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1 4/20/06 Exploiting Instruction-Level Parallelism with Software Approaches Original by Prof. David A. Patterson
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1 4/20/06 Exploiting Instruction-Level Parallelism with Software Approaches Original by Prof. David A. Patterson.

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Page 1: 1 4/20/06 Exploiting Instruction-Level Parallelism with Software Approaches Original by Prof. David A. Patterson.

14/20/06

Exploiting Instruction-Level Parallelism with Software Approaches

Original by

Prof. David A. Patterson

Page 2: 1 4/20/06 Exploiting Instruction-Level Parallelism with Software Approaches Original by Prof. David A. Patterson.

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Basic Pipeline Scheduling and Loop Unrolling

• This code, a scalar to an array:for (i=1000; i>0; i=i–1)

x[i] = x[i] + s;• Assume following latency all examples

– A dependent instruction must be separated from the source instruction by a distance in clock cycles equal to latency of the source instruction to avoid stall

– 5-stage pipeline

From 柯皓仁 , 交通大學

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FP Loop: Where are the Hazards?

Loop: L.D F0,0(R1) ;F0=array element

ADD.D F4,F0,F2 ;add scalar from F2

S.D F4,0(R1) ;store result

DADDUI R1,R1,#-8 ;decrement pointer 8Bytes

BNE R1,R2,Loop ;branch R1!=R2

Where are the stalls?

• First translate into MIPS code:

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FP Loop Showing Stalls

• 10 clocks: Rewrite code to minimize stalls?

1 Loop: L.D F0,0(R1) ;F0=vector element

2 stall

3 ADD.D F4,F0,F2 ;add scalar in F2

4 stall

5 stall

6 S.D F4,0(R1) ;store result

7 DADDUI R1,R1,#-8 ;decrement pointer 8Bytes

8 stall

9 BNE R1,R2,Loop ;branch R1!=zero

10 stall ;delayed branch slot

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Revised FP Loop Minimizing Stalls

6 clocks, but just 3 for execution, 3 for loop overhead;How make faster?

Instruction Instruction Latency inproducing result using result clock cyclesFP ALU op Another FP ALU op 3FP ALU op Store double 2 Load double FP ALU op 1

1 Loop: L.D F0,0(R1)

2 DADDUI R1,R1,#-8

3 ADD.D F4,F0,F2

4 stall

5 BNE R1,R2,Loop ;delayed branch

6 S.D F4,8(R1) ;altered & interchanged with DADDUI

Swap BNE and S.D by changing address of S.D

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Loop Unrolling

• Replicate the loop body multiple times and adjust the loop termination code

• Take n loop bodies and concatenate them into 1 basic block.

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1 Loop:L.D F0,0(R1)2 ADD.D F4,F0,F23 S.D F4,0(R1) ;drop DADDUI & BNE4 L.D F6,-8(R1)5 ADD.D F8,F6,F26 S.D F8,-8(R1) ;drop DADDUI & BNE7 L.D F10,-16(R1)8 ADD.D F12,F10,F29 S.D F12,-16(R1) ;drop DADDUI & BNE10 L.D F14,-24(R1)11 ADD.D F16,F14,F212 S.D F16,-24(R1)13 DADDUI R1,R1,#-32 ;alter to 4*-814 BNE R1,R2,LOOP

14 + 4 x (1+2)+2 = 28 clock cycles, or 7 per iteration Assumes R1 is multiple of 4

Unroll Loop Four Times (straightforward way)

2 cycles stall1 cycle stall

1 cycle stall

1 cycle stall

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Unrolled Loop Detail

• Do not usually know upper bound of loop

• Suppose it is n, and we would like to unroll the loop to make k copies of the body

• Instead of a single unrolled loop, we generate a pair of consecutive loops:

– 1st executes (n mod k) times and has a body that is the original loop

– 2nd is the unrolled body surrounded by an outer loop that iterates (n/k) times

– For large values of n, most of the execution time will be spent in the unrolled loop

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Unrolled Loop That Minimizes Stalls

• What assumptions made when moved code?

– OK to move store past DADDUI even though changes register

– OK to move loads before stores: get right data?

1 Loop:L.D F0,0(R1)2 L.D F6,-8(R1)3 L.D F10,-16(R1)4 L.D F14,-24(R1)5 ADD.D F4,F0,F26 ADD.D F8,F6,F27 ADD.D F12,F10,F28 ADD.D F16,F14,F29 S.D F4,0(R1)10 S.D F8,-8(R1)11 DADDUI R1,R1,#-3212 S.D F12,16(R1)13 BNE R1,R2,LOOP14 S.D F16,8(R1) ; 8-32 = -24

14 clock cycles, or 3.5 per iteration

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Steps Compiler Performed to Unroll

• Determine if it is legal to move the instructions and adjust the offset.

• Determine the unrolling loop would be useful by finding if the loop iterations were independent.

• Use different registers to avoid unnecessary constraints.

• Eliminate the extra tests and branches.• Determine that the loads and stores in the

unrolling loop can be interchanged.• Schedule the code, preserving any

dependences needed.

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Data Dependence for the Loop Unrolling

Loop: L.D F0,0(R1) ADD.D F4,F0,F2 S.D F4, 0(R1) DADDUI R1,R1,#-8 L.D F6,0(R1) ADD.D F8,F6,F2 S.D F8, 0(R1) DADDUI R1,R1,#-8 L.D F10,0(R1) ADD.D F12,F10,F2 S.D F12, 0(R1) DADDUI R1,R1,#-8 L.D F14,0(R1) ADD.D F16,F14,F2 S.D F16, 0(R1) DADDUI R1,R1,#-8 BNE R1, R2, LOOP

Loop unrolling and techniques affect dependences

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Where are the name dependencies?

1 Loop:L.D F0,0(R1)2 ADD.D F4,F0,F23 S.D F4,0(R1) ;drop DADDUI & BNE4 L.D F0,-8(R1)5 ADD.D F4,F0,F26 S.D F4,-8(R1) ;drop DADDUI & BNE7 L.D F0,-16(R1)8 ADD.D F4,F0,F29 S.D F4,-16(R1) ;drop DADDUI & BNE10 L.D F0,-24(R1)11 ADD.D F4,F0,F212 S.D F4,-24(R1)13 DADDUI R1,R1,#-32 ;alter to 4*-814 BNE R1,R2,LOOP

How can remove them?

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Where are the name dependencies?

1 Loop:L.D F0,0(R1)2 ADD.D F4,F0,F23 S.D F4,0(R1) ;drop DADDUI & BNE4 L.D F6,-8(R1)5 ADD.D F8,F6,F26 S.D F8,-8(R1) ;drop DADDUI & BNE7 L.D F10,-16(R1)8 ADD.D F12,F10,F29 S.D F12,-16(R1) ;drop DADDUI & BNE10 L.D F14,-24(R1)11 ADD.D F16,F14,F212 S.D F16,-24(R1)13 DADDUI R1,R1,#-32 ;alter to 4*-814 BNE R1,R2,LOOP

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Compiler Perspectives on Code Movement

• Name Dependencies are Hard to discover for Memory Accesses

– Does 100(R4) = 20(R6)?– From different loop iterations, does 20(R6) = 20(R6)?

• Our example required compiler to know that if R1 doesn’t change then:

0(R1) -8(R1) -16(R1) -24(R1)

There were no dependencies between some loads and stores so they could be moved by each other

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Limitation to Gains of Loop Unrolling

• A decrease in the amount of overhead amortized with each unroll

– Unroll 4 times – 2 out 14 cycles are overhead 0.5 cycles per iteration

– Unrolled 8 times 0.25 cycles per iteration

• Code size limitations– Large code size is not good for embedded

computer– Large code size may increase cache miss rate

• Compiler limitations– Potential shortfall in registers that is created by

aggressive unrolling and scheduling

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Static Branch Prediction• Simplest: Predict taken

– average misprediction rate = untaken branch frequency, which for the SPEC programs is 34%.

– Unfortunately, the misprediction rate ranges from not very accurate (59%) to highly accurate (9%)

• Predict on the basis of branch direction? – choosing backward-going branches to be taken

(loop)– forward-going branches to be not taken (if)– SPEC programs, however, most forward-going

branches are taken => predict taken is better

• Predict branches on the basis of profile information collected from earlier runs

– Misprediction varies from 5% to 22%

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Misprediction Rate for a Profile-based Predictor

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Accuracy Comparison

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Advanced Compiler Support for Exposing and Exploiting ILP

• Detecting and Enhancing loop-level parallelism

• Finding and eliminating dependent computations

• Software pipelining• Global code scheduling

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Detect and Enhance LLP

• Loop-level parallelism (ILP)– Analyzed at the source or close to it– Most analysis is done once instructions have been

generated

• Loop-level analysis– Determine what dependences exist among the operands

in a loop across the iterations of that loop– Determine whether data accesses in later iterations are

dependent on data values produced in earlier iterations» Such dependence is called a loop-carried dependence

(LCD)» LCD forces successive loop iterations to execute in

series– Finding loop-level parallelism involves recognizing

structures such as loops, array references, and induction variable computations

» The compiler can do this analysis more easily at or near the source level

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Example 1

for (i=1; i <= 100; i=i+1) {

A[i+1] = A[i] + C[i]; /* S1 */

B[i+1] = B[i] + A[i+1];/* S2 */

}

Assume that A, B, and C are distinct, non-overlapping arrays

• S1 uses a value computed by S1 in an earlier iteration (A[i])

– Loop-carried dependence

• S2 uses a value computed by S2 in an earlier iteration (B[i])

– Loop-carried dependence

• S2 uses a value computed by S1 in the same iteration (A[i+1])

– Not loop-carried– Multiple iterations of the loop

could execute in parallel, as long as each pair of statements in an iteration were kept in order

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Example 2

for (i=1; i <= 100; i=i+1) {

A[i] = A[i] + B[i]; /* S1 */

B[i+1] = C[i] + D[i]; /* S2 */

}

• S1 uses a value computed by S2 in an earlier iteration (B[i+1])

– Loop-carried dependence

• Dependence is not circular– Neither statement depends

on itself, and although S1 depends on S2, S2 does not depend on S1

• A loop is parallel if it can be written without a cycle in the dependences

– Absence of a cycle gives a partial ordering on the statements

The loop-carried dependence does not prevent parallelism

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Example 2 (Cont.)

A[1] = A[1] + B[1]

for (i=1; i <= 99; i=i+1) {

B[i+1] = C[i] + D[i];

A[i+1] = A[i+1] + B[i+1];

}

B[101] = C[100] + D[100]

• Transform the previous code to conform to the partial ordering and expose the parallelism

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Recurrence

for (i=2; i<=100; i=i+1) {

Y[i] = Y[i-1] + Y[i];

}

for (i=6; i<=100; i=i+1) {

Y[i] = Y[i-5] + Y[i];

}

• A recurrence is when a variable is defined based on the value of that variable in an earlier iteration

• A form of loop-carried dependences

• Dependence distance– How long the earlier

instruction for a recurrence

– Larger distance more ILP

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An Example to Eliminate False Dependences

for (i=1; i <= 100; i=i+1) {

Y[i] = X[i] / C; /* S1 */

X[i] = X[i] + C; /* S2 */

Z[i] = Y[i] + C; /* S3 */

Y[i] = C – Y[i]; /* S4 */

}

for (i=1; i <= 100; i=i+1)

{

T[i] = X[i] / C; /* S1 */

X1[i] = X[i] + C; /* S2 */

Z[i] = T[i] + C; /* S3 */

Y[i] = C – T[i]; /* S4 */

}

True dependence: S1S3, S1S4 (Y[i])Antidependence: S1S2 (X[i])Antidependence: S3S4 (Y[i])Output dependence: S1S4 (Y[i])

Antidependence: XX1Antidependence: YTOutput dependence: YT

X has been renamed to X1 Compiler replace X by X1 -- or –Copy X1 to X

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Finding Dependences

• Why we do it?– Good scheduling of code– Determining which loops might contain parallelism– Eliminating name dependences

• Barriers to analysis of array-oriented dependence– Reference via pointers rather than predictable array

indices– Array indexing is Indirect through another array: x[y[i]]

(non-affine)– False dependency

• General: NP hard problem– Specific cases can be done precisely– Current problem: a lot of special cases that don’t apply

often– The good general heuristic is the holy grail

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Eliminating Dependent Computations – Techniques

• Eliminate or reduce a dependent computation – within a basic block and within loop

• Algebraic simplification + Copy propagation (eliminate operations that copy values within a basic block)

• Tree-height reduction – increase the code parallelism

DADDUI R1, R2, #4

DADDUI R1, R1, #4DADDUI R1, R2, #8

DADDUI R1, R2, R3DADDUI R4, R1, R6DADDUI R8, R4, R7

DADDUI R1, R2, R3DADDUI R4, R6, R7DADDUI R8, R1, R4

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Eliminating Dependent Computations – Techniques

(Cont.)• Most compilers require that optimizations that

rely on associativity (e.g. tree-height reduction) be explicitly enabled

– Integer/FP arithmetic (range and precision) may lead to round-error

• Optimization related to recurrence– Recurrence: expressions whose value on one iteration is

given by a function that depends on previous iteration– When a loop with a recurrence is unrolled, we may be

able to algebraically optimized the unrolled loop, so that the recurrence need only be evaluated once per unrolled iteration

» sum = sum + x sum = sum + x1 + x2 + x3 + x4 + x5 (5 dependent operations) sum = ((sum + x1) + (x2 + x3)) + (x4 + x5) (3 dependent operations)

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Software Pipelining

• Observation: if iterations from loops are independent, then can get more ILP by taking instructions from different iterations

• Software pipelining: reorganizes loops so that each iteration is made from instructions chosen from different iterations of the original loop (~ Tomasulo in SW)

Iteration 0 Iteration

1 Iteration 2 Iteration

3 Iteration 4

Software- pipelined iteration

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Software Pipelining ExampleBefore: Unrolled 3 times 1 L.D F0,0(R1) 2 ADD.D F4,F0,F2 3 S.D F4,0(R1) 4 L.D F6,-8(R1) 5 ADD.D F8,F6,F2 6 S.D F8,-8(R1) 7 L.D F10,-16(R1) 8 ADD.D F12,F10,F2 9 S.D F12,-16(R1) 10 DADDUI R1,R1,#-24 11 BNE R1,R2,LOOP

After: Software Pipelined 1 S.D F4,16(R1) ;Stores M[i] 2 ADD.D F4,F0,F2 ; Adds to

M[i-1] 3 L.D F0,0(R1); Loads M[i-

2] 4 DADDUI R1,R1,#-8 5 BNE R1,R2,LOOP

• Symbolic Loop Unrolling– Maximize result-use distance – Less code space than unrolling– Fill & drain pipe only once per loop vs. once per each unrolled iteration in loop unrolling

SW Pipeline

Loop Unrolled

ove

rlap

ped

op

s

Time

Time

5 cycles per iteration

Assume that DADDUI is scheduled before ADD.D, and L.D (with an adjusted offset) is placed in the branch delay slot

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Hardware Support for Exposing More Parallelism at Compile-

Time

• Conditional or Predicated Instructions– Discussed before in context of branch prediction– Conditional instruction execution

• Two-issue superscalar– First instruction slot Second instruction slot

LW R1,40(R2) ADD R3,R4,R5ADD R6,R3,R7

BEQZ R10,LLW R8,0(R10)LW R9,0(R8)

– Waste slot since 3rd LW dependent on result of 2nd LW

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Hardware Support for Exposing More Parallelism at Compile-

Time• Use predicated version load word (LWC)?

– load occurs unless the third operand is 0

• First instruction slot Second instruction slot

LW R1,40(R2) ADD R3,R4,R5

LWC R8,0(R10),R10 ADD R6,R3,R7

BEQZ R10,L

LW R9,0(R8)

• If the sequence following the branch were short, the entire block of code might be converted to predicated execution, and the branch eliminated

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Hardware Support for Memory Reference Speculation

• To move loads across stores, when it cannot be absolutely certain that such a movement is correct, a special instruction to check for address conflicts

– The special instruction is left at the original location of the load and the load is moved up across stores

– When a speculated load is executed, the hardware saves the address of the accessed memory location

– If a subsequent store changes the location before the check instruction, then the speculation has failed

– If only load instruction was speculated, then it suffices to redo the load at the point of the check instruction

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What if Can Chance Instruction Set?

• Superscalar processors decide on the fly how many instructions to issue

– HW complexity of Number of instructions to issue O(n2)

• Why not allow compiler to schedule instruction level parallelism explicitly?

• Format the instructions in a potential issue packet so that HW need not check explicitly for dependences

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VLIW: Very Large Instruction Word

• Each “instruction” has explicit coding for multiple operations

– In IA-64, grouping called a “packet”– In Transmeta, grouping called a “molecule” (with “atoms” as

ops)

• Tradeoff instruction space for simple decoding– The long instruction word has room for many operations– By definition, all the operations the compiler puts in the long

instruction word are independent => execute in parallel– E.g., 2 integer operations, 2 FP ops, 2 Memory refs, 1 branch

» 16 to 24 bits per field => 7*16 or 112 bits to 7*24 or 168 bits wide

– Need compiling technique that schedules across several branches

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Recall that Unrolled Loop That Minimizes Stalls

1 Loop:L.D F0,0(R1)2 L.D F6,-8(R1)3 L.D F10,-16(R1)4 L.D F14,-24(R1)5 ADD.D F4,F0,F26 ADD.D F8,F6,F27 ADD.D F12,F10,F28 ADD.D F16,F14,F29 S.D F4,0(R1)10 S.D F8,-8(R1)11 DADDUI R1,R1,#-3212 S.D F12,16(R1)13 BNE R1,R2,LOOP14 S.D F16,8(R1) ; 8-32 = -24

14 clock cycles, or 3.5 per iteration

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Loop Unrolling in VLIW

Memory Memory FP FP Int. op/ Clockreference 1 reference 2 operation 1 op. 2 branch

L.D F0,0(R1) L.D F6,-8(R1) 1L.D F10,-16(R1) L.D F14,-24(R1) 2L.D F18,-32(R1) L.D F22,-40(R1) ADD.D F4,F0,F2 ADD.D F8,F6,F2 3L.D F26,-48(R1) ADD.D F12,F10,F2 ADD.D F16,F14,F2 4

ADD.D F20,F18,F2 ADD.D F24,F22,F2 5S.D F4,0(R1) S.D F8,-8(R1) ADD.D F28,F26,F2 6S.D F12,-16(R1) S.D F16,-24(R1) 7S.D F20,24(R1) S.D F24,16(R1) DADDUI R1,R1,#-56 8S.D F28,8(R1) BNE R1,R2,LOOP 9

Unrolled 7 times to avoid delays 7 results in 9 clocks, or 1.3 clocks per iteration Average: 2.5 ops per clock Note: Need more registers in VLIW

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Trace Scheduling

• Parallelism across IF branches vs. LOOP branches?

• Two steps:– Trace Selection

» Find likely sequence of basic blocks (trace) of (statically predicted or profile predicted) long sequence of straight-line code

– Trace Compaction» Squeeze trace into few VLIW instructions» Need bookkeeping code in case prediction is wrong

• This is a form of compiler-generated speculation– Compiler must generate “fixup” code to handle cases in which

trace is not the taken branch– Needs extra registers: undoes bad guess by discarding

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Advantages of HW (Tomasulo) vs. SW (VLIW) Speculation

• HW advantages:– HW better at memory disambiguation since knows actual addresses– HW better at branch prediction since lower overhead– HW maintains precise exception model– HW does not execute bookkeeping instructions– Same software works across multiple implementations– Smaller code size (not as many nops filling blank instructions)

• SW advantages:– Window of instructions that is examined for parallelism much higher– Much less hardware involved in VLIW (unless you are Intel…!)– More involved types of speculation can be done more easily– Speculation can be based on large-scale program behavior, not just

local information

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Superscalar vs. VLIW

• Smaller code size• Binary

compatibility across generations of hardware

• Simplified Hardware for decoding, issuing instructions

• No Interlock Hardware (compiler checks?)

• More registers, but simplified Hardware for Register Ports

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Summary#1: Hardware versus Software Speculation

Mechanisms• To speculate extensively, must be able to

disambiguate memory references– Much easier in HW than in SW for code with pointers

• HW-based speculation works better when control flow is unpredictable, and when HW-based branch prediction is superior to SW-based branch prediction done at compile time

– Mispredictions mean wasted speculation

• HW-based speculation maintains precise exception model even for speculated instructions

• HW-based speculation does not require compensation or bookkeeping code

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Summary#2: Hardware versus Software Speculation Mechanisms

• Compiler-based approaches may benefit from the ability to see further in the code sequence, resulting in better code scheduling

• HW-based speculation with dynamic scheduling does not require different code sequences to achieve good performance for different implementations of an architecture

– may be the most important in the long run?

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Summary #3: Software Scheduling

• Instruction Level Parallelism (ILP) found either by compiler or hardware.

• Loop level parallelism is easiest to see– SW dependencies/compiler sophistication determine if compiler

can unroll loops– Memory dependencies hardest to determine => Memory

disambiguation– Very sophisticated transformations available

• Trace Sceduling to Parallelize If statements• Superscalar and VLIW: CPI < 1 (IPC > 1)

– Dynamic issue vs. Static issue– More instructions issue at same time => larger hazard penalty– Limitation is often number of instructions that you can

successfully fetch and decode per cycle

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Homework

• 4.6, 4.8, 4.10