Transcript
MAE 241 - Statics
Summer 2009
Dr. Konstantinos A. SierrosOffice Hours: M and W 10:30 – 11:30 (263 ESB new add)
kostas.sierros@mail.wvu.eduTeaching Blog: http://wvumechanicsonline.blogspot.com
Determine the internal normal force, shear force, and moment at point C in the simply supported beam. Point C is located just to the right of the 1500-lb –ft couple moment.
Determine the internal normal force, shear force, and moment at point C in the simply supported beam.
Draw the shear and moment diagrams for the simply supported beam.
7.3 Relations between distributed load, shear and moment
Distributed loading• Distributed loading is positive when the loading acts upward• The internal shear force and bending moment are assumed to act in the positive sense according to the established sign convention• Distributed loading has been replaced by a resultant force ΔF that acts at distance k Δx
7.3 Relations between distributed load and shear
)(xwdx
dV
Slope of shear diagram Distributed load intensity
7.3 Relations between distributed load and shear
Change in shear Area under loading curve
dxxwV )(
7.3 Relations between the shear and moment
Vdx
dM
Slope of momentdiagram
Shear
VdxM
Change in moment Area under shear
diagram
7.3 Couple moment
Letting Δx→0
Moment equilibrium requires;
ΣM = 0 ; ΔM = Mo+
The ‘jump’ in the moment diagram isupward if Mo is clockwise.
ΔM is downward when Mo is counterclockwise.
7.4 Cables
7.4 Cables
• Flexible cables and chains combine strength with lightness• Assume cable is perfectly flexible and inextensible• The cable takes a form of several straight line segments• Use equations of equilibrium and geometry
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