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Chapter 14. Chemical Equilibrium 14.1Characteristics of Chemical Equilibrium 14.2The Equilibrium Constant 14.3Determining Equilibrium Constants 14.5The Meaning of Equilibrium Constant14.6Using Equilibrium Constants14.7Shifting a Chemical Equilibrium: Le Chatelier's
Principle 14.8Equilibrium at the Nanoscale14.9Controlling Chemical Reactions: The Haber-Bosch
Process
14-3CHEM 102, Fall 2011, LA TECH
Different types of arrows are used in chemical equations associated with equilibria.
Single arrow
Assumes that the reaction proceeds to completion as written.
Two single-headed arrows
Used to indicate a system in equilibrium.
Two single-headed arrows of different sizes.
May be used to indicate when one side of an equilibrium system is favored.
Chemical equilibrium
14-4CHEM 102, Fall 2011, LA TECH
Chemical EquilibriumBranch of chemistry dealing with reactions
where reactants and products coexist in a dynamic equilibrium
the rates of forward and backward reactions have comparable rates reaction
14-5CHEM 102, Fall 2011, LA TECH
Chemical Equilibrium
Equilibrium region.
A point is finally reached where the forward and reverse reactions occur at the same rate.
H2 + I2 2HI
There is no net change in the concentration of any of the species.
14-6CHEM 102, Fall 2011, LA TECH
Chemical EquilibriumP
art
ial P
ressu
re
Time
HI
I2
H2
Equilibrium
Region
Kinetic
Region
14-7CHEM 102, Fall 2011, LA TECH
Complete Reaction
Con
cen
trati
on
Time
Kinetic No change Region
14-8CHEM 102, Fall 2011, LA TECH
Equilibrium
A state where the forward and reverse conditions occur at the same rate.
Dynamic
Equilibrium
I’m in static
equilibrium.
14-9CHEM 102, Fall 2011, LA TECH
This type of plot
shows the energy
changes during
a reaction.
This type of plot
shows the energy
changes during
a reaction.
Forward and Backward Reactions
H
activation
energy
Pote
nti
al
En
erg
y
Reaction coordinate
14-10CHEM 102, Fall 2011, LA TECH
Value of K
rate of forward Reaction k+ K = ------------------------------ = --- rate of backward Reaction k-
K = a (infinity) -> Irreversible reactions
K = 0 -> No reaction
K = between 0 and 1 -> Equilibrium reactions
14-11CHEM 102, Fall 2011, LA TECH
Law of mass ActionDefines an equilibrium constant (K) for the process
j A + k B l C + m D
[C]l[D]m
K = ----------------- ; [A], [B] etc are
[A]j[B]k Equilibrium concentrations
Pure liquid or solid concentrations are not written in the expression.
14-12CHEM 102, Fall 2011, LA TECH
Equilibrium ExpressionAn equilibrium expression could be written
for any reaction
[HI]2
K = ----------- = 16 L/mol [H2][I2]Keq >> 1 reaction will go mainly to products
Keq ~ 1 reaction will produce roughly equal amounts of product and reactant
Keq << 1 reaction will go mainly to reactants
14-13CHEM 102, Fall 2011, LA TECH
k is constant at a temperature
Initial @ Equilibrium
N2O4 NO2 N2O4 NO2 Keq
0.00 0.02 0.0014 0.017 0.21
0.00 0.03 0.0028 0.024 0.21
0.00 0.04 0.0045 0.031 0.21
0.02 0.00 0.0045 0.031 0.21
N2O4(g)
colorless
2NO2(g)
Dark brown
K eq [ ]
[ ]NON O
2
2 4
2
14-14CHEM 102, Fall 2011, LA TECH
Calculating Stepwise EquilibriumAdd two equations with K1 and K2 to get Keq
Keq = K1 x K2
Subtract one equations with K2 from another with K2 to get Keq
Keq = K1 / K2
Doubling K1 to get Keq
Keq = (K1)2 ;tripling Keq = (K1)3 etc.
Reversing a reaction with K1 get Keq
Keq = (K1)½
14-15CHEM 102, Fall 2011, LA TECH
Stepwise Equilibrium
(1) N2(g) + O2(g) 2NO(g) [NO]
2
Kc1 =
[N2][O2]
(2) 2NO(g) + O2(g) 2NO2(g) [NO2]
2
Kc2 =
[NO]2
[O2]Add to Combine (1.) & (2.)
N2(g) + 2O2(g) 2NO2(g)
[NO]2
[NO2]2
Kc = = Kc1 Kc2
[N2][O2] [NO]2
[O2]
14-16CHEM 102, Fall 2011, LA TECH
Stepwise Equilibrium
Consider the reactions
2NO + O2 <===> 2 NO2 K = a
2 NO2 <===> N2O4 K = b
The value of the equilibrium constant for the reaction
2NO + O2 <===> N2O4 is
a. a + b
b. ab
c. (a/b)2
d. (ab)2
e. ab/2
14-17CHEM 102, Fall 2011, LA TECH
Stepwise Equilibrium
Consider the reactions
2NO + O2 <===> 2 NO2 K = a
2 NO2 <===> N2O4 K = b
The value of the equilibrium constant for the reaction
4NO + 2O2 <===> 2 N2O4 is
a. a + b
b. ab
c. (a/b)2
d. (ab)2
e. ab/2
14-18CHEM 102, Fall 2011, LA TECH
Homogenous equilibrium: Chemical equilibrium where reactants and products are in same phase.
Heterogeneous equilibrium: Chemical Equilibrium where at least one phase of a reactant or product is different from the rest.
Types of Equilibria
14-19CHEM 102, Fall 2011, LA TECH
Homogenous equilibrium: Chemical equilibrium where reactants and products are in same phase.
Heterogeneous equilibrium: Chemical Equilibrium where at least one phase of a reactant or product is different from the rest.
Kc (K) - equilibrium constant calculated based on [A]-Concentrations.
Kp- equilibrium constant calculated based on partial pressure (p)
Kp = K(RT) Dn
R = universal gas constant
T = Kelvin Temperature,
Dn = (sum of stoichiometric coefficients of gaseous products) - (sum of the stoichiometric coefficients of gaseous reactants)
14-27CHEM 102, Fall 2011, LA TECH
For the following equilibrium, Kc = 1.10 x 107
at 700. o
C. What is the Kp?
2H2 (g) + S2 (g) 2H2S (g)
Kp = Kc (RT)Dng
T = 700 + 273 = 973 K
R = 0.08206
Dng = ( 2 ) - ( 2 + 1) = -1
atm L
mol K
Partial pressure & Equilibrium Constants
14-28CHEM 102, Fall 2011, LA TECH
Kp = Kc (RT)Dng
= 1.10 x 107
(0.08206 ) (973 K)
= 1.378 x105
atm L
mol K[ ]-1
Partial pressure & Equilibrium Constants
14-29CHEM 102, Fall 2011, LA TECH
Determining Equilibrium ConstantsICE Method
1. Derive the equilibrium constant expression for the balanced chemical equation
2. Construct a Reaction Table with information (ICE) about reactants and products
3. Include the amounts reacted, x, in the Reaction Table
4. Calculate the equilibrium constant in terms of x
14-30CHEM 102, Fall 2011, LA TECH
TerminologyInitial concentration:concentration (M) of reactants and products
before the equilibrium is reached.
Equilibrium ConcentrationConcentration (M) of reactants and products
After the equilibrium is reached.
14-31CHEM 102, Fall 2011, LA TECH
Example: An equilibrium is established by placing 2.00 moles of N2O4(g) in a 5.00 L and heating the flask to 407 K. It was determined that at equilibrium the concentration of the NO2(g) is 0.525 mol/L. What is the value of the equilibrium constant?
N2O4(g) 2 NO2(g)
[NO2]2
Kc =
[N2O4]
N2O4(g) 2 NO2(g)
[Initial] (mol/L) 0.40 0
[Change] -x 2x
[Equilibrium]
0.40- 0.243= 0.138 0.525
x-1/2 x
0.40 - 1/2x = 0 + x
14-32CHEM 102, Fall 2011, LA TECH
What is the value of the equilibrium constant?
0.525 = 0 + x [NO2]2
Kc =
[N2O4]
0.40 - 1/2x
x = 0.525 [NO2] = 0.40 - 1/2x
= 0.40 - 1/2(0525)
= 0.138
[NO2]2
(0.525)2
Kc = =
[N2O4] 0.138
= 2.00
NO2(g ) N2O4(g)
14-33CHEM 102, Fall 2011, LA TECH
Equilibrium Calculations
Hydrogen iodide, HI, decomposes according to the equation
2 HI(g) H2(g) + I2(g)
When 4.00 mol of HI placed in a 5.00-L vessel at 458ºC, the equilibrium mixture was found to contain 0.442 mol I2. What is the value of Kc for the reaction?
14-34CHEM 102, Fall 2011, LA TECH
Initial 4.00/5=.80 0 0
Change -2x x x
Equilibrium 0.80-2x x x=0.442/5
x = 0.0884
Equilibrium concentrations
[HI] = 0.80 - 2x = 0.8 - 2 x 0.0884 = 0.62
[H2] = x = 0.0884
[I2] = x = 0.0884 [H2] [I2] 0.0884 x 0.0884Kc = ---------------- = ------------------------- = 0.0201 [HI]2 (0.62) 2
2 HI(g) H2(g) + I2(g)
14-35CHEM 102, Fall 2011, LA TECH
Selected Equilibrium Constants
14-36CHEM 102, Fall 2011, LA TECH
What is the reaction quotient, Q
(Q) is constant in the equilibrium expression when initial concentration of reactants and products are used.
SO2(g)+ NO2(g) NO(g) +SO3(g)
[NO][SO3]
Q = ----------------
[SO2][NO2]
comparing to K and Q provide the net direction to achieve equilibrium.
14-37CHEM 102, Fall 2011, LA TECH
We can predict the direction of a reaction by calculating the reaction quotient.
Reaction quotient, Q
For the reaction: aA + bB eE + fF
Q has the same form as Kc with one important difference. Q can be for any set of concentrations, not
just at equilibrium.
Q =[E]
e [F]
f
[A]a [B]
b
Equilibrium calculations
14-38CHEM 102, Fall 2011, LA TECH
Any set of concentrations can be given and a Q calculated. By comparing Q to the Kc
value, we can predict the direction for the reaction.
Q < Kc Net forward reaction will occur.
Q = Kc No change, at equilibrium.
Q > Kc Net reverse reaction will occur.
Reaction quotient
14-39CHEM 102, Fall 2011, LA TECH
Predicting the Direction of a Reaction
14-40CHEM 102, Fall 2011, LA TECH
Consider the following reaction:
SO2(g) + NO2(g) NO(g) + SO3(g)
(Kc = 85.0 at 460oC)
Given: 0.040 mole of SO2(g), 0.500 mole of NO2(g), 0.30 mole of NO(g),and 0.020
mole of SO3(g) are mixed in a 5.00 L flask, Determine: