34 LAMPIRAN Lampiran 1. Perhitungan Kurva Baku Pembuatan kurva baku ibuprofen dengan seri konsentrasi 10, 20, 30, 40, 50 dan 60 ppm 10 ppm = V 1 x C 2 = V 2 x C 2 V 1 x 100 ppm = 25 mL x 10 ppm V 1 2,5 m 2500 μ 20 ppm = V 1 x C 2 = V 2 x C 2 V 1 x 100 ppm = 25 mL x 20 ppm V 1 5 m 5000 μ 30 ppm = V 1 x C 2 = V 2 x C 2 V 1 x 100 ppm = 25 mL x 30 ppm V 1 7,5 m 7500 μ 40 ppm = V 1 x C 2 = V 2 x C 2 V 1 x 100 ppm = 25 mL x 40 ppm V 1 10 m 10.000 μ 50 ppm = V 1 x C 2 = V 2 x C 2 V 1 x 100 ppm = 25 mL x 50 ppm V 1 12,5 m 12.500 μ 60 ppm = V 1 x C 2 = V 2 x C 2 V 1 x 100 ppm = 25 mL x 60 ppm V 1 15 m 15.000 μ
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2,5 m 2500 μ 5 m 5000 μ 7,5 m 7500 μ 10 m 10.000 μ 12,5 m ...eprints.unwahas.ac.id/1859/7/LAMPIRAN.pdf35 Lampiran 2. Contoh Perhitungan Kadar Ibuprofen Contoh perhitungan DE 45
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LAMPIRAN
Lampiran 1. Perhitungan Kurva Baku
Pembuatan kurva baku ibuprofen dengan seri konsentrasi 10, 20, 30, 40, 50 dan
60 ppm
10 ppm = V1 x C2 = V2 x C2
V1 x 100 ppm = 25 mL x 10 ppm
V1 2,5 m 2500 μ
20 ppm = V1 x C2 = V2 x C2
V1 x 100 ppm = 25 mL x 20 ppm
V1 5 m 5000 μ
30 ppm = V1 x C2 = V2 x C2
V1 x 100 ppm = 25 mL x 30 ppm
V1 7,5 m 7500 μ
40 ppm = V1 x C2 = V2 x C2
V1 x 100 ppm = 25 mL x 40 ppm
V1 10 m 10.000 μ
50 ppm = V1 x C2 = V2 x C2
V1 x 100 ppm = 25 mL x 50 ppm
V1 12,5 m 12.500 μ
60 ppm = V1 x C2 = V2 x C2
V1 x 100 ppm = 25 mL x 60 ppm
V1 15 m 15.000 μ
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Lampiran 2. Contoh Perhitungan Kadar Ibuprofen
Contoh perhitungan DE45 (%) pada FIII Replikasi 1
A. Perhitungan kadar zat aktif terdisolusi dalam media disolusi 900 mL
suppositoria ibuprofen dengan berat 3009 mg yang diuji disolusi pada
waktu 5 menit diperoleh absorbansi 1315406, kemudian nilai luas area
dimasukkan kurva baku dengan persamaan y = 94258x + 481718
diperoleh kadar 124,519 mg
Y = BX + A
Y = 94258x + 481718
1315406 = 942580x + 481718
X = 1315406 – 481718
942580
X = 8,845
zat terlarut = 8,845mg x 900 ml x 2,5
1000 mL
= 19,900 µg/m
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B. Perhitungan kadar hasil disolusi dari suppositoria ibuprofen