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162 Lecture Notes Chem 51A S. King Chapter 13 Infrared Spectroscopy I. Background Nearly every portion of the electromagnetic spectrum has been used to elucidate the structures of atoms and molecules. The Electromagnetic Spectrum: A variety of techniques are available, including Ultraviolet/Visible (UV/Vis) Infrared (IR) and Nuclear Magnetic Resonance (NMR) Spectroscopy. These techniques are based on the fact that molecules have different kinds of energy levels, and therefore absorb radiation in several regions of the electromagnetic spectrum. When a molecule absorbs light of a given frequency, specific molecular effects occur, depending on the wavelength absorbed. Low energy radiowaves, for example, cause nuclear spin flip transitions, whereas more energetic UV radiation results in electrons being promoted to higher energy levels. Energy is proportional to the frequency of light absorbed: 10 !2 10 0 10 2 10 4 10 6 10 8 10 10 10 12 10 20 10 18 10 16 10 14 10 12 10 10 10 8 10 6 10 4 radiowave microwave infrared X-ray "!ray visible UV 400 nm 750 nm visible spectrum # (s !1 ) $ (nm)
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162 Lecture Notes Chem 51A S. King Chapter 13 Infrared ...

Jan 01, 2017

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Page 1: 162 Lecture Notes Chem 51A S. King Chapter 13 Infrared ...

162

Lecture Notes Chem 51A

S. King

Chapter 13 Infrared Spectroscopy

I. Background Nearly every portion of the electromagnetic spectrum has been used to elucidate the structures of atoms and molecules. The Electromagnetic Spectrum: A variety of techniques are available, including Ultraviolet/Visible (UV/Vis) Infrared (IR) and Nuclear Magnetic Resonance (NMR) Spectroscopy. These techniques are based on the fact that molecules have different kinds of energy levels, and therefore absorb radiation in several regions of the electromagnetic spectrum. When a molecule absorbs light of a given frequency, specific molecular effects occur, depending on the wavelength absorbed. Low energy radiowaves, for example, cause nuclear spin flip transitions, whereas more energetic UV radiation results in electrons being promoted to higher energy levels. Energy is proportional to the frequency of light absorbed:

!

10!2 100 102 104 106 108 1010 1012

1020 1018 1016 1014 1012 1010 108 106 104

radiowavemicrowaveinfraredX-ray"!ray

visi

ble

UV

400 nm 750 nm

visible spectrum

# (s!1)

$ (nm)

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163

Molecular effects associated with different regions of the EM spectrum:

II. IR Spectroscopy IR radiation causes groups of atoms to vibrate with respect to the bonds that connect them.

We will mostly be concerned with stretching vibrations because bending vibrations occur in a

region of the spectrum that is difficult to interpret.

Wavelength (!)

10"10 meter

10"8 meter

10"6 meter

10"4 meter

10"2 meter

100 meter102 meter

gamma rays

X-rays

vaccum UV

near UV

visible

infrared (IR)

microwave

radio

106 kcal

104 kcal

102 kcal

10 kcal

1 kcal

10"6 kcal10"4 kcal10"2 kcal

ionization

electronic transitions

molecular vibrations

rotational motion

nuclear spin transitions

Energy/mole Molecular effects

C

O

H

HH

rest of molecule

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164

A. The frequency of the stretching vibration depends on two quantities: m1 and m2: the masses of the atoms f: the force constant, or spring constant (a measure of the stiffness of the bond)

• Heavier atoms vibrate more slowly than lighter ones. • The force constant is larger for stronger bonds (it takes more energy to

stretch a stronger bond) and smaller for weaker bonds, thus stronger bonds usually vibrate at a higher frequency than weaker bonds between similar atoms.

Examples:

O H

C H

1.

2.

3. H Csp

H Csp2

H Csp3

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165

B. The intensity of the absorption is proportional to the strength of the dipole moment of the molecule. ∴ A symmetrical bond with no dipole moment will show only a weak absorption or none at all.

C. For a given type of bond, the frequency shows little change with the rest of the molecule.

∴ IR is especially useful in indicating the functional groups present in a molecule. How do you interpret an IR spectrum?

1) You will usually be given the molecular formula of the compound. Use it to evaluate the units of unsaturation (see Chapter 10.)

2) Divide the spectra into 3 regions, and look for characteristic bands using

the IR chart given: X-H region sp region double bond region

3) Practice, practice, practice!

CH3H3C

O H

CH

H

R

H

C O!+ !"

R

H

C O!+ !"

R

H

C C

R

H

C C

R

H

R

H

vs.

polar bond non-polar bond

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166

Interpretation of Infrared Spectra

Aldehydes

Carboxylate

Amides

Acids

Esters

Acid Chlorides

Anhydrides

1725

1550-1610 and 1400

1650

1710

1725 - 1750

1800

1800 - 1840 (2 bands)

1350 and 1550

1600 - 1700

1600 - 1670 weak unless conjugatedDoubleBondRegion

1740

1715

1680

Conjugation:subtract 30

Ring Contraction:add 30 for each contraction

1770

1770

1740

1710andAcyclicKetones:

Carbonyl Groups:

Nitro

Imines

Alkenes

spRegion

(weak or absent if highly symmetrical)

2350

2200

2100

Carbon dioxide

Nitriles

Acetylenes

X-HRegion

secondary

primary

2700 -2800

2900 - 3000

3000 - 3200

3200 -3300

3300 - 3500

2800 - 3600 very broad

3700 - 3500 sharp or3200 - 3600 broad (H-bonded)

1 band:

2 bands:

C-H Bonds

Amines &Amides

Acids

Phenol &Alcohols RO H

R O

R N

HN

C C

C C

O

O

H

H

H

C C H

H

C C

O

HR

C N

NHH

NRH

O C O

C N

C C

NO2

O OO

O

OCl

O

O O

O

OO

OO

O

O

OR

OH

O

O

NH2

O

O

O

H

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168

OH

OH

O

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169

O

OOH

NH2

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170

CN

Br

NH2

O