# Kinematics JUNIOR EAMCET. Distance and Displacement O A B 4m 3m 5m O to B: distance is 7m and displacement is 5m

Mar 26, 2015

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Kinematics JUNIOR EAMCET Slide 2 Distance and Displacement O A B 4m 3m 5m O to B: distance is 7m and displacement is 5m Slide 3 Distance and Displacement O A B C 4m 3m 5m O to C along OABC: distance is 11m and displacement is 3m Slide 4 Distance and Displacement O A B C 4m 3m 5m O to O along OABCO: distance is 14m and displacement is zero Slide 5 Arc of a Circle RR A B Arc length AB is R AB jaw length is Slide 6 Average Speed and Average Velocity u v tt v s u s Both averge speed and average velocity Slide 7 Average Speed and Average Velocity v s u s Both averge speed Both averge velocity Slide 8 Train Crossing a Bridge Post Train BridgeTrain u s Time of crossing the post is Time of crossing the bridge is u s L Slide 9 Average Speed and Averge Velocity AB R Average speed = Average velocity = Average acceleration = u u Slide 10 Direction of Acceleration uv uv a a Direction of acceleration is v u Acceleration is positive if v > u Acceleration is negative if v < u Slide 11 Sign Application + g Downward direction is positive Freely falling body S, u, v, g, h are all positive Body projecte up Upward direction is positive a = g u, v, h are all positive Slide 12 Body Projected From the Top of a Tower u Upward direction is positive a = g s = h u is positive s, g are negative Slide 13 Tossing in a Train If V t = V b : a = 0; the ball falls in the hand If V t > V b : a > 0 the ball falls bedhind If V t < V b : a < 0; the ball falls in front Slide 14 V n V n-1 = a V n = u + an V n-1 = u + a(n 1) S n S n-1 = a Slide 15 u v s t Displacement = average velocity time If u = 0 Slide 16 Slide 17 A B a u A B a u A B a u A travels with acceleration a, B with uniform velocity u If they start simultaneously Time of meet is If A is ahead of B d d If B is ahead of A Slide 18 Slide 19 Slide 20 One Body Projected and the Other Falling Freely u = 0 u = u Time of meet is h Height of meet is h = h 1 + h 2 Slide 21 u u h Time taken to reach the ground is t 1 when throuwn up Time taken to reach the ground is t 2 when thrown down t1t1 t2t2 Time of free fall is Initial velocity u = Height h = Slide 22 Water Drops from the Tap h (n 1)t = t is time interval with which the drops are released Ratio of displacements of 4 th, 3 rd, 2 nd and 1 st drops is 1 : 3 : 5 : 7 Slide 23 h height of the window u velocity at the top of the window t time of crossing the window Slide 24 If the velocity is reduced by after travelling a distnce x, then the total distance it can travel is Slide 25 If th front and back of the train cross a post with velocities u and v, the center will cross the same post with velocity ---- u v x Slide 26 Graphical Representation v t Uniform velocity a a O -a 10m/s 35 7 9 -5 Slide 27 Graphical Representation v t Uniform velocity 10/3 a O -5 10m/s 35 7 9 -5 15 20 10 -5 Slide 28 Graphical Representation v tO v max Slide 29 v t O P V t Graph The slope gives acceleration Acceleration is positive if < 90 Acceleration is negative if > 90 Area represents displacement Displacement is positive if area is above x - axis Slide 30 Graphical Representation v t u constant a u = 0 a u -a O Slide 31 AB s u v Distance is 2s Displacement is zero Time for forward journey is Time for return journey is Average speed is Slide 32 u a t u a t d Slide 33 Slide 34 Equations of Motion X = a + bt + ct 2 Slide 35 Problem Find the acceleration Slide 36 Problem

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