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Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3 Objective: SWBAT perform stoichiometric conversions from mole to mass, from mass to mass Catalyst: How many basketballs are in a dozen? How many turkeys are in a dozen? How was your break? *This week… bring scientific calculators if you have them!
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Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

Jan 23, 2016

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Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3. Objective: SWBAT perform stoichiometric conversions from mole to mass, from mass to mass Catalyst: How many basketballs are in a dozen? How many turkeys are in a dozen? How was your break? - PowerPoint PPT Presentation
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Page 1: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

Stoichiometry and the mole- Your new bfflNovember 22+33-1, 2.009 * 103

Objective: SWBAT perform stoichiometric conversions

from mole to mass, from mass to mass

Catalyst: How many basketballs are in a dozen? How many turkeys are in a dozen? How was your break?

*This week… bring scientific calculators if you have them!

Page 2: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

Exit Question

What do you need to do to get where you want to be in this class?

Page 3: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

Agenda

Catalyst/Welcome Back Test Review/Tracking/Corrections OMG! YOUR NEW BFFL! The mole. Bring back the train tracks Exit Question

Page 4: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

What is a mole to us chemists? A benign overgrowth of cells because of

a failure in mitosis? NO! But gross… A rascly little rodent? NOOOO! A TV show featuring celebrities? NOOOOO! Then WHAT IS IT?????!!!???!?!?!???!!!!

Page 5: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

The Mole

Think of the term “a dozen”…

How many donuts are in a dozen?

How many eggs are in a dozen?

Page 6: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

The Mole

Just like a dozen refers to 12 objects…

Page 7: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

The Mole

Just like a dozen refers to 12 objects…

… the mole refers to …

Page 8: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

The Mole

Just like a dozen refers to 12 objects…

… the mole refers to …

6.02 x 1023

particles

Page 9: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

The Mole

This number is called Avogadro’s number…

6.02 x 1023

602,000,000,000,000,000,000,000

Page 10: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

Avogadro’s Number

1 mol = 6.02 x 1023 atoms

1 mol = 6.02 x 1023 molecules

Why do YOU think we would do this?

Page 11: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

Interpreting Equations

4 Fe + 3 O2 2 Fe2O3

“4 moles of iron react with 3

moles of oxygen gas toproduce 2 moles of iron(III)

oxide”Coefficients in chemical

reactions just refer to how many moles are reacting!

Page 12: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

Interpreting Equations

C3H8 + 5 O2 3 CO2 + 4H2O

“1 mole of propane (C3H8)reacts with 5 moles of oxygen

gas to produce 3 moles of carbon

dioxide and 4 moles of water”

Page 13: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

How many moles needed?(moles – moles)

C3H8 + 5 O2 3 CO2 + 4H2O

If you start with 10.0 molesof propane (C3H8), how many

moles of oxygen gas is neededto fully combust (react)?

Page 14: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

How many moles produced? (moles – moles)

C3H8 + 5 O2 3 CO2 + 4H2O

If you start with 10.0 molesof propane (C3H8), how manymoles of carbon dioxide will

be produced?

Page 15: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

What’s the point of all this?

Key Point #1:Stoichiometry relates the amount of REACTANTS with the amount of PRODUCTS. It all relates back to the mole…

Scientists use stoichiometry to plan reactions! And guess what else is coming back….

Page 16: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

TRAIN TRACKS!!!

Step 1: What to what?

Step 2: Write conversion factor(s)

Step 3: Train tracks

Page 17: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

Avogadro’s Number

1 mol = 6.02 x 1023 atoms

How many atoms are in .25 mol N2?

Page 18: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

Avogadro’s Number

1 mol = 6.02 x 1023 atoms

How many atoms are in .25 mol N2?

.25 mol N2

Page 19: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

Avogadro’s Number

1 mol = 6.02 x 1023 atoms

How many atoms are in .25 mol N2?

.25 mol N2

1 mol N2

6.02 x 1023 atoms

I guess you can use your calculator for this…

Page 20: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

Your turn! Whiteboards.

How many atoms are in 1.1 moles of C12H22O11?

Page 21: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

OOOH, I want some more train tracks! Key Point #2:

Molar mass the amount of grams in the mole of a substance.

But Mr. J, how am I ever going to find out this information?

Page 22: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

Molar Mass

1 mol C =

Page 23: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

Molar Mass

1 mol C = 12 g C

Page 24: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

Molar Mass

The atomic weight of an atom is also the molar mass of that atom.

Carbon has an atomic weight of 12.01.

In 1 mole of carbon, there are 12.01 grams.

In 1 mole of sodium, how many grams are there?

Page 25: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

Molar Mass

1 mol Na =

Page 26: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

Molar Mass

1 mol Na = 23 g Na

Page 27: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

Molar Mass-Can you figure out this one??

1 mol CO2 =

Page 28: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

Molar Mass

1 mol CO2 =

C = 12 g O = 16 gO = 16 g

Page 29: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

Molar Mass

1 mol CO2 =

C = 12 g + O = 16 g + O = 16 g

Page 30: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

Molar Mass

1 mol CO2 = 44 g CO2

C = 12 g + O = 16 g + O = 16 g

Page 31: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

Molar Mass

1 mol KNO3 =

K = + N = + O =

Page 32: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

Molar Mass

1 mol KNO3 =

K = 39 g + N = 14 g + (3) O = 16 g

Page 33: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

Molar Mass

1 mol KNO3 = 101 g

K = 39 g + N = 14 g + (3) O = 16 g

Page 34: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

Molar Mass- Let’s try a problem

1 mol KNO3 = 101 g If we have 3.5 moles of KNO3, how many

grams would we have?

Page 35: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

Molar Mass

1 mol CH4 =If we have 20 grams CH4, how many

moles of CH4 do we have?

Page 36: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

Independent Practice

1, 11, 16… we will go over to show you how to solve this hilarious assignment!

Attach your work on a separate sheet of paper.

Page 37: Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3

Exit Question

How many molecules are in a mole of NH4?

How many grams are there in 2.3 moles of NH4?