Top Banner

of 11

Linear Inequalities and Linear Equations

Jun 02, 2018

Download

Documents

dorathi
Welcome message from author
This document is posted to help you gain knowledge. Please leave a comment to let me know what you think about it! Share it to your friends and learn new things together.
Transcript
  • 8/11/2019 Linear Inequalities and Linear Equations

    1/11

    Linear Inequalities and Linear Equations

    Inequalities

    The term inequality is applied to any statement involving one of the symbols , , .

    Example of inequalities are:

    i. x 1

    ii. x + y + 2z > 16

    iii. p2+ q2 1/2

    iv. a2+ ab > 1

    Fundamental Properties of Inequalities

    1. If a b and c is any real number, then a + c b + c.

    For example, -3 -1 implies -3+4 -1 + 4.

    2. If a b and c is positive, then ac bc.

    For example, 2 3 implies 2(4) 3(4).

    3. If a b and c is negative, then ac bc.

    For example, 3 9 implies 3(-2) 9(-2).

    4. If a b and b c, then a c.

    For example, -1/2 2 and 2 8/3 imply -1/2 8/3.

  • 8/11/2019 Linear Inequalities and Linear Equations

    2/11

    Solution of Inequality

    By solution of the one variable inequality2x + 3 7 we mean any number which

    substituted for x yields a true statement.

    For example, 1 is a solution of 2x + 3 7 since 2(1) + 3 = 5 and 5 is less than and equal to

    7.

    By a solution of the two variable inequalityx - y 5 we mean any ordered pair of numbers

    which when substituted for x and y, respectively, yields a true statement.

    For example, (2, 1) is a solution of x - y 5 because 2-1 = 1 and 1 5.

    By a solution of the three variable inequality2x - y + z 3 we means an ordered triple of

    number which when substituted for x, y and z respectively, yields a true statement.

    For example, (2, 0, 1) is a solution of 2x - y + z 3.

    A solution of an inequality is said to satisfy the inequality. For example, (2, 1) is satisfy x -

    y 5.

    Two or more inequalities, each with the same variables, considered as a unit, are said to

    form a system of inequalities. For example,

    x 0

    y 0

    2x + y 4

    Notethat the notion of a system of inequalities is analogous to that of a solution of asystem of equations.

    Any solution common to all of the inequalities of a system of inequalities is said to be a

    solution of that system of inequalities. A system of inequalities, each of whose members is

    linear, is said to be a system of linear inequalities.

    Geometric Interpretation of Inequalities

    An inequality in two variable x and y describes a region in the x-y plane (called its graph),

  • 8/11/2019 Linear Inequalities and Linear Equations

    3/11

    namely, the set of all points whose coordinates satisfy the inequality.

    The y-axisdivide, the xy-plane into two regions, called half-planes.

    Right half-plane

    The region of points whose coordinates satisfy inequality x > 0.

    Left half-plane

    The region of points whose coordinates satisfy inequality x < 0.

    Similarly, the x-axisdivides the xy-plane into two half-planes.

    Upper half-plane

    In which inequality y > 0is true.

    Lower half-plane

    In which inequality y < 0is true.

    What is x-axis and y-axis? They are simply lines. So, the above arguments can be applied

    to any line.

    Every line ax + by = c divides the xy-plane into two regions called its half-planes.

    On one half-plane ax + by > c is true.

    On the other half-plane ax + by < c is true.

    Linear Equations

    One Unknown

    A linear equation in one unknown can always be stated into the standard form

    ax = b

    where x is an unknown and a and b are constants. If a is not equal to zero, this equation

    has a unique solution

    x = b/a

    Two Unknowns

    A linear equation in two unknown, x and y, can be put into the form

  • 8/11/2019 Linear Inequalities and Linear Equations

    4/11

    ax + by = c

    where x and y are two unknowns and a, b, c are real numbers. Also, we assume that a

    and b are no zero.

    Solution of Linear Equation

    A solution of the equation consists of a pair of number, u = (k1, k2), which satisfies the

    equation ax + by = c. Mathematically speaking, a solution consists of u = (k1, k2)

    such that ak1+ bk2= c. Solution of the equation can be found by assigning arbitrary

    values to x and solving for y ORassigning arbitrary values to y and solving for x.

    Geometrically, any solution u = (k1, k2)of the linear equation ax + by = cdetermine a

    point in the cartesian plane. Since a and b are not zero, the solution u correspond precisely

    to the points on a straight line.

    Two Equations in the Two Unknowns

    A system of two linear equations in the two unknowns x and y is

    a1x + b1x = c1a2x + b2x = c2

    Where a1, a2, b1, b2 are not zero. A pair of numbers which satisfies both equations is called

    a simultaneous solution of the given equations or a solution of the system of equations.

    Geometrically, there are three casesof a simultaneous solution

    1. If the system has exactly one solution, the graph of the linear equations intersect in

    one point.

    2. If the system has no solutions, the graphs of the linear equations are parallel.

    3. If the system has an infinite number of solutions, the graphs of the linear equations

    coincide.

    The special cases (2) and (3) can only occur when the coefficient of x and y in the two

  • 8/11/2019 Linear Inequalities and Linear Equations

    5/11

    linear equations are proportional.

    OR => a1b2-a2b1= 0 => = 0

    The system has no solution when

    The solution to system

    a1x + b1x = c1a2x + b2x = c2

    can be obtained by the elimination process, whereby reduce the system to a single equation

    in only one unknown. This is accomplished by the following algorithm

    ALGORITHM

    Step 1 Multiply the two equation by two numbers which are such that

    the resulting coefficients of one of the unknown are negative of

    each other.

    Step 2 Add the equations obtained in Step 1.

    The output of this algorithm is a linear equation in one unknown. This equation may besolved for that unknown, and the solution may be substituted in one of the original

    equations yielding the value of the other unknown.

    As an example, consider the following system

    3x + 2y = 8 ------------ (1)

    2x - 5y = -1 ------------ (2)

    Step 1: Multiply equation (1) by 2 and equation (2) by -3

  • 8/11/2019 Linear Inequalities and Linear Equations

    6/11

    6x + 4y = 16

    -6x + 15y = 3

    Step 2: Add equations, output of Step 1

    19y = 19

    Thus, we obtain an equation involving only unknown y. we solve for y to obtain

    y = 1

    Next, we substitute y =1 in equation (1) to get

    x = 2

    Therefore, x = 2 and y = 1 is the unique solutionto the system.

    n Equations in n Unknowns

    Now, consider a system of n linear equations in n unknowns

    a11x1+ a12x2+ . . . + a1nxn= b1a21x1+ a22x2+ . . . + a2nxn= b2

    . . . . . . . . . . . . . . . . . . . . . . . . .

    an1x1+ an2x2+ . . . + annxn= bn

    Where the aij, biare real numbers. The number aijis called the coefficient of xjin the i

    th

    equation, and the number biis called the constant of the ith equation. A list of values for

    the unknowns,

    x1= k1, x2= k2, . . . , xn= kn

    or equivalently, a list of n numbers

    u = (k1, k2, . . . , kn)

    is called a solution of the system if, with kj substituted for xj, the left hand side of each

    equation in fact equals the right hand side.

  • 8/11/2019 Linear Inequalities and Linear Equations

    7/11

    The above system is equivalent to the matrix equation.

    or, simply we can write A = B, where A = (a ij), = (xi), and B = (bi).

    The matrix is called the coefficient matrixof the system of n linear

    equations in the system of n unknown.

    The matrix is called the augmented matrixof n linear

    equations in n unknown.

    Note for algorithmic nerds: we store a system in the computer as its augmented matrix.

    Specifically, system is stored in computer as an N (N+1) matrix array A, the augmented

    matrix array A, the augmented matrix of the system. Therefore, the constants b1, b2, . . . ,

    bnare respectively stored as A1,N+1, A2,N+1, . . . , AN,N+1.

    Solution of a Triangular System

    If aij= 0 for i > j, then system of n linear equations in n unknown assumes the triangular

    form.

    a11x1+ a12x2+ . . . + a1,n-1xn-1 + a1nxn = b1 a22x2+ . . . + a2,n-1xn-1 + a2nxn = b2

  • 8/11/2019 Linear Inequalities and Linear Equations

    8/11

    . . . . . . . . . . . . . . . . . . . . . . . . . . . .

    an-2,n-2xn-2+ an-2,n-1xn-1 + an-2,nxn-1 + a2nxn= b2an-1,n-1xn-1+ an-1,nxn= bn-1

    amnxn= bn

    Where |A| = a11a22. . . ann; If none of the diagonal entries a11,a22, . . ., anniszero, the system has a unique solution.

    Back Substitution Method

    we obtain the solution of a triangular system by the technique of back substitution,

    consider the above general triangular system.

    1. First, we solve the last equation for the last unknown, xn;

    xn= bn/ann

    2. Second, we substitute the value of xnin the next-to-last equation and solve it for the

    next-to-last unknown, xn-1:

    .

    3. Third, we substitute these values for xnand xn-1in the third-from-last equation and solve

    it for the third-from-last unknown, xn-2:

    .

    In general, we determine xkby substituting the previously obtained values of xn, xn-1, . . . ,

    xk+1in the kthequation.

    .

  • 8/11/2019 Linear Inequalities and Linear Equations

    9/11

    Gaussian Elimination

    Gaussian elimination is a method used for finding the solution of a system of linear

    equations. This method consider of two parts.

    1. This part consists of step-by-step putting the system into triangular system.

    2. This part consists of solving the triangular system by back substitution.

    x - 3y - 2z = 6 --- (1)

    2x - 4y + 2z = 18 --- (2)

    -3x + 8y + 9z = -9 --- (3)

    First Part

    Eliminate first unknown x from the equations 2 and 3.

    (a) multiply -2 to equation (1) and add it to equation (2). Equation (2) becomes

    2y + 6z = 6

    (b) Multiply 3 to equation (1) and add it to equation (3). Equation (3) becomes

    -y + 3z = 9

    And the original system is reduced to the system

    x - 3y - 2z = 6

    2y + 6z = 6

    -y + 3z = 9

    Now, we have to remove the second unknown, y, from new equation 3, using only the

    new equation 2 and 3 (above).

    a, Multiply equation (2) by 1/2 and add it to equation (3). The equation (3) becomes 6z =

    12.

    Therefore, our given system of three linear equation of 3 unknown is reduced to thetriangular system

    x - 3y - 2z = 6

  • 8/11/2019 Linear Inequalities and Linear Equations

    10/11

    2y + 6z = 6

    6z = 12

    Second Part

    In the second part, we solve the equation byback substitutionand get

    x = 1, y = -3, z = 2

    In the first stage of the algorithm, the coefficient of x in the first equation is called the

    pivot, and in the second stage of the algorithm, the coefficient of y in the second equationis the point. Clearly, the algorithm cannot work if either pivot is zero. In such a case one

    must interchange equation so that a pivot is not zero. In fact, if one would like to code this

    algorithm, then the greatest accuracy is attained when the pivot is as large in absolute value

    as possible. For example, we would like to interchange equation 1 and equation 2 in theoriginal system in the above example before eliminating x from the second and third

    equation.

    That is, first step of the algorithm transfer system as

    2x - 4y + 2z = 18

    x - 4y + 2z = 18

    -3x + 8y + 9z = -9

    Determinants and systems of linear equations

    Consider a system of n linear equations in n unknowns. That is, for the following system

    a11x1+ a12x2+ . . . + a1nxn= b1 a21x1+ a22x2+ . . . + a2nxn= b2 . . . . . . . . . . . . . . . . . . . . . . . . .

    an1x1+ an2x2+ . . . + annxn= bn

    Let D denote the determinant of the matrix A +(aij) of coefficients; that is, let D =|A|. Also,

    let Nidenote the determinants of the matrix obtained by replacing the ithcolumn of A by

    the column of constants.

  • 8/11/2019 Linear Inequalities and Linear Equations

    11/11

    Theorem.If D 0, the above system of linear equations has the

    unique solution .

    This theorem is widely known as Cramer's rule. It is important to note that Gaussianelimination is usually much more efficient for solving systems of linear equations than is

    the use of determinants.

    http://www.personal.kent.edu/~rmuhamma/Algorithms/algorithm.html