many forms. '#ese in$%ude e%e$tri$a%

    energy, $#emi$a% energy, #eat energy and %ig#t energy.

    Me$#ani$a% energy is t#e energy t#at wi%% !e

    $onsidered in M2. (t $omes in two forms ) (inetic

    and potentialenergy.

    %nerg&is a measure of a arti$%es $aa$ity to do work.

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    inetic and potential energ&

    inetic %nerg&

    *ineti$ energy is t#e energy a arti$%e ossesses due to itsmotion.

    *ineti$ Energy is defined as

    w#ere mis mass in kg and vis seed in ms+1.

    ravitational Potential %nerg&

    ra-itationa% otentia% Energy is t#e energy a arti$%e

    ossesses due to its position. (t is stored energy.

    /#ange in ra-itationa% otentia% Energy is defined as

    w#ere mis mass in kg,gis a$$e%eration due to gra-ity and his

    t#e -erti$a% distan$e tra-e%%ed in metres.

    mv2

    mgh,

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    inetic energ&

    ind t#e kineti$ energy of t#e fo%%owing

    a 5 arti$%e of mass 0. kg tra-e%%ing at ms+1

    ! 5 $ar of mass 700 kg tra-e%%ing at 1 ms+1

    $ 5 !u%%et of mass 20 g tra-e%%ing at 00 ms+1

    a *.E., in 8ou%es, 9 : m : -2

    9 : 0. : 2

    9 /

    ! *.E., in 8ou%es, 9 : m : -2

    9 : 700 : 1

    2

    9 0 #10

    $ *.E., in 8ou%es, 9 : m : -2

    9 : 0.02 : 002

    9 #100

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    ind t#e gra-itationa% otentia% energy of t#e fo%%owing, stating

    w#et#er it is a gain or %oss in gra-itationa% otentia% energy

    ravitational potential energ&

    a ..E., in 8ou%es, 9 m:g: h

    9 2 : 7. :

    9 1/.2 '#is is a gain in ..E.

    ! ..E., in 8ou%es, 9 m:g: h

    9 00 : 7. : 0

    9 #31 000 '#is is a %oss of ..E.

    $ ..E., in 8ou%es, 9 m:g: h

    9 0 : 7. : ;

    9 12 200 '#is is a gain in ..E.

    a 5 arti$%e of mass 2 kg raised a -erti$a% distan$e of m

    ! 5 %ift of mass 00 kg des$ending 0 m -erti$a%%y

    $ 5 man of mass 0 kg $%im!ing a -erti$a% distan$e of ; m.

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    %nerg& *uestion

    4uestion ind t#e gain in kineti$ energy of a $ar of mass

    00 kg as it a$$e%erates from 10 ms+1

    to 2 ms+1

    .

    (nitia% *.E. 9 : m: v2

    9 : 00 : 102

    9 40 000

    ina% *.E. 9 : m: v2

    9 : 00 : 22

    9 20 000

    '#erefore t#e gain in kineti$ energy of t#e $ar is #0 0005.

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    %nerg& *uestion #

    4uestion # 5 $#i%d of mass 30 kg s%ides down a s%ide of

    %engt# 4 m in$%ined at an ang%e of 30< to t#e #ori=onta%. Bymode%%ing t#e $#i%d as a arti$%e and t#e s%ide as a smoot#

    in$%ined %ane, find t#e %oss of gra-itationa% otentia% energy

    of t#e $#i%d.

    30

    ..E. 9 m:g: h

    9 30 : 7. : 4sin30

    @ire$tion of motion

    2 kg

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    'or( *uestion 6

    4uestion 6 5 stone of mass 0 g fa%%s from t#e to of

    a $%iff of #eig#t ; m. ind t#e work done !y gra-ity ast#e stone fa%%s.

    0.0g >

    Work done 9 for$e : distan$e

    9 ?0.0 : 7. : ;

    9 36.;

    '#erefore t#e work done !y gra-ity is 6/.71 5.

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    'or( *uestion 3

    4uestion 3 5 arti$%e of mass kg is u%%ed m u a

    roug# %ane in$%ined at an ang%e of 60< to t#e #ori=onta%.'#e $oeffi$ient of fri$tion !etween t#e %ane and t#e

    arti$%e is 0.3.

    60

    a ind t#e work done against fri$tion.

    ! ind t#e work done against gra-ity.

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    'or( *uestion 3

    a 'o find t#e work done against t#e fri$tiona% for$e it is first

    ne$essary to find t#e fri$tiona% for$e.Aeso%-ing erendi$u%ar to t#e %ane

    R9 g$os60< 9 2.g

    F9R

    9 0.3 : 2.g9 ;.3

    '#e fri$tiona% for$e is ;.3 >.

    '#e distan$e tra-e%%ed in t#e dire$tion oosite to t#e

    fri$tiona% for$e is m.

    Work done against fri$tion 9 ;.3 : 9 12.2 5.

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    'or( *uestion 3

    ! 'o find t#e work done against gra-ity it is ne$essary to

    $a%$u%ate t#e -erti$a% distan$e tra-e%%ed.

    Work done against gra-ity 9 g: sin60ewtonFs e$ond Law.

    5 arti$%e of mass mkg is mo-ed a distan$e of

    dm #ori=onta%%y !y a $onstant #ori=onta% for$eF>.

    Let t#e initia% seed !e ums+1

    and t#e fina% seed !evms+1.

    Work @one 9 /#ange in *ineti$ Energy

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    Remember:

    s= distance

    u= initial velocity

    v= final velocity

    'or(-energ& principle

    By >ewtonFs e$ond Law

    F9 maa9FGm

    '#is gi-es Fd9 mv2) mu2

    in$e t#e for$e is assumed $onstant, t#e a$$e%eration

    $an a%so !e assumed $onstant.Hsing v29 u2D 2as

    v29 u2D 2 :FGm : d

    2Fd

    mv2

    = u2

    D

    mv29 mu2DFd

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    'or(-energ& *uestion

    4uestion 5 arti$%e of mass 3 kg is u%%ed 6 m !y a

    #ori=onta% for$e of 10 > a$ross a smoot# #ori=onta% surfa$e.(f t#e arti$%e started from rest, find its seed w#en it #as

    tra-e%%ed 6 m.

    10 >3 kg

    @ire$tion of motion

    Work done 9Fd9 10 : 6 9 60

    Fd9 mv2) mu2

    Work done 9 mv2) mu29 60

    : 3 : v2) 0 9 60

    1.v29 60

    v9 6.32 ?3 s.f.

    '#erefore t#e seed of t#e arti$%e w#en it #as

    tra-e%%ed 6 m is /.6# ms-.

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    'or(-energ& *uestion #

    4uestion # ind t#e #ori=onta% for$e t#at $auses a arti$%e

    of mass 2. kg to in$rease seed from 2 ms+1

    to ms+1

    o-era distan$e of 10 m on a smoot# #ori=onta% surfa$e.

    Work done 9 $#ange in kineti$ energy

    (nitia% *.E. 9 : 2. : 229

    ina% *.E. 9 : 2. : 29 31.2

    /#ange in kineti$ energy 9 26.2

    Work done 9Fd9 10F9 26.2F9 2.62

    '#erefore t#e reIuired for$e is #./#1 N.

    ' ( d di i ti f

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    'or( and dissipative forces

    Work done against a dissipative forceis eIua% to t#e %oss of

    t#e tota% me$#ani$a% energy of t#e system.

    5 dissipative forceis a for$e w#i$# $auses a arti$%e to

    %ose energy.

    ri$tion and air resistan$e are e&am%es of dissiati-e for$es.

    '#is means t#at t#e rin$i%e of $onser-ation no %onger

    a%ies, as t#e tota% me$#ani$a% energy of t#e arti$%e is

    not $onstant.

    ' ( d di i ti f

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    'or( and dissipative forces

    %)ample 5 arti$%e of mass 3 kg is mo-ing down a roug#

    s%oe in$%ined at an ang%e of 30< to t#e #ori=onta%. '#earti$%e asses a ointAat 3 ms+1and a ointB2 m down

    t#e s%oe at 4 ms+1. /a%$u%ate t#e work done against fri$tion.

    ain in *.E. 9 : 3 : 42) : 3 : 32

    9 10. "

    Loss in ..E. 9 3 :g: 1 9 27.4 "

    sin30< 9 h 2

    Loss of energy 9 27.4 ) 10. 9 1.7

    Work done against fri$tion 9 2.8 5

    h2 m

    30, find t#e ower rodu$ed !y t#e $y$%ist.

    in$e t#e seed is $onstant t#ere is no a$$e%eration.

    '#erefore, dri-ing for$e 9 resistan$e for$e.

    @ri-ing for$e 9 20 >

    Ke%o$ity 9 ; ms+1

    ower 9 20 : ; 9 30 '

    %)amination st&le *uestions

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    $ontents

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    %)amination-st&le *uestions

    %nerg&

    'or(

    $onservation of energ&

    'or(-energ& and dissipative forces

    Power

    %)amination-st&le *uestions

    %)am *uestion

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    %)am *uestion

    %)amination-st&le *uestion 5 $ar of mass 1000 kg

    mo-es a%ong a straig#t, #ori=onta% road. '#e $ar engine isworking at a $onstant rate of 4 kW and t#e tota% resistan$e

    to t#e motion of t#e $ar is 00 >.

    a ind t#e a$$e%eration of t#e $ar w#en its seed is 1 ms +1.

    '#e $ar $omes to a #i%% w#i$# is in$%ined at an ang%e of to t#e #ori=onta%, w#ere sin9 0.1. '#e resistan$e to t#e

    motion of t#e $ar is un$#anged.

    ! ind t#e ma&imum seed of t#e $ar u t#e #i%% w#en it

    is working at a rate of 4 kW.

    %)am *uestion

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    %)am *uestion

    ower 9 or$e : Ke%o$ity

    5%ying >ewtonFs e$ond Law,F9 ma

    3000 ) 00 9 1000a1000a9 200

    a9 2.'#erefore t#e a$$e%eration of

    t#e $ar w#en it is tra-e%%ing at

    1 ms+1is #.1 ms-#.

    00 > D1000

    aa 'o $a%$u%ate t#e a$$e%eration

    it is first ne$essary to$a%$u%ate t#e dri-ing for$e.

    oweror$e 9

    Ke%o$ityo,

    4 0009 9 30001

    D

    %)am *uestion

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    %)am *uestion

    RD

    1000g00 >

    5%ying >ewtonFs e$ond Law u t#e s%oe,

    D) 00 ) 1000gsin9 0D9 00 D 1000g: 0.1 9 140

    '#e dri-ing for$e of t#e $ar is 140 >.

    ower 9 or$e : Ke%o$ity

    ! Before $a%$u%ating t#e

    ma&imum seed of t#e $arit is first ne$essary to

    $a%$u%ate t#e dri-ing for$e.

    '#e ma&imum seed of t#e $ar is 60.3 ms-

    .

    ower

    Ke%o$ity 9 or$e

    . ( )4 000

    30 4 3 s.f.140

    v = =

    %)am *uestion #

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    %)am *uestion #

    %)amination-st&le *uestion # 5 stone of mass 0. kg is

    s%iding down a roug# %ane in$%ined at an ang%e of 1< to t#e

    #ori=onta%.

    '#e stone asses a ointAwit# a seed of 10 ms+1and a

    ointBwit# a seed of 6 ms+1.

    a ind t#e %oss of me$#ani$a% energy of t#e stone as itmo-es from ointAto ointB.

    ! /a%$u%ate t#e $oeffi$ient of fri$tion !etween t#e stone and

    t#e %ane.

    %)am *uestion #

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    %)am *uestion #

    a Loss of energy of t#e stone 9 %oss of *.E. D %oss of ..E.

    (nitia% *.E. 9 : 0. : 102

    ina% *.E. 9 : 0. : 62

    Loss of *.E. 9 2 ) 7 9 16 "

    1 at an ang%e of 30< to t#e %ine of greatest s%oe of t#e

    %ane.

    '#e a$$e%eration of t#e ar$e% u t#e %ane is 0.1 ms+2

    andt#e tota% resistan$e to motion isR>.

    a ind t#e work done !y t#e for$e in #au%ing t#e ar$e%,

    from rest, 10 m u t#e s%oe.

    ! By $onsidering work and energy, find t#e -a%ue of R.

    %)am *uestion 6

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    %)am *uestion 6

    a Work done 9 for$e : distan$e

    in$e t#e for$e a$ts at an ang%eof 30< to t#e s%oe, t#e

    $omonent of for$e a$ting a%ong

    t#e s%oe must !e $a%$u%ated.

    300 >

    30