1 10 pt 15 pt 20 pt 25 pt 5 pt 10 pt 15 pt 20 pt 25 pt 5 pt 10 pt 15 pt 20 pt 25 pt 5 pt 10 pt 15 pt 20 pt 25 pt 5 pt 10 pt 15 pt 20 pt 25 pt 5 pt Mendelian Genetics More Genetics Problems Linked Genes Chromosomal Disorders Bio Trivia
Jan 04, 2016
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Mendelian Genetics
More GeneticsProblems
Linked Genes
ChromosomalDisorders Bio Trivia
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I 5
If a man with Huntington’s marries a normal female, what percentage of the offspring are
likely to have Huntington's?
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I 5aIf a man with Huntington’s
marries a normal female, what percentage of the offspring are
likely to have Huntington's?
50%
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I 10The ability of one gene to control the expression of another gene is known
as ____________.
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I 10aThe ability of one gene to control the expression of another gene is known
as episatsis.
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I 15In the cross: RrTt x
Rrtt, what is the probability of getting
an offpring that is dominant for both
traits?
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I 15aIn the cross: RrTt x
Rrtt, what is the probability of getting
an offpring that is dominant for both
traits?¾ x ½ = 3/8
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I 20
What is the probability of flipping a tails three times in a row?
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I 20a
What is the probability of flipping a tails three times in a row?
½ x ½ x ½ = 1/8
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I 25An AABb individual is mated with another AABb
individual. The possible number of genetically
different kinds of offspring is _____.
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I 25aAn AABb individual is mated with another AABb
individual. The possible number of genetically
different kinds of offspring is 3.
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II 5If one parent is blood type AB and the other is type O, what fraction of their offspring will be blood type A?
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II 5aIf one parent is blood type AB and the other is type O, what fraction of their offspring will be blood type A?
½
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II 10The result of the following cross indicates the orange eyes are _____ black eyes.
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II 10aThe result of the following cross indicates the orange eyes are recessive to black eyes.
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II 15If a parent is
AaBBCcddEe, how many different types
of gametes can it produce?
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II 15aIf a parent is
AaBBCcddEe, how many different types
of gametes can it produce?
2 x 1 x 2 x 1 x 2 = 8
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II 20A woman is A+ and has B- child. A father with this
blood type could NOT be the father:
A. A+B. B-C. AB +D. AB-
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II 20aA woman is A+ and has B- child. A father with this
blood type could NOT be the father:
A. A+
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II 25An organism homozygous for red color was crossed with an organism homozygous for blue color. The offspring were green. Two of the green organisms were crossed. What is (are) the expected phenotypes in this second group of offspring?
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II 25aAn organism homozygous for red color was crossed with an organism homozygous for blue color. The offspring were green. Two of the green organisms were crossed. What is (are) the expected phenotypes in this second group of offspring?
1 Red: 2 green: 1 blue
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III 5If two genes are linked _____.
a. they are on different chromosomes
b. they assort independently
c. they code for the same protein
d. they are on the same chromosome
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III 5aIf two genes are linked _____.
d. they are on the same chromosome
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III 10If a color-blind woman marries a man with normal vision, the female offspring will be __________, and the male offspring will be __________.
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III 10aIf a color-blind woman marries a man with normal vision, the female offspring will be normal, and the male offspring will be color-blind.
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III 15Four genes (A, B, C, and D) are on the same chromosome. The crossover frequencies below are obtained. What is the correct sequence of genes? A-B 19% A-D 21%B-C 14% C-D 16% A-C 5% B-D 2%
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III 15a
Four genes (A, B, C, and D) are on the same chromosome. The crossover frequencies below are obtained. Which is the correct sequence of genes? A-B 19% A-D 21%B-C 14% C-D 16% A-C 5% B-D 2%
ACBD or DBCA
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III 20A father (whose father was color-blind) and a normal
woman can produce:A. a color-blind son
B. a color-blind daughterC. no color-blind childrenD. sons that have a 50% chance of being color-blind.
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III 20aA father (whose father was color-blind) and a normal
woman can produce:
C. no color-blind children
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III 25In a particular species of mammal, black hair (B) is dominant to green hair (b), and red eyes (R) are dominant to white eyes (r). When a BbRr individual is mated with a bbrr individual, the observed offspring are: black-red 1,070; black-white 177; green-red 180; green-white 1,072. How far apart are the B and R genes?
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III 25a
In a particular species of mammal, black hair (B) is dominant to green hair (b), and red eyes (R) are dominant to white eyes (r). When a BbRr individual is mated with a bbrr individual, the observed offspring are: black-red 1,070; black-white 177; green-red 180; green-white 1,072. How far apart are the B and R genes? 14.3 MU
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IV 5A chart of
chromosomes in which they are arranged by
number is called a _________________.
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IV 5aA chart of
chromosomes in which they are arranged by
number is called a karyotype.
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IV 10
A male with a Barr body has what
disorder?
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IV 10a
A male with a Barr body has what
disorder?Klinefelter’s Syndrome XXY
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IV 15The exchange of parts between nonhomologous chromosomes
is called _____.
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IV 15aThe exchange of parts between nonhomologous chromosomes
is called translocation.
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IV 20The only known viable human monosomy is:
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IV 20aThe only known viable human monosomy is Turner’s Syndrome.
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IV 25If non-disjunction occurs in Meiosis I, what types of
gametes will be produced?A. n and n + 1B. n and n-1
C. n + 1 and n – 1D. n, n + 1, and n - 1
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IV 25aIf non-disjunction occurs in Meiosis I, what types of
gametes will be produced?
C. n + 1 and n – 1
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V 5Who am I?
a.Mendel b. Morgan
c. Kleinfelter d. Turner
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V 5a
Who am I?
b. Thomas Hunt Morgan
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V 10Ophioglossum reticulatum, a type of
fern, has the most chromosomes of any organism. How many
chromosomes does each cell have?
a. 110 b. 256
c.1260 d. 2448
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V 10a• Polyploidy is a common conduction
in plants, but seemingly taken to its limits in the Ophioglossum
reticulatum. This fern has roughly 630 pairs of chromosomes or 1260
chromosomes per cell
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V 15 What is this condition called?
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V 15a Polydactyly
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V 20If you read 5 bases/second, how long would it take you to read the entire human genome (without stopping)?
a.7 years b. 19 years
c. 48 years d. 87 years
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V 20aIt would take 19 years to read aloud without stopping, at 5 bases per second, the entire sequence of the genome within the nucleus of the human embryo
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V 25Why was Aberforth
Dumbledore prosecuted?
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V 25aFor practicing inappropriate charms on a
goat