Apr 01, 2015
Calculate the number of protons, neutrons, and electrons in an atom given its mass number and atomic number.
Define an isotope and explain why atomic masses are not whole numbers.
To calculate how we get atomic masses of elements with isotopes.
1. Find the element on the periodic table. 2. Find the Atomic Number of the
element. 3. Atomic Number = # of protons in the
element.*Remember the # of protons of an atom
determines what element it is representing.
How many protons do the following elements have?1. Oxygen
8
2. Zinc 30
3. Bismuth 83
Atomic Mass = protons + neutrons If we know the # of protons from the
Atomic Number, then …
Atomic Mass - # of protons = # of neutrons
*Remember you should take the atomic mass on the periodic table and round it first
Oxygen1. Atomic Mass from the Periodic Table:
15.999 > 16
2. Subtract the # of protons (Atomic Number) from the Atomic Mass
16 – 8 = 8
*There are 8 neutrons in a neutral oxygen atom.
In a neutral atom, there must be the same number of positive and negative charges. Therefore…
# of protons = # of electron The # of electrons = Atomic Number.
Atoms that have the same number of protons but different numbers of neutrons.
They will have the same Atomic Number but different Atomic Masses.
In nature most elements are found as a mixture of isotopes.
No matter where a sample of an element is obtained, the relative abundance of each isotope is the constant.
Example: In a banana there is 93.25%
potassium with 20 neutrons, 6.7302% have 22 neutrons, and 0.0117% have 21 neutrons.
39
Potassuim-39 or K-39 or 19K
protons-19electrons-19 neutrons-20
*Both protons and neutrons are very close in mass to 1 amu.
*Atomic Mass Unit = 1/12 the mass of carbon-12
Masses of subatomic Particles
Particle Mass (amu
Electron 0.000549
Proton 1.007276
Neutron 1.008665
We take weighted averages of those elements based on the abundance of the isotopes.
Weighted Average = mass of isotope x percent abundance
(decimal form) Then add the values that each isotope
gives.
Element X has 2 natural isotopes. The isotopes with mass 10.012 amu has a relative abundance of 19.91%. The isotope with mass 11.009 amu has a relative abundance of 80.09%. What is this element?
1. Calculate the average atomic mass. 2. Compare this mass to the Periodic Table to find
your element.
Isotope A: mass = 10.012 amu @ 19.91%Isotope B: mass = 11.009 amu @ 80.09%
A: 10.012 x .1991 = 1.993
B: 11.009 x .8009 = 8.817
Now Add them: 1.993 + 8.817 = 10.81amu
Average Atomic Mass for Element X = 10.81 amu