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UTS KINEMATIKA & DINAMIKA RIZA FARRASH KARIM – 130638803 – TEKNIK MESIN
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12_Riza Farrash Karim.pptx

Sep 28, 2015

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UTS KINEMATIKA & DINAMIKA

UTS KINEMATIKA & DINAMIKARIZA FARRASH KARIM 130638803 TEKNIK MESIN1

ABOCKETERANGAN:O-A = 0.03 mA-B = 0.15 mA-C = 0.15 mA-CGI = 0.05 mA-CGII = 0.05 mAO = 12 rad/s CWAO = 2 rad/s2 CCWSudut O-A ke Sb. Y = 60oCG I CG II SKALA 1:1SKALA 1:33.33OVVBVAVCVCGIIVCGIVBAVCAVCGIIAVCGIAKECEPATANPERHITUNGAN KECEPATANvA = vO + vAO = AO x rAOvA = 12*0.03 = 0.36 m/s = 12 cm

vB = vA + vBAvB = terukur 2.503 cm = 0.075 m/s

vC = vA + vCAvC = terukur 12.19 cm = 0.366 m/s

vCGII = vA + vCGIIAvCGII = terukur 11.97 cm = 0.359 m/s

vCGI = vA + vCGIAvCGI = terukur 8.257 cm = 0.248 m/s

SKALA 8:1aAaBaBAaCaCAaCGIaCGIIaCGIAaCGIIAPERCEPATAN*sebagian garis vector diluar slide untuk menjaga panjang an nyaPERCEPATAN CG MENGGUNAKAN KESEBAGUNANPERCEPATAN CG MENGGUNAKAN KESEBAGUNANPERHITUNGAN PERCEPATANaA = aO + aAO = aAn + aAt = AO2 rAO + AOrAOaA = 1220.03 + 2 . 0.03 = 4.32 + 0.06 = 4.32 m/s2 = 34.56 cm di gambar

aB = aA + aBAaB = terukur 27.35 cm = 3.419 m/s2

aC = aA + aCAaC = terukur 3.196 cm = 0.4 m/s2

aCGI = aA + aCGIAaCGI = terukur 31.84 cm = 3.98 m/s2

aCGII = aA + aCGIIAaCGII = terukur 23.256 cm = 2.907 m/s22

ABCDKETERANGAN:O-A = 1.8 mO-B = 3.4 mD-B = 1.3 mD-O = 2.4 mC-O = 8.2 mBO = 12 rad/s CWBO = 2 rad/s2 CCWSudut strut = 35oOOKETERANGAN:O-A = 1.8 mO-B = 3.4 mD-B = 1.3 mD-O = 2.4 mC-O = 8.2 mO-CG = 2.05 mBO = 12 rad/s CWBO = 2 rad/s2 CCWSudut strut = 35oABCDOOCGVAVBVDVDBVCVCGKECEPATANSKALA 1:8PERHITUNGAN KECEPATANvA = vO + vAO = AO x rAOvA = 12*1.8 = 21.6 m/s = 2.7 cm

vB = vO + vBO = BO x rBOvB = 12*3.4 = 40.8 m/s = 5.1 cm

vD = vB + vDB = vDOvD = terukur 9.72 cm = 77.737 = DO x rDO = DB x rDBDO = vDO / 2.4 = 32.39 rad/sDB = vDB/rDB = 48.98/1.3 = 37.677 rad/s

vC = DO x rCOvC = 32.39 x 8.2 = 265.598 m/s

vCG = DO x rCGvCG = 32.39 x 2.05 = 66.4 m/s

aAaBaDaCGaCPERCEPATANSKALA 1:128*Komponen at dan an dari aB dan aA tidak dapat ditampilkan karena sangat kecil PERHITUNGAN PERCEPATANaA = aO + aAO = aAn + aAt = AO2 rAO + AOrAOaA = 1221.8 + 2 . 1.8 = 259.2 + 3.6 = 259.225 m/s2 = 2.025 cm di gambar

aB = aO + aBO = aBn + aBt = BO2 rBO + BOrBOaB = 1223.4 + 2 . 3.4 = 489.6 + 6.8 = 489.647 m/s2 = 3.825 cm di gambar

aD = aO + aDO = aDOn + aDOt = 32.3922.4 + aDOt = 19.67 cm + aDOtaD = aB + aDB = aB + DB2rDB + DBrDB = 14.417 cm + aDBtPerpotongannya menghasilkan DO = CO = 602.06 rad/s2

aC = aO + aCO = CO2 rCO + COrCO = 77.48 cm = 9918.653 m/s2aCG = CG2 rCG + CGrCG = 19.372 cm = 2479.66 m/s23

ABCDEKETERANGAN:O-A = 1.2 mA-B = 4.8 mO-C = 3 mO-B = 2.4 mB-D = 4.8 mA-D = 9.5 mE-D = 0.6 mE-C = 5.2 mAO = 12 rad/s CWAO = 2 rad/s2 CCWSudut motor = 35oABCDEKETERANGAN:O-A = 1.2 mA-B = 4.8 mO-C = 3 mO-B = 2.4 mB-D = 4.8 mA-D = 9.5 mE-D = 0.6 mE-C = 5.2 mAO = 12 rad/s CWAO = 2 rad/s2 CCWSudut motor = 35oVAVBVBAVDAVDVCVDBVEVECPERHITUNGAN KECEPATANvA = vO + vAO = AO x rAO = 12 x 1.2 = 14.4 m/s = 14.4 cmvB = vA + vBA = 13.492 cm = 13.492 m/sBO = vBO/rBO = 13.492/2.4 = 5.622 rad/sBA = vBA/rBA = 3.54/4.8 = 0.738 rad/s

vC = CO x rCO = 5.622 x 3 = 16.866 m/svD = vB + vDB = vA + vDA = 12.353 cm = 12.353 m/sDB = vDB/rDB = 3.932/4.8 = 0.819 rad/sDA = vDA/rDA = 7.37/9.5 = 0.776 rad/svE = vD + vED = vC + vEC = 14.29 cm = 14.29 m/sED = vED/rED = 1.96/0.6 = 3.27 rad/sEC = vEC/rEC = 5.18/5.2 = 0.996 rad/sSKALA 1:1aAaBaCaEaDSKALA 1:4PERHITUNGAN PERCEPATAN

aA = AO2rAO + AOrAOaA = 1221.2 + 2 . 1.2aA = 172.817 m/s2 = 43.2 cm

aB = aA + aBA = aA + (0.738)2(4.8) + aBAtaB = aO + aBO = ( 5.622)2(2.4) + aBOtBerdasarkan pertemuan masing masing at, aB = 93.6 m/s = 23.4 cmAt BO/rBO = 54.235/2.4 = 22.598 (AO)

aC = aO + aCO = CO2rCO + COrCO = 5.62223 + 22.598 . 3 = 116.56 m/s = 29.14 cmaD = aB + aDB = aB + (0.819)2(4.8) + aDBtaD = aA + aDA = aD + (0.776)2(9.5) + aDAtBerdasarkan pertemuan masing masing at, aD = 98.3 m/s = 24.586 cm

aE = aD + aED = aD + (3.27)2(0.6) + aEDtaE = aC + aEC = aC + (0.996)2(5.2) + aECtBerdasarkan pertemuan masing masing at, aE = 134.58 m/s = 33.646 cmSELESAI