Staad Pro Advanced Topic

7/28/2019 Staad Pro Advanced Topic

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Advanced Topics inSTAAD.Pro

S! tley Institute


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STAAD.Pro

TRAINING MANUALADVANCED TOPICS

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S1 A D . l ' > o i '"'l< of , o p " < l " ~ CO"'P"'" P"'I""" orRt . . . EO"O N " . B 'i.o'oI io en'" Ahbo"8b ,. trr ... bl. "'.0 ",.d. '" ,.,. t l o ~ . " " ,.. .e . of ..........08 ' . . . . . REI ",iU.o, ocr'p' "'po .. " " ~ for .. ""lOU."'0' 0, .. "..p . . . . . . ,"" io 0' ' ' ' re, ." of ,b t . " 8 ' of,b. . . P"'8 . . . .

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About STAAD.Pro

"AAD,P ,o i . , " " , , , 1 P"' ' ' ' ' ' ' "">", ' ' ' ' ' '; '1 . ,d optimlutio, o t . k


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About the STAAD.Pro Documentation,b, do, ," , , , , , t , ," , , fo , " AAD, Pro


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Table of Contents

~ I o d < h n g Frobl


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Zero StiffnessI..


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Question

Ans wer

Wh . l dO


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,In , SPACE r" m. ,ttuctut< , conntiolll morh . mod


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Understanding Instabilities


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Que s l io n I hne imtability ",uning m< ag in m}' output fil< lik< that,hown b


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, _________________ ''','00',0,.0''''.'..'',.,,'',-"',__,,_,.,'-,0,0,'0m


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____________________________________________________________ ' ' ' ' ' ' " " , ' , ' ' , . , ' . , , . , ' ' " ! ! " " ~ " . " " . , ' !O,.!.. ,

in ord" fur the abo," 1 of


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. " , , ' " ' " O " " " O c " " _ ~ ' " " " " ' ~ ~ " " " _ ' _ ~ " " " ' ~ ' - - - - - - - - - - - - - - - - - l ,O\-.r1al1'ing m


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m


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. .,.'",o o ,o ..." . o , ~ . _ ''''__o .' ' ~ , . , o _________________________________________________________

Ques tion

A ns we r

If th"r< u e imtab ility m. "'"S" -do it m.on my rul t ,rna}' b< un,i,fact0f)"Th


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Ques tion

Answe r

' UAD ,h . T' ' ' ' ' '.. " .... _ d ,- .."d To,, , .~Som


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" 'TOTA L APPL IED L OAD ( K G METE ) SUMMARY ( LOADING"UMMATION FORCE-X = 0.00SUMMATION FORCE-Y = -8 17.84SUMMATION FORCE-Z = 0.00SUMMATION OF MOMENTS AROUND TH E ORIGlNMX= 291.23 MY= 0.00 MZ= -3598 .50

'TOTA L REACTION LOAD ( K G M ETE ) SUMMARY( LOADING 1 )SUMMATION FOACE-X = 0.00SUMMATION FORCE-Y = 8 17.84 ~SUMMATION FORCE-Z = 0.00SUMMATION OF MOMENTS AROUND TH E ORIGINMX = -291.23 MY = 0.00 MZ= 3598.50

MAXIMUM DISPLACE M ENTS ( eM IRADIANS ) ( LOADING 1)MAXIMUMS AT NODEX = 1.00499 -04 25Y = -3.1 8 980 -0 1 12Z = 1.1 8670-0 2 23AX = 1.52986E-{)4 5RY = 1.22373E-{)4 23RZ= 1.07!l35 -03 8

Go through ,II


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r------------------"""',o"".-'.,""""..,,"", ""'--""'"00"""""""..Que s t io n What j, the m


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'TAAD .ho T"." ' ' '1 " .... A .v""'; T'1' ' ' '

For uampl


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"

Question

Answer

R


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[ f the imabih,,. i . at the Ju t join! [or


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Seismic Analysis UsingUBC And IRC Codes


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8u i c principl5; 0.0625 0.2941:0.07690.3479; 0.0833 0.3713;

r----------------- . r C ' c ' c o " " ' ~ ' o ' r " " ' " ' ' " ' " ..,""'-c""'u --'"'_r.O".c..0.1 0 .3113 ; 0 .1 25 0 .3713 ; 0 .1667 0.371 3 ; 0 .18950 .3713; 0 .25 0 .21115; 0.2857 0.2463 ;


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Question

0.3333 0.2111 ; 0.4 0 .1759 ; 0.5 0.1407 ; 0.6667 0 .1056 ;1 0 .0704 ;..2 0 .03 44 ; 10 0 .00 1312 ;

Coni

Answer: Yo. .Q u e s t ion : Con [did< hew man}' moo I wont to include in the ; :'>IOOi l weight i , the 'oul weight actu.:JI,.m


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Answe r When the weight of the bui lding j , ac l

a wh en the numb


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Question

Answe r

Question

Alt


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Ques tion

A nswe r

Ques tion

A nswer

"action print


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-( ' ,I""od) ' ) n l " ' q ~ . n "1"'" p u ~ lu 'pu ,,,bpu, " ' ' ' - ' I ' U ~wnn,>d, .mod"" u, .n l ' ,1 lInn, ,nd,n" I'np'-"pu, ,_",13

. : n " ' l 01 tnno" PI"0J uo,,""P X .q l u, u o n ~ ' H l 'qo19 [Rl0 l 'q l 0'1' IOU"uo , , " "P X 'I{! u, a ' q ' .nq 1'1'" ' ' ! 1 ' q , ~ punn "m u, '' In , nf

01 iu , ,"" ' ' ' ' ' I lnq -Jo{D ' " SSlIS I>I{!f'> u. W'I{! ,wn, ,J1u.nb"qn,p u ~ >pOW q ~ . 'OJ u o , , ~ . , , '>.-II'" OW.IS l 'ql &U"lU!l11

m,1 - . n , P'''I ,,,,au,,p 'I{! 'OJ u o n " " p ~ ' I { ! u, uon" " 1'' ' ' ''I{! 01 dn PP ' IOU ""P " " " " P ~ ' I { ! U'"H,!, "''1 [RlOl 'I{! VP"'W

P ' q ' ~ l l ~ ' I { ! 00 -' Idunn '''01 '1Uon,ull uoddns 1''1019 'q l p u ~".,'!' .n q 'I{! U ' ~ l > q d'qmon'I '" ''!1 > l ~ I ' 1 . I O ' '" lIt",iIl ua IP"'I{!>W SSlIS 'I{! 01 p ,ad"" , ' " " row .,0l{! JO ,mod",

'I{!"l'ldna 1[,," P"'I{!>W Jo{D 'I{! " " I ',IU"" , ~ d , . ,0 i ' IO j-,nqd u, ,' I " n u " , , . . , n ~ ' un

, .uod" , nlo'q"I{! 01 " , , , [ ' , , ~ o - , d d , J a n'I{! "I{! ' ' ' ' '[''1I - ' In" , SSlIS 'I{! Iml{! I>qil'q q ,nw" lIn" , wn, > l n l " ' q ~ >111

,W>t'lo,d ,'= UI "I{! ou I l " ~ no.\ ->lIIn >w


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Support'! :'>1000 1 :".100< 2 Sum of Squa. . < SqUOI< root

Reaction R


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4. 30_1136;4 .8 0 .0911; 6 0 .0583; 7 0_0429; 8 0 .03211; 10 0.021; 20O.oosa ; 30 0 .0023;

SPECTRUM SRSS Z 1 Ace SCALE 0_9806 DAMP 0.05C.03 0_8702; 0.05 ' .0 752 ; 0.1 1.5876; 0.15 2. 1; 0_3 2.1 ; 0 .52 .1 ; 0.71.5;0 .9 1.1687 ; 1.1 0_954 5; 1.3 (UI077 ; 1 5 0.7; 1.7 0 .6176 ; 1.90 .5526 ;2.1 0.4762; 2_3 0 .397 ; 2 .5 0_336; 2.70 .2881; 2 .9 0.2497; 3 . 10 .2 185 ;3_30.1928 ; 35 0_171 4 ; 3.7 0.1534; 3 .9 0.1381; 4. 1 0.1249;4.3 0 . 11 36 ;4.8 0 .0911 ; 6 0 .0583; 7 0 .0429 ; B 0 .Q328 ; 10 0.021; 200 .00 53 ; 30 0 .0023 ;

SPECTRUM SRSS X 1 Z 1 Ace SCALE O.980S DAMP 0 .050 .03 0_B702; 0.05 1.0752 ; 0.1 1.5876; 0 .2 2.1 ; 0_3 2 .1 ; 0 .52 .1 ; 0 .7 1.5;0 .9 1.1 687 ; 1. 1 0.954 5; 1.3 0.8077 ; 1 50.7 : 1.7 0 .6176 ; 1.90 .5526 ;2.1 0 .4 76 2 ; 2 .3 0.397; 2 .5 0.336; 2. 70 .2881; 2 .9 0.2497; 3 . 10.2185;3 .3 0 .1928 ; 3.5 0.171 4: 3.7 0 .15..34 ; 3 .9 0 .1381; 4.1 0.1249 ;4.30.1136 :4.80 .0911 ; 6 0 .0583 ; 7 0 .0 4 29 ; 8 0 .0328 ; 100 .021; 200 .005..3 ; 30 0 .0023 ;Lo.ul combination S i , III SRSS of 1 & 2.LOAD COMB lNAT lON SRSS 5 Uberlagerung

'TAAD.h . T" .Lh I " .... A'""" T'1' ' ' '

11 .021 .0

Should load cu . S produce th. nIn< .",w


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Answer Load ca I mcting in the Z direction at aniIll


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Time History analysis of a structurefor. .seismic a c ~ ~ e l e r a t i o n s

Time hi


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Th< input which i , r


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0.0000 0_00f.30000200 0_0036400()40Q 0_000990O,OWO O.00428{)Q_OBOO Q,00758llQl000 O,Q1087QWltil. it rno,. not b< 'pp.,,


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a. load. which will ,.;old th. rnn , \,u u ~ " i c h will popubt c1a,,;cill}' when tho < > a d c a u < i n ~unit, IDOl" on tho


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Odin in , 'be input dataTh


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Th. bu" for

Que s t io n : I want to mol ', a cune oIong a burn How do [ me ,h . mljngload g


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\'alu< 10 lOro

Ques t i on Coold you 1


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Que s t io n: i< thor< OIl}' n}' to g


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..,AXLTYP2

""'".,


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Pressure loads on panels - Floor loads

Que s l i o n I om modeling a ,11 building comin ing of column< ODd burn ,Th< floo r ,lab j, onon - ' t ructuul ctinS on it . j, not m.OIl! 10 be an int.gral pmof the homing '} '1


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Answe r:

ThI< uniform or.> load , on tho floor (think of the lo.d uwood.n pill." ,upP""ting box ofpopul . Sine< the


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manui!.

Question

Answer

A,. thOle an}- graphicil tool< 10 uornin< the indi,';duil 1'.,,


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rna)' uk< ::\!


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Answer

1 tl


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ZfVV.KiE -0 .1 8.1YRANGE 11.9 12. 1 FLOAD - 0.35 XRA/lKiE 4.9 10 .1ZRANGE -l .9 16 .1

~ - - - + - - - + - - - ~, T '., 'W ,,,~ '. ~ "'. '. '"~ '" '"11 " ",

,


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Wind load generation

O.riptionWind load g


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til< Thnicil Ref


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LOAD lOWSB..FWBGHTY-l.LOAD 2_0WIND LOAD X-l. TYPE 1LOAD 3 _OZWIND LOAD Z ~ T Y I ' E ,___Th< "ond pa n of the command com;" , of the actual]"adapplication ODd i t done through th< Wr-;D LOAD command uthown abo,"

Que 51 io n What i t the ' a cr


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Question

A nsw er

00


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Hpod or.> j, p.,-i1I


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Answer Th< commond , , 'ntH accommodat ill of tho abo," For


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b < ' ~ ~ < n m

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