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EE 261 Krish Chakrabarty 1 MOS Transistor Theory So far, we have viewed a MOS transistor as an ideal switch (digital operation) Reality: less than ideal EE 261 Krish Chakrabarty 2 Introduction So far, we have treated transistors as ideal switches An ON transistor passes a finite amount of current Depends on terminal voltages Derive current-voltage (I-V) relationships Transistor gate, source, drain all have capacitance I = C (V/t) -> t = (C/I) V Capacitance and current determine speed Also explore what a “degraded level” really means
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MOS Transistor Theorypeople.ee.duke.edu/~krish/teaching/Lectures/MOS-theory... · 2004-08-29 · 2 EE 261 Krish Chakrabarty 3 MOS Transistor Theory • Study conducting channel between

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Page 1: MOS Transistor Theorypeople.ee.duke.edu/~krish/teaching/Lectures/MOS-theory... · 2004-08-29 · 2 EE 261 Krish Chakrabarty 3 MOS Transistor Theory • Study conducting channel between

1

EE 261 Krish Chakrabarty 1

MOS Transistor Theory

• So far, we have viewed a MOS transistor as an ideal switch (digital operation)– Reality: less than ideal

EE 261 Krish Chakrabarty 2

Introduction• So far, we have treated transistors as ideal

switches• An ON transistor passes a finite amount of current

– Depends on terminal voltages– Derive current-voltage (I-V) relationships

• Transistor gate, source, drain all have capacitance– I = C (∆V/∆t) -> ∆t = (C/I) ∆V– Capacitance and current determine speed

• Also explore what a “degraded level” really means

Page 2: MOS Transistor Theorypeople.ee.duke.edu/~krish/teaching/Lectures/MOS-theory... · 2004-08-29 · 2 EE 261 Krish Chakrabarty 3 MOS Transistor Theory • Study conducting channel between

2

EE 261 Krish Chakrabarty 3

MOS Transistor Theory

• Study conducting channel between source and drain• Modulated by voltage applied to the gate (voltage-controlled device)• nMOS transistor: majority carriers are electrons (greater mobility), p-substrate doped (positively doped)• pMOS transistor: majority carriers are holes (less mobility), n-substrate (negatively doped)

EE 261 Krish Chakrabarty 4

Terminal Voltages• Mode of operation depends on Vg, Vd, Vs

– Vgs = Vg – Vs

– Vgd = Vg – Vd

– Vds = Vd – Vs = Vgs - Vgd

• Source and drain are symmetric diffusion terminals– By convention, source is terminal at lower voltage– Hence Vds ≥ 0

• nMOS body is grounded. First assume source is 0 too.• Three regions of operation

– Cutoff– Linear– Saturation

Vg

Vs Vd

VgdVgs

Vds+-

+

-

+

-

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EE 261 Krish Chakrabarty 5

Gate Biasing

p-substrate

n+ n+

Source Gate Drain

Channel

+ -

E

SiO2

VSS (Gnd)

• Vgs=0: no current flows fromsource to drain (insulated by two reverse biased pn junctions

• Vgs>0: electric field created across substrate

• Electrons accumulate under gate: region changes from p-typeto n-type

• Conduction path between source and drain

EE 261 Krish Chakrabarty 6

nMOS Device Behavior

Vgs << Vt

Polysilicon gatep-substrate

Accumulationmode

• Enhancement-mode transistor: Conducts when gate biasVgs > Vt

• Depletion-mode transistor: Conducts when gate bias is zero

Vgs = Vt

Depletion mode

Depletion region

Oxide insulator

Vgs > Vt

Inversion mode

Depletion region

InversionRegion(n-type)

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EE 261 Krish Chakrabarty 7

nMOS Cutoff

• No channel• Ids = 0

+-

Vgs = 0

n+ n+

+-

Vgd

p-type body

b

g

s d

EE 261 Krish Chakrabarty 8

nMOS Linear• Channel forms• Current flows from d to s

– e- from s to d

• Ids increases with Vds

• Similar to linear resistor

+-

Vgs > Vt

n+ n+

+-

Vgd = Vgs

+-

Vgs > Vt

n+ n+

+-

Vgs > Vgd > Vt

Vds = 0

0 < Vds < Vgs-Vt

p-type body

p-type body

b

g

s d

b

g

s d Ids

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EE 261 Krish Chakrabarty 9

nMOS Saturation

• Channel pinches off• Ids independent of Vds

• We say current saturates• Similar to current source

+-

Vgs > Vt

n+ n+

+-

Vgd < Vt

Vds > Vgs-Vt

p-type bodyb

g

s d Ids

EE 261 Krish Chakrabarty 10

I-V Characteristics

• In linear region, Ids depends on– How much charge is in the channel?– How fast is the charge moving?

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EE 261 Krish Chakrabarty 11

Channel Charge

• MOS structure looks like parallel plate capacitor while operating in inversion– Gate – oxide – channel

• Qchannel =

n+ n+

p-type body

+

Vgd

gate

+ +source

-

Vgs

-drain

Vds

channel-

Vg

Vs Vd

Cg

n+ n+

p-type body

W

L

tox

SiO2 gate oxide(good insulator, εox = 3.9)

polysilicongate

EE 261 Krish Chakrabarty 12

Channel Charge

• MOS structure looks like parallel plate capacitor while operating in inversion– Gate – oxide – channel

• Qchannel = CV• C =

n+ n+

p-type body

+

Vgd

gate

+ +source

-

Vgs

-drain

Vds

channel-

Vg

Vs Vd

Cg

n+ n+

p-type body

W

L

tox

SiO2 gate oxide(good insulator, εox = 3.9)

polysilicongate

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EE 261 Krish Chakrabarty 13

Channel Charge• MOS structure looks like parallel plate capacitor

while operating in inversion– Gate – oxide – channel

• Qchannel = CV• C = Cg = εoxWL/tox = CoxWL• V =

n+ n+

p-type body

+

Vgd

gate

+ +source

-

Vgs

-drain

Vds

channel-

Vg

Vs Vd

Cg

n+ n+

p-type body

W

L

tox

SiO2 gate oxide(good insulator, εox = 3.9)

polysilicongate

Cox = εox / tox

EE 261 Krish Chakrabarty 14

Channel Charge• MOS structure looks like parallel plate capacitor while

operating in inversion– Gate – oxide – channel

• Qchannel = CV• C = Cg = εoxWL/tox = CoxWL• V = Vgc – Vt = (Vgs – Vds/2) – Vt

n+ n+

p-type body

+

Vgd

gate

+ +source

-

Vgs

-drain

Vds

channel-

Vg

Vs Vd

Cg

n+ n+

p-type body

W

L

tox

SiO2 gate oxide(good insulator, εox = 3.9)

polysilicongate

Cox = εox / tox

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EE 261 Krish Chakrabarty 15

Carrier velocity

• Charge is carried by e-• Carrier velocity v proportional to lateral E-field

between source and drain• v =

EE 261 Krish Chakrabarty 16

Carrier velocity

• Charge is carried by e-• Carrier velocity v proportional to lateral E-field

between source and drain• v = µE µ called mobility• E =

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EE 261 Krish Chakrabarty 17

Carrier velocity

• Charge is carried by e-• Carrier velocity v proportional to lateral E-field

between source and drain• v = µE µ called mobility• E = Vds/L• Time for carrier to cross channel:

– t =

EE 261 Krish Chakrabarty 18

Carrier velocity

• Charge is carried by e-• Carrier velocity v proportional to lateral E-field

between source and drain• v = µE µ called mobility• E = Vds/L• Time for carrier to cross channel:

– t = L / v

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EE 261 Krish Chakrabarty 19

nMOS Linear I-V

• Now we know– How much charge Qchannel is in the channel– How much time t each carrier takes to cross

dsI =

EE 261 Krish Chakrabarty 20

nMOS Linear I-V

• Now we know– How much charge Qchannel is in the channel– How much time t each carrier takes to cross

channelds

QIt

=

=

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EE 261 Krish Chakrabarty 21

nMOS Linear I-V• Now we know

– How much charge Qchannel is in the channel– How much time t each carrier takes to cross

channel

ox 2

2

ds

dsgs t ds

dsgs t ds

QItW VC V V VL

VV V V

µ

β

=

= − −

= − −

ox = WCL

β µ

EE 261 Krish Chakrabarty 22

nMOS Saturation I-V

• If Vgd < Vt, channel pinches off near drain– When Vds > Vdsat = Vgs – Vt

• Now drain voltage no longer increases current

dsI =

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EE 261 Krish Chakrabarty 23

nMOS Saturation I-V

• If Vgd < Vt, channel pinches off near drain– When Vds > Vdsat = Vgs – Vt

• Now drain voltage no longer increases current

2dsat

ds gs t dsatVI V V Vβ = − −

EE 261 Krish Chakrabarty 24

nMOS Saturation I-V

• If Vgd < Vt, channel pinches off near drain– When Vds > Vdsat = Vgs – Vt

• Now drain voltage no longer increases current

( )2

2

2

dsatds gs t dsat

gs t

VI V V V

V V

β

β

= − −

= −

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EE 261 Krish Chakrabarty 25

nMOS I-V Summary

( )2

cutoff

linear

saturatio

0

2

2n

gs t

dsds gs t ds ds dsat

gs t ds dsat

V VVI V V V V V

V V V V

β

β

< = − − <

− >

• Shockley 1st order transistor models

EE 261 Krish Chakrabarty 26

Current-Voltage Relations

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EE 261 Krish Chakrabarty 27

Current-Voltage Relationsk n: transconductance of transistorW : width-to-length ratioL

• As W increases, more carriers available to conduct current

• As L increases, Vds diminishes in effect (more voltage drop). Takes longer to push carriers across the transistor, reducing current flow

EE 261 Krish Chakrabarty 28

Example• For a 0.6 µm process

– From AMI Semiconductor– tox = 100 Å– µ = 350 cm2/V*s– Vt = 0.7 V

• Plot Ids vs. Vds– Vgs = 0, 1, 2, 3, 4, 5– Use W/L = 4/2 λ

( )14

28

3.9 8.85 10350 120 /100 10ox

W W WC A VL L L

β µ µ−

• ⋅ = = = ⋅

0 1 2 3 4 50

0.5

1

1.5

2

2.5

Vds

I ds (m

A)

Vgs = 5

Vgs = 4

Vgs = 3

Vgs = 2Vgs = 1

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EE 261 Krish Chakrabarty 29

pMOS I-V

• All dopings and voltages are inverted for pMOS• Mobility µp is determined by holes

– Typically 2-3x lower than that of electrons µn

– 120 cm2/V*s in AMI 0.6 µm process• Thus pMOS must be wider to provide same

current– In this class, assume µn / µp = 2 to 3

EE 261 Krish Chakrabarty 30

Capacitance

• Any two conductors separated by an insulator have capacitance

• Gate to channel capacitor is very important– Creates channel charge necessary for operation

• Source and drain have capacitance to body– Across reverse-biased diodes– Called diffusion capacitance because it is associated

with source/drain diffusion

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EE 261 Krish Chakrabarty 31

Gate Capacitance• Approximate channel as connected to source• Cgs = εoxWL/tox = CoxWL = CpermicronW• Cpermicron is typically about 2 fF/µm

n+ n+

p-type body

W

L

tox

SiO2 gate oxide(good insulator, εox = 3.9ε0)

polysilicongate

EE 261 Krish Chakrabarty 32

The Gate Capacitance

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EE 261 Krish Chakrabarty 33

Diffusion Capacitance• Csb, Cdb

• Undesirable, called parasitic capacitance• Capacitance depends on area and perimeter

– Use small diffusion nodes– Comparable to Cg

for contacted diff– ½ Cg for uncontacted– Varies with process

EE 261 Krish Chakrabarty 34

Diffusion Capacitance

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EE 261 Krish Chakrabarty 35

Parasitic Resistances

W

LD

Drain

Draincontact

Polysilicon gate

DS

G

RS RD

VGS,eff

RS = (LS/W)R + RC

RD = (LD/W)R + RC

RC: contact resistanceR : sheet resistance per square

of drain-source diffusion

EE 261 Krish Chakrabarty 36

Body Effect• Many MOS devices on a common substrate

– Substrate voltage of all devices are normally equal

• But several devices may be connected in series– Increase in source-to-substrate voltage as we proceed vertically

along the chain

d1

d2

s1

s2

V12

V11

g1

g2

Vsb1 = 0

Vsb2 = 0• Net effect: slight increasein threshold voltage Vt,Vt2>Vt1

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EE 261 Krish Chakrabarty 37

Pass Transistors

• We have assumed source is grounded• What if source > 0?

– e.g. pass transistor passing VDD

VDDVDD

EE 261 Krish Chakrabarty 38

Pass Transistors

• We have assumed source is grounded• What if source > 0?

– e.g. pass transistor passing VDD

• Vg = VDD– If Vs > VDD-Vt, Vgs < Vt

– Hence transistor would turn itself off

• nMOS pass transistors pull no higher than VDD-Vtn– Called a degraded “1”– Approach degraded value slowly (low Ids)

• pMOS pass transistors pull no lower than Vtp

VDDVDD

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EE 261 Krish Chakrabarty 39

Pass Transistor Ckts

VDDVDD

VSS

VDD

VDD

VDD VDD VDD

VDD

EE 261 Krish Chakrabarty 40

Pass Transistor Ckts

VDDVDD Vs = VDD-Vtn

VSS

Vs = |Vtp|

VDD

VDD-Vtn VDD-VtnVDD-Vtn

VDD

VDD VDD VDD

VDD

VDD-Vtn

VDD-2Vtn

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EE 261 Krish Chakrabarty 41

Effective Resistance

• Shockley models have limited value– Not accurate enough for modern transistors– Too complicated for much hand analysis

• Simplification: treat transistor as resistor– Replace Ids(Vds, Vgs) with effective resistance R

• Ids = Vds/R– R averaged across switching of digital gate

• Too inaccurate to predict current at any given time– But good enough to predict RC delay

EE 261 Krish Chakrabarty 42

RC Delay Model• Use equivalent circuits for MOS transistors

– Ideal switch + capacitance and ON resistance– Unit nMOS has resistance R, capacitance C– Unit pMOS has resistance 2R, capacitance C

• Capacitance proportional to width• Resistance inversely proportional to width

kgs

dg

s

d

kCkC

kCR/k

kgs

dg

s

d

kC

kC

kC

2R/k

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EE 261 Krish Chakrabarty 43

RC Values

• Capacitance– C = Cg = Cs = Cd = 2 fF/µm of gate width– Values similar across many processes

• Resistance– R ≈ 6 KΩ in 0.6um process– Improves with shorter channel lengths

• Unit transistors– May refer to minimum contacted device (4/2 λ)– Or maybe 1 µm wide device– Doesn’t matter as long as you are consistent

EE 261 Krish Chakrabarty 44

Activity1) If the width of a transistor increases, the current willincrease decrease not change

2) If the length of a transistor increases, the current willincrease decrease not change

3) If the supply voltage of a chip increases, the maximum transistor current will

increase decrease not change4) If the width of a transistor increases, its gate capacitance willincrease decrease not change

5) If the length of a transistor increases, its gate capacitance willincrease decrease not change

6) If the supply voltage of a chip increases, the gate capacitance of each transistor will

increase decrease not change

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EE 261 Krish Chakrabarty 45

DC Response

• DC Response: Vout vs. Vin for a gate• Ex: Inverter

– When Vin = 0 -> Vout = VDD

– When Vin = VDD -> Vout = 0– In between, Vout depends on

transistor size and current– By KCL, must settle such that

Idsn = |Idsp|– We could solve equations– But graphical solution gives more insight

Idsn

Idsp Vout

VDD

Vin

EE 261 Krish Chakrabarty 46

Transistor Operation

• Current depends on region of transistor behavior• For what Vin and Vout are nMOS and pMOS in

– Cutoff?– Linear?– Saturation?

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EE 261 Krish Chakrabarty 47

nMOS Operation

Vgsn >

Vdsn >

Vgsn >

Vdsn <

Vgsn <SaturatedLinearCutoff

Idsn

Idsp Vout

VDD

Vin

EE 261 Krish Chakrabarty 48

nMOS Operation

Vgsn > Vtn

Vdsn > Vgsn – Vtn

Vgsn > Vtn

Vdsn < Vgsn – Vtn

Vgsn < Vtn

SaturatedLinearCutoff

Idsn

Idsp Vout

VDD

Vin

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EE 261 Krish Chakrabarty 49

nMOS Operation

Vgsn > Vtn

Vdsn > Vgsn – Vtn

Vgsn > Vtn

Vdsn < Vgsn – Vtn

Vgsn < Vtn

SaturatedLinearCutoff

Idsn

Idsp Vout

VDD

Vin

Vgsn = Vin

Vdsn = Vout

EE 261 Krish Chakrabarty 50

nMOS Operation

Vgsn > Vtn

Vin > Vtn

Vdsn > Vgsn – Vtn

Vout > Vin - Vtn

Vgsn > Vtn

Vin > Vtn

Vdsn < Vgsn – Vtn

Vout < Vin - Vtn

Vgsn < Vtn

Vin < Vtn

SaturatedLinearCutoff

Idsn

Idsp Vout

VDD

Vin

Vgsn = Vin

Vdsn = Vout

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EE 261 Krish Chakrabarty 51

pMOS Operation

Vgsp <

Vdsp <

Vgsp <

Vdsp >

Vgsp >SaturatedLinearCutoff

Idsn

Idsp Vout

VDD

Vin

EE 261 Krish Chakrabarty 52

pMOS Operation

Vgsp < Vtp

Vdsp < Vgsp – Vtp

Vgsp < Vtp

Vdsp > Vgsp – Vtp

Vgsp > Vtp

SaturatedLinearCutoff

Idsn

Idsp Vout

VDD

Vin

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EE 261 Krish Chakrabarty 53

pMOS Operation

Vgsp < Vtp

Vdsp < Vgsp – Vtp

Vgsp < Vtp

Vdsp > Vgsp – Vtp

Vgsp > Vtp

SaturatedLinearCutoff

Idsn

Idsp Vout

VDD

Vin

Vgsp = Vin - VDD

Vdsp = Vout - VDD

Vtp < 0

EE 261 Krish Chakrabarty 54

pMOS Operation

Vgsp < Vtp

Vin < VDD + Vtp

Vdsp < Vgsp – Vtp

Vout < Vin - Vtp

Vgsp < Vtp

Vin < VDD + Vtp

Vdsp > Vgsp – Vtp

Vout > Vin - Vtp

Vgsp > Vtp

Vin > VDD + Vtp

SaturatedLinearCutoff

Idsn

Idsp Vout

VDD

Vin

Vgsp = Vin - VDD

Vdsp = Vout - VDD

Vtp < 0

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EE 261 Krish Chakrabarty 55

I-V Characteristics• Make pMOS is wider than nMOS such that βn = βp

Vgsn5

Vgsn4

Vgsn3

Vgsn2Vgsn1

Vgsp5

Vgsp4

Vgsp3

Vgsp2

Vgsp1

VDD

-VDD

Vdsn

-Vdsp

-Idsp

Idsn

0

EE 261 Krish Chakrabarty 56

DC Transfer Curve

• Transcribe points onto Vin vs. Vout plot

CVout

0

Vin

VDD

VDD

A B

DE

Vtn VDD/2 VDD+Vtp

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EE 261 Krish Chakrabarty 57

Operating Regions

• Revisit transistor operating regions

CVout

0

Vin

VDD

VDD

A B

DE

Vtn VDD/2 VDD+VtpEDCBA

pMOSnMOSRegion

EE 261 Krish Chakrabarty 58

Operating Regions

• Revisit transistor operating regions

CVout

0

Vin

VDD

VDD

A B

DE

Vtn VDD/2 VDD+VtpCutoffLinearESaturationLinearDSaturationSaturationCLinearSaturationBLinearCutoffApMOSnMOSRegion

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EE 261 Krish Chakrabarty 59

Beta Ratio• If βp / βn ≠ 1, switching point will move from VDD/2• Called skewed gate• Other gates: collapse into equivalent inverter

Vout

0

Vin

VDD

VDD

0.51

2

10p

n

ββ

=

0.1p

n

ββ

=

EE 261 Krish Chakrabarty 60

Noise Margins• How much noise can a gate input see before it

does not recognize the input?

IndeterminateRegion

NML

NMH

Input CharacteristicsOutput Characteristics

VOH

VDD

VOL

GND

VIH

VIL

Logical HighInput Range

Logical LowInput Range

Logical HighOutput Range

Logical LowOutput Range

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EE 261 Krish Chakrabarty 61

Logic Levels

• To maximize noise margins, select logic levels at

VDD

Vin

Vout

VDD

βp/βn > 1

Vin Vout

0

EE 261 Krish Chakrabarty 62

Logic Levels• To maximize noise margins, select logic levels at

– unity gain point of DC transfer characteristic

VDD

Vin

Vout

VOH

VDD

VOL

VIL VIHVtn

Unity Gain PointsSlope = -1

VDD-|Vtp|

βp/βn > 1

Vin Vout

0