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Jhon Alexi Ortiz Meléndez Jesús Eivar Meléndez ONCE Ing. Diego Solarte Inecuaciones
12

Jhon Alexi Melendez y Jesus Eivar Melendez

Jan 18, 2017

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Page 1: Jhon Alexi Melendez y Jesus Eivar Melendez

Jhon Alexi Ortiz MeléndezJesús Eivar Meléndez

ONCEIng. Diego Solarte

Inecuaciones

Page 2: Jhon Alexi Melendez y Jesus Eivar Melendez

INECUACIONES 1)3X+9>53X>5-93X>-4 ____-2___ -1-------0------1-----2-----X>-4/3 S= ( -1.33 + 00)X>-1.33

Page 3: Jhon Alexi Melendez y Jesus Eivar Melendez

2) 3x+6<53x<5-6 (-0,33)3x<-1 _---------- -2 ------- -1___._0____1____2___X-<1/3 S= ( -00,-0.33)X<-0.33

Page 4: Jhon Alexi Melendez y Jesus Eivar Melendez

3) 9>7-8x8x>7-98x>-2X>-2/8 (0,33)X> -1/4 _______._____0--------------1----------X>-0.25 S=(-00,25+00)

Page 5: Jhon Alexi Melendez y Jesus Eivar Melendez

4) 1/5x+9/4≥81/5x≥8-9/41/5x≥1.75 _____-6__-4__-2__0__2__4__6__8_.-------10----x≥8.75 S= [8.75 , +00)

Page 6: Jhon Alexi Melendez y Jesus Eivar Melendez

5) -8/5x-14≤3x+8-2x-3x≤8-4-5x≤4x≤4/-5 ------------.___-8__-7__-6__-4____-2___0______x≤-0.8 S=-00 , -7.5)

Page 7: Jhon Alexi Melendez y Jesus Eivar Melendez

6) -2x+4≤3x+8-2x-3x≤8-4-5x≤4x≤ (-0.8)X ≤-0.8 ------ -2------ ---- -1___0___1___ S=(-00, -0.8)

Page 8: Jhon Alexi Melendez y Jesus Eivar Melendez

7) x²-x-6<0 (x-3).(x+2)<0A= 1, b= -1 c= -b caso 1 (x-3)>0 x+2 <0(x-3) (x+2) < 0 x>3 x<-2x1-2 X1-2 = (-1)± _____0___3------- -----____-2____0 X1-2 = 1± S=01+5= = 3 = -2

Page 9: Jhon Alexi Melendez y Jesus Eivar Melendez

caso 2 (x-3)<0x+2>0x<3 2 -------0----3____ ____-2-----0---------S= (-2,3)

Page 10: Jhon Alexi Melendez y Jesus Eivar Melendez

8) x²-5x-24 0(x-8) . (x+3) ≤ 0

(x-8) __-__ -8_____0______ +___+__(x+3) _-__-_______0_-__-__3__+__+__x²-5x-240 __-___-_-_-___0__-_____+___+__S= -8,3]

Page 11: Jhon Alexi Melendez y Jesus Eivar Melendez

9) 18x-3x² >0X(18-3x) >018-3x>018>3x x__-____-_______0_____+____+____>x 6>x ____-____-______0___-__6____+___ 6 >x 18x-3x²>0___+____+_______0_____-___-____+_S= (-,0) (6+)

Page 12: Jhon Alexi Melendez y Jesus Eivar Melendez

10) 6x²-7x-3>0(x+1,5) . (x-0,33)>0

(x+1.5) ___-__-__-_____ 0__1.5__+___+__+__(x-0,33) _-__-0.33_-_____0__+__+__+___+__6x²-7x-3-<0_+__-0.33__-____0_-_1.5__+__+__+__S=(00,-0.33) (1,5+00)