1 PHYSICS MR BALDWIN Speed & Velocity 9/15/2014 AIM: What is motion and how does it change? DO NOW: What do you understand about the terms speed and acceleration? Home Work:
Dec 26, 2015
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PHYSICS MR BALDWINSpeed & Velocity
9/15/2014AIM: What is motion and how does it change?
DO NOW: What do you understand about the terms speed and acceleration?
Home Work:
Laws of Motion• Everything in the universe is in nonstop
motion.• Motion is the rule, not the exception.• The laws which govern the motion of atoms
and stars apply to the motion in our everyday lives.
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Distance and DisplacementDistinction between distance and displacement.
Distance traveled (dashed line) is a measure of length along the actual path.
Displacement (blue line) is how far the object is from its starting point, regardless of how it got there.
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Speed & VelocitySpeed: time rate of change of distance :
how far an object travels in a given time interval
Velocity includes directional information: time rate of change of displacement
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Average Speed & Instantaneous Speed• The instantaneous speed is the speed as given on your speedometer. The speed at that instant.
•Speed given by the speedometer
dv
t
• The average speed is the total distance traveled by an object divided by the total time taken to travel that distance.
CHECK: Determine the units
Unit: m/s; km/h; mph
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CHECKCHECK: : Can you write other forms Can you write other forms of the equation to determine the other of the equation to determine the other
two quantities two quantities tt & & dd??
dt =
d
=t
d v t
Problem Solving Technique: G.U.S.S.
• Givens; Unknown; Substitute & Solve
1.Write out your Givens.
2.Identify your Unknown.Check for unit consistency. If not…convert!
3.Substitute into equation (with units)Find an equation relating quantities.
4.Solve for unknown.
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QUIZ CHECK.What is the average speed of a car (in km/h & m/s) that travels 240 miles in 6 hours. Given
that 1-mile = 1.609 km = 1609 m
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PHYSICS MR BALDWINSpeed & Velocity
9/17/2014AIM: What is the difference between constant and changing motion?(What is acceleration?)DO NOW: Look at the runner below. What can you infer about the runner?
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Look at the picture below. What can you infer about the runner in red shorts?
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CHECKCHECK: : Can you write other forms Can you write other forms of the equation to determine the other of the equation to determine the other
two quantities two quantities tt & & dd??
dt =
d
=t
d v t
QUANTITY & SYMBOL
•Distance d
•Time t
•Velocity; speed v
•Mass m
UNITS
•meters (m; km; mi)
•seconds (s)
•meters/sec (m/s)– Km/h– mph
•kilogram (kg)
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• Uniform motion refers to motion that has a constant velocity– Speed & direction remains the same– Such as your car on cruise control– Moving at 50 mph on a straight road
• Accelerated motion refers to motion with changing velocity– As you round a curb– Hit the gas or brake
Uniform & Accelerated Motion
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AccelerationAcceleration is the change of velocity divided by time.
f iv va
t
Unit: m/s2Determine its Unit.
Where a: acceleration; vf: final velocity; vi:initial velocity
What is the acceleration of a car whose speed increases from 15 m/s (about 34 mi/h) to 25 m/s
(about 56 mi/h) in 20s?
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PHYSICS MR BALDWINSpeed & Velocity
9/18/2014AIM: What is motion and how does it change?
DO NOW: A skater increases his speed from 2.0 m/s to 10.0 m/s in 3.0 s. What is his acceleration?
Home Work: Worksheet 2.2
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Check
Which of the following statements correctly define acceleration?
A. Acceleration is the rate of change of displacement of an object.
B. Acceleration is the rate of change of velocity of an object.
C. Acceleration is the amount of distance covered in unit time.
D. Acceleration is the rate of change of speed of an object.
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Accelerated Motion
Acceleration is also a vector. Therefore, we need the sign.
Deceleration occurs when the acceleration is opposite in direction to the velocity.
Determine the car’s acceleration.
What can you infer about the value of the acceleration?
Check
What happens when the velocity vector and the acceleration vector of an object in motion are in same direction?
A. The acceleration of the object increases.
B. The speed of the object increases.
C. The object comes to rest.
D. The speed of the object decreases.
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A car is moving with an initial velocity of vi m/s. After reaching a highway, it moves with a constant acceleration of a m/s2, what will be the velocity (vf) of the car after traveling for t seconds?
A. vf = vi + at
B. vf = vi + 2at
C. vf2 = vi
2 + 2at
D. vf = vi – at
Check
A. vf = vi + at
B. vf = vi + 2at
C. vf2 = vi
2 + 2at
D. vf = vi – at
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PHYSICS MR BALDWINAccelerated Motion 9/19/2014
AIM: How are acceleration, velocity, distance and time related?DO NOW: Look at the runner in the red shorts below. What can you infer about the runner’s velocity and distance for each time interval?
Acceleration
There are two major indicators of the change in velocity in this motion diagram. Can you identify them?
Changing Velocity
The change in the spacing of the dots and the differences in the lengths of the velocity vectors indicate the changes in velocity.
AccelerationCan you identify which one is speeding up and which one is slowing down?
Changing Velocity
If an object speeds up, each subsequent velocity vector is longer. Also, the subsequent distances increases.
If the object slows down, … (you fill in the rest)
Acceleration
Velocity-Time Graphs
What can be said about the distances here?
Acceleration
Velocity-Time Graphs
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MATHEMATICAL
ANALYSIS OF MOTION
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The acceleration, assumed constant, is the rate of change of velocity.
Relating Acceleration, Speed & Time
f if i
v va v v at
t
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Relating Acceleration, Speed & Time
0
The acceleration is given by
We know that the average velocity is give by: 2
Substituting into the equation, we get
1
2 21
Thus,2
f i
i f
i ii
i
v va
tv v
v
v v at
v v atv v at
v v at
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Average Speed & Distance Traveled During Constant Acceleration
In addition, as the velocity is increasing at a constant rate, we know that
2
2
1Substituting into the distance equation,
21 1
we get2 2
1Thus
2
i
i i
i
v v at
d vt v at t v t at
d v t at
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Equations of Motion (Please write on Index cards)
2
2 2 2 2
For Uniform (Constant) Motion, we use
; OR
For Accelerated Motion, we use
OR
1
2
2 OR 2
f if i
i
f i f i
d dv t d v t
t v
v vv v at a
t
d v t at
v v ad v v ad
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• OBJECT STARTS FROM REST
• OBJECT RELEASED FROM REST
• OBJECT DROPPED
• OBJECT STOPS
• OBJECT COMES TO REST
• OBJECT SLOWS TO A HALT
SOME KEY PHRASES
INITIAL VELOCITY IS ZERO
FINAL VELOCITY IS ZERO
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MOTION
OF
FALLING
BODIES
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PHYSICS MR BALDWINFreefall
9/22/2014AIM: How do we describe the motion of an object in freefall?
DO NOW: In your own words, how would you define or describe freefall?
Home Work: Freefall worksheet
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Freefall Motion
Near the surface of the Earth, all objects experience approximately the same acceleration due to gravity.
Look at the image to
the left. What can you
infer about the apple’s
motion?
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Uniformly Accelerated Motion
Galileo’s Law of Freely Falling Bodies:
In the absence of air resistance, all objects, regardless of size, shape or mass, fall with the same acceleration.
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Uniformly Accelerated Motion
The acceleration due to gravity
at the Earth’s surface is
approximately 9.80 m/s2.
CHECK
• What is freefall?
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Equations of Motion
2
2 2 2 2
For Uniform (Constant) Motion, we use
; OR
For Accelerated Motion, we use
OR
1
2
2 OR 2
f if i
i
f i f i
d dv t d v t
t v
v vv v at a
t
d v t at
v v ad v v ad
Rearrange the formulas letting a = – g
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NOTE
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• The equations can be used to find time of flight from speed or distance, respectively.
• Remember that an object thrown into the air represents two mirror-image flights, one up and the other down.
• Acceleration of an object moving up is negative.• Magnitude of the acceleration up or down is the
same
PHYSICS MR BALDWIN
Freefall Motion 9/23/2014AIM: How is the motion of an object affected when projected upwards?
DO NOW: Describe the velocity of an object after it has been thrown vertically upwards with a speed of 20 m/s and returns back to it initial position.
Home Work: Worksheet - Acceleration due to gravity
Back to “HOW FAR?”• Recall that
• But for the object thrown upwards with some velocity, let d become ‘h’ (to stand for height), and vi is different from 0, with the acceleration a = -g (only due to gravity):
• DERIVE THE EQUATION FOR HEIGHT
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2id v t a t
2
2
1tgtvh i
Now to “HOW FAST?”• Recall that
• But for the object thrown upwards with some vi different from 0, with the acceleration a= -g (only due to gravity):
• DERIVE THE EQUATION FOR OBJECT’S VELOCITY.
f iv v a t
f iv v g t
From this, we can answer “HOW LONG”• If we know the height to which the object rises, we can
determine HOW LONG it takes to get there.• What happens to the velocity at the top of the object’s
motion?
• vf = 0
• DERIVE THE EQUATION FOR THE TIME TAKEN FOR THE OBJECT TO REACH MAXIMUM HEIGHT.
if i
vv v g t t
g
“HOW LONG”: What goes up must come down
• When we throw an object UP and it returns to its initial position, the total displacement is…_________
• Time of FLIGHT is duration of time object is in the air• d = 0• DERIVE THE EQUATION FOR THE TIME OF
FLIGHT
2 21 10
2 21
0 0 &2
2
i i
ii
d v t a t v t a t
v a t t tv
tg
TEST YOURSELF:A ball goes up • We have a situation to consider…The ball’s direction
of travel is in the OPPOSITE direction of its acceleration.
• THUS…• SO, what will happen to the speed as the ball rises? • DECREASE• Let’s say we gave the ball an initial upward velocity of
about 40 m/s.1. After 2 s, what will the velocity of the ball be?2. How long will the ball be in the air?3. How far will it rise in the air?
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http://phet.colorado.edu/sims/projectile-motion/projectile-motion_en.html
http://jersey.uoregon.edu/vlab/block/Block.html
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GRAPHICAL
ANALYSIS
OF
LINEAR MOTION
PHYSICS MR BALDWIN
Graphing Motion 9/29 & 30/2014
AIM: How do we graphically represent the motion of an object?
DO NOW: Draw a distance-time graph of the function
Draw a velocity-time graph of the function
You can USE your calculator.
Home Work: Worksheet - Analyzing Graphs of Motion Without Numbers
25td
tv 10
50
• Looking at the equation of motion for distance of accelerated motion, what will the resulting distance-time graph look like?
• PARABOLA
• Looking at the equation of motion for velocity of accelerated motion, what will the resulting velocity-time graph look like?
• STRAIGHT LINE (LINEAR)
CHECK
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Distance-Time graph of Uniformly Accelerated Motion
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2id v t at
0
100
200
300
400
500
600
0 5 10 15 20 25
What type of curve is this?
520
5
10
15
20
25
0 1 2 3 4 5
Finding Speed: What can you say about the slope of the graph at any time?
The slope of the tangent to the distance-time graph at any point is the instantaneous speed at that point.
4.00 m/s
8.00 m/s
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0.00
2.00
4.00
6.00
8.00
10.00
0.00 1.00 2.00 3.00 4.00 5.00
VE
LO
CIT
Y (m
/s)
TIME (s)
Speed-Time Graph of Uniformly Accelerated Motion
f iv v at What information can we gain from the Slope of the velocity-time graph?
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0.00
2.00
4.00
6.00
8.00
10.00
0.00 1.00 2.00 3.00 4.00 5.00
TIME (s)
SP
EE
D (
m/s
)Speed-Time Graph of Uniformly Accelerated Motion
f iv v at Slope gives acceleration of the body at each point.
4.00 m/s
2.00 s
Slope 2.00 m/s2
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This is a graph of d vs. t for an object moving with uniform motion.
The speed is the slope of the d-t graph.
Distance-Time graph of an object moving at Constant Speed
CHECK
Which line has the greater speed? Explain.
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Graphical Analysis of Linear MotionOn the left we have a graph of velocity-time for an object with varying velocity; on the right we have the resulting distance-time graph.
CHECKWhat can you infer about the motions of the object during periods 1 – 4?
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Graphical Analysis of Linear Motion
The distance, d, is the area beneath the velocity-time graph.
The smaller the rectangles the more precise the distance
CHECKHow would you find the area under the velocity-time graph?
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PREDICTING MOTION GRAPHS
1. Draw a distance-time graph for an object 10 m away from a starting point at rest for 10 s.
2. Draw a distance-time graph for an object moving at a constant rate of 2.0 m/s.
3. Draw a distance-time graph for an object moving at a constant rate of 4.0 m/s.
4. Draw a velocity-time graph for an object moving at a constant rate of 10 m/s.
5. Draw a velocity-time graph for an object moving at a constant rate of –10 m/s.
6. Draw a velocity-time graph for an object accelerating at a constant rate of 2.0 m/s2.
7. Draw a velocity-time graph for an object decelerating at a constant rate of 2.0 m/s2.