Coordinate Geometry - Weebly...Coordinate Geometry Distance & midpoint Gradient Gradient of Parallel & Perpendicular Lines Area of Rectilinear Figures (Given vertices) Example Solution

Coordinate Geometry

Distance & midpoint

Gradient

Gradient of Parallel & Perpendicular Lines

Area of Rectilinear Figures (Given vertices)

Example

Solution

Circles & Curves

Circles

An equation given in the form of 02222 =++++ cfygxyx is known as the general form.

To find its centre C and radius r, 2 methods:

Method 1 Method 2

1. Find g and f Use “completing the square” to express

2. Use the formula: 02222 =++++ cfygxyx as

cfgr

fgCbaC

−+=

−−=

22

),(),(

cfgfygx

cfgfygx

−+=+++

=+−−+++2222

2222

)()(

0)()(

Hence, cfgr

fgCbaC

−+=

−−=

22

),(),(

To summarize,

Standard Form

In general, the equation of a circle with centre (a, b) and radius r is given as

222 )()( rbyax =−+−

General Form

In general, the equation of a circle with centre (a, b) and radius r is given as

02222 =++++ cfygxyx

Example

Curves

Example

Practice (Past Year Questions)

Linear Law

Example

Practice

Example