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1A + 2B 1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10
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1A + 2B 1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Dec 27, 2015

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Page 1: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

1A + 2B 1C + 1DCalculate the equilibrium

concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. Kc = 2.0 x 10-10

Page 2: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Drill:1A + 2B 1C + 1D

Calculate the equilibrium concentrations of each

species when a solution is made with 1.0 M A &

1.0 M B. Kc = 2.0 x 10-12

Page 3: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Acid/Base

Page 4: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Properties of Acids·Sour taste, Change color of dyes, Conduct electricity in solution, React with many metals, React with bases to form salts

Page 5: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Properties of Bases·Bitter taste, Feel slippery, Change color of dyes, Conduct electricity in solution, React with acids to form salts

Page 6: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Arrhenius·Acids: release H+ or H3O+ in solution

·Bases: release OH- in solution

Page 7: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Arrhenius·Acid: HA H+ + A-

·HCl H+ + Cl-

·Base: MOH M+ + OH-

·NaOH Na+ + OH-

Page 8: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Bronsted-Lowry·Acid: Proton donor

·Base:

Proton Acceptor

Page 9: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Bronsted-Lowry· HA + H2O H3O+ + A-

· HI + H2O H3O+ + I-

· Acid Base CA CB

· NH3 + H2O NH4+ + OH-

· Base Acid CA CB

Page 10: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Lewis Acid/Base·Acid: Electron

Acceptor

·Base: Electron Donor

Page 11: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Lewis Acid/BaseH3N: + BF3 H3N-BF3

Base Acid Neutral

Page 12: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Common Names· H+ Hydrogen ion

· H3O+ Hydronium ion

· H- Hydride ion

· OH- Hydroxide ion

· NH3 Ammonia

· NH4+ Ammonium ion

Page 13: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Amphiprotism·Can act like an acid or a base

·Can donate or accept protons

Page 14: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Strong Acids or Bases·Strong acids or bases ionize 100 % in solution

·Weak acids or bases ionize <100 % in solution

Page 15: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Drill: Name each of the following:

KOH HBrAl(OH)3 H2CO3

HClO4 NH3

Page 16: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Naming Acids· All acids are H-anion

· If the anion is:

· -ides hydro___ic acids

· -ates ___ic acids

· -ites ___ous acids

Page 17: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Naming Bases·Almost all bases are metal hydroxides

·Name by normal method

·Ammonia (NH3) as well as many amines are bases

Page 18: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Strong Acids or Bases·Strong acids or bases ionize 100 % in solution

·Weak acids or bases ionize <100 % in solution

Page 19: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Strong Acids· HClO4 Perchloric acid

· H2SO4 Sulfuric acid

· HNO3 Nitric acid

· HCl Hydrochloric acid

· HBr Hydrobromic acid

· HI Hydroiodic acid

Page 20: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Strong Bases· All column I hydroxides

· Ca(OH)2 Calcium hydroxide

· Sr(OH)2 Strontium hydroxide

· Ba(OH)2 Barium hydroxide

Page 21: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Strong Acid/BaseIonizes 100 % (1 M)

HA H+ + A-

1 M – all 1 1

Page 22: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Binary Acids·Acids containing only 2 elements

·HCl Hydrochloric acid

·H2S Hydrosulfuric acid

Page 23: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Ternary Acids· Acids containing 3 elements

·H2SO4 Sulfuric acid

·HNO3 Nitric acid

Page 24: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Monoprotic Acids·Acids containing only one ionizable hydrogen

·HBr Hydrobromic acid

·HC2H3O2 Acetic acid

Page 25: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Diprotic Acids·Acids containing 2 ionizable hydrogens

·H2SO4 Sulfuric acid

·H2CO3 Carbonic acid

Page 26: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Triprotic Acids·Acids containing 3 ionizable hydrogens

·H3PO4 Phosphoric acid

·H3AsO4 Arsenic acid

Page 27: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Polyprotic Acids· Acids containing more than

one ionizable hydrogens

·H4SiO4 Silicic acid

·H2CO2 Carbonous acid

Page 28: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Monohydroxic Base

·A base containing only one ionizable hydroxide

·NaOH Sodium hydroxide

·LiOHLithium hydroxide

Page 29: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Neutralization Rxn· A reaction between an acid

& a base making salt & H2O

·HA(aq) + MOH(aq)

MA(aq) + H2O(l)

Page 30: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Neutralization Rxn

HCl(aq) + NaOH(aq)

NaCl(aq) + H2O(l)

Page 31: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

pH·The negative log of the hydrogen or hydronium ion concentration

·pH = -log[H+]

·pOH = -log[OH-]

Page 32: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Calculate the pH of each of the following:1) [H+] = 0.040 M2) [HCl] = 0.0025 M 3) [HBr] = 0.080 M

Page 33: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Calculate the pOH of each of the following:

1) [OH-] = 0.030 M2) [KOH] = 0.0025 M3) [NaOH] = 4.0 x 10-7 M

Page 34: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Standard Solution

·A solution with known

concentration

Page 35: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Drill: Identify: acid, base, CA, & CB HCO3

- + H2O

H2CO3 + OH-

Page 36: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Titration·A method of determining the concentration of one solution by reacting it with a standard solution

Page 37: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Titration Formula for monoprotic solutions

MAVA = MBVB

Page 38: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Titration FactWhen titrating acids

against bases, the end

point of the titration is

at the equivalence point

Page 39: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Equivalence Point

·The point where the concentrations of the two solutions in the titration are equal

Page 40: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Acid/Base Equivalence PointThe point where the H+

concentration is equal to

the OH- concentration

Page 41: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Titration Fact No changes will be observed when titrating acids against bases; thus, one must use an indicator to see changes

Page 42: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Indicator·An organic dye that changes color when the pH changes

Page 43: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

·Calculate the molarity of 25.0 mL HCl when it’s titrated to its equivalence point with 50.0 mL 0.200 M NaOH

Page 44: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Titration Formula for monoprotic solutions

MAVA = MBVB

Page 45: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Dilution Formula

M1V1 = M2V2

Page 46: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

·Calculate the mL of 16.0 M HNO3 it takes to make 4.0 L of 0.100 M HNO3

Page 47: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Make Calculations·Calculate the mL of 12.5 M HCl required

to make 2.5 L of 0.200 M HCl

Page 48: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Molarity

·Moles of solute per liter of solution

(M)

Page 49: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Normality·Number of moles of hydrogen or hydroxide ions per liter of solution (N)

Page 50: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Titration Formulafor Acid/Base

·NAVA = NBVB

·Elliott’s Rule:

·#HMAVA = #OHMBVB

Page 51: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Make Calculations·Calculate the molarity of 30.0 mL H2CO3 when it’s titrated to its equivalence point with 75.0 mL 0.200 M NaOH

Page 52: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Make Calculations·Calculate the molarity of 40.0 mL H3PO4 when it’s titrated to its equivalence point with 30.0 mL 0.20 M Ba(OH)2

Page 53: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Calculate the volume of 0.250 M HCl

needed to titrate 50.00 mL 0.200 M NaOH to its equivalence point

Page 54: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Calculate the molarity 25.0 mL H3PO4 that

neutralizes 50.00 mL 0.200 M Ca(OH)2 to its equivalence point

Page 55: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Titration Curve:Strong acid vs

strong base

Page 56: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.
Page 57: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Titration Curve:Strong acid vs

strong base; then weak acid vs strong base

Page 58: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.
Page 59: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.
Page 60: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Titration Curve:Strong base vs

strong acid; then weak base vs strong acid

Page 61: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.
Page 62: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

3.2 g HI is dissolved in a

1250 mL aqueous solution.

Calculate its pH.

Page 63: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Calculate the volume of 0.10 M H3PO4 that

neutralizes 50.00 mL 0.200 M Ca(OH)2 to its

equivalence point

Page 64: 1A + 2B  1C + 1D Calculate the equilibrium concentrations of each species when 150 mL 2.5 M A is mixed with 100.0 mL 2.5 M B. K c = 2.0 x 10 -10.

Drill: Calculate the molarity of 25.00 mL of H3PO4 that was titrated to its equivalence point

with 75.00 mL of0.125 M Ba(OH)2.