Rotational Diffusion and Viscosity of Liquid Crystals E.M. Terentjev M.A. Osipov (~1988) C.J. Chan (~2002) Department of Physics
Dec 21, 2015
Rotational Diffusion and Viscosity
of Liquid Crystals
E.M. Terentjev
M.A. Osipov (~1988) C.J. Chan (~2002)
Department of Physics
Today:
• Summary of the continuum Leslie-Ericksen approach to nematic viscosity: symmetry and basic physical features• Summary of the continuum Leslie-Ericksen approach to nematic viscosity: symmetry and basic physical features
• Building the Microscopic theory of continuum linear response:general principles and available options
• Summary of the continuum Leslie-Ericksen approach to nematic viscosity: symmetry and basic physical features
• Building the Microscopic theory of continuum linear response:general principles and available options
• Part 1 – Mean-field Microscopic Stress Tensor, from first principles, examine rod-like and disk-like limiting cases
• Summary of the continuum Leslie-Ericksen approach to nematic viscosity: symmetry and basic physical features
• Building the Microscopic theory of continuum linear response:general principles and available options
• Part 1 – Mean-field Microscopic Stress Tensor, from first principles, examine rod-like and disk-like limiting cases
• Part 2 –Kinetic theory of rotational diffusion: a) from stochastic Langevin to kinetic Fokker-Planck
formulationb) eliminating fast variables (velocities) – Smoluchovski
equationc) equilibrium case – spectrum of rotational relaxation modes
• Summary of the continuum Leslie-Ericksen approach to nematic viscosity: symmetry and basic physical features
• Building the Microscopic theory of continuum linear response:general principles and available options
• Part 1 – Mean-field Microscopic Stress Tensor, from first principles, examine rod-like and disk-like limiting cases
• Part 2 –Kinetic theory of rotational diffusion: a) from stochastic Langevin to kinetic Fokker-Planck formulationb) eliminating fast variables (velocities) – Smoluchovski equationc) equilibrium case – spectrum of rotational relaxation modes
• Part 3 – Solving non-equilibrium kinetic equation:a) the “Doi trick”b) antisymmetric stress tensor
• Summary of the continuum Leslie-Ericksen approach to nematic viscosity: symmetry and basic physical features
• Building the Microscopic theory of continuum linear response:general principles and available options
• Part 1 – Mean-field Microscopic Stress Tensor, from first principles, examine rod-like and disk-like limiting cases
• Part 2 –Kinetic theory of rotational diffusion: a) from stochastic Langevin to kinetic Fokker-Planck formulationb) eliminating fast variables (velocities) – Smoluchovski equationc) equilibrium case – spectrum of rotational relaxation modes
• Part 3 – Solving non-equilibrium kinetic equation:a) the “Doi trick”b) antisymmetric stress tensor
• Final steps: Leslie coefficients – limits of rod- & disk-like nematic; smectics; experiment
• Summary of the continuum Leslie-Ericksen approach to nematic viscosity: symmetry and basic physical features
• Building the Microscopic theory of continuum linear response:general principles and available options
• Part 1 – Mean-field Microscopic Stress Tensor, from first principles, examine rod-like and disk-like limiting cases
• Part 2 –Kinetic theory of rotational diffusion: a) from stochastic Langevin to kinetic Fokker-Planck formulationb) eliminating fast variables (velocities) – Smoluchovski equationc) equilibrium case – spectrum of rotational relaxation modes
• Part 3 – Solving non-equilibrium kinetic equation:a) the “Doi trick”b) antisymmetric stress tensor
• Final steps: Leslie coefficients – limits of rod- & disk-like nematic; smectic; experiment
• The missing link: translational part of viscosity…
Leslie-Ericksen continuum
Balance of local forces (stress) and local torques (nematic):
0)(
)(
)(
)(
n
ST
n
L
0)(
)(
)(
)(
u
ST
u
L
],,,[221 EnnFdL uux
],[ ux nRdST Lagrangian
Entropy production
Potential energy: Frank elasticity Order-parameter expansionSmectic (n-layer coupling)Gels (n-elastic matrix coupling)
Dissipation function: friction arising from relative motion of fluid and internal variable n(Q: symmetry criteria?.. A: assign a dissipation to each principal deformation mode)
)])([()])([(
)]([4][2)(
22
121
25
24
21
nnn
nnAnnAnnAR
dtd
dtd
Linear nematic viscosity (Leslie-Ericksen): strain rates + n-rotation rates
Here: DT )(21 uu
W ucurl21 ][ nn Relative to
)])([()])([(
)]([4][2)(
22
121
25
24
21
nnn
nnAnnAnnAR
dtd
dtd
)])([()]([
)]([4][2)(
22
121
25
24
21
nnDnD
nnCnnCnnCF
Viscous flow:
Elastic deformation:
Symmetry: 3 flow geometries
G. D. V.
n nn
)(
)(
54221
64321
421
c
b
a
)2(
)(
65481
5
441
4
654121
1
A
A
A
221 )( n KFFrank elasticity: Penalises local torques… balanced by boundaries
or by viscous torques (antisymmetric visc.stress)
Balance of forces:
Balance of torques:
elastvisc)( uuu
Assuming , non-dimensional number: K
vL
nK
v ~
)(
)(r
2
E
)])([()])([(
)]([4][2)(
22
121
25
24
21
nDnn
nDnAnDnAnDnAR
dtd
dtd
Viscous flow:
)()]([][ 212 DKI dt
ddtd nωΩnnnn
Anisotropic continuum with linear friction
Improvements• Qij theory (Sonnet & Virga)• Flow with n-gradients
• Compressible medium (acoustics)• non-Newtonian (beyond G*=C+iA)
>>1
Microscopic Theory of Viscosity
General scheme: 1) Determine the Microscopic Stress tensor, M, from local molecular dynamics2) Identify the kinetic (Fokker-Planck) equation for ensemble in flow3) Solve is to find the (non-equilibrium) molecular distribution function4) The answer:
Macroscopic (continuum) stress tensor
vdvP ),()(σM
What about classical isotropic liquids?
ijijjiij Pvv
This requires a lot more complicated theory than is possible in liquid crystals, where the orientational mean field allows to capture all anisotropic effects – and relative values of all Leslie coefficients (if nematic).
However, no mean-field theory will ever determine the isotropic viscosity: the only constant that would survive if Q=0; This requires the full pair-correlation
function description of molecular distribution.
Bits of history: 1975-1982 Diogo-Martins 1978 Tsebers 1982 Marucci
1980-1983 Kuzuu-Doi
1989-1991 Osipov-TerentjevChrzhanovska-SokalskiFialkowski Kroger1990-1995 S.T. Wu (expt)
MarucciSemenov
Larson
Microscopic Stress tensor
a
“Number” density
)()(
rxx
r
),()()()( 2 rrxrrxrrx Ox
…formally expanding in powers of r
r
r
N
1
)()(
rrxx
N
m1
)(][)(
rrxrωvxp
Momentum (rigid body rotation)
Mσ)(
dt
d xpDefinition:
)()(][)(][)(1
rrxrrrωvrrxrωrωvxp
mmN
…evaluating the t-derivative
…we obtain the translational and the orientational parts of M:
)()]()()()([
)()][)(][σ
21112
''
'21M
rxIΓIΓIIωIωωIωI
rxFrrxvv
Tr
m
Uniaxial particles; Uniaxial mean-field
kiikik aaIII )( || Ia
a
Ellipsoid: p=a/b2
52
||22
51 );( mbIbamI
),,()( '''
aarrrΓ
Ua
ak
jijkiAlso: the torque
Finally (only orientational part):
)(]1
1
1
1
1
))((1
1[σ
2
2
22
2
22
2M
rxa
aaaaaa
a
aaaωωaaωaω
U
p
pU
p
U
p
p
Ip
p
Averaging over (fast) angular velocity distribution gives the “kinetic” part of M
(which is the momentum flux due to motion of molecules, in contrast to the “potential” part of M representing the flux due to intermolecular forces.
)()(1
13 3
12
2
rxδaa
p
pTkB
In a dilute gas, e.g. a solution of rod-polymers, the kinetic part, M=3kBT(aa1/3), is the main contribution; but in a dense molecular liquid – the potential part is dominant.
Cylinder: p=a/b2
21
||22
121 );3( mbIbamI
Equilibrium is, of course:
Tk
U
BeP)( na
Non-equilibrium distribution functionMean-field kinetic theory
Full Fokker-Planck description with sources (velocity gradients) is reduced due to two-step relaxation feature: the distribution of velocities relaxes much faster to the Maxwell-like form with the mean avavaaΩ )curl(curl)( 2
121
1
121
2
2
D
p
p
12
ITkB
a Tk
D BrotSeparation of time scales is assured:
The reduced Smoluchowski equation (for pdf only dependent on coordinates)relaxes much slower to the steady state; dissipation and effective friction forces during this relaxation is the main source of viscous response in dense liquids.
]))(curl[(])[(
)()(
||22
2
PI
IP
PTk
PPP
aaaa
Baaat
aΩva
ΓΩ
)( na MFaU
From stochastic (Langevin) to kinetic (F-P)
Full angular velocity of uniaxial object: ωaΨ ψ ωaL II IIψ
Equation of (rotational) motion: ΓΩωaωaψaL )ψ(ψ |||| III
)ψ(ψ
)()(),,,ψ( P-P-P-tPt
ωω
aa
aω
PI
PI
aξξaaaξξaaωω 22
2
2||
2 1
ψ)()(
1
aaξξ TkTk BB )(22 ||
)]([)( PI
PP at
Γaa
ωω
PI
TkP
IP
IP
I
TkP
IBB
ψ2
1)curl-ψ(
ψ)(ψ)(
2
1)(
||21
||
||||
vaaωaa
ωΩω
ω
Arrive at full F-P equation for rotational motion:
Eliminating fast variables Integrating out and
ψ ω
1) Ignore the relaxation of (too fast):ψ
),,(~
221 )curl-ψ(
2 tPeP Tk
I
B
II
ωava
Put in and integrate over ψ
),(~
2)-(2 tPeP Tk
I
B aΩω
Naively: and integrate over
2) Ignore the relaxation of (faster than the coordinate a):ω
ω )( PP at Ω (?!)
Substitute to F-P, only retain leading terms in <<1 and expand in powers of small deviation , matching the terms of the same order gives Y(a, ). THEN integrate over …..ω
)]([)( PI
PP at
Γaa
ωω
P(I
PI
TkP
IB )()curl
2)(
2
1)( || aωvaaa
ωΩω
ω
Diffusive corrections to the coordinate-only kinetic equation arise from the last bits of non-relaxed Maxwell distribution:
])-[,()(),(~
2)-(2 Ωωaa
Ωω
YtPePa
Tk
I
B
Solving the F-P equation
)( na MFaU
])[(]))(curl[( 2||2 PPI
Iaaa ΩΩaΩva
Spectrum of rotational relaxation modes: eigenfunction expansion in equilibrium fluid
),()( tPPt aa )()(1
0 aa n
t
nn wecwP n
)][()( 12 PUPPP MFaTkaaat B Ω
n aTkU BMFew /)(
0 )( aLook for solutions in the form… then
)()()( 0 aa wfw nn
nn
nMF
B
n ffU
Tk
f
22
2 11cot
nTk
U
Tk
Uf
ee BB sinsin
1)()(
Gives self-consistent integral equation for wn
0 0
)(
2
)(
sin)(sin
11)(
x
nTk
xU
n
Tk
U
n dzzzwdxex
Cew BB
2sin)( JSMFU na
Equilibrium relaxation time(s)
Could only solve by expansion to leading order in the smallest non-zero eigenvalue [] (i.e. the longest relaxation time ):
0 0
)()(
12
)(
sinsin
111)(
x Tk
zU
Tk
xU
Tk
U
n dzzedxex
ew BBB
...11
)( 2
2
121
120
wwwwn
Condition of periodicity states: w()=w()=const (of order 1 for normalized w) gives:
1sinsin
110 0
)()(
12
x Tk
zU
Tk
xU
dzzedxex
BB
The longest relaxation time [of diffusion over the orientational barrier U() ]:
2sinJSUMF
0 0
)()(
1 sinsin
1 x Tk
zU
Tk
xU
B
dzzedxexTk
BB Take limits: S0 and S1
2sinJSUMF
Felderhof, and many others… (1989-now)
...)1(1 Tk
JS
Tk BB
S0 Tk
JS
B
B
BeJS
Tk
Tk
2/3
1
S1
Solving the non-equilibrium F-P eq.
In order to calculate the ensemble average of microscopic stress tensor M in a system with flow gradients, we need to find the correction to equilibrium pdf
P(a,,t) }{)()(3eq.3
1 pressureconstTkB
rxδaa
}{0)()(eq.
symmetryU
rxnaa a
])[(]))(curl[( 2||2 PPI
Iaaa ΩΩaΩva
)][()( 12 PUPPP MFaTkaaat B Ω
It turns out that there is no need to average the symmetric part of M (there is a “trick” allowing its direct evaluation). To average the antisymmetric part, describing the torques, we may only consider the t-dependent rotation of n (without any ~ v).
Symmetric part of <M>: ),(
~21
31
2
2
sym
M 2)(31
1σ
tP
B
UUUTk
p
p
aa
aaaaaa
aδaa
)][()( 12 PUPPP MFaTkaaat B Ω
)( 31 δaa Multiply by …and integrate da
WWDDDp
p
tSHL
aaaaaaaaaaaaδaa 21
2
2
21
31 :2
1
1...
WWDDDp
p
tSHL
aaaaaaaaaaaaδaa 21
2
2
21
31 :2
1
1...
UUUTk
SHRB
aaa aaaaaδaa 21
6... 31
aaaaaav ;;(1
12
2
2symGQ
tp
pTkBM
WWDDDp
p
tSHL
aaaaaaaaaaaaδaa 21
2
2
21
31 :2
1
1...
Solving the non-equilibrium F-P eq.
)][()( 12 PUPPP MFaTkaaat B Ω
To average the antisymmetric part of M , describing the torques, we may only consider the t-dependent rotation of n (without any ~ v).
)][(0 eq1
eq2 PUP MFaTkaa B
);(1)(eq tYPP na,na,
212
23 )( naJSUMF
]1)[)((3
][2
12 YTk
JSYUY
BaaTka B
nana
Using the fact that (na) is negligibly small.
Thus find ))(()/(2
)/(nana
TkJS
TkJS
TkY
B
B
B
And the average aaa dYeUU Tk
U
aaM B
21
antisym
][)1257()/(2
)/(4
2
701 nnnn
SS
TkJS
TkJS
B
B
Leslie coefficients, and consequences
)43(
)43(
257
][
1257][
41
171
1
121
6
41
171
1
121
5
4
2
1
1351
4
1
1211
121
3
4/2/
351
111
121
2
4
2
1
11
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
SSS
SSS
SS
SggS
SSggS
S
p
p
p
p
p
p
p
p
p
p
p
p
p
p
kTJSkTJS
p
p
p
p
An issue with isotropic Leslie coefficient 4An issue with the “Arrhenius” activation energy and dependenceRod-like (p>>1) or disk-like (p<<1) nematic liquidsTorque balance not always possible: director rotation vs. tumbling
1
1
2
3
...)(...
...)(...tan
gp
gp
Rods (p>>1) give tan ~ 1;
~45o
Disks (p<<1) suggest tan>>1; ~90o
Conclusions
• First-principle derivation of the microscopic stress tensor
• Derivation of full F-P equation allows any level of accuracy, as long as the
corresponding HD problem is resolved
• Separation of time scales gives the relevant (Smoluchowski) equation, with
the hierarchy of sources in powers of a)<<1
• Leslie coefficients expressed either as an expansion in powers of {S}, or as
Arrhenius-style activation exponentials {exp –D/kT}
• What about inhomogeneous particle density xrx (i.e. in mixtures)?
• How to solve for the full spectrum of relaxation modes (including coupling)?
• Non-axisymmetric particles (the derivation depends on general ik)?
• Non-axisymmetric mean-field U(a•n) (e.g. biaxial phases, or smectics)?
• Could one re-formulate the whole theory in terms of Q-tensor?
• Moving away from the mean-field approximation (pair correlation functuions)?
• First-principle derivation of the microscopic stress tensor • Derivation of full F-P equation allows any level of accuracy, as long as the corresponding HD problem is resolved• Separation of time scales gives the relevant (Smoluchowski) equation, with the hierarchy of sources in powers of a)<<1• Leslie coefficients expressed either as an expansion in powers of {S}, or as Arrhenius-style activation exponentials {exp –D/kT}
The translational part of viscous coefficients, giving a part of 4 (and all of the
residual isotropic viscosity!..) is a totally different story…
•What about inhomogeneous particle density xrx (i.e. in mixtures)?
• How to solve for the full spectrum of relaxation modes (including coupling)?• Non-axisymmetric particles (the derivation depends on general ik)?• Non-axisymmetric mean-field U(a•n) (e.g. biaxial phases, or smectics)?• Could one re-formulate the whole theory in terms of Q-tensor?• Moving away from the mean-field approximation (pair correlation functions)?
Thank you