Atomic structure (part 1)

Post on 21-May-2015

133 Views

Category:

Education

4 Downloads

Preview:

Click to see full reader

DESCRIPTION

Introduction to the structure of atoms from the view of a chemist - what are neutrons protons and electrons and how are they organized ? How are electrons organized - in 3 quantum numbers. Experimental evidence from the Bohr model.

Transcript

ATOMIC STRUCTURE

Lesson by Dr.Chris

UP, May 2014

WHAT WE WILL LEARN … PART 1:

STRUCTURE OF ATOMS

The space is made up of electrons

The mass is in the core

ATOMIC SCALES

1 mm

ATOMIC MASS

1 atomic mass unit “amu” = 1/12 of the mass of 12C atom

The carbon-12 atom has a mass of 12.000 u, and yet it contains

12 objects (6 protons and 6 neutrons) that each have a mass

greater than 1.000 u, not to mention a small contribution from the 6 electrons.

MASS DEFECT

Mass of nucleus < sum of p + n + e !

Why ?

Some of the mass is converted to be the BINDING

ENERGY of the nucleus that holds it together ->

“mass defect”

For 12C:

Mass defect = Dm = 6 * 1.008664 u + 6 * 1.007276 u +

6 * 0.00054858 u - 12.000 u = 0.098931 u

The binding energy in the carbon-12 atom is

therefore 0.098931 u * 931.5 MeV/u = 92.15 MeV

(binding energies for electrons is just some eV !)

PROTONS AND NEUTRONS ARE NOT FUNDAMENTAL PARTICLES

ATOM SYMBOLS

Ne 20

10

Atomic number Z

= no. of protons = no. of electrons

Mass number A

= no. of protons + neutrons

EXAMPLES

How many protons, electrons and neutrons are in:

SOLUTION

Cl can have 18 or 20 neutrons

35.45 is a mix of 2/3 35Cl and 1/3 37Cl

Element number

= no. of protons = no. of electrons

Mass number, not integer !

=> mix of ISOTOPES with different no. of neutrons !

Z

A

ISOTOPES

Nearly all elements have isotopes,

that means the same elements

(no. of protons = Z) has different no. of

neutrons, and therefore different mass

Example:

Copper exists to 69.2% of 63Cu and the rest

of 65Cu with masses 62.93 and 64.93

what is the atomic mass of the mixture ?

ISOTOPES AND MS

Isotope patterns are important to identify

fragments in MS

For example:

***** BREAK *****

WHERE ARE THE ELECTRONS ?

3 kinds of spectra:

WHERE DO THE LINES COME FROM ?

Bohr (1913)

emission spectra of hydrogen gas

Lines correspond to energies that are emitted by electrons:

emitted

ELECTRONS ARE “FIXED” ON ORBITS !

Electrons can move between distinct

energy levels, they cannot exist just anywhere in the atom = quantum

THE HYDROGEN EMISSION SPECTRUM

Electrical charged hydrogen gas will emit a blue color and also UV radiation

QUESTION

How many lines in the emission spectrum and at which energies (in cm-1) ?

Solution: 3 levels 3 lines

Transition A:

∆E = E3 – E2 =

-20’000 + 50’000 cm-1 =

30’000 cm-1 =

λ = 1/30’000cm-1 * 107 nm/1 cm = 333 nm

We can express energy as wavenumber, because h and c are constant:

= const * 1/λ = const * ν

RYDBERG EQUATION

From which energy level does an electron

come to n=2 when visible light of 410 nm

is emitted ?

What is the Ionization energy of hydrogen from this formula ?

-1

ELECTRONS AS WAVES

Electrons can be regarded to be waves

instead of particles.

DeBroglie:

EXPLAINS WHY ELECTRONS CAN ONLY EXIST ON CERTAIN ORBITS

ENERGY OF “WAVE-ELECTRONS”

We can model the behavior of an electron

in a restricted area

(“particle in a box”)

Quantization comes from

the fact that a wave has

to “fit” into the boundaries

Only wavelengths are allowed:

Use in DeBroglie:

Therefore the kinetic energy is:

n is the main quantum number

indicating the energy level

3 QUANTUM NUMBERS

Because a particle is moving in 3D, we

also get 3 quantum numbers

n: main quantum number (start with 1)

l : angular “ ( 0,1 .. n-1)

m: magnetic “ ( -l … 0 … +l )

Electrons can live only in these “orbitals”

(spaces) defined by 3 quantum numbers

Up to 2 electrons can exist in one orbital

WATCH A DEMO VIDEO

http://www.youtube.com/watch?v=Fw6dI7cguCg

Main spectral lines = n

Fine structure = l

With magnetic field:

Zeeman effect

magnetic quantum no. m

QUESTIONS

How many orbitals are possible for the

energy level n = 2

and how many electrons can live there

maxium ?

n = 2

l = 0 and 1 (“s” and “p” level) m = 0 and -1, 0, +1 (px, y and z)

***** BREAK *****

Part 2:

ELECTRONIC SHIELDING AUFBAU PRINCIPLE (PERIODIC TABLE)

ELECTRON SHIELDING

The nuclear charge experienced by an electron is reduced by shielding by other electrons.

Trends in effective nuclear charge can be used to rationalize the trends in many properties.

As a result of the combined effects of penetration and shielding, the order of energy levels in a shell of a many electron atom is s < p < d < f

(Atkin p.16)

ELECTRON SHEILDING

Different from

Hydrogen, there are

electron-electron

interactions in the other elements

Each electron experiences an effective nuclear charge: Zeff = Z - σ

EXAMPLE LI (1S2 2S1)

The PAULI-EXCLUSION PRINCIPLE says

that no 2 electrons can have the same 4

quantum numbers (n l m and s)

=> the 1s orbital can not have 3 electrons,

but max. 2 (n=1, l=0, m=0, s= +/- ½)

=> The 3rd electron goes to the next energy level n=2, but now, into s or p level ?

LI ELECTRON CONFIGURATION

Because of the form

of the function of 2s

it has electron

density closer to the

nucleus than 2p

less shielding by

1s electrons

lower energy

Z EFF FOR LI ELECTRONS

The 2 1s electrons influence

each other and shield the pos. charge

The 2s electron experiences

the shielding by the 2

“inner” electrons very

strongly, but not as full 2 neg. charges

CONSEQUENCE FOR ALL ELMENTS

As a result of penetration and shielding,

the order of energies in many-electron

atoms is typically

ns < np < nd < nf

because, in a given shell,

s orbitals are the most penetrating and f orbitals are the least penetrating.

The order of energy changes at Ca – Sc !

SLATER’S RULES ZEFF = Z – S ESTIMATION OF S:

EXAMPLE: K – WHERE IS THE 19TH ELECTRON ?

HOMEWORK (PRESENT NEXT LESSON)

Calculate the shielding for the valence electron(s) of:

Ca compare 4s2 <-> 3 d2

Sc compare 3d1 <-> 4 p1

Cu (1) compare 4s1 <-> 4 p1

Cu (2) compare 3d10 4s1 <-> 3d9 4s2

Mn compare 3d5 4s2 <-> 3d7

Co (1) compare 3d7 4s2 <-> 3 d9

Co (2) compare 3d7 4s2 <-> 3d8 4s1

Cr (1) compare 3d5 4s1 <-> 3d4 4s2 Cr (2) compare 3d5 4s1 <-> 3 d6

Questions: explain

1. How shielding determines the AUFBAU

principle

2. trend of atomic radius in PT (left to right)

3. -”- ionization energies -- “ --

4. - “ - electronegativities -- “ –

top related