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Copyright R. Janow Spring 2010 Physics 106 Final Exam When? May. 10 Tuesday, 2:30 — 5:00 pm Duration: 2.5 hours Where? ECEC-100 (SEC-008, 10) What? Phys-106 (75%), Phys-105 (25%) How? Review sessions (today’s lecture and next week’s recitation) Equation sheet Prof. Janow review session on Monday May 9, 3:00-5:00 pm in THL-2 Sample exams on my website: web.njit.edu/~cao/106 What if? 28 multiple choice problems (2.5hr/28 ~ 5 min/prob) 24 correct answers yields a score of 100% Today follows Thursday schedule: Chap. 14.1-14.5 HW13 due by 11:00 pm on May 10
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Copyright R. Janow Spring 2010 Physics 106 Final Exam When? May. 10 Tuesday, 2:30 — 5:00 pm Duration: 2.5 hours Where? ECEC-100 (SEC-008, 10)

Dec 19, 2015

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Page 1: Copyright R. Janow Spring 2010 Physics 106 Final Exam  When?  May. 10 Tuesday, 2:30 — 5:00 pm  Duration: 2.5 hours  Where?  ECEC-100 (SEC-008, 10)

Copyright R. Janow Spring 2010

Physics 106 Final Exam When?

May. 10 Tuesday, 2:30 — 5:00 pm Duration: 2.5 hours

Where? ECEC-100 (SEC-008, 10)

What? Phys-106 (75%), Phys-105 (25%)

How? Review sessions (today’s lecture and next week’s recitation) Equation sheet Prof. Janow review session on Monday May 9, 3:00-5:00 pm in THL-2 Sample exams on my website: web.njit.edu/~cao/106

What if? 28 multiple choice problems (2.5hr/28 ~ 5 min/prob) 24 correct answers yields a score of 100%

Today follows Thursday schedule: Chap. 14.1-14.5 HW13 due by 11:00 pm on May 10

Page 2: Copyright R. Janow Spring 2010 Physics 106 Final Exam  When?  May. 10 Tuesday, 2:30 — 5:00 pm  Duration: 2.5 hours  Where?  ECEC-100 (SEC-008, 10)

Copyright R. Janow Spring 2010

Physics 106 Lecture 13

Fluid Mechanics SJ 8th Ed.: Chap 14.1 to 14.5

• What is a fluid?• Pressure• Pressure varies with depth• Pascal’s principle• Methods for measuring pressure• Buoyant forces • Archimedes principle• Fluid dynamics assumptions• An ideal fluid• Continuity Equation• Bernoulli’s Equation

Page 3: Copyright R. Janow Spring 2010 Physics 106 Final Exam  When?  May. 10 Tuesday, 2:30 — 5:00 pm  Duration: 2.5 hours  Where?  ECEC-100 (SEC-008, 10)

Copyright R. Janow Spring 2010

What is a fluid?

Solids: strong intermolecular forces definite volume and shape rigid crystal lattices, as if atoms on stiff springs deforms elastically (strain) due to moderate stress

(pressure) in any direction

Fluids: substances that can “flow” no definite shape molecules are randomly arranged, held by weak cohesive intermolecular

forces and by the walls of a container liquids and gases are both fluids

Fluid Statics - fluids at rest (mechanical equilibrium)

Fluid Dynamics – fluid flow (continuity, energy conservation)

Liquids: definite volume but no definite shape often almost incompressible under pressure (from all sides) can not resist tension or shearing (crosswise) stress no long range ordering but near neighbor molecules can be held weakly together

Gases: neither volume nor shape are fixed molecules move independently of each other comparatively easy to compress: density depends on temperature and pressure

Page 4: Copyright R. Janow Spring 2010 Physics 106 Final Exam  When?  May. 10 Tuesday, 2:30 — 5:00 pm  Duration: 2.5 hours  Where?  ECEC-100 (SEC-008, 10)

Copyright R. Janow Spring 2010

Mass and Density

• Density is mass per unit volume at a point:

V

m or

V

m

• scalar• units are kg/m3, gm/cm3..• water= 1000 kg/m3= 1.0 gm/cm3

• Volume and density vary with temperature - slightly in liquids• The average molecular spacing in gases is much greater than in liquids.

Page 5: Copyright R. Janow Spring 2010 Physics 106 Final Exam  When?  May. 10 Tuesday, 2:30 — 5:00 pm  Duration: 2.5 hours  Where?  ECEC-100 (SEC-008, 10)

Copyright R. Janow Spring 2010

Force & Pressure

• Pressure is a scalar while force is a vector

• The direction of the force producing a pressure is perpendicular to some area of interest

n̂APAPF

• The pressure P on a “small” area A is the ratio of the magnitude of the net force to the area

A/FP or A

F P

n̂PA

• At a point in a fluid (in mechanical equilibrium) the pressure is the same in any directionh

Pressure units: 1 Pascal (Pa) = 1 Newton/m2 (SI) 1 PSI (Pound/sq. in) = 6894 Pa. 1 milli-bar = 100 Pa.

Page 6: Copyright R. Janow Spring 2010 Physics 106 Final Exam  When?  May. 10 Tuesday, 2:30 — 5:00 pm  Duration: 2.5 hours  Where?  ECEC-100 (SEC-008, 10)

Copyright R. Janow Spring 2010

Forces/Stresses in Fluids

• Fluids do not allow shearing stresses or tensile stresses.

Tension Shear Compression

• The only stress that can be exerted on an object submerged in a static fluid is one that tends to compress the object from all sides

• The force exerted by a static fluid on an object is always perpendicular to the surfaces of the object

Question: Why can you push a pin easily into a potato, say, using very little force, but your finger alone can not push into the skin even if you push very hard?

Page 7: Copyright R. Janow Spring 2010 Physics 106 Final Exam  When?  May. 10 Tuesday, 2:30 — 5:00 pm  Duration: 2.5 hours  Where?  ECEC-100 (SEC-008, 10)

Copyright R. Janow Spring 2010

Pressure in a fluid varies with depth

Fluid is in static equilibrium The net force on the shaded volume = 0

• Incompressible liquid - constant density • Horizontal surface areas = A• Forces on the shaded region:

– Weight of shaded fluid: Mg

– Downward force on top: F1 =P1A

– Upward force on bottom: F2 = P2A

y1

y2 Mg

F1

F2

y=0

P1

P2

h

MgAPAP F 2y 10

AhVM

• In terms of density, the mass of the shaded fluid is:

The extra pressure at extra depth h is:

ghPPP 12

yyh 21 ghAAP AP 2 1

Page 8: Copyright R. Janow Spring 2010 Physics 106 Final Exam  When?  May. 10 Tuesday, 2:30 — 5:00 pm  Duration: 2.5 hours  Where?  ECEC-100 (SEC-008, 10)

Copyright R. Janow Spring 2010

Pressure relative to the surface of a liquid

ghPP h 0

All points at the same depth are at the same pressure; otherwise, the fluid could not be in equilibrium

The pressure at depth h does not depend on the shape of the container holding the fluid

air

Ph

P0

liquid

h

Example: The pressure at depth h is:

P0 is the local atmospheric (or ambient) pressure

Ph is the absolute pressure at depth h

The difference is called the gauge pressure

P0

Ph

Preceding equations also hold approximately for gases such as air if the density does not vary much across h

Page 9: Copyright R. Janow Spring 2010 Physics 106 Final Exam  When?  May. 10 Tuesday, 2:30 — 5:00 pm  Duration: 2.5 hours  Where?  ECEC-100 (SEC-008, 10)

Copyright R. Janow Spring 2010

Atmospheric pressure and units conversions

• P0 is the atmospheric pressure if the liquid is open to the atmosphere.

• Atmospheric pressure varies locally due to altitude, temperature, motion of air masses, other factors.

• Sea level atmospheric pressure P0 = 1.00 atm

= 1.01325 x 105 Pa = 101.325 kPa = 1013.25 mb (millibars)

= 29.9213” Hg = 760.00 mmHg ~ 760.00 Torr

= 14.696 psi (pounds per square inch)

Pascal (Pa)

bar (bar) atmosphere(atm)

torr(Torr)

pound-force persquare inch (psi)

1 Pa ≡ 1 N/m2 10−5 9.8692×10−6 7.5006×10−3 145.04×10−6

1 bar 100,000 ≡ 106  dyn/cm2 0.98692 750.06 14.5037744

1 atm 101,325 1.01325 ≡ 1 atm 760 14.696

1 torr 133.322 1.3332×10−3 1.3158×10−3 ≡ 1 Torr; ≈ 1 mmHg

19.337×10−3

1 psi 6.894×103 68.948×10−3 68.046×10−3 51.715 ≡ 1 lbf/in2

Page 10: Copyright R. Janow Spring 2010 Physics 106 Final Exam  When?  May. 10 Tuesday, 2:30 — 5:00 pm  Duration: 2.5 hours  Where?  ECEC-100 (SEC-008, 10)

Copyright R. Janow Spring 2010

Pressure Measurement: Barometer

• Invented by Torricelli (1608-47)• Measures atmospheric pressure P0 as it varies

with the weather• The closed end is nearly a vacuum (P = 0)• One standard atm = 1.013 x 105 Pa.

Mercury (Hg)

near-vacuum

ghP Hg

0

One 1 atm = 760 mm of Hg = 29.92 inches of Hg

m 0.760 )m/s .)(m/kg10(13.6

Pa 101.013

g

Ph

23

5

Hg

80930

How high is the Mercury column?

m 10.34 )m/s .)(m/kg10(1.0

Pa 101.013

g

Ph

23

5

water

8093

0

How high would a water column be?

Height limit for a suction pump

Page 11: Copyright R. Janow Spring 2010 Physics 106 Final Exam  When?  May. 10 Tuesday, 2:30 — 5:00 pm  Duration: 2.5 hours  Where?  ECEC-100 (SEC-008, 10)

Copyright R. Janow Spring 2010

Pascal’s Principle

• The pressure in a fluid depends on depth h and on the value of P0 at the surface

• All points at the same depth have the same pressure.

A change in the pressure applied to an enclosed incompressible fluid is transmitted undiminished to every point of the fluid and to the walls of the container.

Example: open container

ghPP h 0

FP

p0

ph

• Add piston of area A with lead balls on it & weight W. Pressure at surface increases by P = W/A

gh P P exth

• Pressure at every other point in the fluid (Pascal’s law), increases by the same amount, including all locations at depth h.

PPP ext 0

Ph

Page 12: Copyright R. Janow Spring 2010 Physics 106 Final Exam  When?  May. 10 Tuesday, 2:30 — 5:00 pm  Duration: 2.5 hours  Where?  ECEC-100 (SEC-008, 10)

Copyright R. Janow Spring 2010

Pascal’s Law Device - Hydraulic pressA small input force generates a large output force

xA xA 21 21

xF Work xF Work 2 21 211

• Assume no loss of energy in the fluid, no friction, etc.

• Assume the working fluid is incompressible• Neglect the (small here) effect of height on pressure

• The volume of liquid pushed down on the left equals the volume pushed up on the right, so:

Other hydraulic lever devices using Pascal’s Law:• Squeezing a toothpaste

tube• Hydraulic brakes• Hydraulic jacks• Forklifts, backhoes

A

A

x

x

1

2

2

1

A

A

x

x

F

F

2

1

1

2

1

2

mechanical advantage

Page 13: Copyright R. Janow Spring 2010 Physics 106 Final Exam  When?  May. 10 Tuesday, 2:30 — 5:00 pm  Duration: 2.5 hours  Where?  ECEC-100 (SEC-008, 10)

Copyright R. Janow Spring 2010

Archimedes Principle C. 287 – 212 BC• Greek mathematician, physicist and engineer• Computed and volumes of solids• Inventor of catapults, levers, screws, etc.• Discovered nature of buoyant force – Eureka!

Why do ships float and sometimes sink?Why do objects weigh less when submerged in a fluid?

• An object immersed in a fluid feels an upward buoyant force that equals the weight of the fluid displaced by the object. Archimedes’s Principle– The fluid pressure increases with depth and exerts forces that are the same

whether the submerged object is there or not. – Buoyant forces do not depend on the composition of submerged objects. – Buoyant forces depend on the density of the liquid and g.

ball of liquidin equilibrium

hollow ball same

upward force

identical pressures at every point

Page 14: Copyright R. Janow Spring 2010 Physics 106 Final Exam  When?  May. 10 Tuesday, 2:30 — 5:00 pm  Duration: 2.5 hours  Where?  ECEC-100 (SEC-008, 10)

Copyright R. Janow Spring 2010

Archimedes’s principle - submerged cube

• The pressure at the top of the cube causes a downward force of Ptop A

• The larger pressure at the bottom of the cube causes an upward force of Pbot A

• The upward buoyant force B is the weight of the fluid displaced by the cube:

• The extra pressure at the lower surface compared to the top is:

fltopbot ghPPP

gMgVghAPA B flfl fl

A cube that may be hollow or made of some material is submerged in a fluidDoes it float up or sink down in the liquid?

• The weight of the actual cube is:

gV gM F cubecubeg

Similarly for irregularly shaped objects

cube is the average density

The cube rises if B > Fg (fl > cube)The cube sinks if Fg> B (cube > fl)

Page 15: Copyright R. Janow Spring 2010 Physics 106 Final Exam  When?  May. 10 Tuesday, 2:30 — 5:00 pm  Duration: 2.5 hours  Where?  ECEC-100 (SEC-008, 10)

Copyright R. Janow Spring 2010

Archimedes's Principle: totally submerged object

Object – any shape - is totally submerged in a fluid of density fluid

The direction of the motion of an object in a fluid is determined only by the densities of the fluid and the object– If the density of the object is less than

the density of the fluid, the unsupported object accelerates upward

– If the density of the object is more than the density of the fluid, the unsupported object sinks

The apparent weight is the external force needed to restore equilibrium, i.e.

netgapparent F B F W

The upward buoyant force is the weight of displaced fluid:

fluiduidfl gV B The downward gravitational force on the object is:

objectobjectobjectg gV gM F The volume of fluid displaced and the object’s volume are equal for a totally submerged object. The net force is:

objectobjectuidfl[ gnet V g ] FBF

Page 16: Copyright R. Janow Spring 2010 Physics 106 Final Exam  When?  May. 10 Tuesday, 2:30 — 5:00 pm  Duration: 2.5 hours  Where?  ECEC-100 (SEC-008, 10)

Copyright R. Janow Spring 2010

Archimedes’s Principle: floating object

ggnet F B 0 FBF

At equilibrium the upward buoyant force is balanced by the downward weight of the object:

An object sinks or rises in the fluid until it reaches equilibrium. The fluid displaced is a fraction of the object’s volume.

The volume of fluid displaced Vfluid corresponds to the portion of the object’s volume below the fluid level and is always less than the object’s volume.

Equate:

objectobjectgfluiduidfl gVFgV B

Solving:

objectobjectfluiduidfl VV

V

V

uidfl

object

object

fluid

Objects float when their average density is less than the density of the fluid they are in. The ratio of densities equals the fraction of the object’s volume that is below the surface

Page 17: Copyright R. Janow Spring 2010 Physics 106 Final Exam  When?  May. 10 Tuesday, 2:30 — 5:00 pm  Duration: 2.5 hours  Where?  ECEC-100 (SEC-008, 10)

Copyright R. Janow Spring 2010

Example: What fraction of an iceberg is underwater?

V

V

V

V

uidfl

object

object

fluid total

underwater

displaced seawater

glacial fresh water ice

Apply Archimedes’ Principle

3iceobject kg/m . 3109170

3seawaterfluid kg/m . 310031

From table:

%. V

V

total

underwater 0389

What if iceberg is in a freshwater lake?3

freshwaterfluid kg/m . 310001

1.7% V

V

total

underwater 9

Water expands when it freezes. If not.......ponds, lakes, seas freeze to the bottom in winter

Floating objects are more buoyant in saltwaterFreshwater tends to float on top of seawater...

Page 18: Copyright R. Janow Spring 2010 Physics 106 Final Exam  When?  May. 10 Tuesday, 2:30 — 5:00 pm  Duration: 2.5 hours  Where?  ECEC-100 (SEC-008, 10)

Copyright R. Janow Spring 2010

Fluids’ Flow is affected by their viscosity

• Viscosity measures the internal friction in a fluid.

• Viscous forces depend on the resistance that two adjacent layers of fluid have to relative motion.

• Part of the kinetic energy of a fluid is converted to internal energy, analogous to friction for sliding surfaces

Low viscosity• gases

Medium viscosity• water• other fluids that pour and flow easily

High viscosity• honey• oil and grease• glass

Ideal Fluids – four approximations to simplify the analysis of fluid flow:

• The fluid is nonviscous – internal friction is neglected• The flow is laminar (steady, streamline flow) – all particles

passing through a point have the same velocity at any time.• The fluid is incompressible – the density remains constant• The flow is irrotational – the fluid has no angular momentum

about any point. A small paddle wheel placed anywhere does not feel a torque and rotate

Page 19: Copyright R. Janow Spring 2010 Physics 106 Final Exam  When?  May. 10 Tuesday, 2:30 — 5:00 pm  Duration: 2.5 hours  Where?  ECEC-100 (SEC-008, 10)

Copyright R. Janow Spring 2010

Flow of an ideal fluid through a short section of pipe

Constant density and velocity within volume element dV Incompressible fluid means d/dt = 0

Mass flow rate = amount of mass crossing area A per unit time = a “current”sometimes called a “mass flux”

length dx

velocity v

cross-section area A

Av dt

dxA

)V(dt

d

dt

dM I rateflow massmass

AdxdV cylinder in fluid fo volume

Av I rateflow massmass

Av I rateflow volumevol

v J areaflow/unit massmass

Page 20: Copyright R. Janow Spring 2010 Physics 106 Final Exam  When?  May. 10 Tuesday, 2:30 — 5:00 pm  Duration: 2.5 hours  Where?  ECEC-100 (SEC-008, 10)

Copyright R. Janow Spring 2010

Equation of Continuity: conservation of mass• An ideal fluid is moving through a pipe of nonuniform diameter• The particles move along streamlines in steady-state flow• The mass entering at point 1 cannot disappear or collect in the pipe

• The mass that crosses A1 in some time interval is the same as the mass that crosses A2 in the same time interval.

1

2

222111 vA vA outflow massinflow mass • The fluid is incompressible so:

ttancons a 21

vA vA 2211

• This is called the equation of continuity for an incompressible fluid

• The product of the area and the fluid speed (volume flux) at all points along a pipe is constant.

The rate of fluid volume entering one end equals the volume leaving at the other endWhere the pipe narrows (constriction), the fluid moves faster, and vice versa