29 July Quantitative Aptitude

8/14/2019 29 July Quantitative Aptitude

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www.afterschoool.tk AFTERSCHOOOL MATERIAL FO

QUANTITATIVE APTITUDE

AFTERSCHOOOL DEVELOPING CHANGEMAKERS

CENTRE FOR SOCIAL ENTREPRENEURSHIP

PGPSE PROGRAMME

World Most Comprehensive programme in socialentrepreneurship & spiritual entrepreneurship

OPEN FOR ALL FREE FOR ALL


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QUANTITATIVE APTITUDE

Dr. T.K. Jain.

AFTERSCHOOOL

Centre for social entrepreneurship

Bikaner

M: 9414430763

[email protected]

www.afterschool.tk

www.afterschoool.tk
http://www.afterschool.tk/http://www.afterschoool.tk/http://www.afterschoool.tk/http://www.afterschool.tk/


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IN HOW MANY WAYS CAN YOU

SELECT 3 LETTERS FROM

SUCCESS? SUCCESS contains 7 letters. Here we have

CC, SSS thus we have actually 4 lettersonly (as C & S are repeated.

We have a possibility that we take only sss.(1 option). We have a possibility that wetake 2 C and three other digits : 3c3 =1. wehave a possibility that we take 2 C & 2 S.We have 3c2*2c2 = 3

We have a possibility that we take 1 letterfrom all four (any 3) 4c3 = 4. Thus totalpossibilities are 4+3+1+1 = 9 answer.


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In how many ways can you select 10

balls from 21 balls of same colour

and same type?21c10.

21! / (11! * 10!)

=21*20*19*18*17*16*15*14*13*12/10*9*8*7*6*5*4*3*2*1

= 16796 answer.


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How many five digit positive integers

have the product of their digits equal

to 2000? We know that in order to get 2000, we have to find

factors of 2000. factors of 2000 are: 2*5*2*5*2*5*2 Thus the possible numbers can be numbers like :

28555, 25558, 85552, 25855 etc. We know that wehave to have 3 five and 4 two. Thus the possibilitiesare 2,8, 5^3 or 4^2 *5^3. thus with all thesepossibilities, we have to find all permutations. Forfirst digit we have 4 options (2,4,8,5), but next wehave reducing options. Let us solve it differently.

(2,8,5,5,5,): 5! / 3! = 120/6 = 20. (4,4,5,5,5,): 5! / (3! * 2!) = 10 = 20 +10 = 30 answer.


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How many solutions for X & Y can

you find which satisfy the condition

X^2 = 14 + Y^2 ?X ^2 Y^2 = 14 (X+Y) (X-Y) = 14.

X+Y and X-Y may be 7 & 2 or 14 * 1 X+Y= 7

X-Y = 2. putting these together, we get2X = 9 or X = 4.5 (which doesnt fullfillour condition).

Thus we cant find any such solution.


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A car travels at 50 for first half of

journey and reduces the speed by

half subsequently for remaining halfeach time. What is its average speed

in entire journey?

Average speed = total distance / total time Speed = 50, 25, 12.5, 6.25 and so on. Let us assume that total time taken is T. Distance = speed * time. Distance = 50 *T/2 + 25 *T/4 +12.5 *T/8 . So on. Thus we have an infinite series. Total of the series = A / 1-r = 50T/2 (3/4) =33.3 T

Thus answer is 33.3T/ T = 33 answer .


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We have different rates in our

restaurant. If there are 200 persons,

we charge Rs. 165 per person. Ifthere are 150 persons, we charge

170 per person. What would be the

charge if there are 100 persons?

X + 150 Y = 170*150

X + 200Y = 165*200

50 Y = 7500 or Y = 150.; X will be 3000thus when there will be 100 persons,

= 3000+150*100 = 18000/100 = 180

answer.


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Answer continued . . . Sum of

infinite series . . . . .Sum = A / (1-R)

A = first term

R = ratio; R = Second term / First term

In the given question, A = 50T / 2.

Ratio is thus, the solution is 25T / (1-

1/4)

= 25T / .75 = 33T


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ABOUT A FTERSCH OOOLAfterschoool conducts three year integrated PGPSE (after

class 12th along with IAS / CA / CS) and 18 month PGPSE

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Hyderabad (the founder is alumnus from IIMA & ISB Hyderabad) Meditation, spiritualisation, and self development Essential softwares for business Business plan, Research projects Participation in conferences / seminars Workshops on leadership, team building etc. Written submissions of research projects/articles / papers Interview of entrepreneurs, writing biographies of entrepreneurs Editing of journals / newsletters

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29 July Quantitative Aptitude

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