Dec 31, 2015
1. The atmosphere in a tank might be too 1. The atmosphere in a tank might be too lean if it is:lean if it is:
A. Capable of supporting combustion because the hydrocarbon content is above the UFL (Upper Flammable Limit) B. Capable of supporting a fire once started C. Incapable of supporting combustion because the hydrocarbon content is below the (LFL) Lower Flammable Limit D. Not safe for ballasting
Flammable Limit or Explosive Range
If the oxygen is less than 10% inside a tank, the hydrocarbon vapor will not burn and therefore it will be classified as Too LeanToo Lean.
But if oxygen is more than 10% inside the tank there will be a chance the hydrocarbon vapor will ignite and it is called Too RichToo Rich.
2. Keeping the draft at or below the load Keeping the draft at or below the load line mark will insure that the unit has line mark will insure that the unit has adequate:adequate:
A. Lightweight displacement B. Reserve buoyancy C. Reserve ballast D. Critical motions
3.Your vessel is floating in water whose 3.Your vessel is floating in water whose density is 1010. Your fresh water density is 1010. Your fresh water allowance is 8 inches. How far below her allowance is 8 inches. How far below her mark may she be loaded so as to float at mark may she be loaded so as to float at her mark in salt water whose density is her mark in salt water whose density is 1025?1025?
A. 4.8 inches B. 6.4 inches C. 3.2 inches D. 8.0 inches
3. Solution: 3. Solution: A. I = FWA x (Change in Density)
25
= 8 inches x ( 1025 – 1010 )
25
= 8 inches x 15
25
A. I. = 4.8 inches
4. A vessel is to lift a cargo weighing 30 4. A vessel is to lift a cargo weighing 30 tons with her boom whose head is 30 feet tons with her boom whose head is 30 feet from center line. The ship’s displacement from center line. The ship’s displacement excluding the weight to be lifted is 8,700 excluding the weight to be lifted is 8,700 tons. KM is 21.5 ft; KG is 20.5 ft. What will tons. KM is 21.5 ft; KG is 20.5 ft. What will be the list of the vessel when the cargo is be the list of the vessel when the cargo is lifted?lifted?
A. 1.4 B. 3.4 C. 2.8 D. 5.8
• INCLINING EXPERIMENT•
• GM = Weight x Distance• Displ. x Tan List• Dist. = GM x Displ. x Tan List• Weight• Weight = GM x Displ x Tan List• Distance• Tan List = Weight x Distance• Displ. x GM
GM = KM – KG GM = 21.5ft – 20.5ft.
GM = 1.0 footGM = 1.0 foot
TAN LIST = W x D
GM x = 30 t x 30 ft.
1 ft x 8,700 t
= 900 / 8,700
= 0 .1030927 inv. Tan
LIST = 5 .88°
5. The change in trim of a vessel may be
found by: A. Looking at the hydrostatic properties
table for the draft of the vessel B. Dividing the trim moments by MTI C. Subtracting the LCF from the LCB D. Dividing longitudinal moments by the
6. Your vessel measures 119 ft. long by Your vessel measures 119 ft. long by 17 ft. in beam. If the natural rolling period 17 ft. in beam. If the natural rolling period at a draft of 5’ 05” is 6 seconds, what is at a draft of 5’ 05” is 6 seconds, what is the GM?the GM?
A. 1.55 ft. B. 1.36 ft. C. 1.14 ft. D. 1.96 ft.
Rolling Period = 0.44 x Beam of the Vsl.
GM
Rolling Period = 0.797 x Beam of the Vsl.
GM
• GM = 0.44 x Beam of the Vsl. ²
Rolling Period
6. Solution:
GM = 0.44 x Beam ²
R.P.
GM = 0.44 x 17 ft ²
6 secs.
GM = 1.55 ft.GM = 1.55 ft.
7. Repairing damage to the hull at or 7. Repairing damage to the hull at or above the waterline reduces the threat of:above the waterline reduces the threat of:
A. Free surface effects B. Wind overturning moments C. Continued progressive flooding D. Capsizing the vessel
8. Cargoes that gives off fumes that 8. Cargoes that gives off fumes that may contaminate other cargo is known may contaminate other cargo is known as a:as a:
A. Delicate cargo B. Toxic cargo C. Dirty cargo D. Odorous cargo
9. 9. A vessel is fitted with deep tanks with a A vessel is fitted with deep tanks with a capacity of 1,000 tons of fresh water. capacity of 1,000 tons of fresh water. What quantity of peanut oil with specific What quantity of peanut oil with specific gravity of 0.92 could be carried in such gravity of 0.92 could be carried in such tanks?tanks?
A. 920 tons B. 907 tons C. 840 tons D. 850 tons
9. Solution:9. Solution:
WT. = R. D of Peanut Oil x Cap. Of FW
R. D of FW
WT = 0 .92 ton/m³ x 1,000 tons
1,000 ton/m³
WT = 920 tons WT = 920 tons
10. You are loading a cargo of canned 10. You are loading a cargo of canned goods with a stowage factor of 65. If you goods with a stowage factor of 65. If you allow 15% for broken stowage, how allow 15% for broken stowage, how many tons can be loaded in a space of many tons can be loaded in a space of 55,000 cubic feet?55,000 cubic feet?
A. 719 B. 846 C. 687 D. 973
10. Solution:10. Solution:Allowance = 100 % - B.S./ 100 = 100 % - 15% / 100 Allowance = 0.85Allowance = 0.85 Wt. = Volume x Allowance Stowage Factor = 55,000 ft³ x 0.85 65 ft³/ ton = 46,750 ft³ 65 ft³/ ton Wt. = 719.23 tons Wt. = 719.23 tons
11. The difference between the starboard 11. The difference between the starboard and port drafts caused by shifting a and port drafts caused by shifting a weight transversely is:weight transversely is:
A. List B. Trim C. Heel D. Flotation
12. Non-flammable gases should have 12. Non-flammable gases should have what kind of label?what kind of label?
A. Green B. Skull and crossbones C. White D. Red
Indicate dangerous goods that must be stored at a safe distance fromexplosive goodsexplosive goods.
13. An unstable upright equilibrium An unstable upright equilibrium position on a vessel means that the position on a vessel means that the metacenter is:metacenter is:
A. Higher than the baseline B. At the same height as the center of
gravity C. Lower than the center of gravity D. On the longitudinal centerline
14. Corrosive liquids and acids should 14. Corrosive liquids and acids should have what kind of label?have what kind of label?
A. Skull and cross bone B. Red C. Yellow D. White
15. A consignment of lumber is to be 15. A consignment of lumber is to be loaded, each piece measures 3 inches loaded, each piece measures 3 inches thick, 12 inches wide and 16 feet long. thick, 12 inches wide and 16 feet long. There are 30,000 pieces to be loaded. There are 30,000 pieces to be loaded. How many board feet is the shipmentHow many board feet is the shipment?
A. 96,000 B. 1,440,000 C. 1,200,000 D. 14,400,000
1. BF = L1. BF = L'' x W x W'' x H x H'' x 12 x 12
2. BF = L2. BF = L'' x W x W'' x H x H""
3. BF = L3. BF = L'' x W x W"" x H x H"" / 12 / 12
BF = L‘ x W“ x H“ / 12
BF = 16‘ x 12“ x 3“ / 12
BF = 576 / 12
BF = 48
BF = 48 x 30,000 pcs.
BF = 1,440,000BF = 1,440,000
16. In which case may metacentric height 16. In which case may metacentric height be considered an indication of a vessel’s be considered an indication of a vessel’s stability?stability?
A. For all angles of inclination B. For small angles of inclination C. In no case D. For large angles of inclination
17. Containers of flammable solids 17. Containers of flammable solids should be conspicuously labeled by the should be conspicuously labeled by the shipper with a:shipper with a:
A. Red and white label B. Orange label C. Green label D. Yellow label
Indicate dangerous goods that must beseparated from flammable solids,flammable solids,spontaneously combustible agentsspontaneously combustible agents or agents that are dangerous when wetdangerous when wet by a longitudinal intermediate spaceor on deck by at least 24 metresat least 24 metres..
18. In handling break bulk hazardous 18. In handling break bulk hazardous
materials, it is forbidden to use:materials, it is forbidden to use: A. Pallets B. Cargo nets C. Slings D. Metal bale hooks
19. A vessel displacing 18,000 tons has a 19. A vessel displacing 18,000 tons has a KG of 50 feet. A crane is used to lift KG of 50 feet. A crane is used to lift cargo weighing 20 tons from a supply cargo weighing 20 tons from a supply vessel. When lifting, the head of the vessel. When lifting, the head of the crane boom is 150 feet above the keel. crane boom is 150 feet above the keel. What is the change in KG?What is the change in KG?
A. 0.11 foot B. 0.17 foot C. 0.32 foot D. 0.25 foot
19. Solution: 19. Solution: GG‘ = Wt x Dist = 20 tons x (150 ft – 50 ft ) 18,000 tons = 20 tons x 100 ft 18,000 tons = 2,000 ft/ton 18,000 tons GG‘ = 0.11 ft.
20. A cargo of 75 tons is to be lifted with A cargo of 75 tons is to be lifted with a boom located 50 feet from the ship a boom located 50 feet from the ship centerline. The ship’s displacement centerline. The ship’s displacement including the suspended cargo is 6,000 including the suspended cargo is 6,000 tons and GM six feet. The list of the ship tons and GM six feet. The list of the ship with the cargo suspended from the boom with the cargo suspended from the boom will be:will be:
A. 5.40 B. 5.00 C. 6.50 D. 5.94
20. Solution: 20. Solution:
TAN LIST = W x D
GM x = 75 t x 50 ft
6 ft. x 6,000 t
= 3,750
36,000
LIST = 0.104166 inv Tan
LIST = 5.94°
21. When the height of the metacenter is 21. When the height of the metacenter is greater than the height of the center of greater than the height of the center of gravity, the upright equilibrium position gravity, the upright equilibrium position is stable and stability is:is stable and stability is:
A. Neutral B. Unstable C. Negative D. Positive
22. In preparation for receiving chilled 22. In preparation for receiving chilled reefer cargo, the reefer space has been reefer cargo, the reefer space has been pre-cooled for over 24 hours. You may pre-cooled for over 24 hours. You may begin loading when the space has been begin loading when the space has been cooled to a temperature betweencooled to a temperature between:
A. –10 F and +10 F B. 42 F and 55 F C. 12 F and 20 F D. 28 F and 40 F OR -2º C and 4º C
23. When a vessel is inclined at a small 23. When a vessel is inclined at a small angle the center of buoyancy will:angle the center of buoyancy will:
A. Remain stationary B. Move towards the high side C. Move to the height of the metacenter D. Move towards the low side
24. A tank is loaded with 9,000 barrels of 24. A tank is loaded with 9,000 barrels of gasoline. The temperature of the product gasoline. The temperature of the product is 80is 80 F, and it has a coefficient of F, and it has a coefficient of expansion of .0008. The net amount of expansion of .0008. The net amount of cargo loaded is:cargo loaded is:
A. 8,856 barrels B. 8,944 barrels C. 9,144 barrels D. 9,072 barrels
24. Solution:24. Solution:
Standard Loading Temp. = 60° F
Net bbls = Gross +/- ( Gross x Coefficient x ( Diff. In temperature ))
= 9,000 +/- (9,000 x 0.0008 (80°F - 60°F))
= 9,000 +/- ( 7.2 x 20°F )
= 9,000 - 144
Net bbls. = 8,856
25. Bilge soundings indicate:Bilge soundings indicate: A. Whether the ship is taking on water B. Whether the cargo is leaking or not C. The amount of condensation in the hold D. All of these
26. If the metacentric height is large, a If the metacentric height is large, a vessel will:vessel will:
A. Have a slow and easy motion B. Be stiff C. Be tender D. Have a tendency to yaw
STIFF VESSELSTIFF VESSEL
1. Large GM2 Bottom Heavy3. Short R. P.4. Fast Roll
TENDER VESSELTENDER VESSEL
1. Small GM2. Top Heavy3. Large R. P.4. Slow Roll
Tankers andBulk Carriers
Car Carriers andCar Carriers andContainersContainers
M
K
EFFECT OF DIFF. GM ON THE PERIOD OF ROLLEFFECT OF DIFF. GM ON THE PERIOD OF ROLL
ZG
G ZG IS HIGHG IS HIGHGM IS SMALLGM IS SMALLSMALL GZSMALL GZSLOW ROLLSLOW ROLL
TENDERG IS LOWG IS LOWGM IS LARGEGM IS LARGELARGE GZLARGE GZFAST ROLLFAST ROLL
STIFF
STIFF VESSELSTIFF VESSEL
STIFF VESSELSTIFF VESSEL
TENDER VESSELTENDER VESSEL
TENDER SHIPTENDER SHIP
27. Certain cargoes must be segregated 27. Certain cargoes must be segregated
because of their:because of their: A. Inherent characteristics B. Weight C. Danger to human D. Destination
28. The shearing stress on a ship’s 28. The shearing stress on a ship’s structure are usually GREATEST at:structure are usually GREATEST at:
A. Midships B. The stem C. The bow D. Ships quarter length points
SHEARING STRESSSHEARING STRESS
EMPTYEMPTYFULLFULL
29. If a vessel is loaded in such a 29. If a vessel is loaded in such a manner that she is said to be sagging, manner that she is said to be sagging, what kind of stress is placed on the what kind of stress is placed on the sheer strakes?sheer strakes?
A. Thrust B. Compression C. Tension D. Racking
• HOGGING CONDITION
• SAGGING CONDITION
COMPRESSION STRESS
TENSIONSTRESS
TENSION STRESS
WEIGHT IS CONCENTRARED AT BOTH ENDS
WEIGHT IS CONCENTRATED AT AMIDSHIP
WL
WL
30. How much force would be required to 30. How much force would be required to lift a weight of 200 lbs., using a gun tackle lift a weight of 200 lbs., using a gun tackle rigged to disadvantage rigged to disadvantage disregardingdisregarding friction?friction?
A. 150 lbs. B. 100 lbs. C. 50 lbs. D. 200 lbs.
MECHANICAL ADVANTAGEMECHANICAL ADVANTAGE
• Single Purchase 1
• Gun Tackle 2
• Luff Tackle 3Luff Tackle 3
• Handy Billy 3Handy Billy 3
• Watch Tackle 3Watch Tackle 3
• Two Fold 4
• Double Luff 5
• Three Fold 6
30. Solution: 30. Solution:
Force = Wt x (1 + 10% nos of Sheaves)
Mechanical Advantage
Force = Weight
Mechanical Advantage
= 200 lbs.
2
Force = 100 lbsForce = 100 lbs.
31. You are loading bagged coffee beams, 31. You are loading bagged coffee beams, to keep cargo leakage from being to keep cargo leakage from being contaminated by ships structure, you contaminated by ships structure, you should:should:
A. Hose down the deck before loading the
cargo B. Place the cargo on a layer of spaced
dunnage C. Use separation cloths between the deck
and cargo D. Use bag-on-bag stowage
32. The wave period and the apparent 32. The wave period and the apparent rolling period of a vessel are the same:rolling period of a vessel are the same:
A. Rolling period decreases B. Rolling period increases C. Synchronous rolling occurs D. Roll period is dampened
33. In order to check your vessel’s stability a 33. In order to check your vessel’s stability a weight of 40 tons is lifted with the jumbo weight of 40 tons is lifted with the jumbo boom, the boom head being 50 feet from the boom, the boom head being 50 feet from the ship’s centerline. The clinometer is then ship’s centerline. The clinometer is then carefully read and shows a list of 5º. The carefully read and shows a list of 5º. The vessel’s displacement is 8,000 tons including vessel’s displacement is 8,000 tons including the suspended weight. What will be the the suspended weight. What will be the metacentric height of the vessel at this time?metacentric height of the vessel at this time?
A. 2.74 feet GM B. 2.86 feet GM C. 2.80 feet GM D. 2.93 feet GM
33. Solution: 33. Solution:
Tan List = W x D
GM x GM = W x D
Tan List x = 40 t x 50 ft.
Tan 5° x 8,000 t
GM = 2.86 ft.GM = 2.86 ft.
34. What can be used to measure the 34. What can be used to measure the percentage of oxygen inside a chain percentage of oxygen inside a chain locker?locker?
A. Combustible gas indicator B. Oxygen indicator C. Flame safety lamp D. H2S meter
35. A vessel behaves as if all of its 35. A vessel behaves as if all of its weight is acting downward through the weight is acting downward through the center of gravity, and all its support is center of gravity, and all its support is acting upward through the:acting upward through the:
A. Center of buoyancy B. Tipping center C. Keel D. Amidships
36. A slow and easy motion in a seaway 36. A slow and easy motion in a seaway is an indication of a:is an indication of a:
A. Low center of gravity B. Small GM C. Stiff vessel D. Large GZ
37. When loading a container vessel, the 37. When loading a container vessel, the operation is basically that of vertical operation is basically that of vertical loading. The important factors to be loading. The important factors to be considered when loading containers are considered when loading containers are port of discharge:port of discharge:
A. Availability of dunnage, and docking B. Crushability, and inherent vice C. Sweat, and weight D. Weight and refrigeration
38. The lashing of a stack of containers 38. The lashing of a stack of containers with interlocking fittings restrain the with interlocking fittings restrain the forces that causes:forces that causes:
A. Toppling
B. Crushing
C. Racking
D. Buckling
39. When loading or discharging dry mud 39. When loading or discharging dry mud or cement, crew members should use or cement, crew members should use goggles and:goggles and:
A. Ear plug B. Rubberized boots C. Facial respirator mask D. Fireman’s outfit
40. The important stability parameter, 40. The important stability parameter, KG is defined as the:KG is defined as the:
A. Height of the metacenter above the keel B. Height of the center of buoyancy above
the keel C. Metacentric height D. Height of the center of gravity above
the keel
41.Which of the following steps is NOT 41.Which of the following steps is NOT generally taken when gas-freeing a tank?generally taken when gas-freeing a tank?
A. Washing the tank interior with sea
water B. Fresh air ventilation C. Application of degreasing solvents D. Removal of sludge and corrosion
products
42. Reid vapor pressure is: A. The lowest temperature and pressure that will cause a flammable liquid to give off vapors B. Exerted by liquid cargo on a cargo hose body C. Exerted by liquid cargo on the sides of a tank D. A measurement of the amount of flammable vapors given off by a liquid at a certain temperature
43. When loading bulk liquid cargo, what is 43. When loading bulk liquid cargo, what is the first action you should take if a cargo the first action you should take if a cargo valve jammed open?valve jammed open?
A. Trip the pump relief valve B. Order the dock man to shut down C. Run out the vessel’s or terminal firehose D. Call the owner, operator, or terminal
supervisor
44. It is possible, and sometimes 44. It is possible, and sometimes necessary to strengthen the deck of a necessary to strengthen the deck of a vessel for carriage of deck cargo by:vessel for carriage of deck cargo by:
A. Welding steel “feet” to the deck, on which the cargo is placed B. Placing bunker on the deck C. Building a stage on which to place the cargo D. Erecting vertical pillars under the deck to support the cargo
Hold pillarsHold pillars
Floor platingFloor platingRider plateRider plate
45. Which of the following statements 45. Which of the following statements about ventilation of bulk coal is TRUE?about ventilation of bulk coal is TRUE?
A. Coal should not be ventilated, all oxygen
should be excluded from the cargo B. Coal should be surface ventilated only C. Coal should be through ventilated only if
temperature in the center of the cargo
exceed 125ºF D. Coal should be through ventilated to
remove methane and reduce the heat of
spontaneous combustion
46. A vessel’s bottom will be subjected to 46. A vessel’s bottom will be subjected to tension when weight is concentrated:tension when weight is concentrated:
A. At both ends of the vessel B. Amidships . C. Aft D. Forward
47. Hygroscopic cargoes should be 47. Hygroscopic cargoes should be ventilated in cases when:ventilated in cases when:
A. The dew point of the air in the hold is very
low B. Going from a warm to a cold climate C. The dew point of the outside air is greater
than the dew point of the air in the hold D. The outside dew point is 60º F and the
cargo temperature is 54º F
48. Segregation of cargoes refers to:48. Segregation of cargoes refers to: A. Separation of cargoes by destination B. Classifying cargoes according to their
toxicity C. Separating cargoes so that one cannot
damage the other because of its inherent
characteristics D. Listing of cargoes in order of their
flammability
49. Which of the following weld faults can 49. Which of the following weld faults can only be detected by a method that only be detected by a method that examines the internal structure of a weld?examines the internal structure of a weld?
A. Under cut B. Lack of penetration C. Overlap D. Lack of reinforcement
50. The amount of strain on each runner 50. The amount of strain on each runner of a married fall system lifting 2,000 lbs. of a married fall system lifting 2,000 lbs. When the angle made by the legs is 90º When the angle made by the legs is 90º would be:would be:
A. 1,414 lbs. B. 1,000 lbs. C. 2,000 lbs. D. 1,154 lbs.
50. Solution: 50. Solution:
Strain = Weight
2 x ½ Cos = 2,000 lbs.
2 x Cos 45°
= 2,000 lbs
1.41421
Strain = 1.414 lbs.
51. What is the area of a circle with a 51. What is the area of a circle with a radius of 4 feet after a sector of 111 radius of 4 feet after a sector of 111 degrees has been removed?degrees has been removed?
A. 3.90 feet B. 8.67 feet C. 34.77 feet D. 50.27 feet
51. Solution51. Solution: :
Area of Circle = x Radius²
= 3.1416 x 4²
= 3.1216 x 16
Area of Circle = 50.26 ft.Area of Circle = 50.26 ft.
Area of Circle after removal of 111° sector
360° - 111° / 360° = 0.69166
0.69166 x 50 . 26
Area of Circle = 34.77 ft.Area of Circle = 34.77 ft.
52. A term applied to a fore and aft 52. A term applied to a fore and aft girder running along the side of the ship girder running along the side of the ship and also to the outboard strake of and also to the outboard strake of plating on any deck:plating on any deck:
A. Stringer B. Camber C. Keel D. Frames
SIDE S
TRINGER
SIDE S
TRINGER
53. If additional weight is added above 53. If additional weight is added above the center of gravity, the vessel will:the center of gravity, the vessel will:
A. Reduce reserve buoyancy B. Increase GM C. Reduce righting moments D. All of these
54. It is a form of longitudinal 54. It is a form of longitudinal deformation under stress by which the deformation under stress by which the middle part of the vessel structure sinks middle part of the vessel structure sinks below the extremities:below the extremities:
A. Sagging B. Racking C. Hogging D. Torsion
• 55. When a weight of 800 lbs. is 55. When a weight of 800 lbs. is suspended, what is the stress on the suspended, what is the stress on the hauling part when using a gun tackle hauling part when using a gun tackle rove to least advantage?rove to least advantage?
• A. 320 lbs.
• B. 347 lbs.
• C. 400 lbs.
• D. 480 lbs.
55. Solution:55. Solution:
Force = Weight x ( 1 + 10% N.O.S )
Mechanical Advantage
Force = Weight
Mechanical Advantage
Force = 800 lbs 2 Force = 400 lbsForce = 400 lbs.
• 56. The definition “A” mixture of 56. The definition “A” mixture of hydrocarbon products composed hydrocarbon products composed predominantly of propane, butane, predominantly of propane, butane, butylene or butadiene which is liquefied butylene or butadiene which is liquefied by compression at normal atmospheric by compression at normal atmospheric temperature for storage, transport and temperature for storage, transport and handling refers to:handling refers to:
• A. LPG
• B. Grade A products
• C. Grade B products
• D. LNG
57. When working cargo with a Burton or 57. When working cargo with a Burton or married fall arrangement, the part of the married fall arrangement, the part of the cargo gear most likely to fail would be cargo gear most likely to fail would be the:the:
A. Guy B. Topping lift C. Boom D. Gooseneck
58. What term indicates the midship 58. What term indicates the midship portion of a vessel that has a constant portion of a vessel that has a constant cross section?cross section?
A. Middle body B. Amidship C. Half of length D. Moulded length
59. Spontaneous heating of coal rapidly 59. Spontaneous heating of coal rapidly accelerate at the approximate minimum accelerate at the approximate minimum temperature of:temperature of:
A. 88° F
B.B. 100° F100° F
C. 111° F
D. 119° F
• 60. Transverse frames are more widely 60. Transverse frames are more widely spaced on a ship that is designed with spaced on a ship that is designed with the:the:
• A. Longitudinally system of framing
• B. Isometric system of framing
• C. Centerline system of framing
• D. Transverse system of framing
61. This is the ratio of the immersed 61. This is the ratio of the immersed volume to the area of the load volume to the area of the load waterplane multiplied by the mean waterplane multiplied by the mean draught:draught:
A. Vertical prismatic coefficient B. Prismatic coefficient C Waterplane area coefficient D. Midship section area coefficient
BLOCK COEFFICIENTBLOCK COEFFICIENT ( Cb )( Cb )
Cb = Vol. of Displ. Vol. of the Block = Vol. of Displ. L x B x Draft
BLOCK COEFFICIENTBLOCK COEFFICIENT
WATERPLANE COEFFICIENTWATERPLANE COEFFICIENT ( Cw )( Cw )
CwCw = Area of Waterplane Area of Rectangle ABCD = Area of Waterplane L x B
MIDSHIP COEFFICIENT ( Cm )MIDSHIP COEFFICIENT ( Cm )
CmCm = Midships Area (Am) Area of Rectangle = Midships area (Am) B x d
PRISMATIC COEFFICIENT ( Cp )PRISMATIC COEFFICIENT ( Cp )
CpCp = Volume of Ship Volume of Prism = Volume of Ship L x Am
62. On tank vessels that use an automatic 62. On tank vessels that use an automatic tape well, free movement of the tape is tape well, free movement of the tape is normally checked by:normally checked by:
A. Operating the hand clutch B. Comparing with a hand tape C. Removing the side plate D. Using litmus paste
63. The advantage in using a single whip 63. The advantage in using a single whip tackle is:tackle is:
I.I. The strain on the hauling part is less The strain on the hauling part is less
than the weightthan the weight
II. The direction of the pull of force II. The direction of the pull of force
needed to lift the weight is changedneeded to lift the weight is changed A. I only B. II only C. Both I and II D. Neither I nor II
64. “Block Stowage” means: A. Storing all cargo for a port in the same
area B. Having the cargo on pallets C. Using separation cloths to separate
different kinds of cargo D. Using port marks on the cargo
65. When a vessel is stationary and in a 65. When a vessel is stationary and in a hogging condition, the main deck is in hogging condition, the main deck is in under:under:
A. Tension stress B. Compression stress C. Racking stress D. Shear stress
66. 66. A vessel is drawing 38’08” in salt A vessel is drawing 38’08” in salt water. What would she have to do in water. What would she have to do in order to maintain the same draft in order to maintain the same draft in brackish water?brackish water?
A. Discharge cargo and lighten up before
proceeding B. Load additional cargo C. Proceed slowly with no change to
deadweight tons D. Load clean ballast
• 67. If a vessel goes from salt water to 67. If a vessel goes from salt water to fresh water and wishes to keep the fresh water and wishes to keep the same draft, you would:same draft, you would:
• A. Discharged ballast
• B. Take on ballast
• C. Do nothing as it does remain the same
• D. None of these
68. If the cargo to be loaded in the hold is 68. If the cargo to be loaded in the hold is bulk grain, the limber boards should be:bulk grain, the limber boards should be:
A. Covered with tarpaulin with battens B. Disinfected with bitumastic C. Caulked with oakum D. Cleaned and limed washed
69. All lines in the loadline are _______ in 69. All lines in the loadline are _______ in thickness thickness..
A. 16 mms B. 20 mms C. 24 mms D. 25 mms
70. Safety shackles are fitted with:70. Safety shackles are fitted with: A. A threaded bolt, locknuts, cotter pins B. A threaded bolt C. A round pin with a cotter pin D. Round pins and locknuts
71. Loadline markings indicate the drafts 71. Loadline markings indicate the drafts at which, for various conditions and at which, for various conditions and types or classes of vessels, there will still types or classes of vessels, there will still be left a sufficient percentage of ______ be left a sufficient percentage of ______ to ensure the vessel’s safety.to ensure the vessel’s safety.
A. Reserve buoyancy B. Intact buoyancy C. Longitudinal stability D. Transverse
72. The result of two forces acting in 72. The result of two forces acting in opposite directions and along parallel opposite directions and along parallel lines, is an example of what type of lines, is an example of what type of stress?stress?
A. Shear B. Tensile C. Compression D. Strain
73. Which of the following is an 73. Which of the following is an advantage gained by building a vessel by advantage gained by building a vessel by Isherwood system of construction?Isherwood system of construction?
A. It provided a great deal of longitudinal
strength B. It provides for transverse strength than
any other system C. It reduces the need for a large amount of
longitudinals D. It eliminates the need for any transverse
framing
74. 74. Which of the following most important Which of the following most important in prevention of sweat damage to cargo in in prevention of sweat damage to cargo in the hold?the hold?
A. Dew point of the outside air B. Dew point of the air in the cargo hold C. Outside temperature D. Temperature of the cargo
75. What is the simplest member of the 75. What is the simplest member of the olefin family, the largest volume organic olefin family, the largest volume organic chemical and is used in more than 30% of chemical and is used in more than 30% of all petrochemical products?all petrochemical products?
A. Ethylene B. Aromatics C. Propylene D. Butadiene Use for production of synthetic
rubber
Use in manufacture of resin, fibres and elastomers
Use as raw material in organicUse as raw material in organic industryindustry
76. Barium cyanide solid is classed as 76. Barium cyanide solid is classed as “poison B” and cannot be stowed near“poison B” and cannot be stowed near:
A. Acids B. Flammable solids C. Flammable liquids D. Benzene
77. What do you call the principle of 77. What do you call the principle of separating the oil residues from water? separating the oil residues from water? The seawater is discharged at sea while The seawater is discharged at sea while the oil residue is retained on board.the oil residue is retained on board.
A. Decantation B. Separation C. Division D. Segregation
78. What do you call the plan showing 78. What do you call the plan showing the longitudinal, vertical section passing the longitudinal, vertical section passing through the meridian line of vessel?through the meridian line of vessel?
A. Sheer plan B. Docking arrangement C. Stowage plan D. Bon jean curve
79. Where would you find the draft marks 79. Where would you find the draft marks on a ship?on a ship?
A. Area of water line near stem and stern
B. Midships near the waterline C. Voids D. Deep tanks
80. Your draft at the dock is 27’ 06”. 80. Your draft at the dock is 27’ 06”. What will be your draft when at sea?What will be your draft when at sea?
A. 26’ 10” B. 26 ’08” C. 26’ 11” D. 28’ 02”
80. Solution: 80. Solution:
New Draft Old Density
Old Draft New Density
New Draft 1,000 kgs/m³
27.5‘ 1,025 kgs/m³
New Draft = 27.5‘ x 1,000 kgs/m³
1,025 kgs/m³
New Draft = 26.829 or 26‘ 10"New Draft = 26.829 or 26‘ 10"
81. On the vessel cargo hold a gasoline 81. On the vessel cargo hold a gasoline powered forklift truck is used, what powered forklift truck is used, what precaution should you take?precaution should you take?
A. See that ventilation is supplied on
account to truck poisonous exhaust B. See to it that hold are well lighted during
the night time C. Trucks are operated by experience
stevedore D. All of the above
82. What are “liquefied flammables”?82. What are “liquefied flammables”?
A. Toxic
B. Poison
C. Completely odorless in their pure natural
state
D. Odorized to help detect leaks
83. What do you mean by the term 83. What do you mean by the term “cargo tank length”“cargo tank length” as used in part 157 of as used in part 157 of the pollution regulations?the pollution regulations?
A. Length from the collision bulkhead to the
forward bulkhead of the machinery
spaces B. Length of any individual cargo space,
from bulkhead to bulkhead C. Diagonal measurement of a cargo tank D. Greatest distance between two opposite
cargo tank bulkhead
84. What would you do first when you 84. What would you do first when you notice oil on the water near vessel while notice oil on the water near vessel while taking on fuel?taking on fuel?
A. Stop loading B. Notify the terminal superintendent C. Notify the senior deck officer D. Determine whether your vessel is the
source
85. 85. What distance will a weight of 152.4 What distance will a weight of 152.4 tons have to be moved in order to remove tons have to be moved in order to remove a 2 degrees list from a vessel of a 2 degrees list from a vessel of displacement 9,144 tons and GM 1.03 m?displacement 9,144 tons and GM 1.03 m?
A. 2.16 m B. 2.29 m C. 3.20 m D. 5.52 m
85. Solution: 85. Solution:
Tan List = W x D
GM x Dist = Tan List x GM x
Weight
= Tan 2° x 1.03 m x 9,144 tons
152.4 tons
Distance = 2.16 m
86. Which part provides for the vertical Which part provides for the vertical control and positioning of the boom in a control and positioning of the boom in a yard and stay rig?yard and stay rig?
A. Topping lift B. Cargo whip C. Back stay D. Spider block
87. What do you call a rope ladder with a 87. What do you call a rope ladder with a wooden rung?wooden rung?
A. Jacob’s ladder B. Pilot ladder C. Jury ladder D. Life ladder
88. What are these devices which secure 88. What are these devices which secure standing and running rigging that standing and running rigging that includes cleats, bitts, chocks, fair leads includes cleats, bitts, chocks, fair leads and pad eye?and pad eye?
A. Deck fittings B. Deck devices C. Deck stores D. Deck gears
89. 89. What do you call the cargo gear What do you call the cargo gear mode of 4 legs of equal length of either mode of 4 legs of equal length of either rope or wire, one end of each leg being rope or wire, one end of each leg being spliced into an iron ring, the other end spliced into an iron ring, the other end into the eye of a hook?into the eye of a hook?
A. Bridle B. Chain sling C. Bull rope D. Sling
90. When a double bottom tank is full of 90. When a double bottom tank is full of fresh water, it holds 120 tons. Find how fresh water, it holds 120 tons. Find how many tons of oil of relative density 0.84 it many tons of oil of relative density 0.84 it will hold?will hold?
A. 100.8 tons B. 108.0 tons C. 110.7 tons D. 112.8 tons
90. Solution: 90. Solution:
Weight = R.D. of Oil x Cap. Of FW
R.D. of FW
Weight = 0.84 x 120 tons
1.000
Weight = 100.8 tonsWeight = 100.8 tons
91. After discharging refrigerated cargo, 91. After discharging refrigerated cargo, what are the advantages of thoroughly what are the advantages of thoroughly airing the cold storage compartment?airing the cold storage compartment?
A. To remove bad smell B. To dry the holds flooring and bilges C. To clean the cargo hold D. For removal of CO2 and other gases,
odors and dampness
92. Which of the following conditions will 92. Which of the following conditions will cause a vessel’s bottom to be subjected cause a vessel’s bottom to be subjected to tension stresses?to tension stresses?
A. Concentration of weight amidship B. Concentration of weight forward C. Concentration of weight aft D. Concentration of weight at both end
of the vessels
93. What is the use of the dunnage in 93. What is the use of the dunnage in bagged of rice and other goods that was bagged of rice and other goods that was closely packed?closely packed?
A. Air passage B. Division C. Drainage D. Spacing
94. Metacentric height is a measure of:94. Metacentric height is a measure of:
I.I. The righting arm of the vesselThe righting arm of the vessel
II. Initial stability of a vesselII. Initial stability of a vessel A. I only B. II only C. Both I and II D. Neither I nor II
95. It is customarily stated as the 95. It is customarily stated as the number of cubic feet one ton of 2,240 number of cubic feet one ton of 2,240 pounds (long ton) of a particular lot of pounds (long ton) of a particular lot of cargo will occupy:cargo will occupy:
A. Stowage factor B. Deadweight cargo C. Insured cargo D. Measurement cargo
96. The highest deck which runs the full 96. The highest deck which runs the full length of the ship is:length of the ship is:
A. Main deck B. Poop deck C. Deck house D. Shelter deck
97. What do you call the metal chimney 97. What do you call the metal chimney or passage through which the smoke or passage through which the smoke and gases are led from the uptakes to and gases are led from the uptakes to the open air?the open air?
A. Smokestack B. Smoke pipe C. Funnel D. Chimney
98. Your vessel measures 30 meters long 98. Your vessel measures 30 meters long by 5 meters in beam. If the rolling period by 5 meters in beam. If the rolling period is 6 seconds, find the GM:is 6 seconds, find the GM:
A. 0.44 m B. 0.56 m C. 0.48 m D. 0.58 m
• 98. Solution:
• GM = 0.797 x Beam ²
R.P.
• GM = 0.797 x 5 m ²
6 secs.
• GM = 0.44 m
99. 99. Which of the following are essential Which of the following are essential parts of the keel?parts of the keel?
I.I. Middle line keelsonMiddle line keelson
II.II. Side keelson Side keelson A. I only B. II only C. Both I and II D. Neither I nor II
100. In British Harbor, the Department of 100. In British Harbor, the Department of Transportation has given authority to Transportation has given authority to any person to inspect the oil record book any person to inspect the oil record book of a ship:of a ship:
A. Harbor Master B. Representative of the Agent C. Marine Surveyor D. Port State Control