1 © Penerbitan Pelangi Sdn. Bhd. Paper 1 1. Bearing of P from Q = 040° Answer: B 2. Bearing of E from F = 120° Answer: C 3. North 75° M N Bearing of M from N = 180° + 75° = 255° Answer: C 4. North 30° Q P Bearing of P from Q = 360° − 30° = 330° Answer: D Paper 1 1. 70° 75° North 35° 75° R Q P ∠PRQ = 180° − 70° − 35° = 75° Bearing of R from Q = 180° + 75° = 255° Answer: D 2. 80° 50° 50° North E F G ∠EFG = 180° − 80° –––––––––– 2 = 50° Bearing of G from F = 050° Answer: A 3. North North 120° 120° Y X Answer: D 28 Bearing
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1 © Penerbitan Pelangi Sdn. Bhd.
Paper 1
1. Bearing of P from Q = 040°
Answer: B
2. Bearing of E from F = 120°
Answer: C
3. North
75°M
N
Bearing of M from N = 180° + 75°= 255°
Answer: C
4. North
30°
Q
P
Bearing of P from Q = 360° − 30°= 330°
Answer: D
Paper 1
1.
70°
75°
North
35°
75°RQ
P
∠PRQ = 180° − 70° − 35° = 75°
Bearing of R from Q = 180° + 75° = 255°
Answer: D
2.
80°
50° 50°
North
E
F G
∠EFG = 180° − 80°––––––––––2
= 50°
Bearing of G from F = 050°
Answer: A
3. North
North
120°
120°
Y
X
Answer: D
28 Bearing
2
Mathematics SPM Chapter 28
© Penerbitan Pelangi Sdn. Bhd.
4.
F
North
North
25°
35°50°
G
H
70°50°
300°
∠HFG = 180° – 70° – 25° = 85°Bearing of H from F = 360° − 35° = 325°Answer: D
5.
F
E
North North
105°
105°
Bearing of E from F = 180° − 105° = 075°Answer: B
6.
34°
242°
62°
62°
Y
X
Z
North
North
∠XZY = 242° – 180° = 62°Bearing of Y from X= 62° + 34°= 096°
Answer: A
7.
30°
North
Q
P
Answer: C
Paper 1
1.
70°
North
PQ
Bearing of P from Q = 360° − 70° = 290°
Answer: D
2. North
130°
N
M
Answer: B
3. North
EF70°
70°
Bearing of E from F = 070°
Answer: B
4. North
West
45°E
F
Bearing of E from F = 360° − 45° = 315°
Answer: D
3
Mathematics SPM Chapter 28
© Penerbitan Pelangi Sdn. Bhd.
5. North
(East)28°E F
G
Bearing of G from E = 90° + 28° = 118°
Answer: B
6. North
75°75°P
Q
Bearing of P from Q = 180° + 75° = 255°
Answer: C
7. North
160°
40° 20°
60°
40°
GF
E
Bearing of G from F = 40° + 60° = 100°
Answer: B
8.
M
L
N
North
130°
50°
50° 50°
Bearing of N from M = 180° + 50° = 230°
Answer: C
9. North
PQ
R
150°50°50°
080°
Bearing of Q from R = 050°
Answer: D
10.
55°
North
55°
M
N
125°
Bearing of M from N = 360° − 55° = 305°
Answer: C
11. North
K
J
H
130°
30°
30°
∠JHK = 180° − 130° − 30° = 20°
Answer: A
4
Mathematics SPM Chapter 28
© Penerbitan Pelangi Sdn. Bhd.
12. North
70°80°
30°
30°
R
Q
P
∠PQR = 180° − 30° − 70° = 80°
Bearing of R from Q = 360° − (80° + 30°) = 250°
Answer: D
13.
40°
180° + 40°= 220°
North
E
F
Answer: D
14. North
30°
100°
40°
10°
P
Q
R
30°
∠PRQ = 180° − 100°–––––––––––2
= 40°
Bearing of R from Q = 180° − 10° = 170°
Answer: B
15. NorthNorth R
QP 20 km
60°30° 60°
30°
∠PRQ = 180° − 30° − 60° = 90°
Answer: D
16. North
G
50°
40°40°
E
F
Bearing of G from F = 360° − 40° = 320°
Answer: D
17. NorthNorth
x
P
Q
40°20°
60°60°
40°
R
x = 180° − 20° = 160°
Answer: C
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