1 Copyright (c) 1999 by Harcourt Brace & Company All rights reserved Names of Acids • Perchloric • Sulfuric • Hydrochloric • Nitric • Sulfurous (H 2 SO 3 ) • Phosphoric • Acetic • Nitrous (HNO 2 ) • Dihydrogen phosphate ion H 2 PO 4 - • Hydrogen phosphate ion, HPO 4 2- • Ammonium,NH 4 +
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1 Copyright (c) 1999 by Harcourt Brace & Company All rights reserved Names of Acids Perchloric Sulfuric Hydrochloric Nitric Sulfurous (H 2 SO 3 ) Phosphoric.
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Copyright (c) 1999 by Harcourt Brace & CompanyAll rights reserved
Names of Acids• Perchloric
• Sulfuric
• Hydrochloric
• Nitric
• Sulfurous (H2SO3)
• Phosphoric
• Acetic
• Nitrous (HNO2)
• Dihydrogen phosphate ion H2PO4
-
• Hydrogen phosphate ion,
HPO4 2-
• Ammonium,NH4+
2
Copyright (c) 1999 by Harcourt Brace & CompanyAll rights reserved
Weak Acids & Bases
• Work examples writing reactions. MUST INCLUDE CHARGES FOR IONS!!
• H3PO4
• HOCl
• Co(H2O)6 2+
• HCO3-
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FORMULAS
• Ka (Kb) = Kw
pH = - log [H3O+]
pOH = -log [OH-]
pH + pOH = 14
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Equilibria Involving A Weak AcidEquilibria Involving A Weak Acid
You have 1.00 M HOAc. Calc. the equilibrium You have 1.00 M HOAc. Calc. the equilibrium concs. of HOAc, Hconcs. of HOAc, H33OO++, OAc, OAc--, and the pH., and the pH.
Copyright (c) 1999 by Harcourt Brace & CompanyAll rights reserved
Equilibria Involving A Weak AcidEquilibria Involving A Weak AcidEquilibria Involving A Weak AcidEquilibria Involving A Weak Acid
Step 2.Step 2. Write K Write Kaa expression expression
You have 1.00 M HOAc. Calc. the equilibrium concs. You have 1.00 M HOAc. Calc. the equilibrium concs. of HOAc, Hof HOAc, H33OO++, OAc, OAc--, and the pH., and the pH.
Ka 1.8 x 10-5 = [H3O+][OAc- ]
[HOAc]
x2
1.00 - xKa 1.8 x 10-5 =
[H3O+][OAc- ][HOAc]
x2
1.00 - x
This is a quadratic. Solve This is a quadratic. Solve using quadratic formula or using quadratic formula or method of approximations method of approximations (see Appendix A).(see Appendix A).
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Useful Rule of Thumb:Useful Rule of Thumb: If 100 • KIf 100 • Kaa < C < Coo, then okay , then okay
to assume not much to assume not much dissociateddissociated
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Calculate the pH of a 0.0010 M solution of Calculate the pH of a 0.0010 M solution of formic acid, HCOformic acid, HCO22H.H.
HCOOH + HHCOOH + H22O O HCOO HCOO-- + H + H33OO++
KKaa = 1.8 x 10 = 1.8 x 10-4-4
Equilibria Involving A Weak AcidEquilibria Involving A Weak Acid
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Equilibria Involving A Weak BaseEquilibria Involving A Weak BaseEquilibria Involving A Weak BaseEquilibria Involving A Weak Base
You have 0.010 M NHYou have 0.010 M NH33. Calc. the pH.. Calc. the pH.
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1. Electronegativity 1. Electronegativity of Oof O
2.2. Polarity of O—H Polarity of O—H bond bond
3.3. The H atom of OThe H atom of O—H is readily —H is readily attracted to polar attracted to polar HH22O. O.
Acetic acidAcetic acid
Partial Partial chargescharges
(-)(-)(+)(+)
(+)(+)
(-)(-)
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High electronegativity of Cl withdraws High electronegativity of Cl withdraws electrons from the rest of the molecule. electrons from the rest of the molecule.
This makes the O—H bond highly polar. The H This makes the O—H bond highly polar. The H of O—H is very positive.of O—H is very positive.
Acetic acidAcetic acid Trichloroacetic acidTrichloroacetic acidKKaa = 1.8 x 10 = 1.8 x 10-5-5 KKaa = 0.3 = 0.3
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These ions are These ions are BASES.BASES.As the charge goes up, they interact more As the charge goes up, they interact more
strongly with polar water molecules & strongly with polar water molecules & become more and more basic .become more and more basic .
NONO33--
COCO332-2-
Basicity of OxoanionsBasicity of OxoanionsBasicity of OxoanionsBasicity of Oxoanions
POPO443-3-
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• Lewis acid = electron Lewis acid = electron pair acceptor (BFpair acceptor (BF33))
• Lewis base = Lewis base = electron pair donor electron pair donor (NH(NH33))
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A Lewis acid and base can interact by A Lewis acid and base can interact by sharing an electron pair.sharing an electron pair.
Formation of Formation of hydronium ion hydronium ion is an excellent is an excellent example.example.
Lewis Acids & BasesLewis Acids & Bases
HH
H
BASEACID
O—H••••
••O—H
H+H
H
H
BASEACID
O—H••••
••O—H
H+++
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Other good examples involve metal ions.Other good examples involve metal ions.
HH
Co2+ ••
BASEACID
O—H••••
••O—H
Co2+
Lewis Acids & BasesLewis Acids & Bases
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Other good examples involve metal ions.Other good examples involve metal ions.
COORDINATE COVALENT BONDSCOORDINATE COVALENT BONDS because both electrons are supplied by one because both electrons are supplied by one of the atoms of the bond.of the atoms of the bond.
HH
Co2+ ••
BASEACID
O—H••••
••O—H
Co2+
HH
Co2+ ••
BASEACID
O—H••••
••O—H
Co2+
Lewis Acids & BasesLewis Acids & Bases
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The combination of metal The combination of metal ions (Lewis acids) with ions (Lewis acids) with Lewis bases such as Lewis bases such as HH22O and NHO and NH33 ------> ------>
COMPLEX IONSCOMPLEX IONS
All metal ions form All metal ions form complex ions with water complex ions with water —and are of the type —and are of the type [M(H[M(H22O)O)xx]]n+n+ where x = 4 where x = 4
and 6.and 6.
Lewis Acids & BasesLewis Acids & Bases
[Cu(NH[Cu(NH33))44]]2+2+
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Copyright (c) 1999 by Harcourt Brace & CompanyAll rights reserved
The Fe2+ in heme can interact with O2 or CO in a Lewis acid-base reaction.
Lewis Acids & BasesLewis Acids & Bases
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Many complex ions containing water Many complex ions containing water undergo undergo HYDROLYSISHYDROLYSIS to give acidic to give acidic solutions. solutions.
Lewis Acids & BasesLewis Acids & Bases
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Many complex ions containing water undergo Many complex ions containing water undergo HYDROLYSISHYDROLYSIS to give acidic solutions. to give acidic solutions.
[Cu(H[Cu(H22O)O)44]]2+2+ + H + H22O ---> [Cu(HO ---> [Cu(H22O)O)33(OH)](OH)]++ + H + H33OO++
Lewis Acids & BasesLewis Acids & Bases
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Many complex ions containing water Many complex ions containing water undergo undergo HYDROLYSISHYDROLYSIS to give acidic to give acidic solutions. solutions.
This explains why water solutions of FeThis explains why water solutions of Fe3+3+, , AlAl3+3+, Cu, Cu2+2+, Pb, Pb2+2+, etc. are acidic., etc. are acidic.
Lewis Acids & BasesLewis Acids & Bases
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AMPHOTERICAMPHOTERIC ( (some metal hydroxides)some metal hydroxides)
Al(OH)Al(OH)33(s) + 3 H(s) + 3 H++ --> Al --> Al3+3+ + 3 H + 3 H22OO
Here Al(OH)Here Al(OH)33 is a Brønsted base. is a Brønsted base.
Here Al(OH)Here Al(OH)33 is a Lewis acid. is a Lewis acid.
Lewis Acids & BasesLewis Acids & Bases
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Neutral Lewis AcidNeutral Lewis AcidNeutral Lewis AcidNeutral Lewis AcidCarbon dioxide is a neutral Lewis acid.Carbon dioxide is a neutral Lewis acid.
+1.5+1.5 -0.75-0.75-0.75-0.75
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Many complex ions are very Many complex ions are very stable.stable.
CuCu2+2+ + 4 NH + 4 NH33 [Cu(NH[Cu(NH33))44]]2+2+
K for the reaction is called K for the reaction is called
KKformationformation
or a “formation constant”or a “formation constant”
Here K = 6.8 x 10Here K = 6.8 x 101212. Reaction is . Reaction is strongly product-favored.strongly product-favored.
Lewis Acids & BasesLewis Acids & Bases
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Formation of complex ions explains why you Formation of complex ions explains why you can dissolve a ppt. by forming a complex can dissolve a ppt. by forming a complex ion. ion.
AgCl(s) + 2 NHAgCl(s) + 2 NH33
Ag(NHAg(NH33))22+ + + Cl+ Cl--
Lewis Acids & BasesLewis Acids & Bases
AgCl(s)
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Formation of complex ions explains why you Formation of complex ions explains why you can dissolve a ppt. by forming a complex ion. can dissolve a ppt. by forming a complex ion.
AgCl(s) AgCl(s) AgAg++ + Cl + Cl-- K Kspsp = 1.8 x 10 = 1.8 x 10-10-10
AgAg++ + 2 NH + 2 NH33 --> Ag(NH --> Ag(NH33))22++ K Kformform = 1.6 x 10 = 1.6 x 1077