07/04/2013Bahman R. Alyaei1 Chapter 8 Digital Transmission Systems Part 3.

07/04/2013 Bahman R. Alyaei 1

Chapter 8Chapter 8

Digital Transmission SystemsDigital Transmission SystemsPart 3Part 3


14 Types of SDH Multiplexing14 Types of SDH Multiplexing

• SDH multiplexing combines low-speed digital signals such as 2, 34, and 140 Mbps signals with required Overhead to form a frame called STM-1.

• It also multiplexes ATM and ISDN signals into SDH frame.

• SDH is a Byte-Interleaving multiplexing system.


Continue…Continue…

• SDH multiplexing includes two types:

1. Multiplexing lower-order SDH signals into higher-order signals.

2. Multiplexing low-rate tributary signals into SDH signal. The goods of different size is

analogous to different data rates such as 140 Mbps, 34 Mbps, and 2 Mbps.


14.1 Multiplexing 140 Mbps 14.1 Multiplexing 140 Mbps Signal into STM-1Signal into STM-1

• First, the 140 Mbps PDH signal (E4) is adapted via bit rate justification into Container level 4 (C-4).

• The C-4 has 9 x 260 = 2340 bytes.

• The frame rate of C-4 is 8000 frames/Sec, every 125 μS.

• The rate of E4 signal after adaptation is 9 x 260 x 8 x 8000 = 149.760 Mbps



• A column of POH is added in front of every C-4 block in order to implement real-time monitoring over the 140 Mbps path signals.

• The resulting block is called Virtual Container level 4 (VC-4) with a rate of 9 x 261 x 8 x 8000 = 150.336 Mbps.


C-4

260

9 139.264 Mbps149.760 Mbps

149.760 Mbps150.336 Mbps C-4PO

H

9

261

PO

H9

1


150.336 Mbps 149.760 MbpsVC-49

261

C-4PO

H

9

261

VC-49

261

=


Continue…Continue…• The VC-4 is loaded into the information Payload

of the STM-1 frame.

• Location of the VC-4 within the Payload may float when it loads.

• Part of the VC-4 is transmitted in one STM-1 frame and another part in the next frame.

• This problem is solved by adding AU-PTR before the VC-4.

• It will indicate the start of the VC-4 in the Payload.


Payload

Payload

AU-PTR

AU-PTR

AU-PTR

AU-PTR

VC-4



Continue…Continue…• The resulting block (VC-4 + AU-PTR) is

called Administrative Unit level 4 (AU-4).• It has the same basic structure of STM-1

frame (9 rows x 270 columns), but only without SOH.

• AU-4 = VC-4 + AU-PTR

= STM-1 – SOH• To complete the STM-1 frame, the SOH is

added to AU-4.


=VC-4

AU-PTR

270

9

270

9AU-4

270

9AU-4

SOH

SOH

3

5

9




• The complete procedure of multiplexing 140 Mbps signal into STM-1 is as follow:

1. 140 Mbps PDH signal adapted into container C-4.

2. Add POH to C-4 to form VC-4.

3. Add AU-PTR to VC-4 to form AU-4.

4. Add SOH to AU-4 to form STM-1.



C-4C-4

139.264Mbps

C-4PTR

C-4PTR

SOH

SOH

PO

H

PO

H

PO

H

155.52Mbps

AU-4 VC-4 C4

STM-1


14.2 Multiplexing 34 Mbps 14.2 Multiplexing 34 Mbps Signals into STM-1 Frame Signals into STM-1 Frame

• Three different 34 Mbps signals can be multiplexed into one STM-1 frame as follow:

• First, the 34 Mbps PDH signal is adapted via bit rate adaptation into container level 3 (C-3).

• The C-3 has 9 raw x 84 column = 756 Bytes.

• A column of POH is added in front of every C-3 block in order to implement real-time monitoring over the 34 Mbps signals

• The resulting block is called VC-3.


C-3

84

9 34 Mbps48.384 Mbps

48.96 Mbps C-3PO

H

9

85

PO

H

9

1

34 Mbps


C-3PO

H

9

85

34 MbpsVC-3

85

948.96 Mbps

VC-3

85

9 =


Continue…Continue…• Every VC-3 is assigned a 3-Byte Tributary Unit

Pointer (TU-PTR) which allows VC-3 to float in the Payload.

• The area in which the VC-3 is allowed to float with the aid of TU-PTR is called Tributary Unit level 3 (TU-3).

• TU-PTR contains an address which indicates the start of the VC-3 in the TU-3.

• TU-3 frame structure is incomplete, therefore, 6-Bytes pseudo-random data (R) are stuffed to fill the gap of TU-3.

• The resulting block is called Tributary Unit Group 3 (TUG3).


VC-3

85

9

TU

-PT

R3

1

VC-3

86

9

TU

-PT

R3


VC-3

86

9

TU

-PT

R3

TU-3

86

9

P T

R3

=

TU-3

86

9

P T

R3

VC-3


TU-3

86

9

P T

R3

R6

1

TU-3

86

9

P T

R3

R634 Mbps49.536 Mbps


TU-3

86

9

P T

R3

R6

TUG-3

86

9 =

TUG-3

86

9 34 Mbps49.536 Mbps



• Three TUG-3 blocks are byte interleaved into a container C-4.

• Since the resulting structure has only 258 columns (3 x 86), two columns of stuffed bits are added to complete the C-4 structure.

• Finally, C-4 is multiplexed into STM-1 signal which is similar to multiplexing 140 Mbps signal into STM-1.


TUG-3 #2

86

9 TUG-3 #3

86

9TUG-3 #1

86

9

. . . . . . .9

258


TU-3 # 1

86

9

P T

R3

R6

TU-3 # 2

86

9

P T

R3

R6

TU-3 # 3

86

9

P T

R3

R6

. . . . .9

258


. . . . .9

258

Incomplete C-49

258


Incomplete C-4R R

258

9

2

C-4

260

9

C-4

260

9 34 Mbps149.760 Mbps



• The complete procedure of multiplexing 34 Mbps signal into STM-1 is as follows:

1. The 34 Mbps signal is adapted into container C-3.

2. POH is added to C-4 to form VC-3.

3. TU-PTR is added to VC-3 to form TU-3.

4. Stuffing bits is added to TU-3 to fill the gap and form TUG-3.



5. By byte interleaving three TUG-3 blocks and adding two columns of stuffing bits, C-3 is formed.

6. A higher-order POH is added to V-4 to form VC-4.

7. AU-PTR is added to VC-4 to form AU-4.

8. Finally, SOH is added to AU-4 to form STM-1 signal.


C-4VC-4

34 Mbps

PO

H

155.52Mbps

C-3

PO

H

C-3

PO

H

=VC-3

TU

-PT

R

VC-3

TU

-PT

R

TU-3 =

TU-3TUG-3 =TUG-3TUG-3

Incomplete C-4

TUG-3

Incomplete C-4=C-4=PTR

VC-4PTRAU-4 =

SOH

SOH

AU-4

SOH

SOH

STM-1 AU-4

SOH

SOH=


C-4

VC-4

34 Mbps

155.52Mbps

C-3VC-3TU-3TUG-3

STM-1 AU-4

+ POH+TU-PTR+Stuffed

bits

3 x TUG3 Interleave + Stuffed bits

+ HO-POH

+AU-PTR+SOH


14.3 Multiplexing 2 Mbps Signals 14.3 Multiplexing 2 Mbps Signals into STM-1 Frameinto STM-1 Frame

• 63 E1 signals (2 Mbps) can be multiplexed into one STM-1 signal.

• First, the 2Mbps signal is adapted via bit rate adaptation into container level 1, order 2, C-12

• Container C-12 accommodate 34 bytes.• A Multiframe is formed by arranging

Four C-12 basic frames side-by-side.



• Since the frequency of E1 is 8000 frames/sec.

• Therefore, the frame frequency of C-12 basic frame is also 8000 frames/sec.

• Hence, the frequency of the C-12 Multiframe is 2000 frames/sec.

• When a Multiframe multiplexed into STM-1 frame, they are placed in four successive STM-1 frames, instead of one single frame.


Continue…Continue…• The Multiframe is used for the convenience of

rate adaptation.• If E1 (2 Mbps) signals have standard rate of

2.048 Mbps, each C-12 will accommodate 256 bits (32 bytes) Payload (2.048 Mbps /8000 = 256 bits).

• However, when the rate of the E1 signals is not standard, the average bit number accommodated into each C-12 is not an integer.

• In this case, a Multiframe of four C-12 frames is used to accommodate signals.


C-12

43

9

2 Mbps

3

C-12C-12C-12C-12

125 μS 125 μS 125 μS 125 μS

500 μS


Continue…Continue…• To monitor the performance of each 2 Mbps

signal, a Lower-Order Path Overhead (LO-POH) with the size of one byte is added to the notch in the top-left corner of each C-12.

• Each Multiframe has four different LO-POH bytes: V5, J2, N2, and K4.

• The combination of a C-12 and a LO-POH byte is called Virtual Container level 1, order 2 (VC-12).


C-12C-12C-12C-12

K4N2J2V5

C-12C-12C-12C-12

K4N2J2V5


VC-12VC-12VC-12VC-12

C-12C-12C-12C-12

K4N2J2V5

Equal



• Every Multiframe is assigned a four-byte Tributary Unit Pointer (TU-PTR) which allow it to float.

• There are four different pointer bytes: V1, V2, V3, and V4.

• The first two (V1, V2) contains an address indicating the start of the Multiframe.

• Then the information structure changes into Tributary Unit level 1, order 2 (TU-12) with 9 raws x 4 columns.



V4V3V2V1


V4V3V2V1



V4V3V2V1

TU-12TU-12TU-12TU-12

Equal

9

4



• Three TU-12 frames from different Multiframes are byte interleaved to form a Tributary Unit Group 2 (TUG-2).

• In the next step, seven TUG-2 frames are byte interleaved in the same manner and add two columns of stuffed bits to form a TUG-3 structure.

• And finally, the procedure of multiplexing TUG-3 into STM-1 signal is the same as mentioned before.


V5

V1

9

4

V5

V1

9

4

V5

V1

9

4

V5 V5 V5

V1V1V1

9

12


V5 V5 V5

V1V1V1

9

12

9

12

TUG-2

Equal


9

12

TUG-2 #1 TUG-2 # 2 TUG-2 # 6 TUG-2 # 7……..

Incomplete TUG-39

84

Incomplete TUG-39

86

RR

TUG-3

86

9

Byte interleaving

RR9

2

Equal


Continue..Continue..

• The complete procedure of multiplexing of 2 Mbps signal into STM-1 is as follow:

1. 2 Mbps signal is adapted into C-12.

2. Add LO-POH to C-12 to form VC-12.

3. Add TU-PTR to VC-12 to form TU-12.

4. Multiplex three TU-12 frames to form TUG-2.



5. Multiplex seven TUG-2 frames and add two columns of stuffing bits to form TUG-3.

6. Multiplex three TUG-3 frames and add two columns of stuffing bits to form C-4.

7. Add HO-POH to C-4 to form VC-4.8. Add AU-PTR to VC-4 to form AU-4.9. Add SOH to AU-4 to form STM-1.


C-12C-12VC-12TU-12 VC-12TUG-2

Incomplete TUG-3 RR Incomplete TUG-3RRTUG-3

RR

2 Mbps

==

C-4

VC-4

PO

H

C-4=

TU-12TU-12

TU-12

TUG-2TUG-2

TUG-2TUG-2

TUG-2TUG-2

TUG-2

=

TUG-3TUG-3

TUG-3

Incomplete C-4PO

H

AU-4

155.52Mbps

STM-1


C-12VC-12TU-12TUG-2

TUG-3C-4

2 Mbps

VC-4

AU-4STM-1

+ LO-POH+TU-PTR3 x TU-127 x TUG-2 + Stuffing bits

3 x TUG-3 + Stuffing bits+ HO-POH+AU-PTR

+SOH

155.52Mbps


SDH Multiplexing Structure

STM-1 AU-4

TU-3

AUG-1

TUG-3 VC-3 C-3

VC-4 C-4

TU-12 VC-12 C-12

TUG-2

×1 ×1

×3

×1

×7

×3

139264 kbit/s

34368 kbit/s

2048 kbit/s

Pointer processing

Multiplexing

Mapping

Aligning

AUG-4

AUG-16

AUG-64

STM-4

STM-16

STM-64

×1

×1

×1

×4

×4

×4



15 SDH Timing Compensation15 SDH Timing Compensation

AU-PTR

Basic SDH Overhead structure

07/04/2013 Bahman R. Alyaei 53SDH Regenerator Section Overhead Layer


SDH Multiplexer Section Overhead Layer


SDH Multiplexer Section Overhead Layer



• The SDH signal was designed to be timing tolerant to support:

1. Plesiochronously timed,

2. Lower-rate signals,

3. Slight timing differences between synchronously timed NEs.



• Two mechanisms allow for robust timing compensation:

1.Variable bit justification of the lower-rate signal,

2.Pointer (PTR) adjustments between synchronous elements in the SDH network.



• PTR adjustments allow the VC-4 to float with respect to the SDH frame.

• Therefore, a single VC-4 Payload frame typically crosses the STM-1 frame boundary.

• The PTR is contained in the H1 and H2 bytes of the AU-PTR, and it is a count of the number of bytes the VC-4’s POH J1 byte is away from the H3 bytes, not including the SOH bytes.

• A valid VC-4 PTR can range from 0 to 782.


PTR Bytes Designating the Start of the VC-4

POH



• When timing differences exist, dummy bytes can be inserted into the VC-4 without affecting the data.

• The PTR is adjusted to indicate where the real POH starts, the receiving end can effectively recover the Payload (i.e. ignore the dummy bytes).

• When justified bytes are used, they are always in the same location, regardless of where the POH starts.



• H3 bytes are called Negative Justification bytes and carry real Payload data for one frame during a PTR decrement.

• The three bytes following the last H3 byte in the VC-4 are called Positive Justification bytes and carry three dummy bytes of information for one frame during a PTR increment.


1. f1 = f2

• If there is no timing difference between two nodes, the incoming STM-1 Payload bit rate is identical to the transmitting source that drives the outgoing STM-1 frame rate.

• So, in this case, no PTR Adjustments are needed.

Input frequency

(Rate)

Output frequency

(Rate)



2. f1< f2• There is a constant lack of Payload

data to place into the outgoing SDH signal.

• To compensate, three dummy bytes are placed into the Positive stuff bytes and the data is moved to the right by three bytes, so the VC-4 PTR is incremented by one.


Incrementing the Pointer

Value



3. f1 > f2• Then, three extra VC-4 Payload

bytes are stored into the Negative stuff bytes, H3, in the MSOH for one frame, while all the Payload data is moved to the left by three bytes and the PTR is decreased by one.


Decrementing the Pointer Value


Continue…Continue…• The only equipment that can perform Path PTR

Adjustments is MSTE (DXC and Access Multiplexer).

• Also, Path PTR Adjustments are not performed by PTE (i.e. Access Multiplexer, where the Payload data enters the SDH network) even though there are potential timing differences at these locations as well.

• The timing differences at PTEs are due to Plesiochronously-timed tributary signals and are corrected by traditional bit justification techniques.


15 Multiplexing Revisited15 Multiplexing Revisited

• In SDH terms, multiplexing of non-SDH signals means adapting these signals to the structure and timing of an STM-1 signal, enabling these non-SDH signals to be transported inside the SDH network.

• The first step in the multiplexing of a non-SDH signal is mapping.

• Mapping of a non-SDH signal means increasing the frequency of the non-SDH signal to a pre-determined frequency and adding OH for each one of the non-SDH signals.


15.1 Multiplexing 140 Mbps 15.1 Multiplexing 140 Mbps RevisitedRevisited



• The first step is increasing the frequency of the 140 Mbps signal to the value of 149.76 Mbps, by using variable bit justification.

• The resulting structure is called a C-4.

• Next, add nine OH bytes to the C-4; this OH is called POH.



• These nine bytes are: J1, B3, C2, G1, F2, H4, Z4, and Z5, and the resulting structure is called a VC-4.

• The second step is the addition of a VC-4 PTR.

• The resulting structure is called AU-4. Finally, MSOH and RSOH are added to the AU-4 to create the STM-1 signal.


15.2 Multiplexing 34 Mbps Revisited15.2 Multiplexing 34 Mbps Revisited



• The multiplexing of 34 Mbps signals into an STM-1 is similar to that of 140 Mbps signals.

• The major difference is that, because a VC-4 has a maximum Payload Capacity of 149.76 Mbps, it can transport three 34 Mbps signals.

• Each of the three transported 34 Mbps signals is assigned a separate set of POH identical to the POH used with the 140 Mbps signal.



• Another difference is that there are two levels of pointers:

1. One PTR for the VC-4,2. One separate PTR for each of the

three 34 Mbps signals.• The synchronized 34 Mbps signals

are called C-3s, and the structures created by adding the POH are called VC-3s.



• The three VC-3s along with their PTRs are called TU-3s.

• Once the three TU-3s have been created, they are combined to form the Payload of the VC-4.


15.3 Multiplexing 2 Mbps Revisited15.3 Multiplexing 2 Mbps Revisited



• The multiplexing of 2 Mbps signals into a STM-1 is similar to that of 34 Mbps signals.

• In this case, the STM-1 signal can transport 63 separate 2 Mbps signals.

• Therefore, as in the case of 34 Mbps signals, there are two levels of PTRs.

• Also, the POH assigned to each 2 Mbps signal is different from that used in 140 and 34 Mbps signals.



• The POH for a 2 Mbps signal consists of four bytes: V5, J2, Z6, and Z7.

• Unlike mapping of 140 and 34 Mbps signals, the types of 2 Mbps mappings are:

1. Plesiochronous,

2. Bit synchronous,

3. Byte synchronous.


Continue…Continue…• Each C-12 along with its POH is called VC-

12.• Each VC-12 along with its VC-12 PTR is

called TU-12.• Three byte interleaved TU-12s is called

TUG-3.• The Payload of the VC-4 is created by

combining 7 TUG-3s with fixed justification.

07/04/2013Bahman R. Alyaei1 Chapter 8 Digital Transmission Systems Part 3.

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