Контролабилност система и повратна спрега по стању система М.Божић, САУ, 2013/14.
., , 2013/14.
/
9.1
.
, , .
.
- - -
),(
),(
uxgy
uxfdtdx
==
nRtx )(pRtu )(mRty )(
DuCxy
BuAxdtdx
+=+=
(9.2)
/
buyadtdya
dtyda
dtyd
n
n
nn
n
=++++
121
1
L
=
=
11
2
1
/
/
nnn dtyd
dtdyy
x
xx
x MM
1
21 1
00
01000010
xy
bux
aaadtdx
n
=
+
= M
LL
LL
/ (1)
/ , ,
duxbxbxby nnn ++++= 1211 L
[ ] duxbbby
ux
aaadtdx
nn
n
+=
+
=
11
21 1
00
01000010
L
ML
LLL
9.1
.9.1
sincos)(sincos)(
2
2
mglpmlmlJFmlpbmlpmM
=++++=++
&&&&&&&&&&
, m J, , l m , b , g , p .9.1.
9.1..
u=F, . 9.1,
=0 sin0, cos1 (..)
Tppx ],,,[ &&=Tpy ][ =
++
++
=
sinsin
coscos 21
2 mglumlpb
mlmlJmlmM
p
p
p
dtd
&&&&
&&
9.1..
u
MmlmMJml
MmlmMJmlJ
p
p
MmlmMJmlb
MmlmMJmMmgl
MmlmMJbmlJ
MmlmMJglm
p
p
dtd
++
++++
++
+++
+++
++=
2
2
2
22
2
2
2
22
)(
)(
00
0)()(
)(0
0)(
)()(
0
10000100
&&
&&
xy
=00100001
() , =0.
,
( ) , .
, =0.
)( 4321 && kpkkpkKxu +++==[ ]Tppx &&= [ ]4321 kkkkK =
u(t) y(t) , (9.2) . A, B C (9.2) , D .
(9.7)
- . (9.2) Txz =
uBzATBuzTATBuAxTdtdz ~~)( 1 +=+=+=
DuzCDuzCTDUCxy +=+=+= ~1DDCTCTBBTATA ==== ~,~,~,~ 11
(1)(1)
z(t) x(t),
(9.9) , (9.7) (9.9) (9.2).
+== t tAtA duBeTTxeTtzTtx0
)(~1~11 )(~)0()()( A~
x(t)
.
uxdtdx
nn
+
=
MO2
1
2
1
0
0
uxx iiii +=&
9.2
=
n
A
0
0
2
1
O
=
kkn
kk
kk
k
t
tt
At
0
0
)( 21
O
=
tn
t
t
At
e
ee
e
0
02
1
O
(Jordan)
i ixi Ji.
=
kJ
JJ
J
LO
L
0
0
2
1
=
i
i
i
iJ
LO
L
01
101
i
=
tJ
tJ
tJ
Jt
ke
ee
e
LOMLL
00
0000
2
1
=
t
titt
tittt
tJ
i
iii
iiii
i
e
ietete
ietettee
e
LM
L
000
)!2(...0
)!1(!22
12
.
( s-) .
s-.
x(0)- (9.14) u(t)
x(t) t>0 x(0)?
BuAxdtdx +=
(1)(1)
: Za stawa modela kontinualnog sistema ija je jednaina staa (9.14) aemo da su potpuno kontrolabilna ako je za svako poetno stae x(0) za bilo koje eeno terminalno stae x* mogue nai upravae u(t) u nekom konanom vremenskom intervalu [0,] tako da se obezbedi uslov x()=x*.
:
u(t) (0,t) x(t), , B, AB,..., An-1B .
n.
.
dtBuedBuetxt
At
tA )()()(00
)( == 0t)(...)()( 1
110 +++= nnA AAIe
+++= t t t nn dtuBAdtuABdtuBtx0 0 0
11
10 )()(...)()()()()(
[ ]BAABBW nC 1= L
, x(0)=0, u(t)0,
9.5
(9.16)
. ( )
(9.16) ( ).
uBzAuz
aaaa
dtdz
nn
~~
0
001
0100
00100001
121
+=
+
=
MM
L
=
1000
101
~ 21121
1
LM
LL
n
n
C
aaaaa
W
. 9.3.
S
S
u S , u S.
.9.3
uxdtdx
uxdtdx
+=
+=
22
11
=
1111
CW
z=Tx .[ ]BAABBW nC 1= L
TABTBTATBA == 1~~BTATBTATTATTBTATBA 211212 )(~~ ===
M.~~ BTABA nn =[ ] [ ] CnnC TWBAABBTBABABW === 11 ~~~~~~ LL
1~ = CCWWT
.
-
,
K AZ(s)
Cxy
BuAxdtdx
=+=
))(()( txftu =
)()()( trKtKxtu r+=
nnnn
Z pspspsBKAsIsA ++++=+= 111)det()( L)det( BKAsI +
rBKxBKAdtdx
r+= )(
9.8
(): :
r(t)=r0 ess=0
[ ]xyuxdtdx 01;
10
0010 =
+
=
rKxkxku r+= 2211
[ ]xyrKx
kkdtdx
r
011010
21
=
+
= 122
21
1det ksks
ksks ++=
+
200
2 2)( ++= sssAZ 202201 2, == kk2
0=rK
.
9.9
!
... 0 .
[ ]xyuxdtdx 01;
01
0010 =
+
=
rKxkxku r+= 2211
)(0
1det 11
221 ksssksskks +=+=
++
x2 je .
, () .
9.10 ,
(9.24)
[ ] .~0
001
0100
00100001
~~
21
121
zbbbzCy
uz
aaaa
uBzAdtdz
n
nn
L
MM
L
==
+
=+=
(1)
(9.24)
.
100
0010001
det)(
121
+
=
s
saaaas
sD
nn
n
M
L
nnnn
n asasassD +++= 111)( L
rKzkzkzkrKzKu rnnr +=+= ~~~~ 2211 L
[ ] .0
00
0100
00100001
~~~~
21
112211
zbbby
r
K
z
kakakaka
dtdz
n
rnnnn
L
MM
L
=
+
=
(2)
. . :
ess=0
:
x: -
, .
nnnnnn
Z kaskaskassA~)~()~()( 11
111 +++++++= L
nnn apk
apk
apk
=
==
~
~
~
222
111
n
n
n
nnr b
pbkaK =+=~
Txz =
CW
1~ = CCWWT rKKxrKTxKu rr +=+= ~
;~~~ 1== CCWWKTKK CW~rKzKu r+= ~