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1 For ions we must adjust the number of electrons available, A: Add one e - to A for each negative charge Subtract one e - from A for each positive charge The Octet Rule: Examples NH 4 + BF 4
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1 For ions we must adjust the number of electrons available, A: Add one e - to A for each negative charge Subtract one e - from A for each positive charge.

Dec 20, 2015

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Page 1: 1 For ions we must adjust the number of electrons available, A: Add one e - to A for each negative charge Subtract one e - from A for each positive charge.

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For ions we must adjust the number of electrons available, A: Add one e- to A for each negative charge Subtract one e- from A for each positive charge

The Octet Rule: Examples

NH4+

BF4–

Page 2: 1 For ions we must adjust the number of electrons available, A: Add one e - to A for each negative charge Subtract one e - from A for each positive charge.

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Example: CO32-

Page 3: 1 For ions we must adjust the number of electrons available, A: Add one e - to A for each negative charge Subtract one e - from A for each positive charge.

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Resonance

There are three possible structures for CO32-

The double bond can be placed in one of three places

These are called equivalent resonance structures

The real structure of the CO32- anion is an

average of these three resonance structures

COO

O

COO

O

COO

O

2- 2- 2-

Page 4: 1 For ions we must adjust the number of electrons available, A: Add one e - to A for each negative charge Subtract one e - from A for each positive charge.

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Resonance

There are no single or double bonds in CO32-

All three bonds are equivalent

They are intermediate between the single and double bond

C

OO

O

2-

Page 5: 1 For ions we must adjust the number of electrons available, A: Add one e - to A for each negative charge Subtract one e - from A for each positive charge.

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Resonance: Other Examples SO3

Page 6: 1 For ions we must adjust the number of electrons available, A: Add one e - to A for each negative charge Subtract one e - from A for each positive charge.

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Resonance: Other Examples NO3

Page 7: 1 For ions we must adjust the number of electrons available, A: Add one e - to A for each negative charge Subtract one e - from A for each positive charge.

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Resonance: Other Examples SO4

2–

Page 8: 1 For ions we must adjust the number of electrons available, A: Add one e - to A for each negative charge Subtract one e - from A for each positive charge.

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Exceptions to the Octet Rule

In those cases where the octet rule does not apply, the substituents attached to the central atom nearly always attain noble gas configurations

The central atom does not have a noble gas configuration but may have fewer than 8 or more than 8 electrons

Page 9: 1 For ions we must adjust the number of electrons available, A: Add one e - to A for each negative charge Subtract one e - from A for each positive charge.

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Examples

BBr3 AsF5

Page 10: 1 For ions we must adjust the number of electrons available, A: Add one e - to A for each negative charge Subtract one e - from A for each positive charge.

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Assignments & Reminders

Go through the recent lecture notes

Read Chapter 7 completely, except for Sections 7-7 & 7-8

Homework #4 due by Oct. 16 @ 3 p.m.

Review Session @ 5:15 p.m. on Sunday

Page 11: 1 For ions we must adjust the number of electrons available, A: Add one e - to A for each negative charge Subtract one e - from A for each positive charge.

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CHAPTER 8

Molecular Structure & Covalent Bonding Theories

Page 12: 1 For ions we must adjust the number of electrons available, A: Add one e - to A for each negative charge Subtract one e - from A for each positive charge.

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Stereochemistry

The study of the three-dimensional shapes of molecules

With the knowledge acquired so far we will be able to predict the shapes of molecules and ions

Our instrument – Valence Shell Electron Pair Repulsion theory (VSEPR theory – R. J. Gillespie)

Page 13: 1 For ions we must adjust the number of electrons available, A: Add one e - to A for each negative charge Subtract one e - from A for each positive charge.

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VSEPR Theory

In any molecule or ion there are regions of high electron density: Bonds (shared electron pairs) Lone pairs (unshared electrons)

Due to electron-electron repulsion, these regions are arranged as far apart as possible

Such arrangement results in the minimum energy for the system

Page 14: 1 For ions we must adjust the number of electrons available, A: Add one e - to A for each negative charge Subtract one e - from A for each positive charge.

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BeCl2

Page 15: 1 For ions we must adjust the number of electrons available, A: Add one e - to A for each negative charge Subtract one e - from A for each positive charge.

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BBr3

Page 16: 1 For ions we must adjust the number of electrons available, A: Add one e - to A for each negative charge Subtract one e - from A for each positive charge.

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CH4

Page 17: 1 For ions we must adjust the number of electrons available, A: Add one e - to A for each negative charge Subtract one e - from A for each positive charge.

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PCl5

Page 18: 1 For ions we must adjust the number of electrons available, A: Add one e - to A for each negative charge Subtract one e - from A for each positive charge.

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SF6

Page 19: 1 For ions we must adjust the number of electrons available, A: Add one e - to A for each negative charge Subtract one e - from A for each positive charge.

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Five Basic Geometries

LinearTrigonal

Octahedral

Trigonal bipyramidal

Tetrahedral

Page 20: 1 For ions we must adjust the number of electrons available, A: Add one e - to A for each negative charge Subtract one e - from A for each positive charge.

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SiF4

Page 21: 1 For ions we must adjust the number of electrons available, A: Add one e - to A for each negative charge Subtract one e - from A for each positive charge.

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NH3

Page 22: 1 For ions we must adjust the number of electrons available, A: Add one e - to A for each negative charge Subtract one e - from A for each positive charge.

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Electronic geometryElectronic geometry Distribution of regions of high

electron density around the central atom

Molecular geometryMolecular geometry Arrangement of atoms around the

central atom

Electronic Geometry and Molecular Geometry

Page 23: 1 For ions we must adjust the number of electrons available, A: Add one e - to A for each negative charge Subtract one e - from A for each positive charge.

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H2O