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Monty hall

Jun 30, 2015

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An attempt to explain the Monty Hall problem.
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Transcript
Page 1: Monty hall

THE MONTY HALL

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WELCOME My name is Ercan Cem

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I will try to present

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the most famous* puzzle of all times.

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the most famous* puzzle of all times.

*arguable

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It is known as The Monty Hall

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POPULAR BECAUSE

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COUNTER INTUITIVE

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THE PUZZLE

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You are in a TV show.

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There are three doors.

1 2 3

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Behind one of them there's a prize.

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It is yours if you guess correctly.

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The format of the show is...

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First, you make a guess.

1 2 3

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The host opens an empty door from the other two.

1 2 3

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The host knows where the prize is.

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He offers you a new option:

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You can stick with your initial choice.

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OR

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Select the other (unopened) door.

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QUESTION

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WHAT IS THE RATIONAL

STRATEGY?

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IS IT...

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Stick?

1 2 3

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OR...

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Select the other?

1 2 3

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OR...

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Is this just a random guess?

1 2 3

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The usual* answer is that the final choice is just a random guess.

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The usual* answer is that the final choice is just a random guess.

*underestimate

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People tend to think that

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at first, each door has the same one in three chance.

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(which is true)

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So, the chance that our guess is correct

is one in three.

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(which is true)

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Once one of the doors is opened

1 2 3

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the unopened two doors

1 2 3

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share the chance of the opened door.

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THEREFORE

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The final decision is a random guess.

1 2 3

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WRONG!

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The answer is:

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If you want to increase your chance,

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you must switch to the other door.

1 2 3

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(we exclude the cases)

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(that you are superstitious about your inital guess)

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OR

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You are a clairvoyant.

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HERE IS THE EXPLANATION

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(without getting too technical)

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FIRST TRY

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When you made your initial guess,

1 2 3

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your chance of being correct was

one in three.

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ALSO,

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As a fact, we know that

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at least one of the remaining

doors is empty.

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AGREE?

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GOOD.

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FURTHERMORE,

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The host will always have a choice to open

an empty door.

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SO,

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when he opens an empty door,

1 2 3

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he does not provide an extra information.

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He does not provide anything new.

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We already know that at least one

other door is empty.

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The chance that our initial guess is correct

is one in three.

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Nothing changed since then.

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After the door is opened,

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that chance is still one in three.

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HOWEVER

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When two doors are left,

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it cannot be the case that each has a chance

of one in three.

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The TOTAL chance must add up to 1.

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THEREFORE

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The chance that the prize is behind the other

door is two in three.

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UNLESS

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You are very supertitious,

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OR

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CLAIRVOYANT

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You must switch.

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Not convinced?

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SECOND TRY

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Imagine that just before the host opens one of the remaining doors,

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the aliens kidnap him.

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Right at this moment, we can reason as follows:

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The host would either open Door- 2, or Door -3.

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Say he opened Door -2

1 2 3

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Then, only Door -1 and Door-3 would be left.

1 2 3

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The chance that the prize is behind Door-1

would be 50%.

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Instead, say he opened Door -3

1 2 3

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Then, only Door -1 and Door-2 would be left.

1 2 3

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The chance that the prize is behind Door-1

would be 50%.

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Hmmm!

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Isn't that reasoning a bit...

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NAIVE?

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BECAUSE

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It suggests that

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the chance that our initial guess is correct was 50% in the first place.

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We KNOW that that is WRONG!

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It is one in three.

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It cannot increase all of a sudden.

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THEREFORE

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The chance that the prize is behind the other

door is two in three.

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Not convinced?

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LAST TRY

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LAST TRY (You’d better be convinced this time.)

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Imagine a deck of cards.

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(52 cards that is.)

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You pick one.

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If it is the ace of spades,

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you win.

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You picked one.

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51 cards are left.

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I KNOW which card is the ace of spades.

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Among the other 51 cards,

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at least 50 of them is NOT the ace of spades.

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I turn 50 cards upside down.

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Right now, there are two unopened cards on the table...

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yours, and the 52nd card.

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Do you REALLY

think that

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the chance that your pick is the ace of spades is 50%?

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TIME TO WRAP UP

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In the last example, the essence of the

puzzle is much clearer.

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That is because we were dealing with larger quantities.

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Things look fuzzier when dealing with only three objects.

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SIDE NOTE

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In the original problem, suppose that the host opens a random door.

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(Translation: It could be the case that the opened door is the one with the prize.)

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If the opened door is empty,

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then the chance that our initial guess is correct indeed rises to one in two.

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HENCE

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Everything depends on

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whether the door was opened at random,

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or with the knowledge that where the prize is.

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Thanks for sparing your time.

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(A simple Google search will get you to endless sources on Monty Hall. There’s even a book devoted on it.)

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(If you enjoyed this puzzle, you can find more at my blog Mathzzle: puzzle.ercancem.com.)

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UNTIL NEXT TIME

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SEE YA!