JJC 2013 9646/JC2 CT2 P1/2013[Turn OverJURONG JUNIOR COLLEGE 2013 JC2 Common Test 2 NameClass12SPHYSICS Higher 2 Structured Questions Candidates answer on the Question Paper. No additional materials are required. 9646/1 2 Jul 2013 1 hour 15 minutesREAD THESE INSTRUCTIONS FIRST Do not open this booklet until you are told to do so. Write yourname and class in the space provided at the top of this page. Write in dark blue or black pen. You may use a soft pencil for any diagrams, graphs or rough working. Do not use highligh ters, glue or correction fluid. Section A Answerevery question. Section B Answer any two questions. At the end of the ex amination, fasten al l your work secu rely together. The number of ma rks is given i n brackets [ ] at the end of each question or part question. ForExaminer’s Use1 2 3 4 Total (This question paper consists of 17 printed pages)
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Candidates answer on the Question Paper.No additional materials are required.
9646/1
2 Jul 2013
1 hour 15 minutes
READ THESE INSTRUCTIONS FIRST
Do not open this booklet until you are told to do so.
Write your name and class in the space provided at the top of thispage.
Write in dark blue or black pen.You may use a soft pencil for any diagrams, graphs or rough working.Do not use highlighters, glue or correction fluid.
Section A Answer every question.
Section B Answer any two questions.
At the end of the examination, fasten all your work securely together.The number of marks is given in brackets [ ] at the end of eachquestion or part question.
For Examiner’s Use
1
2
3
4
Total
(This question paper consists of 17 printed pages)
speed of light in free space, c = 3.00 10 8 m s 1 permeability of free space, o = 4 10 7 H m 1 permittivity of free space,
o = 8.85 1012
F m1
= (1/(36 )) 109
F m1
elementary charge, e = 1.60 10 19 C the Planck constant, h = 6.63 10 34 J s unified atomic mass constant, u = 1.66 10 27 kg rest mass of electron, m e = 9.11 10 31 kg rest mass of proton, m p = 1.67 10 27 kg molar gas constant, R = 8.31 J K 1 mol 1 the Avogadro constant, N A = 6.02 10 23 mol 1 the Boltzmann constant, k = 1.38 10 23 J K 1 gravitational constant, G = 6.67 10 11 N m 2 kg 2 acceleration of free fall, g = 9.81 m s 2
Formulae
uniformly accelerated motion, s = ut + 12 at 2
v 2 = u2 + 2 as work done on/by a gas, W = p V hydrostatic pressure, p = gh gravitational potential,
=Gm
r
displacement of particle in s.h.m., x = x o sin t velocity of particle in s.h.m., v = v o cos t
v = 2 2( )o x x
mean kinetic energy of a molecule of an idealgas E = 3
2 kT
resistors in series, R = R 1 + R 2 + . . . resistors in parallel, 1/R = 1/ R 1 + 1/ R 2 + . . .
electric potential, V =o
Q
ε r 4
alternating current / voltage, x = x o sin t transmission coefficient, T exp( 2kd )
where k =2
2
8 ( )m U E
h
radioactive decay x = x o exp(- λt )decay constant
(b) Light of wavelength 590 nm is incident on a diffraction grating with6.25 x 10 5 lines per metre. The screen is placed 10.0 cm away from the grating.
(i) Determine the total number of images produced by the light transmittedthrough this grating.
number of images = [3]
(ii) Calculate the distance between the first-order maximum and the centralmaximum on the screen.
distance = m [3]
(iii) Another diffraction grating of the same slit separation is placed in front of theoriginal grating such that their slits are perpendicular to one another as shownin Fig. 2.1. A 2-dimensional pattern of bright spots is formed on the screen.
Sketch the pattern obtained, showing clearly the relative separation of thespots up to the 2 nd order maxima. [2]
(c) Fig. 2.2 shows an arrangement used to determine the wavelength of monochromatic light emitted by a laser.
Fig. 2.2
S 1 and S 2 are silts at right angles to the plane of this page. When the silts areilluminated by light from the laser, they form coherent sources of light. Aninterference pattern is formed on the screen from which measurements can betaken to determine the wavelength.
3 A wire frame ABCD is supported on two knife-edges P and Q so that the section PBCQ onthe frame lies within a solenoid, as shown in Fig. 3.1. and Fig. 3.2.
Fig. 5.1
Electrical connections are made to the frame through the knife-edges so that the partPBCQ of the frame and the solenoid can be connected in series with a battery. When
there is no current in the circuit, the frame is horizontal.
(a) When the frame is horizontal and a current passes through the frame and solenoid,what can you say about the direction of the force, if any, due to the magnetic field of the solenoid acting on
(iii) A small piece of paper of mass 0.10 g is placed on the side DQ andpositioned so as to keep the frame horizontal. Given that QC is of length 15.0cm, how far from the knife-edge must the paper be positioned?
distance = m [2]
(d) State Faraday’s and Lenz’s laws of electromagnetic induction.
[2]
(e) A pair of concentric coils is shown in Fig. 3.3.
The outer coil X has 2500 turns and is connected to a variable power supply by theterminals CD. The inner coil Y has 500 turns, a cross-sectional area of
7.25 x10 -4 m 2 and a resistance of 5.00 Ω. Coil Y is connected to a resistor R of resistance 5.00 Ω.
The variation with time t of the magnetic flux density B in coil Y is shown in Fig. 3.4.
(i) Calculate the maximum current in R.
maximum current = A [3]
(ii) On Fig. 3.5, sketch the variation with time t of current I in R. [3]