2.1 – Linear Equations in One Variable Objective – Solve linear equations using properties of equality. - Solve linear equations that can be simplified by combining like terms. -Solve linear equations involving fractions
Jan 20, 2016
2.1 – Linear Equations in One Variable
Objective – Solve linear equations using properties of equality.
-Solve linear equations that can be simplified by combining like terms.
-Solve linear equations involving fractions
Why is this important?
Linear Equations
Linear Equations in one variable – A linear equation in one variable is an equation that can
be written in the form ax + b = c
Where a, b, and c are real numbers and a 0 The Addition and Multiplication Properties of Equality
If a, b, and c, are real numbers, then a=b and a+c = b – c are equivalent equations Also a =b and ac = bc are equivalent equations as
long as c 0
Solve: Addition property of equality
2 x + 5 = 9
2x + 5 -5 = 9 -5
2x = 4
2x = 4
2 2
x = 2
Subtract 5 from both sides
Simplify
Divide both sides by 2
Simplify
Check
To see that 2 is the solution, replace x in the original equation with 2.
2 x + 5 = 9
2 (2) + 5 = 9
4 + 5 = 9
9 = 9
Give it a try
3 x + 6 = 12
3x + 6 – 6 = 12 –6
3x = 6
3x = 6
3 3
x = 2
Check
0.6 = 2 – 3.5c
0.6 = 2 – 3.5 (0.4)
0.6 = 2 – 1.4
0.6 = 0.6
Give it a try!
4.5 = 3 + 2.5 x
4.5 – 3 = 3 + 2.5 x – 3
1.5 = 2.5 x
1.5 = 2.5 x
2.5 2.5
0.6 = x
Solve – Combining like terms
-6 x – 1 + 5x = 3
-6x – 1 + 5x = 3
-x – 1 = 3
-x – 1 + 1 = 3 + 1
-x = 4
-1 -1
x = -4
Give it a try!
-2x + 2 – 4x = 20
-2x + 2 – 4x = 20
-6x + 2 = 20
-6x + 2 – 2 = 20 – 2
-6x = 18
-6 -6
x = -3
Solve: Distributive Property
2 (x – 3) = 5 x – 9
2(x – 3) = 5 x – 9
2x – 6 = 5 x – 9
2x – 6 – 5x = 5x –9 – 5x
-3 x – 6 = - 9
-3 x – 6 + 6 = - 9 + 6
-3x = -3
-3 -3
x = 1
Give it a try!
4 (x – 2) = 6x –10
4x – 8 = 6x – 10
2 = 2 x
1 = x
Solve: Adding/Subtracting Fractions
13 4 6y y
13 4 6
12 12y y
12 12 23 4y y
4 3 2y y
2y
Give it a try!
16 8 8x x
16 8
24 24 248
x x
4 3 3x x
3x
Solve: Multiplying Fractions5 31
22 2 8
x xx
5 312
2 2 88 8
x xx
38 8 8 8
5 12
2 2 8
xxx
4 5 4 16 3x x x 4 20 4 16 3x x x 4 24 15 3x x
11 24 3x 11 21x
2111
x
Give it a try!1 2 32
3 3 9
x xx
Solve: Decimals
0.3x + 0.1 = 0.27 x – 0.02
100(0.3x +0.1) = 100 (0.27x – 0.02)
100(0.3x) + 100 (0.1) = 100(0.27x) – 100(0.02)
30 x + 10 = 27 x – 2
30 x – 27 x = -2 –10
3 x = -12
3x = -12
3 3
x = - 4
Give it a try!
0.2x +0.1 = 0.12x – 0.06
100 (0.2 x + 0.1) = 100 (0.12 x – 0.06)
20 x + 10 = 12 x – 6
20 x – 12 x = -6 – 10
8 x = -16
x = -2
Solve: Contradiction
3x + 5 = 3(x+2)
3 x + 5 = 3 (x + 2)
3 x + 5 = 3x + 6
3 x + 5 – 3 x = 3 x + 6 – 3 x
5 = 6
This is a false statement…The original equation has no solution. Its solution set is written either by { } or
O. This equation is a contradiction.
Give it a try!
5 x – 1 = 5(x+3)
5 x – 1 = 5 x + 15
-1 = 15
{ }
Solve: Identity
6 x – 4 = 2 + 6 (x –1)
6x – 4 = 2 + 6x – 6
6 x – 4 = 6 x – 4
{x/ x is a real number}
6 x – 4 + 4 – 6x – 4 + 4
6 x = 6 x
6x – 6x = 6 x – 6x
0 = 0
This equation is called an identity!
Give it a try!
-4(x – 1) = -4x –9 +13
-4x + 4 = -4x + 4
{x / x is a real number}
Put it in words! Solving a linear equation in one variable
Step 1: Clear the equation of fractions by multiplying both sides of the equation by the LCD
Step 2: Use distributive property to remove grouping symbols such as parentheses.
Step 3: Combine like terms. Step 4: Isolate the variable by adding, subtracting,
multiplying, dividing (equality properties) Step 5: Check the solution in the original equation.