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Контролабилност система и повратна спрега по стању система М.Божић, САУ, 2013/14.
26

13 - Kontrolabilnost Sistema i Povratna Sprega Po Stanju Sistema

Sep 06, 2015

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  • ., , 2013/14.

  • /

    9.1

  • .

    , , .

    .

    - - -

    ),(

    ),(

    uxgy

    uxfdtdx

    ==

    nRtx )(pRtu )(mRty )(

    DuCxy

    BuAxdtdx

    +=+=

    (9.2)

  • /

    buyadtdya

    dtyda

    dtyd

    n

    n

    nn

    n

    =++++

    121

    1

    L

    =

    =

    11

    2

    1

    /

    /

    nnn dtyd

    dtdyy

    x

    xx

    x MM

    1

    21 1

    00

    01000010

    xy

    bux

    aaadtdx

    n

    =

    +

    = M

    LL

    LL

  • / (1)

    / , ,

    duxbxbxby nnn ++++= 1211 L

    [ ] duxbbby

    ux

    aaadtdx

    nn

    n

    +=

    +

    =

    11

    21 1

    00

    01000010

    L

    ML

    LLL

  • 9.1

    .9.1

    sincos)(sincos)(

    2

    2

    mglpmlmlJFmlpbmlpmM

    =++++=++

    &&&&&&&&&&

    , m J, , l m , b , g , p .9.1.

  • 9.1..

    u=F, . 9.1,

    =0 sin0, cos1 (..)

    Tppx ],,,[ &&=Tpy ][ =

    ++

    ++

    =

    sinsin

    coscos 21

    2 mglumlpb

    mlmlJmlmM

    p

    p

    p

    dtd

    &&&&

    &&

  • 9.1..

    u

    MmlmMJml

    MmlmMJmlJ

    p

    p

    MmlmMJmlb

    MmlmMJmMmgl

    MmlmMJbmlJ

    MmlmMJglm

    p

    p

    dtd

    ++

    ++++

    ++

    +++

    +++

    ++=

    2

    2

    2

    22

    2

    2

    2

    22

    )(

    )(

    00

    0)()(

    )(0

    0)(

    )()(

    0

    10000100

    &&

    &&

    xy

    =00100001

  • () , =0.

    ,

    ( ) , .

    , =0.

    )( 4321 && kpkkpkKxu +++==[ ]Tppx &&= [ ]4321 kkkkK =

  • u(t) y(t) , (9.2) . A, B C (9.2) , D .

    (9.7)

    - . (9.2) Txz =

    uBzATBuzTATBuAxTdtdz ~~)( 1 +=+=+=

    DuzCDuzCTDUCxy +=+=+= ~1DDCTCTBBTATA ==== ~,~,~,~ 11

  • (1)(1)

    z(t) x(t),

    (9.9) , (9.7) (9.9) (9.2).

    +== t tAtA duBeTTxeTtzTtx0

    )(~1~11 )(~)0()()( A~

  • x(t)

    .

    uxdtdx

    nn

    +

    =

    MO2

    1

    2

    1

    0

    0

    uxx iiii +=&

  • 9.2

    =

    n

    A

    0

    0

    2

    1

    O

    =

    kkn

    kk

    kk

    k

    t

    tt

    At

    0

    0

    )( 21

    O

    =

    tn

    t

    t

    At

    e

    ee

    e

    0

    02

    1

    O

  • (Jordan)

    i ixi Ji.

    =

    kJ

    JJ

    J

    LO

    L

    0

    0

    2

    1

    =

    i

    i

    i

    iJ

    LO

    L

    01

    101

    i

    =

    tJ

    tJ

    tJ

    Jt

    ke

    ee

    e

    LOMLL

    00

    0000

    2

    1

    =

    t

    titt

    tittt

    tJ

    i

    iii

    iiii

    i

    e

    ietete

    ietettee

    e

    LM

    L

    000

    )!2(...0

    )!1(!22

    12

  • .

    ( s-) .

    s-.

    x(0)- (9.14) u(t)

    x(t) t>0 x(0)?

    BuAxdtdx +=

  • (1)(1)

    : Za stawa modela kontinualnog sistema ija je jednaina staa (9.14) aemo da su potpuno kontrolabilna ako je za svako poetno stae x(0) za bilo koje eeno terminalno stae x* mogue nai upravae u(t) u nekom konanom vremenskom intervalu [0,] tako da se obezbedi uslov x()=x*.

    :

    u(t) (0,t) x(t), , B, AB,..., An-1B .

    n.

    .

    dtBuedBuetxt

    At

    tA )()()(00

    )( == 0t)(...)()( 1

    110 +++= nnA AAIe

    +++= t t t nn dtuBAdtuABdtuBtx0 0 0

    11

    10 )()(...)()()()()(

    [ ]BAABBW nC 1= L

    , x(0)=0, u(t)0,

  • 9.5

    (9.16)

    . ( )

    (9.16) ( ).

    uBzAuz

    aaaa

    dtdz

    nn

    ~~

    0

    001

    0100

    00100001

    121

    +=

    +

    =

    MM

    L

    =

    1000

    101

    ~ 21121

    1

    LM

    LL

    n

    n

    C

    aaaaa

    W

  • . 9.3.

    S

    S

    u S , u S.

    .9.3

    uxdtdx

    uxdtdx

    +=

    +=

    22

    11

    =

    1111

    CW

  • z=Tx .[ ]BAABBW nC 1= L

    TABTBTATBA == 1~~BTATBTATTATTBTATBA 211212 )(~~ ===

    M.~~ BTABA nn =[ ] [ ] CnnC TWBAABBTBABABW === 11 ~~~~~~ LL

    1~ = CCWWT

  • .

    -

  • ,

    K AZ(s)

    Cxy

    BuAxdtdx

    =+=

    ))(()( txftu =

    )()()( trKtKxtu r+=

    nnnn

    Z pspspsBKAsIsA ++++=+= 111)det()( L)det( BKAsI +

    rBKxBKAdtdx

    r+= )(

  • 9.8

    (): :

    r(t)=r0 ess=0

    [ ]xyuxdtdx 01;

    10

    0010 =

    +

    =

    rKxkxku r+= 2211

    [ ]xyrKx

    kkdtdx

    r

    011010

    21

    =

    +

    = 122

    21

    1det ksks

    ksks ++=

    +

    200

    2 2)( ++= sssAZ 202201 2, == kk2

    0=rK

  • .

    9.9

    !

    ... 0 .

    [ ]xyuxdtdx 01;

    01

    0010 =

    +

    =

    rKxkxku r+= 2211

    )(0

    1det 11

    221 ksssksskks +=+=

    ++

    x2 je .

  • , () .

    9.10 ,

    (9.24)

    [ ] .~0

    001

    0100

    00100001

    ~~

    21

    121

    zbbbzCy

    uz

    aaaa

    uBzAdtdz

    n

    nn

    L

    MM

    L

    ==

    +

    =+=

  • (1)

    (9.24)

    .

    100

    0010001

    det)(

    121

    +

    =

    s

    saaaas

    sD

    nn

    n

    M

    L

    nnnn

    n asasassD +++= 111)( L

    rKzkzkzkrKzKu rnnr +=+= ~~~~ 2211 L

    [ ] .0

    00

    0100

    00100001

    ~~~~

    21

    112211

    zbbby

    r

    K

    z

    kakakaka

    dtdz

    n

    rnnnn

    L

    MM

    L

    =

    +

    =

  • (2)

    . . :

    ess=0

    :

    x: -

    , .

    nnnnnn

    Z kaskaskassA~)~()~()( 11

    111 +++++++= L

    nnn apk

    apk

    apk

    =

    ==

    ~

    ~

    ~

    222

    111

    n

    n

    n

    nnr b

    pbkaK =+=~

    Txz =

    CW

    1~ = CCWWT rKKxrKTxKu rr +=+= ~

    ;~~~ 1== CCWWKTKK CW~rKzKu r+= ~