Topic 6: Fields and forces

Topic 6: Fields and forces

State Newton’s universal law ofgravitation.

Students should be aware that themasses in the force law are pointmasses. The force between twospherical masses whose separationis large compared to their radiiis the same as if the two sphereswere point masses with theirmasses concentrated at the centersof the spheres.

6.1 Gravitational force and field

Newton 1642-1727

Newton’s laws of gravitationAnything with mass attracts

anything else with mass. The size of that attraction is given

by my Law of Gravitation:

F = Gm1m2

r2

…where m1 and m2 are the masses of the two objects (in kg), r is the distance between them (in m) and G is “The Universal Gravitational Constant” (= 6.67 x 10-11 Nm2kg-2).

State Newton’s universal law ofgravitation.

Cavendish measurement of GClick to play

Inverse square law

What holds the planet in orbit?

Free Body Force Diagrams revision

The Earth attracts the man and the man attracts the Earth – a Newton III pair of forces where both are gravitational.

A uniform gravitational field is one where the field lines are always the same distance apart - this is almost exactly true close to the Earth's surface (Figure 1(a)).

However if we move back and look at the planet from a distance the field lines clearly radiate outwards (Figure 1(b)), getting further apart as the distance from the Earth increases.

When viewed from an even greater distance the complete field can be seen (Figure 1(c)).

Such a field is called a radial field - the field intensity (g) decreasing with distance.

Diagram 1(d) shows the distortion of the gravitational field lines by high- density rock.

Gravitational Field StrengthConsider a man on the Earth:

Man’s weight = mgBUT we know that this is equal to his gravitational attraction, so…

GMm = mg

r2

GM = g

r2

Therefore:

(this is a vector quantity)

Derive an expression for gravitational field strength at the surface of a planet, assuming that all its mass is concentrated at itscentre.

Gravitational Field StrengthDefine gravitational field strength.

Definition: Force, act, point, unit mass.

Write a definition of gravitational field strength

Determine the gravitational fielddue to one or more point masses.

Derive an expression for gravitational field strength at the surface of a planet, assuming that all its mass is concentrated at itscentre.

Example questions1) Gregoire stands next to Justin and is attracted to him.

If Gregoire’s mass is 70kg and Justin’s is 80kg calculate the size of the attraction if they are 50cm apart.

2) Calculate the gravitational attraction between a proton and an electron if the masses of each are 1.67 x 10-27 and 9.11 x 10-31 kg respectively and they are 5.3nm apart.

3) Calculate the mass of the Earth given that a mass of 1kg has a weight of 9.8N on the Earth (radius 6370km).

4) Use this value to calculate the gravitational attraction between the Earth and the moon, where the mass of the moon is 7.4 x 1022 kg and they are 3.8 x 108 m apart.

Questions

Hamper HL page 183 q’s 1-5.SL page 129 Q’s 1-5.IB question pack Q’s 3,5,6,8.

6.2 Electric force and fieldState that there are two types ofelectric charge.

Static Electricity

+++ ---

------

Conservation of charge

The law of conservation of charge states…………….

One of the fundamental laws of Physics is that charge can never be created or destroyed. Charge is always conserved in any reaction. A simple example of this is the rubbing of a polythene strip with a duster. Initially the strip and the dusted were uncharged but after rubbing the strip gains a net negative charge and the duster gains an equal amount of positive charge – the total charge in the process has been conserved.

State and apply the law ofconservation of charge.

Conductors and insulators.Describe and explain thedifference in the electricalproperties of conductors andinsulators.

In a conductor, the conduction and valence bands overlap. This allows the valence electrons to easily move along the conduction band giving the material low electrical resistance.

In insulators, there is a large forbidden energy band, which makes it difficult for valence electrons to move into the conduction band giving the material a high electrical resistance.

In semiconductors, the forbidden energy band is not too wide. Under certain conditions, electrons in the valence band can gain sufficient energy to cross the gap. This reduces the electrical resistance of the material.

The difference between conductors and insulators is………………

Coulomb’s lawState Coulomb’s law. Students should be aware that the charges

in the force law are point charges.

Coulomb’s Law

Charles Coulomb 1736-

1806

Like gravity, electrostatic force is one of the four fundamental forces. The equation

looks pretty similar too…

Coulomb’s Law

F = kQ1Q2

r2

…where k = 9.0 x 109 Nm2C-2 (the “Coulomb Law Constant”).This comes from k = 1/4πε0 ……where ε0 = permittivity of free space (i.e. 8.85 x 10-12 Fm-1).

Electric field of a point chargeDefine electric field strength.

Write a definition of electric field strength

Students should understand theconcept of a test charge.

Determine the electric fieldstrength due to one or morepoint charges.

Questions on Electric fields

IBID Exercise 6.1 Q’s1,2,3,6,7,8,9,11, 18,19,20,21,24,25,27,30

Hamper HL Page 198 Q’s 20,21.SL Page 135 Q’s 6,7.

IBID Answers

Electric field patterns

Draw the electric field patterns for different charge configurations.

These include the fields due to thefollowing charge configurations:a point charge, a charged sphere,two point charges, and oppositelycharged parallel plates. The latterincludes the edge effect. Studentsshould understand what is meantby radial field.

How do we predict the shape of a field?

• Imagine that you have a unit positive test charge.

• Place it in a point in the field.• Sketch the path it would take.• Repeat this many times until you have

enough field lines• The “density” of the lines represents the

strength of the field.

Point charge

+

Sphere

Positive or negative

2 Point charges

+ +

2 Point charges

+ -

Parallel plates

+

_

Edge effects

Electric FieldsElectric field strength E = F

q

(this is a bit like gravitional field strength g = F/m)

Let’s compare this to Coulomb’s Law: Coulomb’s

LawF = kQq r2

Putting these equations together gives us…

Electric field strength E = kQ(in NC-1) r2

Example questions1) Calculate the electric field strength at a distance of

0.1m from a point charge of 20nC.2) The electric field strength on an electron in hydrogen is

approximately 1x1011 NC-1. How far away from the nucleus is it?

3) Sketch a graph of electric field strength against distance:E

r

Example questions…..

If 3 protons form an equilateral triangle at a distance of 1 micron apart. What is the force on one of them?

Electrostatic force and circular motionConsider an electron orbiting a nucleus in a hydrogen atom:

p

eQ. If the mass of an electron is 9.1x10-31kg and the distance to the proton is 0.11nm how fast is

the electron going?

Using mv2 = kQq we get v = 1.5x106 ms-1

r r2

Conductors and insulators

The difference between conductors and insulators is………………

The law of conservation of charge states…………….

The band structures of a conductor, semiconductor and insulator

A practical exampleConsider a charged polythene strip and a metal ball:

++ +

+--

-- - -

- -- -

- --

Visualising a field Hyperlink

Fields applet

Field for a point charge

Click to play

Electric dipoleClick to play

Falstad.com

Falstad.com

Electric fields around a point charge

Draw the edge effects for the parallel plate

2 Charged Spheres

http://www.falstad.com/emstatic/

Uniform electric fieldsConsider two charged plates:

+

-

Now consider a point charge:

Q V

Work done = QV

For an electron, eV = ½mv2

Visualising the fields

Hyperlink

Questions

IB question pack Q’s 1,9,12,14,15,17.

IBID 6.1 Q’s 4,5

6.3 Magnetic force and field

Permanent magnets and domains

HyperlinkState that moving charges give rise to magnetic fields.

Draw magnetic field patterns due to currents.

These include the fields due to currents in a straight wire, a flat circular coil and a solenoid.

Field around a wire

Click to play

Field around a loopClick to play

B field for a loop

Click to play

Field patterns

Left hand Motor RuleDetermine the direction of the forceon a current-carrying conductor in amagnetic field.

Fleming's left- hand rule

Current-carrying wire in a magnetic field

S

N

F = Force

B = Magnetic

field

I = Current

Q. Where will this wire go?

Comparing magnets and solenoids

N SMagnet:

Solenoid:

Magnetic Field around a Solenoid

Forces on a loop

Click to play

Electric motor

Click to play

Hyperlink

Magnetic Flux DensityClearly, the size of the force on this wire depends on three

things:1. The strength of the magnetic field2. The current in the wire3. The length of the wire (in the field)

These three things are related by the simple formula…

B is called “magnetic flux density” and is measured in Teslas (= 1NA-1m-1). By definition, a magnetic flux density of 1T produces a force of 1N on a 1m long wire with a current of 1A.

Determine the direction of the force ona charge moving in a magnetic field.

Hamper HL page 208 Q’s 37,38 SL Page 141 Q’s 8,9.

Force on a charged particle

Define the magnitude and direction ofa magnetic field.

A magnetic flux density of 1T produces a force of 1N on a 1m long wire with a current of 1A.

Circular pathsRecall:

+ + -2 protons, 2 neutrons, therefore charge =

+2

1 electron, therefore charge = -1

Because of this charge, they will be deflected by magnetic fields:

+

These paths are circular, so Bqv = mv2/r, or r =mv Bq

Circular paths

if angle = 90° the path is circular

if 0 < angle < 90° the path is a helix.How do you work out which bit is circular?

Questions Magnetic fields

Hamper HL page 220 Q’s 1,2. SL Page 142.IB question pack Q’s 2,4,7,10,11,16.

IBID 6.2 Q’s 3,4IBID 6.3 Q’s 1 – 14.

Answers