Announcements WebAssign HW Set 5 due October 10 Problems cover material from Chapters 18

Announcements

• WebAssign HW Set 5 due October 10• Problems cover material from Chapters 18

• HW set 6 due on October 17 (Chapter 19)

• Prof. Kumar tea and cookies Tuesdays from 5 – 6… pm in room 2165

• Exam 1 statistics average 12.78

stand. dev. 3.51

QUESTIONS? PLEASE ASK!

From last time Magnets and earth’s magnetic

Magnetic Fields:

Units are T = N/A.m Use right hand rule to determine

direction of force

Force on a wire: F = B I L sin θ

Continuing Forces and torques

on current carrying wires and loops.

On moving charges. Magnetic Fields and

Amperes law. Forces between two

current carrying wires. d

sinsin

Torque on a Current Loop Torque t = B I A N sin q

Applies to any shape loop N is the number of turns in the

coil Torque has a maximum value

of NBIA (when q = 90°) Torque is zero when the field is

parallel to the plane of the loop

Magnetic Moment m = IAN m is a vector Torque can be written as

t = mB sinq

Example Problem 19.31

A long piece of wire with a mass of 0.100 kg and a length of 4.00 m is used to make a square coil with a side of 0.100 m. The coil is hinged along a horizontal side, carrying a 3.40 A current, and is placed in a vertical magnetic field of 0.010 T. (a) Determine the angle that plane of the coil makes with the vertical when the coil is in equilibrium. (b) Find the torque acting on the coil due to the magnetic force at equilibrium

Electric Motor

electric motor - converts electrical energy to mechanical energy The mechanical energy is

in the form of rotational kinetic energy

An electric motor consists of a rigid current-carrying loop that rotates when placed in a magnetic field

Electric Motor

Torque acting on the loop will rotate the loop to smaller values of θ until the torque becomes 0 at θ = 0°

If the loop turns past this point and the current remains in the same direction, the torque reverses and turns the loop in the opposite direction Bad!!

Electric Motor

So, we need to be clever…

To provide continuous rotation in one direction, the current in the loop must periodically reverse In AC motors, this reversal

naturally occurs In DC motors, a split-ring

commutator and brushes are used

Actual motors would contain many current loops and commutators

Force on a Charged Particle in a Magnetic Field

Consider a particle moving in an external magnetic field so that its velocity is perpendicular to the field

The force is always directed toward the center of the circular path

The magnetic force causes a centripetal acceleration, changing the direction of the velocity of the particle

Force on a Charged Particle

Equating the magnetic and centripetal forces:

Solving for r:

r is proportional to the momentum of the particle and inversely proportional to the magnetic field

Sometimes called the cyclotron equation

Particle Moving in an External Magnetic Field

If the particle’s velocity is not perpendicular to the field, the path followed by the particle is a spiral The spiral path is

called a helix

A cosmic ray proton in interstellar space has an energy of 10 MeV and executes a circular orbit having a radius equal to that of Mercury’s orbit around the Sun (5.8 x 1010 m). What is the magnetic field in that region of space?

Solution to 19.31

Solution to 19.42

A cosmic ray proton in interstellar space has an energy of 10 MeV and executes a circular orbit having a radius equal to that of Mercury’s orbit around the Sun (5.8 x 1010 m). What is the magnetic field in that region of space?

Magnetic Fields – Long Straight Wire

A current-carrying wire produces a magnetic field B Right hand rule # 2 to

determine direction of B

Magnitude of B at a distance r from a wire carrying current of I is:

µo = 4 x 10-7 T.m / A µo is called the permeability

of free space

Ampère’s Law: General relationship between I in

an arbitrarily shaped wire and B produced by the wire:

B|| Δℓ = µo I

Choose an arbitrary closed path around the current

Sum all the products of B|| Δℓ around the closed path

Ampère’s Law Applied to a Long Straight Wire

Use a closed circular path

The circumference of the circle is 2 r

This is identical to the result previously shown

Two long parallel wires separated by a distance 2d carry equal currents in the same direction. The currents are out of the page in the figure. (a) What is the direction of the magnetic field at P on the x-axis set up by the two wires? (b) Find an expression for the magnitude of the field at P. (c) From (b), determine the field midway between the two wires.

Magnetic Force Between Two Parallel Conductors

The force on wire 1 is due to the current in wire 1 and the magnetic field produced by wire 2

The force per unit length is:

Parallel conductors carrying currents in the same direction attract each other

Parallel conductors carrying currents in the opposite directions repel each other

Magnetic Field of a Current Loop

The magnitude of the magnetic field at the center of a circular loop with a radius R and carrying current I is

With N loops in the coil, this becomes:

Magnetic Field of a Solenoid Solenoid – long straight wire is

bent into a coil of several closely spaced loops

Electromagnet - acts like a magnet only when it carries a current

B field lines inside the solenoid are nearly parallel, uniformly spaced, and close together B is nearly uniform and strong

The exterior field is nonuniform, much weaker, and in the opposite direction to the field inside the solenoid

Magnetic Field in a Solenoid, Magnitude

The magnitude of the field inside a solenoid is constant at all points far from its ends

B = µo n I n is the number of turns

per unit length n = N / ℓ

The same result can be obtained by applying Ampère’s Law to the solenoid

A certain superconducting magnet in the form of a solenoid of length 0.5 m can generate a magnetic field of 9.0T in its core when the coils carry a current of 75 A. The windings, made of a niobium-titanium alloy, must be cooled to 4.2K. Find the number of turns in the solenoid.

Solution to 19.42

Solution to 19.54

Solution to 19.60

Announcements WebAssign HW Set 5 due October 10 Problems cover material from Chapters 18

vertical magnetic field

coil torque

loop magnetic moment

current looptorque t

square coil

direction of force force

sin continuingforces

number score

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