Top Banner
10-5 Circles Course 1 Warm Up Warm Up Lesson Presentation Lesson Presentation Problem of the Day Problem of the Day
23

10-5 Circles Course 1 Warm Up Warm Up Lesson Presentation Lesson Presentation Problem of the Day Problem of the Day.

Dec 31, 2015

Download

Documents

Shawn Jenkins
Welcome message from author
This document is posted to help you gain knowledge. Please leave a comment to let me know what you think about it! Share it to your friends and learn new things together.
Transcript
Page 1: 10-5 Circles Course 1 Warm Up Warm Up Lesson Presentation Lesson Presentation Problem of the Day Problem of the Day.

10-5 Circles

Course 1

Warm UpWarm Up

Lesson PresentationLesson Presentation

Problem of the DayProblem of the Day

Page 2: 10-5 Circles Course 1 Warm Up Warm Up Lesson Presentation Lesson Presentation Problem of the Day Problem of the Day.

Warm UpThe length and width of a rectangle are each multiplied by 5. Find how the perimeter and area of the rectangle change.

The perimeter is multiplied by 5, and the area is multiplied by 25.

Course 1

10-5 Circles

Page 3: 10-5 Circles Course 1 Warm Up Warm Up Lesson Presentation Lesson Presentation Problem of the Day Problem of the Day.

Problem of the Day

When using a calculator to find the height of a rectangle whose length one knew, a student accidentally multiplied by 20 when she should have divided by 20. The answer displayed was 520. What is the correct height?1.3

Course 1

10-5 Circles

Page 4: 10-5 Circles Course 1 Warm Up Warm Up Lesson Presentation Lesson Presentation Problem of the Day Problem of the Day.

Learn to identify the parts of a circle and to find the circumference and area of a circle.

Course 1

10-5 Circles

Page 5: 10-5 Circles Course 1 Warm Up Warm Up Lesson Presentation Lesson Presentation Problem of the Day Problem of the Day.

Vocabulary

circlecenterradius (radii)diametercircumferencepi

Insert Lesson Title Here

Course 1

10-5 Circles

Page 6: 10-5 Circles Course 1 Warm Up Warm Up Lesson Presentation Lesson Presentation Problem of the Day Problem of the Day.

A circle is the set of all points in a plane that are the same distance from a given point, called the center.

Center

Course 1

10-5 Circles

Page 7: 10-5 Circles Course 1 Warm Up Warm Up Lesson Presentation Lesson Presentation Problem of the Day Problem of the Day.

A line segment with one endpoint at the center of the circle and the other endpoint on the circle is a radius (plural: radii).

CenterRadius

Course 1

10-5 Circles

Page 8: 10-5 Circles Course 1 Warm Up Warm Up Lesson Presentation Lesson Presentation Problem of the Day Problem of the Day.

A chord is a line segment with both endpoints on a circle. A diameter is a chord that passes through the center of the circle. The length of the diameter is twice the length of the radius.

CenterRadius

Diameter

Course 1

10-5 Circles

Page 9: 10-5 Circles Course 1 Warm Up Warm Up Lesson Presentation Lesson Presentation Problem of the Day Problem of the Day.

Additional Example 1: Naming Parts of a Circle

Name the circle, a diameter, and three radii.

NThe circle is circle Z.

LM is a diameter.

ZL, ZM, and ZN are radii.

M

ZL

Course 1

10-5 Circles

Page 10: 10-5 Circles Course 1 Warm Up Warm Up Lesson Presentation Lesson Presentation Problem of the Day Problem of the Day.

Try This: Example 1

Name the circle, a diameter, and three radii.

The circle is circle D.

IG is a diameter.

DI, DG, and DH are radii.

G

H

DI

Course 1

10-5 Circles

Page 11: 10-5 Circles Course 1 Warm Up Warm Up Lesson Presentation Lesson Presentation Problem of the Day Problem of the Day.

The distance around a circle is called the circumference.

CenterRadius

Diameter

Circumference

Course 1

10-5 Circles

Page 12: 10-5 Circles Course 1 Warm Up Warm Up Lesson Presentation Lesson Presentation Problem of the Day Problem of the Day.

The ratio of the circumference to the diameter, , is the same for any circle. This

ratio is represented by the Greek letter , which is read “pi.”

Cd

Cd

=

Course 1

10-5 Circles

Page 13: 10-5 Circles Course 1 Warm Up Warm Up Lesson Presentation Lesson Presentation Problem of the Day Problem of the Day.

The formula for the circumference of a circle is C = d, or C = 2r.

The decimal representation of pi starts with 3.14159265 . . . and goes on forever without repeating. We estimate pi using either 3.14

or .22 7

Course 1

10-5 Circles

Page 14: 10-5 Circles Course 1 Warm Up Warm Up Lesson Presentation Lesson Presentation Problem of the Day Problem of the Day.

Additional Example 2A: Using the Formula for the Circumference of a Circle

Find the missing value to the nearest hundredth. Use 3.14 for pi.

A. d = 11 ft; C = ?

C = d

C 3.14 • 11

C 34.54 ft

Write the formula.

Replace with 3.14 and d with 11.

11 ft

Course 1

10-5 Circles

Page 15: 10-5 Circles Course 1 Warm Up Warm Up Lesson Presentation Lesson Presentation Problem of the Day Problem of the Day.

Additional Example 2B: Using the Formula for the Circumference of a Circle

Find each missing value to the nearest hundredth. Use 3.14 for pi.

B. r = 5 cm; C = ?

C = 2r

C 2 • 3.14 • 5

C 31.4 cm

Write the formula.

Replace with 3.14 and r with 5.

5 cm

Course 1

10-5 Circles

Page 16: 10-5 Circles Course 1 Warm Up Warm Up Lesson Presentation Lesson Presentation Problem of the Day Problem of the Day.

Additional Example 2C: Using the Formula for the Circumference of a Circle

Find each missing value to the nearest hundredth. Use 3.14 for pi.

C. C = 21.98 cm; d = ?

C = d

21.98 3.14d

7.00 cm d

Write the formula.

Replace C with 21.98 and with 3.14.

21.98 3.14d_______ _______

3.14 3.14 Divide both sides by 3.14.

Course 1

10-5 Circles

Page 17: 10-5 Circles Course 1 Warm Up Warm Up Lesson Presentation Lesson Presentation Problem of the Day Problem of the Day.

Try This: Example 2A

Find the missing value to the nearest hundredth. Use 3.14 for pi.

A. d = 9 ft; C = ?

C = d

C 3.14 • 9

C 28.26 ft

Write the formula.

Replace with 3.14 and d with 9.

9 ft

Course 1

10-5 Circles

Page 18: 10-5 Circles Course 1 Warm Up Warm Up Lesson Presentation Lesson Presentation Problem of the Day Problem of the Day.

Try This: Example 2B

Find each missing value to the nearest hundredth. Use 3.14 for pi.

B. r = 6 cm; C = ?

C = 2r

C 2 • 3.14 • 6

C 37.68 cm

Write the formula.

Replace with 3.14 and r with 6.

6 cm

Course 1

10-5 Circles

Page 19: 10-5 Circles Course 1 Warm Up Warm Up Lesson Presentation Lesson Presentation Problem of the Day Problem of the Day.

Try This: Example 2C

Find each missing value to the nearest hundredth. Use 3.14 for pi.

C. C = 18.84 cm; d = ?

C = d

18.84 3.14d

6.00 cm d

Write the formula.

Replace C with 18.84 and with 3.14.

18.84 3.14d_______ _______

3.14 3.14 Divide both sides by 3.14.

Course 1

10-5 Circles

Page 20: 10-5 Circles Course 1 Warm Up Warm Up Lesson Presentation Lesson Presentation Problem of the Day Problem of the Day.

The formula for the area of a circle is A = r2.

Course 1

10-5 Circles

Page 21: 10-5 Circles Course 1 Warm Up Warm Up Lesson Presentation Lesson Presentation Problem of the Day Problem of the Day.

Additional Example 3: Using the Formula for the Area of a Circle

Find the area of the circle. Use for pi.

d = 42 cm; A = ?

Write the formula to find the area.A = r2

r = d ÷ 2r = 42 ÷ 2 = 21

The length of the diameter is twice the length of the radius.

Replace with and r with 21.22

7 __

A • 44122

7 __ Use the GCF to simplify.

63

A 1,386 cm2 Multiply.

22 7

A • 21222

7

1

42 cm

Course 1

10-5 Circles

Page 22: 10-5 Circles Course 1 Warm Up Warm Up Lesson Presentation Lesson Presentation Problem of the Day Problem of the Day.

Write the formula to find the area.A = r2

r = d ÷ 2r = 28 ÷ 2 = 14

The length of the diameter is twice the length of the radius.

Replace with and r with 14.22

7 __

A • 19622

7 __ Use the GCF to simplify.

28

A 616 cm2 Multiply.

Try This: Example 3

Find the area of the circle. Use for pi.

d = 28 cm; A = ?

22 7

A • 14222

7

1

28 cm

Course 1

10-5 Circles

Page 23: 10-5 Circles Course 1 Warm Up Warm Up Lesson Presentation Lesson Presentation Problem of the Day Problem of the Day.

Lesson Quiz

Find the circumference and area of each circle. Use 3.14 for .

1. 2.

3. Find the area of a circle with a diameter of 20

feet. Use 3.14 for .

C = 25.12 in.

Insert Lesson Title Here

C = 18.84 in.

8 in.

314 ft2

A = 50.24 in2 A = 28.26 in2

3 in.

Course 1

10-5 Circles