LecturePLUS Timberlake1 Chapter 1 Measuring Temperature.

LecturePLUS Timberlake 1

Chapter 1

Measuring Temperature

LecturePLUS Timberlake 2

Temperature

Particles are always moving.

When you heat water, the water molecules move

faster.

When molecules move faster, the substance gets

hotter.

When a substance gets hotter, its temperature goes

up.

LecturePLUS Timberlake 3

Learning Check

Suppose you place water in a freezer.A. The water particles move

1) faster 2) slower 3) the same

B. The water will get

1) hotter 2) colder 3) stay the same

C. The temperature of the water will be

1) higher 2) lower 3) the same

LecturePLUS Timberlake 4

Solution

Suppose you place water in a freezer.

A. The water particles move

2) slower

B. The water will get

2) colder

C. The temperature of the water will be

2) lower

LecturePLUS Timberlake 5

Temperature

Measures the hotness or coldness of an object

Determined by using a thermometer that

contains a liquid that expands with heat and

contracts with cooling.

LecturePLUS Timberlake 6

Temperature Scales

Fahrenheit Celsius Kelvin

Water boils _____°F _____°C ______K

Water freezes _____°F _____°C ______K

LecturePLUS Timberlake 7

Temperature Scales

Fahrenheit Celsius Kelvin

Water boils 212°F 100°C 373 K

Water freezes 32°F 0°C 273 K

LecturePLUS Timberlake 8

Units of Temperature between Boiling and Freezing

Fahrenheit Celsius Kelvin

Water boils 212°F 100°C 373 K

180° 100°C 100K

Water freezes 32°F 0°C 273 K

LecturePLUS Timberlake 9

Learning Check

A. Temperature of freezing water

1) 0°F 2) 0°C 3) 0 K

B. Temperature of boiling water

1) 100°F 2) 32°F 3) 373K

C. Number of Celsius units between the

boiling and freezing points of water

1) 100 2) 180 3) 273

LecturePLUS Timberlake 10

Solution

A. Temperature of freezing water

2) 0°C

B. Temperature of boiling water

3) 373K

C. Number of Celsius units between the

boiling and freezing points of water

1) 100

LecturePLUS Timberlake 11

Fahrenheit Formula

180°F = 9°F = 1.8°F 100°C 5°C 1°C

Zero point: 0°C = 32°F

°F = 9/5 T°C + 32

or

°F = 1.8 T°C + 32

LecturePLUS Timberlake 12

Celsius Formula

Rearrange to find T°C

°F = 1.8 T°C + 32

°F - 32 = 1.8T°C ( +32 - 32)

°F - 32 = 1.8 T°C

1.8 1.8

°F - 32 = T°C

1.8

LecturePLUS Timberlake 13

Temperature Conversions

A person with hypothermia has a body temperature of 29.1°C. What is the body temperature in °F?

°F = 1.8 (29.1°C) + 32 exact tenth's exact

= 52.4 + 32

= 84.4°F tenth’s

LecturePLUS Timberlake 14

Learning Check

The normal temperature of a chickadee is 105.8°F. What is that temperature in °C?

1) 73.8 °C

2) 58.8 °C

3) 41.0 °C

LecturePLUS Timberlake 15

Solution

3) 41.0 °C

Solution:

°C = (°F - 32)

1.8

= (105.8 - 32)

1.8

= 73.8°F

1.8° = 41.0°C

LecturePLUS Timberlake 16

Learning Check

Pizza is baked at 455°F. What is that in °C?

1) 437 °C

2) 235°C

3) 221°C

LecturePLUS Timberlake 17

Solution

Pizza is baked at 455°F. What is that in °C?

2) 235°C

(455 - 32) = 235°C

1.8

LecturePLUS Timberlake 18

Learning Check

On a cold winter day, the temperature falls to -15°C. What is that temperature in °F?

1) 19 °F

2) 59°F

3) 5°F

LecturePLUS Timberlake 19

Solution

3) 5°F

Solution:

°F = 1.8(-15°C) + 32

= -27 + 32

= 5°F

LecturePLUS Timberlake 20

Kelvin Scale

On the Kelvin Scale

1K = 1°C

0 K is the lowest temperature

0 K = - 273°C

K °C

K = °C + 273

LecturePLUS Timberlake 21

Learning Check

What is normal body temperature of 37°C in kelvins?

1) 236 K

2) 310 K

3) 342 K

LecturePLUS Timberlake 22

Solution

What is normal body temperature of 37°C in kelvins?

2) 310 K

K = °C + 273

= 37 °C + 273

= 310. K