PERMUTATION & COMBINATION
Dec 03, 2014
PERMUTATION &
COMBINATION
MULTIPLICATION RULE
If an operation can be performed in r different ways and a second operation can be performed in s different ways, then both the operations can be performed successively in r x s ways.
Multiplication Rule/Principle
10
23
7
9
2 3 4 24=
The number of ways the outfit can be chosen =
PERMUTATION
In permutation, the order of the objects or outcomes is important. Each different order represents a different outcome.
Permutation – variation, order
Arrangement
PERMUTATION
Permutation – the arrangement is important
How many ways can the letter X and Y be arranged?
There are two ways two different permutation
COMBINATIONS
In Combinations, we do not arrange the selections in order.
Combination – grouping,selection
Choices
Combination Arrangement is not important
Or
Are the same one combination
Tom & Jerry Jerry & Tom
Tom & Jerry
Jerry & Tom
They are the same
cat
& the mouse
OR
DIFFERENCES BETWEEN PERMUTATIONS AND COMBINATIONS
PERMUTATIONS COMBINATIONS
Arranging people, digits, numbers, alphabets, letters, colours.
Keywords: Arrangements, arrange,…
Selection of menu, food, clothes, subjects, teams.
Keywords:Select, choice,…
Permutation
Number of ways to arrange n different objects
Number of ways to arrange 3 different objects
6 ways
Number of ways to arrange 4 different objects
24
Number Number of of objects ways 1 ……… ………………………
2 ………. …….…………………
3 ……….. ……………….………
4 ……….. ……………….………
1
2 x 1
1
2
6 3 x 2
2 x 1
24 4 x 6
3 x 2
x 1
5 ……….. ……………………….
120 5 x 24
4 x 3 x 2 x 1
6 x 5 x 4 x 3 x 2 x 1 6 ……….. ……………………….
= 6!
= 5!
= 4!
= 3!
= 2!
= 1!
Factorial
The number of ways to arrange n objects = n !
1. To arrange 10 different objects = 10 !
2. To arrange digits 2, 5, 6, 8
= 4 !4 different
objects3. To arrange 12 finalists
12 different objects
= 12 !
DNADNA
23 pairs of chromosomes23 pairs of chromosomes
23! different ways to arrange23! different ways to arrange
The number of ways to arrange 23 different objects ?
25852016738884976640000
23 !
= 2.6 x 1022
Permutation
Number of ways to arrange r objects from n objects
8choices
7choices
6choices
5choices
4choices
Number of ways to arrange 5 students from 8 students.
8 x 7 x 6 x 5 x 4 = 8 x 7 x 6 x 5 x 4 = 6720
8choices
7choices
6choices
5choices
4choices
number of ways to arrange r from n objects
n (n-1) (n-2) (n-3) (n-(r-1))
)!(
!
rn
nPr
n
1. Questions related to Forming Numbers with digits and conditions
Use Multiplication Rules
Condition 1Find the number of ways to form 5 letter word from the letters W, O,R, L, D, C, U, P with the condition that it must starts with a vowels.
is filled first
W R L D C P
O
O
U 22 7 6 5 4
U =168
0
Find the number of ways to form 6 letter word from the letters B, E, C, K, H, A, M with the condition that it must starts with a consonant.
B CKHM
5
EA
6 5 4 3 2
5x6x5x4x3x2 = 1200
2. Questions related to Forming Numbers with digits and conditions
Use Multiplication Rules Conditions :
Sit side by side, next to each other – group together and consider as 1 object for arranging with other objects, make sure remember the arrangement of the grouped objects itself.
6 !
2!2! = 1440
4. To arrange PENALTY such that vowels are side by side
1 2 3 4 5 6
3. Complimentary Methods
Use:
The number of arrangements of event A
= Total arrangements – arrangement of A’
A
A’
S
Example
Find the number of the arrangement of all nine letters of word SELECTION in which the two letters E are not next to each other.
Solutions:
Total no. of arrangements – No. of arrangements with two E next to each other
141120
!82
!9
Combinationsn objects choose n = 1
N = 4
Choose 1:
A A B B C C DD
AA BB CC DD
Choose 2: AABB AACC AADD BBCC
Choose 3: AABBCC AACCDD BBCCDD
BBDDCCDD
AABBDD
Choose 4: AABBCCDD
= 4 = = 4 = 44CC11
= 6 = 6 = = 44CC22
= 4 = 4 = = 44CC33 = 1 = 1 = = 44CC44
Combinations
)!(!
!
rnr
nCr
n
Conditional Combination 1A football team has 17 local players and 3 imported players. Eleven main players are to be chosen with the condition that it must consist of 2 imported players. Find the number of ways the main player can be chosen.
import local
n
r
3 172 9
3C217C9
= 72930
Condition Combination 2A committee consisting of 6 members is to be chosen from 3 men and 4 women. Find the number of ways at least 3 women are chosen.
W3 M3, or W4 M2,
4C3X 3C3 + 4C4 X 3C2
= 7
CONCLUSIONS
1. Compare and Contrast between Permutations and Combinations.
DIFFERENCES BETWEEN PERMUTATIONS AND COMBINATIONS
PERMUTATIONS COMBINATIONS
1. Order is importent
2. Arranging people, digits, numbers, alphabets, letters, colours, …
3. Keywords: Arrangements, arrange,…
1. Order is not important.
2. Selection of menu, food, clothes, subjects, teams, …
Keywords:Select, choice,…
2. Formula
Difference between the two formulae:
Use the calculator to find the values of permutations and combinations.
)!(!
!
rnr
nCr
n
)!(
!
rn
nPr
n
3. If not sure, try to use the Multiplication Rules
Know the ways how to handle conditions like:
Sit side by side, next to each other, even/odd numbers, more/less than, starts/ends with vowel/consonants, …
Find the number of ways to form 6 letter word from the letters B, E, C, K, H, A, M with the condition that it must starts with a consonant.
B CKHM
5
EA
6 5 4 3 2
5x6x5x4x3x2 = 1200
4. For complicated cases:
Simplify by using Complimentary Methods
The number of arrangements of event A
= Total arrangements – arrangement of A’
A
A’
S
PROBABILITY