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36. Hydrocarbon 4

Jun 04, 2018

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Ajay Surana
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    Alkynes

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    Session objectives

    1. Preparation of alkynes by

    (a) Kolbes method

    (b) dehydrohalogenation of vicinal dihalide

    (c) dehydrohalogenation of geminal dihalide2. Chemical reactions of alkyne

    (a) Addition of halogen, hydrogenhalides.

    (b) Ozonolysis

    3. Confirmatory test for alkyne

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    General characteristics ofalkynes

    General formula CnH2n2sp hybridizationCC bond length 1.2 A0

    Shows chain and functionalisomerism

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    Chain isomerism

    CH3

    CH2 CH2 C CH CH3 CH C CH

    CH3

    CH3

    C CH CH2 C CH2

    Functional group isomerism

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    Preparation

    Kolbe electrolysis

    At anode At cathode

    CH

    2CO22HNaOH2

    CHCOOCH

    .

    Na2

    OH2.

    CHCOO.CH.

    NaCHCOO CHCOO Na2

    NaCOOCH CHCOO C2

    CH

    Sodium maleate-2e-

    e-

    Current

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    Dehydrohalogenation of vicinaldihalides

    CH3

    CH CH2

    Br Br

    CH3

    C

    2KOH (alc)2H2OCH + 2KBr +

    From gem dihalides

    CH3

    Cl

    Cl

    KOH.alc

    + 2 KCI + 2 H2O

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    Miscellaneous methods

    Miscellaneous methodsFrom CaC2

    CaC H O HC CH Ca(OH) 2 2 2

    Lime

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    Chemical properties

    Addition Reactions

    (i) Addition of hydrogen

    CH3C

    NiCH

    3CH

    2CH

    3

    Propyne

    CH + 2H2

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    Chemical properties

    CH3

    H3C

    H H

    CH3

    CH3 C CC C

    H2/ Lindlar

    Catalyst

    H

    H

    CH3

    H3C

    CH3CH3C C CC

    Na/NH3(liq.)

    Trans-2-butene

    Lindlar catalyst

    (H2/Pd/BaSO4) partially reduces adisubstituted alkyne to a cis-alkene.

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    Chemical properties

    Addition of halogens

    HC CHBr

    22

    Br Br| |

    H C C H

    | |

    Br Br

    Addition of hydrogen halides

    HC CH 3 22HBr CH CH Br

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    Mechanism

    CHCH3 C CH3

    CH3 C

    +CH

    3

    Br

    CH3

    CH2

    BrBr

    Br

    Br

    CH3CH3

    CH2

    Br

    CH

    HBr

    (2) more stable (1) less stable

    C CHBr

    Major product

    (Anti Markownikoff addition)

    CH3 CH CHBrCH

    3CH +C HBr

    Peroxide

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    Addition of water

    HC CH + H2O

    HgSO4

    H2SO

    4

    CH2 CHOH

    CH

    3CHO

    Unstable

    CH3

    CH2CH3

    CH3

    CH3

    O

    C C

    H2O/H+

    HgSO4

    C

    CH3C CCH2CH3

    O

    CH3CCH2CH2CH3CH3CH2CCH2CH3

    (Major) (Minor)

    O

    H2O/H+

    HgSO4+

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    Hydroboration oxidation

    CH3C CHCH

    3CH

    HC

    R2BH

    0-10CBR2

    H2O2/OH-

    CH3

    CH

    O

    CH

    H

    CH3CH

    2CHO

    Aldehyde

    Tautomerization

    : :

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    Oxidation of alkynes

    HCCOOH

    COOH

    CH CO2+ H2OStrong heatingalk.

    CHCH3C CH3COOH + CO2+ H2O

    4KMnO.alk

    CH3

    C CCH3

    CH3COOH + CH

    3COOH

    alk . KMnO4

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    Ozonolysis of alkynes

    RC CR + O3

    RC C R

    O

    O O

    RCOOH + RCOOH

    RC C R + H2O

    2

    O O

    H2O

    HC CH + O3 H C C H

    O

    O O

    H C C H + HCOOH

    O O

    H2O

    2

    H2

    O

    MajorMinor

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    Formation of alkynides

    CH AgNO3

    C Ag

    +2 RC + 2 NH4OH

    (Tollens' reagent)

    +2 RC

    White ppt

    + 2 NH4CI 2 H2O +

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    Formation of alkynides

    CH + Cu2Cl

    2 CCu2 RC +2 RC 2 NH4Cl + 2H2O

    Red ppt

    2 NH4OH+ +

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    Acidity of Alkynes

    H

    H

    H H

    H

    H

    H H

    H

    CCC C : :

    :

    C C- - -

    Acetylide anions Vinyl anion Ethyl anion

    - - -2 5 2C H > CH = CH > HC C

    2 2 3 3HC CH>CH =CH >CH -CH

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    Acidity of Alkynes

    HC CH Na HC C Na H 21

    2sodium. acetylide

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    Acidity of Alkynes

    The order of boiling point among hydrocarbons is

    alkynes > alkenes > alkanes.

    These hydrocarbons also possess low dipole moment.

    = 0.80 D

    CH CH C CH CH CH CH CH CH C C CH 3 2 3 2 2 3 3

    = 0.30 D = 0.0 D

    Acetylene having two hydrogen atoms is more acidic

    than a mono substituted acetylene.

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    Class exercise

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    Class exercise 1

    Hence, the answer is (c)

    Solution:

    How will you effect the followingconversions?

    CH4 CH2 CH2(a)

    CH3C CH3COCH3CH(b)

    (a) (i) Cl2+ hn (ii) Wurtz reaction

    (iii) Cl2+ hn (iv) alc. KOH, heat

    (b) (i) HgSO4, H2SO4(20%)

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    Class exercise 2

    Write the structural formula of themain organic product.

    Hence, the answer is (b)

    Solution:

    C CH

    CH3

    (i)

    H2O/H+

    HgSO4

    CH3C CH(ii)2 HOCl

    CH3C CCH

    2CH

    2CH

    3(iii)

    H2/Lindlar's

    Catalyst

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    Solution

    O

    (i)

    CH3CCHCl

    2

    O

    (ii)

    H H

    (iii)

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    Class exercise 3

    Give a chemical test to distinguishbetween 1-butyne and 2-butyne.

    Solution:

    1 butyne will give white ppt. with ammonical AgNO3.

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    Class exercise 4

    A cylinder contains one of thefollowing gases propyne,

    propene, propane. What chemicaltest would you apply to identifythe gases?

    Solution:

    AgNO3(ammonical) is used for alkyne, alk. KMnO4,and heat is applied for alkene. No reaction takes placewith propane with the above mentioned reagents.

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    Class exercise 5

    Write the product of thefollowing reaction.

    Solution:

    CH3CH

    2CHCl

    2

    Alkali

    Boil

    CH3CH2CHO

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    Class exercise 6

    Solution:

    What reaction of an appropriatealkyne would lead to the following

    product?

    H3C

    Br

    Br

    CH2CH3

    C C

    CH3

    C CCH2CH

    3

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    Class exercise 7

    An organic compound (A) havingmolecular formula when treated

    with NaNH2/ NH3followed by reactionwith n-propyl bromide yielded (B) .Compound (A) gives a ketone (C)when treated with acidified HgSO4

    .(B) on oxidation with hot alk. KMnO

    4

    gives two isomeric acids (D) and (E).Deduce structures from (A) to (E).

    Solution:

    A: B:O

    CCOOH

    D

    COOHE:

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    Class exercise 8

    Write the correct product of thefollowing reaction.

    Solution:

    HC CH+2HOCl ? Product

    Cl2CHCHO

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    Class exercise 9

    Write the products of the followingreaction.

    Solution:

    H C C HNa C2H5Br

    KMnO4, Hot

    O3, distillation

    (A) (B)

    (C) + (D) + (E)

    (F) + (G)

    HC C NaA is +

    H C C C2H5B is

    C is CO2

    D is C2H5CO2H

    E is H2O

    F is HCOOH

    G is C2H5COOH

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    Class exercise 10

    Write the intermediate steps of thefollowing reaction

    Solution:

    C6H

    5CHC CH C6H5CH CHCHO

    OH

    H3O+

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    Solution

    C6H

    5CH C CH

    OH

    C6H

    5CH C CH

    OH2

    C6H

    5CH C CHC6H5CH

    C

    CH

    H2O , H

    C6H

    5CH C CH OH

    C6H

    5CH CH CH O

    +

    H2O

    +

    +

    +

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    Thank you