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Mass Spectrometry Part 1
Lecture Supplement:
Take one handout from the stage
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Spectroscopy
Why bother with spectroscopy?
Determine structure of unknown substance
erify purity!identity of known substance
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SpectroscopyWhat methods are commonly used?
"#ot rigorously a type of spectroscopy
Mass spectrometry $MS%"molecular formula
&nfrared spectroscopy $&'%functional groups
#uclear magnetic resonance $#M'%
C/H molecular skeleton
()ray crystallography"
spatial position of atoms
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Spectroscopy
*+ample: unidentified white powder
MS: ,1-.1/#
&': ben0ene ring secondary amine $'2#.%
#M': has ,.2),.),.3()ray: not necessary in this case,.3
,.3
#
.
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Detector 4uiet
m!0 too small
Mass SpectrometryThe Mass Spectrometer
Fundamental operating principle
Determine mass by manipulating flight path of an ion in a magnetic field
sample
introduction
Measure ionmass)to)charge ratio
$m!0%
Detector
&oni0ation
*lectron gun
5 -
6cceleratorplates
Magnet
m!0 7ust right
Detector fires
&oni0ation: ( 5 e) (58 5 2 e)
m!0 too large
Detector 4uiet
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Isotopes
6ston mass spectrum of neon $1919%#e empirical atomic weight 2-82 amu#e mass spectrum: predict single peak at m!0 2-82
'esults m!0 relati;e intensity
2-82 no peak
2-8- 9-58 5 2 e)
mass)to)charge ratio $m!0%
'elati;eionabundance$ + 1% 1@
, .
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The Mass Spectrum
6lternate data presentation888
m!0 $amu% 'elati;e abundance $ 982
13 38-
12 18-
M52
M51
M
Molecular ion $M%: intact ion of substance being analy0ed
ragment ion: formed by clea;age of one or more bonds on molecular ions
12,1.>
13,1.>or12,2.1.3
1>,1.>or12,3.1.3or888
M ) .M ) 2.
M ) 3.
M ) >.
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The Mass SpectrumOrigin of Relative Ion Abundances
M contributors M51 contributors M52 contributors
IsotopeNatural
AbundanceIsotope
Natural
AbundanceIsotope
Natural
Abundance
1. 9989A//< 2. -8-1/< 3. ppm
12, 9A8A93 13, 181-C 1>, ppm
1># 998@3> 1/# -83@@
1@E 998C/9 1CE -8-3C 1AE -82->
19 1--8-
32S 9/8- 33S -8C@ 3>S >822
3/,l C/8CC 3C,l 2>823
C9?r /-8@9 A1?r >9831
12C& 1--8-
This table will be provided on an exam. Do not memorize it.
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The Mass SpectrumRelative Intensity of Molecular Ion ea!s
&magine a sample containing 1---- methane molecules888
Molecule F in sample m!0 'elati;e abundance
12,1.> 9AA9 12 5 $> + 1% 1@ 1--11- 13 5 $> + 1% 1C $11-!9AA9% + 1--< 181
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Formula from Mass SpectrumM51 ,ontributors
,omparing many mass spectra re;eals M51 intensity G181< per , in formula
*+amples: ,2.@ M 1--
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Formula from Mass SpectrumM52 ,ontributors
6nything useful from intensity of M52I
32S : 3>S
&sotopes #atural abundances &ntensity M : M52
1-- : >8>9/8- : >82
3/,l : 3C,l C/8A : 2>82 1-- : 3189
C9?r : A1?r /-8C : >983 1-- : 9C82
,onclusion:Mass spectra of molecules with S, Cl, or Br have significant M+2 peaks
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m!0
'elati;
eab
unda
nc
e$
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122'
elati;eabundance$
, . ?rM: 3@ 5 C 5 C9 122
M:M52abundance
G1:1
12>
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Identifying the Molecular Ions
Which pea!s are molecular ions?
.ighest m!0 not always MM51 has m!0 one more than m!0 of M
?r ,C.C?r
M: m!0 1C-
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Formula from Mass Spectrum
M: 'e;eals mass of molecule composed of lowest mass isotopes
M51: &ntensity of M51 ! 181< number of carbons
M52: &ntensity re;eals presence of sulfur chlorine and bromine
"ummary of Information from Mass "pectrum
#e+t lecture: procedure for deri;ing formula from mass spectrum
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Mass Spectrometry Part 2
Lecture Supplement:
Take one handout from the stage
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Summary of Part 1
"pectroscopy: Study of the interaction of photons and matterJseful to determine molecular structureTypes: MS" &' #M' +)ray crystallography" "not really spectroscopy
M" fundamental principle: Manipulate flight path of ion in magnetic field,harge $0% magnetic field strength are knownH ion mass $m% is determined
Isotopes: #atural abundance of isotopes controls relati;e abundance of ions
Molecular ion #M$ M%&$ M%'$ etc()* &ntact ion of substance being analy0edm!0 of M molecular mass composed of lowest mass isotopes 1. 12, 3/,l etc8
'elati;e abundance of M51!181< gi;es appro+imate number of carbonsM52 re;eals presence of sulfur chlorine or bromine
+ragment ion*rom decomposition of molecular ion before reaching detector6nalysis of fragmentation patterns not important for ,hem 1>,
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Mass Spectrum ormula Structure
#ot tri;ial to do this directlyStructure comes from formulaH formula comes from mass spectrum
,ow do we derive structure from the mass spectrum?
?
,
,.3
,l
,.3
.
,
,.3
,l
,.3
. ,3.C,l
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Mass Spectrum ormula Structure
,ow do we derive formula from the mass spectrum?
m!0 and relati;e intensities of M M51 and M52
6 few useful rules to narrow the choices
M: m!0 CA
,2.@E3,3.C,l
,/.>#
,@.@
etc8
M
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.ow Many #itrogen 6tomsI
,onsider these molecules:
#.3 .2##.2
ormula: #.3 #2.>
32
,C./#3E@
22C
,A.1-#>E2
19>
#E2
,.3
E2#
#E2
#
# #
#
,.3E
E
.3,
,.3
,onclusion=hen m!0 $M% e;en number of # in formula is e;en
1Cm!0 $M%:
-he Nitrogen RuleK=hen m!0 $M% odd number of # in formula is odd
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.ow Many #itrogen 6tomsIA Nitrogen Rule ./ample
M: m!0 CA
,2.@E3
,3.C,l
,/.>#
,@.@
*+ample: ormula choices from pre;ious mass spectrum
m!0 e;en
odd nitrogen countdiscarded
e;en nitrogen count
e;en nitrogen count
e;en nitrogen count
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.ow Many .ydrogen 6tomsI
,@.1>max H for 6 C
Ene pi bond Two pi bonds
,onclusion: *ach pi bond reduces ma+ hydrogen count by two
,.,
,@.12H count max ! 2
,@.1-H count max ! "
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.ow Many .ydrogen 6tomsI
,onclusion: *ach ring reduces ma+ hydrogen count by two
Ene ring Two rings
,@.1>max H for 6 C
,@.12H count max ! 2
,@.1-H count max ! "
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.ow Many .ydrogen 6tomsIEne nitrogen Two nitrogens
,@.1/#
H count max + #
,@.1@#2H count max + 2
,onclusion:
#.2
#
#
,.3
,.3
#.3,
,.3
,@.1>max H for 6 C
#.2 #.2
*ach nitrogen increases ma+ . count by oneor , carbons and # nitrogens ma+ number of . 2, 5 # 5 2
-he ,ydrogen Rule
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Mass Spectrum ormula
rocedure
,hem 1>, atoms: . , # E S ,l ?r &M molecular weight $lowest mass isotopes%
M51: gi;es carbon countM52: presence of S ,l or ?r#o mass spec indicator for & $ssume a%sent unless otherwise specifie&6ccounts for all atoms e+cept E # and .M= ) mass due to , S ,l ?r and & mass due to E # and .Systematically ;ary E and # to get formula candidatesTrim candidate list with nitrogen rule and hydrogen rule
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Mass Spectrumormula./ample 0&
m!0 Molecular ion 'elati;e abundance ,onclusions
1-2 M 1-- to @8@@ @ or CH @8@C to C8-- C
" so no S, Cl, or Br
-x.gen
Li;eninformation
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Mass Spectrumormula./ample 0&
Mass $M% ) mass $, S ,l ?r and &% mass $# E and .%
1-2 ) ,@ 1-2 ) $@ + 12% 3- amu for # E and .
E+ygens #itrogens 3- ) E ) # . ormula #otes
- - 3- ) - ) - 3- ,@.3- iolates hydrogen rule
1 - 3- ) 1@ ) - 1> ,@.1>E 'easonable
2 - 3- ) 32 ) - )2 ,@
.)2
E2
#ot possible
- 2""#itrogen rule
3- ) - ) 2A 2 ,@.2#2 'easonable
Ether data $functional groups from &' #M' integration etc8% further trims the list
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Mass Spectrumormula./ample 0'
m!0 Molecular ion 'elati;e abundance ,onclusions
1/C M 1-- 12 ,A.12,l# 'easonable1""#itrogen rule
Try eight carbons: M ) ,A) ,l 1/C ) $A + 12% ) 3/ 2@ amu for E # and .
#ot enough amu a;ailable for one o+ygen!one nitrogen or no o+ygen!three nitrogens
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Mass Spectrumormula./ample 0'
E+ygens #itrogens 1> ) E ) # . ormula #otes
- 1> ) - ) 1> - ,9,l# 'easonable1""#itrogen rule
Try nine carbons: M ) ,9) ,l 1/C ) $9 + 12% ) 3/ 1> amu for E # and .
#ot enough amu a;ailable for any other combination8
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ormulaStructure
What does the formula reveal about molecular structure?
unctional groups6bsent atoms may eliminate some functional groups
*+ample: ,C.9# has no o+ygen)containing functional groups
Pi bonds and rings'ecall from pre;ious: one pi bond or one ring reduces ma+ . count by two*ach two . less than ma+ . count double bond e4ui;alent $D?*%
&f formula has less than full . count molecule must contain one pi bond or ring
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ormulaStructure1alculating D2.
D?* may be calculated from molecular formula:
Ene D?* one ring or one pi bondTwo D?* two pi bonds two rings or one of eachour D?* possi%leben0ene ring
D?* , ) .2
5 5 1#2
nitrogens
car%ons
h.&rogens an& halogens
D?* , ) $.!2% 5 $#!2% 5 1
A ) N$1-51%!2O 5 $1!2% 5 1
3our pi %on&s an&/or ring
4ossi%le %en5ene ring
*+ample
,A.1-,l#
>
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ormulaStructure1ommon Math .rrors
"mall math errors can have devastating effects3
No calculators on exams
6;oid these common spectroscopy problem math errors:Di;ide by 181 di;ide by 18-D?* cannot be a fractionD?* cannot be negati;e
#e+t lecture: &nfrared spectroscopy part 1