NETAJI SUBHAS OPEN UNIVERSITY ¶ß±Ó¬fl¡ ¬Û±Í¬Sê˜ ( BDP ...€¦ · What do you mean by standard reduction potential of a redox couple ? How does it differ from formal

NETAJI SUBHAS OPEN UNIVERSITY ¶ß±Ó¬fl¡ ¬Û±Í¬Sê˜ ( BDP )

’Ú≈˙œ˘Ú ¬ÛS ¬(Assignment), øάÀ¸•§¬ı˛, 2019 › Ê ≈Ú, 2020 (December-2019 & June-2020)

‹ø26√fl¡ ¬Û±Í¬Sê˜ ( Elective Course )

¬ı˛¸± ˛Ú (Chemistry) ø¡ZÓ¬œ˚˛ ¬ÛS ( 2nd Paper ) Inorganic Chemistry-I : ECH-2

۔̫˜±Ú – 50 QUESTION PAPER CUM ANSWER BOOKLET ˜±ÀÚ¬ı˛ &èQ – 30%

(Full Marks : 50 ) (Weightage of Marks : 30%)

¬Ûø¬ı˛ø˜Ó¬ › ˚Ô±˚Ô Î¬◊M√√À¬ı¬ı˛ Ê√Ú… ø¬ıÀ˙ ∏ ”˘… Œ√›˚˛± √√À¬ıº ’qX ¬ı±Ú±Ú, ’¬Ûø¬ı˛26√ißÓ¬± ¤¬ı— ’¬Ûø¬ı˛©®±¬ı˛ √√ô¶±é¬À¬ı˛¬ı˛ Œé¬ÀS Ú•§¬ı Œfl¡ÀȬ ŒÚ›˚˛± √√À¬ıº ά◊¬Û±ÀôL õ∂Àùü¬ı˛ ”˘…˜±Ú ”ø‰¬Ó¬ ’±ÀÂ√º

Special credit will be given for precise and correct answer. Marks will be deducted for spelling mistakes, untidiness and illegible handwriting.

The figures in the margin indicate full marks.

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NETAJI SUBHAS OPEN UNIVERSITY ¶ß±Ó¬fl¡ ¬Û±Í¬Sê˜ ( BDP ) STUDENT'S COPY

’Ú≈˙œ˘Ú ¬ÛS ¬(Assignment), øάÀ¸•§¬ı˛, 2019 › Ê ≈Ú, 2020 (December-2019 & June-2020)

‹ø26√fl¡ ¬Û±Í¬Sê˜ ( Elective Course )

¬ı˛¸± ˛Ú (Chemistry) ø¡ZÓ¬œ˚˛ ¬ÛS ( 2nd Paper ) Inorganic Chemistry-I : ECH-2

Name (in Block Letter) : ...........................................................................................................

Enrolment No.

Study Centre Name : .............................................................................. Code : .....................

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B.Sc.-AU-16116

B.Sc.-AU-16116

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Ê√è¬ı˛œ øÚÀ«√ / IMPORTANT INSTRUCTION

’±·√±˜œ ø˙鬱¬ı¯ ∏±«ôL ¬Û¬ı˛œé¬±˚˛ ( T.E. Exam.) ÚÓ≈¬Ú ¬ı…¬ı¶ö± ’Ô±«» õ∂ùü¸ √√ ά◊M√√¬ı˛ ¬Û≈øô¶fl¡± (QPAB) õ∂¬ıÓ«¬Ú fl¡¬ı± √√À¬ıº ¤ ◊√√ ÚÓ≈¬Ú ¬ı…¬ı¶ö±¬ı˛ ¸±ÀÔ ¬Û¬ı˛œé¬±ÔπÀ√¬ı˛ ’ˆ¬…ô¶ fl¡¬ı±¬ı˛ Ê√Ú… ¬ıÓ«¬˜±Ú ’Ú ≈˙œ˘Ú ¬ÛÀS õ∂øÓ¬øȬ õ∂Àùü¬ı˛ øÚÀ«√ ’Ú≈˚±˚˛œ øÚø«√©Ü ¶ö±ÀÚ ◊√√ ά◊M√√¬ı ø√ÀÓ¬ √√À¬ıº

New system i.e. Question Paper Cum Answer Booklet (QPAB) will be introduced in the

coming Term End Examination. To get the candidates acquainted with the new system,

now assignment answer is to be given in the specific space according to the instructions.

Detail schedule for submission of assignment for the BDP term End Examination December-2019 & June 2020

1. Date of Publication : 14/02/2020

2. Last date of Submission of answer script by the student to the study centre

: 07/03/2020

3. Last date of Submission of marks by the examiner to the study centre : 08/04/2020

4. Date of evaluated answer scripts distribution by the study centre to the students (Students are advised to check their assignment marks on the evaluated answer scripts and marks lists in the study centre notice board. If there is any mismatch / any other problems of marks obtained and marks in the list, the students should report to their study centre Co-ordinator on spot for correction. The study centre is advised to send the corrected marks, if any, to the COE office within five days. No change / correction of assignment marks will be accepted after the said five days.

: 18/04/2020

5. Last date of submission of marks by the study centre to the Department of C.O.E. on or before

: 20/04/2020

¤‡±ÀÚ øfl¡Â≈√ ø˘‡À¬ıÚ Ú± Do Not Write Anything Here

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ø¬ıˆ¬±· - fl¡ Group-A

Œ˚-Œfl¡±ÀÚ± ≈íøȬ õ∂Àùü¬ı˛ ά◊M√ √¬ı˛ ø√Ú – 10 × 2 = 20 Answer any two of the following : 1. (a) ¬ı…±‡…± fl¡èÚ – Explain :

(i) Cr-¤¬ı˛ ¬ıø˝√ √¶ö– fl¡À鬬ı˛ ˝◊ √√À˘fl¡¬∏CÚ ø¬ıÚ…±¸

!

3s2

3 p6

3d4

4s2 Ú˚˛º 3

The valence shell electronic configuration of Cr is not

!

3s2

3 p6

3d4

4s2

.

(ii) Œflv¡±ø¬ı˛ÀÚ¬ı˛ ˝◊ √√À˘fl¡¬∏CÚ ’±¸øMê √ ¬˝ √√…±À˘±ÀÊ √Ú&ø˘¬ı˛ ˜ÀÒ… ¸¬ı±«øÒfl¡º 3 The electron affinity of chlorine is highest among the halogens. (b) (i) ’ôL¸«øg·Ó¬ Œ˜Ã˘ ¬ı˘ÀÓ¬ øfl¡ Œ¬ı±ÀÁ¡Ú ∑ 2 What do you understand by the term inner transition elements ?

(ii) ˝◊ √√ά◊À¬ı˛øÚ˚˛±À˜±M√√¬ı˛ Œ˜Ã˘ fl¡±À√¬ı˛ ¬ıÀ˘, ¬ı…±‡…± fl¡èÚº 2 What is meant by the term trans-Uranic elements. Explain. 2. (a) øÚά◊øflv¡˚ ¬ıgÚ˙øMê√ ¸•ÛÀfl«¡ ¤¬ı— ¬ıgÚ˙øMê √ Œ˘‡ø‰¬S ¸•ÛÀfl«¡ ’±¬ÛÚ±¬ı˛ Ò±¬ı˛Ì± ¬ı…±‡…± fl¡èÚº øÚά◊flv¡œ˚

ø¬ıˆ¬±Ê√Ú ¤¬ı— øÚά◊flv¡œ˚˛ ¸—À˚±Ê√Ú Œ˚ ˙øMê √¬ı˛ ά◊»¸ Ó¬± ¤˝◊ √√ Œ˘‡ø‰¬S ŒÔÀfl¡ øfl¡¬ı˛+À¬Û Ê √±Ú± ˚±˚˛ ∑ 2 + 1 + 2 Explain the concept of Nuclear Binding Energy and hence the binding energy

curve. How does the curve gives information about nuclear fission and fusion as energy source ?

(b) ¤fl¡øȬ ŒÓ¬Ê√ø¶ç¡˚˛ Œ˜ÃÀ˘¬ı˛ ’Ò«±˚˛ ≈ › ·Î¬ˇ-’±˚˛ ≈ øfl¡ ∑ ŒÓ¬Ê√ø¶ç¡˚˛ ˆ¬±eÀÚ¬ı˛ ¸”S ¬ı…¬ı˝√√±¬ı˛ fl¡À¬ı˛ õ∂øÓ¬øȬ¬ı˛ ·±øÌøÓ¬fl¡ ¬ı˛±ø˙ øÚÌ«˚ fl¡èÚº Ó¬±À√¬ı˛ ¸•Ûfl«¡ ŒÔÀfl¡ ¸Ú±Mê√ fl¡èÚ Œfl¡±ÚøȬ ¬ıάˇº 2 + 2 + 1

What are half-life and average life of a radio-element ? Using radioactive disintegration law, find mathematical expression for each of them.

3. (a) Ê√±¬ı˛Ì-ø¬ıÊ√±¬ı˛Ì ˚ ≈·À˘¬ı˛ õ∂˜±Ì ø¬ıˆ¬¬ı ¬ı˘ÀÓ¬ øfl¡ Œ¬ı±ÀÁ¡Ú ∑ Ù¬˜±«˘ ø¬ıˆ¬À¬ı¬ı˛ ¸Àe ¤¬ı˛ ¬Û±Ô«fl¡… øfl¡ ∑ 2 + 1 What do you mean by standard reduction potential of a redox couple ? How

does it differ from formal potential ?

(b) 0·1 (M) Fe

!

+2 ^¬ıÌÀfl¡ 0·1 (M) Ce

!

+4 ^¬ıÌ ¡Z±¬ı˛± õ∂˙˜Ú fl¡±À˘ õ∂˙˜ ø¬ıˆ¬¬ı [equivalence

point] øÚÌ«˚˛ fl¡èÚº [ Œ√›˚˛± ’±ÀÂ√

!

E°

Fe+3

/ Fe+2

= + 0 "77 V ¤¬ı—

!

E°

Ce+4

/ Ce+3

= + 1"57 V ]

›˝◊ √√ õ∂˙˜ÀÚ ¬ı…¬ı˝√ √+Ó¬ ¤fl¡øȬ ¸”‰¬Àfl¡¬ı˛ [Indicator] Ú±˜ ø˘‡≈Úº 3 + 1

Find out the equivalence point potential during the titration of a 0·1 (M)

Fe

!

+2 solution with 0·1 (M) Ce

!

+4 solution. Given

!

E°

Fe+3

/ Fe+2

= + 0 "77 V

!

E°

Ce+4

/ Ce+3

= + 1"57 V

Name one suitable indicator for the above titration.

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(c) øÚ•ßø˘ø‡Ó¬ ˘…±øȬ˜±¬ı˛ ø‰¬S ŒÔÀfl¡ Ùˬ©Ü ø‰¬S ·Í¬Ú fl¡èÚº

ø‰¬ÀS¬ı˛ õ∂øÓ¬øȬ ø¬ıµ≈¬ı˛ ¶ö±Ú±Ç øÚÌ«À˚˛¬ı˛ ·ÌÚ± Œ√‡±Úº 3

Construct Frost Diagram from the following Latimer Diagram.

show the calculation for evaluation of coordinate of each point of the plot.

4. (a) ¬Û±Î¬◊ø˘-¤¬ı˛ ¬ÛXøÓ¬ ¬ı…¬ı˝√ √±¬ı˛ fl¡À¬ı˛ KCl Œfl¡˘±À¸ K

!

+› Cl

!

" ’±˚˛Ú¡ZÀ˚˛¬ı˛ ’±˚˛Úœ˚˛ ¬ı…±¸±Ò« ·ÌÚ± fl¡èÚº

Œ√›˚˛± ’±À √

!

dK

+ + dCl" = 314 pm. 3

By using Pauling's method, calculate the ionic radii of K

!

+ and Cl

!

" ions in

KCl crystal. Given

!

dK

+ + dCl" = 314 pm.

(b) ’±˚˛Ú±˚Ì ø¬ıˆ¬À¬ı¬ı˛ [Ionisation Potential] ¸—:± øÚº Œ˜ÃÀ˘¬ı˛ ’±˚˛Ú±˚Ì ø¬ıˆ¬¬ı ˜±ÀÚ¬ı ά◊¬Û¬ı˛ õ∂ˆ¬±¬ı ¸‘ø©Üfl¡±¬ı˛œ fl¡±¬ı˛Ì&ø˘ ¸•§Àg ’±À˘±‰¬Ú± fl¡èÚº 1 + 2

Define 'Ionisation Potential'. Discuss the factors controlling the ionisation potential values of elements.

(c) øÚÀ•ß ¬ıøÌ«Ó¬&ø˘ ¬ı…±‡…± fl¡èÚ – [Œ˚-Œfl¡±ÀÚ± ≈√øȬ ] 2 × 2

Explain the following : ( any two ) (i) Œ|Ìœˆ ≈¬Mê√ Œ˜ÃÀ˘¬ı˛ ˝√√±˝◊ √ √E±˝◊ √√ά&ø˘¬ı˛ ø¬ıÊ√±¬ı˛Ì Ò˜« øÚ•ß±øˆ¬˜ ≈À‡ ¬ı‘øX ¬Û±˚˛ º Reducing power of the hydrides of group 15 elements increases down

the group.

(ii) ’±^«ø¬ıÀù≠¯ ∏Ì ø¬ıøSê˚˛±˚ NF

!

3 øÚø©ç¡˚˛ øfl¡c PF

!

3 ¸øSê˚˛º

NF

!

3 is inert to hydrolysis while PF

!

3 is reactive.

(iii) Œ˚±Ê√…Ó¬± õ∂Àfl¡±Àᬠ˝◊ √√À˘fl¡¬∏CÚ ø¬ıÚ…±¸ Ca › Zn ά◊ˆ¬À˚˛¬ı˛ Ê√Ú… 4s

!

2 , øfl¡c õ∂Ô˜ ’±˚˛øÚfl¡¬ı˛Ì ˙øMê √ Zn ’À¬Û鬱 Ca -¤¬ı˛ fl¡˜º

The valence shell electronic configuration of both Ca and Zn is 4s

!

2 but

the first ionisation energy of Ca is lower than Zn.

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õ∂Ô˜ ά◊M√√¬ı˛ / First Answer :

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ø¡ZÓ¬œ˚˛ ά◊M√√¬ı˛ / Second Answer :

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ø¬ıˆ¬±· - ‡¡ Group-B

Œ˚-Œfl¡±ÀÚ± øÓ¬ÚøȬ õ∂Àùü¬ı˛ ά◊M√√¬ı˛ ø√Ú – 6 × 3 = 18

Answer any three of the following : 5. (a) ¬ıÌ«-˘…±À`¬ ¸˜œfl¡¬ı˛ÌøȬ ø˘‡≈Ú ¤¬ı— ¤¬ı˛ ¬Û√&ø˘ ¬ı…±‡…± fl¡èÚº 2

Write down the Born-Lande equation and explain the terms involved. (b) VSEPR Ó¬ÀN¬ı˛ ¸±˝√√±À˚… PCI

!

5-¤¬ı˛ ¸y±¬ı… ’±fl‘¡øÓ¬ øÚÌ«˚˛ fl¡èÚº 2

On the basis of VSEPR theory determine the probable shape of PCI

!

5.

(c) Œ¬ıÀKI ◊¬ı˛ øÚ˚˛˜ ø¬ı¬ı‘Ó¬ fl¡èÚ ¤¬ı— ¤¬ı˛ ŒÔÀfl¡

!

CH2

F2

-¤¬ı˛ ’±fl¡±¬ı˛ › ¬ıgÚ Œfl¡±Ì&ø˘ ’±À˘±‰¬Ú± fl¡èÚº 2

State Bent's rule and hence discuss the shape and bond angles in

!

CH2

F2

.

6. (a) õ∂øÓ¬øȬ õ∂±fl‘¡øÓ¬fl¡ ŒÓ¬Ê√ø¶ç¡˚˛ ’¬ıé¬˚˛ ¸±ø¬ı˛¬ı˛ ¸¬ı±«À¬Û鬱 ’øôL˜ Ê√±Ó¬fl¡ Œ˜Ã˘&ø˘¬ı˛ ˆ¬¬ı˛ ¸—‡…± › ¬Û¬ı˛˜±Ì ≈ Sê˜±Ç Î¬◊À~‡ fl¡èÚº 2

Give the mass numbers and atomic numbers of the end products of each of the natural radioactive series.

(b) ·±øÌøÓ¬fl¡ ¸˜œfl¡¬ı˛À̬ı˛ ¸±˝√√±À˚… ŒÓ¬Ê √ø¶ç¡˚˛ ø¬ıøfl¡¬ı˛Ì ¸”S õ∂fl¡±˙ fl¡èÚº 2 Give the mathematical expression of the 'Radioactive Decay Law'

(c) Ê√±≈√ ¸—‡…± ¬ı˘ÀÓ¬ øfl¡ Œ¬ı±ÀÁ¡Ú ∑ 2 What do you understand by the term 'Magic numbers' ?

7. (a) ’…±ø¸Î¬&ø˘Àfl¡ Ó¬±À√¬ı˛ ˙øMê√ ±S±¬ı˛ ’Ò–Sê˜±Ú ≈¸±À¬ı˛ ¸±Ê√±Ú – 2

!

HClO2

, HClO3

, HClO4

Arrange the following acids in order of their decreasing order of acidity.

!

HClO2

, HClO3

, HClO4.

(b) øÚ•ßø˘ø‡Ó¬ ø¬ıøSê˚˛±øȬ¬ı˛ ’øˆ¬˜ ≈‡ ˚ ≈øMê√ ˝√√fl¡±À¬ı˛ ’Ú ≈˜±Ú fl¡èÚ – 2

!

3FeCl4

" + 18F

" = 3FeF

6

3" + 12Cl

"

Predict the direction of the following reaction and explain —

!

3FeCl4

" + 18F

" = 3FeF

6

3" + 12Cl

"

(c) BF

!

3 ’À¬Û鬱 BCl

!

3 Ó¬œ¬ıË ≈˝◊ √√ ’…±ø¸Î¬ ¬ı…±‡…± — fl¡èÚº 2

Explain — BCl

!

3 is stronger Lewis acid than BF

!

3.

8. (a) ’±˚˛Ú-˝◊ √√À˘fl¡¬∏CÚ ¬ÛXøÓ¬ÀÓ¬ ÚœÀ‰¬¬ı˛ ¸˜œfl¡¬ı˛ÌøȬ¬ı˛ ¸˜Ó¬± ø¬ıÒ±Ú fl¡èÚ – 2

!

KMnO4

+ SO2

+ H2O " K

2SO

4+ MnSO

4+ H

2SO

4

Balance the following equation by ion-electron method :

!

KMnO4

+ SO2

+ H2O " K

2SO

4+ MnSO

4+ H

2SO

4

(b) ÚœÀ‰¬¬ı˛ ø¬ıøSê˚˛±øȬÀfl¡ Œfl¡Ú ¶§Ó¬–Ê√±¬ı˛Ì-ø¬ıÊ√±¬ı˛Ì ø¬ıøSê˚˛± ¬ı˘± ˝√√ ˛ ¬ı…±‡…± fl¡èÚº

!

P4

+NaOH +H2

O"PH3

+NaH2

PO2

. 1

Why the follwowing equation is known as self oxidation-reduction reaction — explain.

!

P4

+NaOH +H2

O"PH3

+NaH2

PO2

.

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(c) øÚ•ßø˘ø‡Ó¬ ’±˚˛Ú&ø˘¬ı˛ ˝◊ √√À˘fl¡¬∏CÚ ø¬ıÚ…±¸

!

2s2

2 p6

˝√√À˘› ’±˚˛Úœ˚˛ ¬ı…±¸…±Ò« ¬Û‘Ôfl¡ Œfl¡Ú ∑ ’±˚˛Ú&ø˘Àfl¡ Sê˜˝}√√±¸˜±Ú ¬ı…±¸±Ò«SêÀ˜ ¸ø7¡¡¡Ó¬ fl¡èÚº

!

O2"

, F"

, Na+

, Mg2+

, Al3+

2 + 1

Although the electronic configurtion of the following ions is

!

2s2

2 p6

but their ionic radii are different — explain.

Arrange the ions in decreasing order of their ionic radii.

!

O2"

, F"

, Na+

, Mg2+

, Al3+

9. (a)

!

PbF4

Œ˚÷øȬ ¸≈ø¶öÓ¬ øfl¡c

!

PbI4

’¶ö±˚˛œ — ¬ı…±‡…± fl¡èÚº 2

The compound

!

PbF4

is stable but

!

PbI4

is unstable — explain.

(b) ά◊√±˝√√¬ı˛Ì¸˝√√ Œfl¡˘±¸ ¸¬ı·±«Ç ¬Û√øȬ ¬ı…±‡…± fl¡èÚº 2

'Explain with example — the term crystal coordination number.

(c) øÚ•ßø˘ø‡Ó¬ Œé¬ÀS ^¬ıÀ̬ı˛ ’…±ø¸Î¬˜±S±˚˛ øfl¡¬ı˛+¬Û ¬Ûø¬ı˛¬ıÓ«¬Ú ˝√√À¬ı — ¬ı…±‡…± fl¡èÚº Œ¬ı±ø¬ı˛fl¡ ’…±ø¸Àά¬ı˛ Ê√ œ˚˛ ø˜|ÀÌ ø¢≠¸±¬ı˛˘ Œ˚±· fl¡¬ı˛± ˝√√ º 2

What will be the change in acidity in the following case ? Explain. Glycerol was added in an aqueous solution of Boric acid.

10. (a) fl¡øÍ¬Ú HgO-’øÓ¬ø¬ı˛Mê√ KI ^¬ıÀÌ Œ˚±· fl¡¬ı˛± ˝√√˘º SHAB ÚœøÓ¬¬ı˛ øˆ¬øM√√ÀÓ¬ ¬ı…±‡…± fl¡èÚ Œ˚ ^¬ıÌøȬ øfl¡ ’±ø•°fl¡, 鬱¬ı˛œ˚˛ ¬ı± õ∂˙˜ ˝√√À¬ıº 2

KI solution is added in excess solid HgO. Explain with help of SHAB principal whether the mixture will be acidic, alkaline or neutral.

(b) øÚ•ßø˘ø‡Ó¬ øÚά◊øflv¡˚˛± ◊ √√ά&ø˘¬ı˛ ˜ÀÒ… ¸¬ı ÔÀfl¡ Œfl¡ fl¡˜ ¶ö±˚˛œ ∑

!

20

40Ca ,

13

30Al ,

50

119Sn ,

25

55Mn ,

16

32Sn . 2

Which of the following nuclides will be least stable ?

!

20

40Ca ,

13

30Al ,

50

119Sn ,

25

55Mn ,

16

32Sn .

(c)

!

XeO3

-¤¬ı˛ ˝◊ √√À˘fl¡¬∏CÚ Î¬È¬ ·Í¬Úfl¡±Í¬±À˜± ¤¬ı— ’±fl¡±À¬ı˛¬ı˛ Œ¬ı˛‡±ø‰¬S ’±“fl ≈¡Úº 2

Give the Lewis dot structure and sketch the shape of

!

XeO3.

õ∂Ô˜ ά◊M√√¬ı˛ / First Answer :

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ø¡ZÓ¬œ˚˛ ά◊M√√¬ı˛ / Second Answer :

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Ó‘¬Ó¬œ˚˛ ά◊M√√¬ı / Third Answer :

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ø¬ıˆ¬±· - ·¡ Group - C

Œ˚-Œfl¡±ÀÚ± ‰¬±¬ı˛øȬ¬ õ∂Àùü¬ı˛ ά◊M√√¬ı˛ ø√Ú – 3 × 4 = 12

Answer any four of the following :

11. (a) ÚœÀ‰¬¬ı˛ Œ˜Ã˘≈√øȬ¬ı˛ ˜ÀÒ… ¸•Ûfl«¡ øfl¡ ∑

!

1

2H ,

2

3He 1

What is the relation between the following two elements ?

!

1

2H ,

2

3He

(b) Œfl¡±ÚƒøȬ¬ı˛ ¬ıgÚ Œfl¡±Ì ¸¬ı±«øÒfl¡ ¬ı…±‡…± fl¡èÚ –

!

NO2

, NO2

+, NO

2

" 2

Which one of the following has the highest bond angle — explain.

!

NO2

, NO2

+, NO

2

"

12. (a) Œfl¡±Úƒ øÓ¬Ú ŒÊ√±Î¬ˇ Œ˜ÃÀ˘¬ı˛ ˜ÀÒ… Œfl¡ÃøÚfl¡ ¸•Ûfl«¡ ¬ıÓ«¬˜±Ú ∑ 1

Which of the three pairs of elements have diagonal relationship ?

(b) VSEPR Ó¬ÀN¬ı˛ ¸±˝√√±À˚…

!

SF6

-¤¬ı˛ ’±fl‘¡øÓ¬ øÚÌ«˚˛ fl¡èÚº 2

Draw the shape of

!

SF6

with the help of VSEPR theory.

13. (a) 鬱¬ı˛Ò±Ó ≈¬&ø˘¬ı˛ ˜ÀÒ… Li Œ˜Ã˘øȬ¬ı˛ ’±˚˛Ú±˚˛Ú ø¬ıˆ¬¬ı ¸¬ı±«øÒfl¡, Ó¬Ô±ø¬Û Ó¬øάˇ» ¬ı˛±¸±˚˛øÚfl¡ Œ|øÌÀÓ¬ ¤øȬ¬ı˛ ¶ö±Ú

¸¬ı ŒÔÀfl¡ ά◊¬ÛÀ¬ı˛ — ¬ı…±‡…± fl¡èÚº 2

The Ionization potential of Li is highest among the alkali metals, still it holds

the highest position of the electrochemical series — Explain.

(b) ’¬ı˛±˝◊ √√ά ’±˚˛Ú fl¡±Àfl¡ ¬ıÀ˘ ∑ 1

What is Auride ion ?

14. (a) 10

!

"8 (N) Ê √ œ˚˛ NaOH ^¬ıÀ̬ı˛ pH fl¡Ó¬ ˝√ √À¬ı ∑ 2

What will be the pH of a 10

!

"8 (N) aqueous solution of NaOH ?

(b) øÓ¬Ú ÒÚ±Rfl¡ ’±Ò±Ú˚ ≈Mê√ ˘…±Lö±Ú±˝◊ √√ά&ø˘¬ı˛ ¸±Ò±¬ı˛Ì ˝◊ √√À˘fl¡¬∏CÚ ø¬ıÚ…±¸ ø˘‡≈Úº 1

Write down the general electronic configuration of tripositive Lanthanide

ions.

QP Code : 20UA108ECH2 B.Sc.-AU-16116

20/24

15. (a) ^±¬ıÀfl¡¬ı˛ Œ˘Àˆ¬ø˘— ¤ÀÙ¬"√ √ [Lavelling effect] ¬ı˘ÀÓ¬ øfl¡ Œ¬ı±ÀÁ¡Ú ∑ 2

What do you mean by 'Lavelling effect of solvents' ?

(b) ¸≈¬Û±¬ı˛ ’…±ø¸Î¬ fl¡±À√¬ı˛ ¬ıÀ˘ ∑ 1

Which are known as super acids ?

16.

!

(CH3

)3

N 鬱¬ı˛fl¡œ˚˛ øfl¡c

!

(SiH3

)3

N -¤¬ı˛ 鬱¬ı˛fl¡œ˚˛Ó¬± Ò˜« ŒÚ˝◊ √√ — ¬ı…±‡…± fl¡èÚº 3

!

(CH3

)3

N is basic but

!

(SiH3

)3

N has no basic property. Explain.

17.

!

H3

PO2

, H3

PO3

, H3

PO4

’…±ø¸Î¬ øÓ¬ÚøȬ¬ı˛ Ó¬œ¬ıËÓ¬±Sê˜ fl¡±¬ı˛Ì¸˝√√ ¬ı…±‡…± fl¡èÚº 3

Explain with reasons the order of strength of acidity of these three acids :

!

H3

PO2

, H3

PO3

, H3

PO4

.

18. ¬øÚ•ßø˘ø‡Ó¬ ¸˜œfl¡¬ı˛Ì&ø˘ÀÓ¬ A, B, C ¸Ú±Mê √ fl¡èÚ – 3

Identify A, B & C in the following equations :

(i)

!

15

30P " # "

14

30Si + A

(ii)

!

1338

K " # " B + $10

e

(iii)

!

13

27Al +

2

4He = C +

0

1n .

õ∂Ô˜ ά◊M√√¬ı˛ / First Answer :

QP Code : 20UA108ECH2 B.Sc.-AU-16116

21/24

QP Code : 20UA108ECH2 B.Sc.-AU-16116

22/24

ø¡ZÓ¬œ˚˛ ά◊M√√¬ı˛ / Second Answer :

QP Code : 20UA108ECH2 B.Sc.-AU-16116

23/24

Ó‘¬Ó¬œ˚˛ ά◊M√√¬ı / Third Answer :

QP Code : 20UA108ECH2 B.Sc.-AU-16116

24/24

‰¬Ó≈¬Ô« ά◊M√√¬ı˛ / Fourth Answer :