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(2) Gears

Apr 04, 2018

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    Chapter 10

    Gears

    Transmits

    Rotary motionTorques

    Why use teeth? Why not frictionrollers?

    Teeth need to be specially shaped toallow smooth engagement.

    Involute curves are ideal.

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    Types of Gears:

    Spur Gear Rack and Pinion

    Internal Gear Helical Gear

    Bevel GearHerrin bone Gear

    Miter Gear Worm Gear

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    Spur Gear Geometry:

    Involute toothUnwind a string from a base circleTrack the path of the string end

    Pitch Diameter (d)Size of equivalent friction rollers

    Pitch circle

    Pitch circle

    Line of Centers

    Base Circle

    Involutetooth profile

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    Number of Teeth (N)Must be an integer value

    Diametral Pitch (Pd)size of a the gear tooth

    d

    NPd =

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    Pressure Angle ()

    Standard values: = 140, 200, 250

    Mating gears must have same

    pressure angle and diamtral pitch.

    Pitch Circle

    Line of Centers

    Pitch Line

    Pressure Angle,

    Pressure LinePitch Circle

    Base Circle

    Base Circle

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    Dedendum Circle

    Addendum C

    Dedendum (b)

    ddendum (a)

    Face Width (F)

    Circular Pitch (p)

    Tooth Thickness

    Pitch Circle

    Flank

    Face Fillet Radius

    Tip Radius

    Pitch Diameter (d)

    Others Features

    Circular Pitch p = d/NBase circle db=d cos These features are standardized for

    interchangeability:

    Addendum a=1/PdDedendum b=1.25/PdFace Width F=12/Pd

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    Example:A 200, full-depth, involute spur gear

    with 18 teeth has a diametral pitch of12. Determine:

    Outside (addendum) diameter. Root (dedendum) diameter. Standard face width. Base circle diameter. Circular pitch.

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    Line of Centers

    Pitch Line

    Pressure Angle,

    Contact Line

    Driven Gear

    Driver Gear

    (pinion)

    123 BaseCircle

    Base

    Circle

    Pitch

    Circle

    Pitch

    Circle

    Addendum

    Circle

    AddendumCircle

    Center Distance, c

    Mating Spur Gears :

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    Center Distance (c)

    cexternal gears=r1 + r2

    cinternal gears=r2 r1

    Example:

    Two mating external 4-pitch, spurgears have 14 and 42 teeth. Determinethe center distance.

    Pitch circle

    Pitch circle

    Line of Centers

    cexternal

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    Contact Ratio (mp) Average number of teeth in

    contact at any instant.

    b

    pp

    Zm =

    Base pitch (pb):

    2

    2

    1

    1 coscos

    N

    d

    N

    dpb

    ==

    Length of contact path (Z):

    sin)cos()(

    sin)cos()(

    1

    2

    1

    2

    11

    2

    2

    2

    2

    22

    rrar

    rrarZ

    ++

    +=

    Larger values have smootherload transfer

    Recommend 1.4 1.5Example:

    Two mating external 4-pitch, spurgears have 18 and 42 teeth. Determine

    the contact ratio.

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    Interference Gears with too few teeth. Top of one gear digs into

    base of the other.

    Use table 10.4 to check. = 140 = 200 =250

    Number ofPinion teeth

    Maximumnumber of

    gear teeth

    Number ofpinion teeth

    Maximumnumber of

    gear teeth

    Number ofpinion teeth

    Maximumnumber of

    gear teeth

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    Gear Kinematics:

    Velocity Ratio (VR)Gear Ratio

    2

    1

    =VR

    + same direction- opposite direction

    3:1 or three to one means VR = 3

    Commonly written :

    1

    2

    1

    2

    2

    1

    N

    N

    d

    dVR ===

    2

    1

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    Example:

    A 5-in gear, rotating at 1725 rpm, cw,

    meshes with a gear having a pitchdiameter of 20 in. Determine the

    velocity of the driven gear.

    An 8-pitch, 18 tooth gear rotates at1200 rpm, ccw. It meshes with a gear

    with a pitch diameter of 6 in.

    Determine the velocity of the drivengear.

    A 10-pitch, 16 tooth gear mates with a

    gear having a pitch diameter of 6 in.

    The driven gear rotates at 300 rpm, cw.Determine the velocity of the driver

    gear.

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    Pitch Line Velocity (vt)

    vt= r11 = r22

    watch units:

    vt= d n/12

    d (in)n (rpm)

    vt (fpm)

    The pitch line speed determines:

    lubrication needed. quality required.

    (accuracy & surface finish)

    21

    1

    2

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    Gear SelectionNeed to decide:

    P Pressure AngleP Suitable diametral pitchP Number of teeth on each gear

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    Number of Teeth for

    Commercially Available, Stock Gears

    32 Diametral Pitch12 16 20 28 36 48 64 80 112

    14 18 24 32 40 56 72 96 128

    24 Diametral Pitch12 18 24 30 42 54 72 96 144

    15 21 27 36 48 60 84 120

    20 Diametral Pitch12 16 24 35 50 80 100 160

    14 18 25 40 60 84 120 180

    15 20 30 45 70 90 140 20016 Diametral Pitch

    12 16 24 32 48 64 96 16014 18 28 36 56 72 128 192

    15 20 30 40 60 80 144

    12 Diametral Pitch12 15 20 28 42 60 84 120 168

    13 16 21 30 48 66 96 132 192

    14 18 24 36 54 72 108 144 216

    10 Diametral Pitch

    12 16 24 30 45 55 80 120 20014 18 25 35 48 60 90 140

    15 20 28 40 50 70 100 160

    8 Diametral Pitch12 16 22 32 44 60 80 11214 18 24 36 48 64 88 120

    15 20 28 40 56 72 96 128

    6 Diametral Pitch12 16 24 33 48 66 96

    14 18 27 36 54 72 10815 21 30 42 60 84 120

    5 Diametral Pitch12 16 24 30 45 70 110 160

    14 18 25 35 50 80 120 180

    15 20 28 40 60 100 140

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    Example:A set of gears must be selected that

    transmit power from a 5 hp motor at1200 rpm to a grinding wheel at 310

    (10) rpm. Select a set of appropriategears.

    Example:A set of gears must be selected that

    transmit power from a 20 hp engine at

    2000 rpm to an air compressor at 660( 10) rpm. These gears must fit into a

    housing with a center distance of 6.00in. Select a set of appropriate gears.

    Example

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    An escalator is being designed to

    transport 6000 people per hour.

    Assume an average weight of 175 lbper person. Determine the required

    power to operate the escalator.

    15 ft

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    Gear Trains:

    Several gear pairs are placed in

    series.

    Why?

    Train Value (TV)out

    in

    TV

    =

    TV = (VR)1 (VR)2 (VR)3

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    ExampleThe gear train shown is used with an

    input speed of 1200 rpm, cw. Giventhe following properties:

    N1=24, N2= 48 & Pd = 16

    N3=24, N4= 48 & Pd=12

    N5=15, N6= 35 & Pd = 10

    Determine the output velocity and

    center distance of the gear train.

    in

    1

    2

    3

    4

    5

    6

    out

    1 2

    3 4

    5 6

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    ExampleThe gear train shown is used with an

    input speed of 1200 rpm, cw. Giventhe following properties:

    N1=24 N2= 36 & Pd = 12

    D3=2.0 in. & Pd=10 N4= 40

    N5=16 & Pd=8 D6= 6.0 inDetermine the output velocity and

    center distance of the gear train.

    in

    out

    1

    2

    3

    45

    6

    4

    1

    2

    63

    5

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    Gear Train Design Select the appropriate ratios for

    each gear pair.

    Factor the TV into suitableratios.

    Example:Design a gear train with a train value

    of +400:1. From interference criteria,no gear should have fewer than 15

    teeth and due to size restrictions, no

    gear should have more than 75 teeth.

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    Worm Gears:

    Able to obtain high ratios inlimited space.

    Shafts are perpendicular andnon-intersecting

    Self-locking 40-50% efficient

    Worm Gear Kinematics:

    worm

    gear

    N

    NVR ==

    2

    1

    2

    1

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    Example:Determine the output speed of the gear

    drive, when the worm is driven at 1200rpm.

    in=1200 rpm1

    2

    34

    5

    N2= 18

    N3=60

    N4=15

    N5=45out = ?