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© 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide 2-2
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© 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

Dec 17, 2015

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Page 1: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

Chapter Goal: To learn how to solve problems about motion in a straight line.

Chapter 2 Kinematics in One Dimension

Slide 2-2

Page 2: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

Kinematics is the name for the mathematical description of motion.

This chapter deals with motion along a straight line, i.e., runners, rockets, skiers.

The motion of an object is described by its position, velocity, and acceleration.

In one dimension, these quantities are represented by x, vx, and ax.

You learned to show these on motion diagrams in Chapter 1.

Chapter 2 Preview

Slide 2-3

Page 3: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

If you drive your car at a perfectly steady 60 mph, this means you change your position by 60 miles for every time interval of 1 hour.

Uniform motion is when equal displacements occur during any successive equal-time intervals.

Uniform motion is always along a straight line.

Uniform Motion

Slide 2-20

Riding steadily over level ground is a goodexample of uniform motion.

Page 4: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

An object’s motion is uniform if and only if its position-versus-time graph is a straight line.

The average velocity is the slope of the position-versus-time graph.

The SI units of velocity are m/s.

Uniform Motion

Slide 2-21

Page 5: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

The distance an object travels is a scalar quantity, independent of direction.

The displacement of an object is a vector quantity, equal to the final position minus the initial position.

An object’s speed v is scalar quantity, independent of direction.

Speed is how fast an object is going; it is always positive.

Velocity is a vector quantity that includes direction. In one dimension the direction of velocity is

specified by the or sign.

Scalars and Vectors

Slide 2-28

Page 6: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

An object that is speeding up or slowing down is not in uniform motion.

In this case, the position-versus-time graph is not a straight line.

We can determine the average speed vavg between any two times separated by time interval t by finding the slope of the straight-line connection between the two points.

The instantaneous velocity is the object’s velocity at a single instant of time t.

The average velocity vavg s/t becomes a better and better approximation to the instantaneous velocity as t gets smaller and smaller.

Instantaneous Velocity

Slide 2-31

Page 7: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

Instantaneous Velocity

Slide 2-32

Motion diagrams and position graphs of an accelerating rocket.

Page 8: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

As ∆t continues to get smaller, the average velocity vavg ∆s/∆t reaches a constant or limiting value.

The instantaneous velocity at time t is the average velocity during a time interval ∆t centered on t, as ∆t approaches zero.

In calculus, this is called the derivative of s with respect to t.

Graphically, ∆s/∆t is the slope of a straight line.

In the limit ∆t 0, the straight line is tangent to the curve.

The instantaneous velocity at time t is the slope of the line that is tangent to the position-versus-time graph at time t.

Instantaneous Velocity

Slide 2-33

Page 9: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

ds/dt is called the derivative of s with respect to t. ds/dt is the slope of the line that is tangent to the

position-versus-time graph. Consider a function u that depends on time as

u ctn, where c and n are constants:

The derivative of a constant is zero:

The derivative of a sum is the sum of the derivatives. If u and w are two separate functions of time, then:

A Little Calculus: Derivatives

Slide 2-46

Page 10: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

Suppose the position of a particle as a function of time is s = 2t2 m where t is in s. What is the particle’s velocity?

Derivative Example

Slide 2-47

Velocity is the derivative of s with respect to t:

The figure shows the particle’s position and velocity graphs.

The value of the velocity graph at any instant of time is the slope of the position graph at that same time.

Page 11: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

Suppose we know an object’s position to be si at an initial time ti.

We also know the velocity as a function of time between ti and some later time tf.

Even if the velocity is not constant, we can divide the motion into N steps in which it is approximately constant, and compute the final position as:

The curlicue symbol is called an integral.

The expression on the right is read, “the integral of vs dt from ti to tf.”

Finding Position from Velocity

Slide 2-54

Page 12: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

The integral may be interpreted graphically as the total area enclosed between the t-axis and the velocity curve.

The total displacement ∆s is called the “area under the curve.”

Finding Position From Velocity

Slide 2-55

Page 13: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

Example 2.6 The Displacement During a Drag Race

Slide 2-58

Page 14: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

Taking the derivative of a function is equivalent to finding the slope of a graph of the function.

Similarly, evaluating an integral is equivalent to finding the area under a graph of the function.

Consider a function u that depends on time as u ctn, where c and n are constants:

The vertical bar in the third step means the integral evaluated at tf minus the integral evaluated at ti.

The integral of a sum is the sum of the integrals. If u and w are two separate functions of time, then:

A Little More Calculus: Integrals

Slide 2-60

Page 15: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

The SI units of acceleration are (m/s)/s, or m/s2. It is the rate of change of velocity and measures how

quickly or slowly an object’s velocity changes. The average acceleration during a time interval ∆t is:

Graphically, aavg is the slope of a straight-line velocity-versus-time graph.

If acceleration is constant, the acceleration as is the same as aavg.

Acceleration, like velocity, is a vector quantity and has both magnitude and direction.

Motion with Constant Acceleration

Slide 2-64

Page 16: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

Suppose we know an object’s velocity to be vis at an

initial time ti.

We also know the object has a constant acceleration of as over the time interval ∆t tf − ti.

We can then find the object’s velocity at the later time tf as:

The Kinematic Equations of Constant Acceleration

Slide 2-81

Page 17: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

Suppose we know an object’s position to be si at an initial time ti.

It’s constant acceleration as is shown in graph (a).

The velocity-versus-time graph is shown in graph (b).

The final position sf is si plus the area under the curve of vs between ti and tf :

The Kinematic Equations of Constant Acceleration

Slide 2-82

Page 18: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

Suppose we know an object’s velocity to be vis at an initial position si.

We also know the object has a constant acceleration of as while it travels a total displacement of ∆s sf − si.

We can then find the object’s velocity at the final position sf:

The Kinematic Equations of Constant Acceleration

Slide 2-83

Page 19: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

The Kinematic Equations of Constant Acceleration

Slide 2-84

Page 20: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

The Kinematic Equations of Constant Acceleration

Slide 2-85

Motion with constant velocity and constant acceleration. These graphsassume si = 0, vis > 0, and (for constant acceleration) as > 0.

Page 21: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

The motion of an object moving under the influence of gravity only, and no other forces, is called free fall.

Two objects dropped from the same height will, if air resistance can be neglected, hit the ground at the same time and with the same speed.

Consequently, any two objects in free fall, regardless of their mass, have the same acceleration:

Free Fall

Slide 2-94

In the absence of air resistance, any twoobjects fall at the same rate and hit theground at the same time. The apple andfeather seen here are falling in a vacuum.

Page 22: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

Figure (a) shows the motion diagram of an object that was released from rest and falls freely.

Figure (b) shows the object’s velocity graph.

The velocity graph is a straight line with a slope:

Where g is a positive number which is equal to 9.80 m/s2 on the surface of the earth.

Other planets have different values of g.

Free Fall

Slide 2-95

Page 23: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

Example 2.14 Finding the Height of a Leap

Slide 2-98

Page 24: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

Example 2.14 Finding the Height of a Leap

Slide 2-99

Page 25: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

Example 2.14 Finding the Height of a Leap

Slide 2-100

Page 26: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

Example 2.14 Finding the Height of a Leap

Slide 2-101

Page 27: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

Figure (a) shows the motion diagram of an object sliding down a straight, frictionless inclined plane.

Figure (b) shows the the free-fall acceleration the object would have if the incline suddenly vanished.

This vector can be broken into two pieces: and .

The surface somehow “blocks” , so the one-dimensional acceleration along the incline is

The correct sign depends on the direction the ramp is tilted.

Motion on an Inclined Plane

Slide 2-102

Page 28: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

Example 2.16 From Track to Graphs

Slide 2-106

Page 29: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

Example 2.16 From Track to Graphs

Slide 2-107

Page 30: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

Example 2.16 From Track to Graphs

Slide 2-108

Page 31: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

Example 2.16 From Track to Graphs

Slide 2-109

Page 32: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

Example 2.19 Finding Velocity from Acceleration

Slide 2-114

Page 33: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

Example 2.19 Finding Velocity from Acceleration

Slide 2-115

Page 34: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

Chapter 2 Summary Slides

Slide 2-116

Page 35: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

General Principles

Slide 2-117

Page 36: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

General Principles

Slide 2-118

Page 37: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

Important Concepts

Slide 2-119

Page 38: © 2013 Pearson Education, Inc. Chapter Goal: To learn how to solve problems about motion in a straight line. Chapter 2 Kinematics in One Dimension Slide.

© 2013 Pearson Education, Inc.

Important Concepts

Slide 2-120