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Thermochemistry study of heat changes in
chemical reactions
Specific heat (s) = cal or jouleg x C g x C
- amount of heat needed to raise the temperature of
one gram of substance by 1 C
ex. specific heat of NaCl = 0.204 cal
g x C
sp heat of H2O = 1.00 cal or 4.18
g x C g x C1 cal = 4.18 joules
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Heat capacity (C) - amount of heat needed to
raise the temperature of a given amount of
substance by 1 C
C = m x s
= g x cal = calg xC C
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Problem 1
If 8.5 g of metal, initially at 82 C is placed in 45.0 mL H2O at
20 C and the final temperature of metal and H2
O is 22C.
Calculate the specific heat (s) of the metal in cal/g x C
q metal = - q water
q metal = m x s x t = - q water = - (m x s x t )
Heat given off by the metal = heat absorbed by the H2O
45g x 1cal/ g x C x (22-20 C) = -90 calories absorbed by
the H2O
s metal = - 90 cal = 0.18 cal
(8.5g)x -60 C g x C
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Problem 2
How many calories would be required to raise
the temperature of 45 g NaCl from 25 C to 85C. The sp heat of NaCl is 0.204 cal/ g x C
q NaCl = m x s x t
45g x 0.204 cal x 60 C = 551 calories
g x C
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Problem 3
Calculate the no. of joules of heat required to raise the
temp. of 125 g of Ag from 100 C to 250 C. The sp heat of
Ag is 2.34 x 102 joule/ kg x K
q Ag = m x s x t
125 g x 1 kg x 2.34 x 102
j x 150K = 4.39 x 102
j1000 g kg x K
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Enthalphy (H) = heat change or change in heat
content in a chemical reaction
H rxn = Hf products - Hf reactants
Q (Heat flow) in a reaction at constant
pressure = H for the reaction(Hrxn)
Hf of a compound, is the Hrxn to form one mole of the
compound from the elements in the standard state.
* The heat content of a free element in the std.state is zero
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Prob. 4
2C2H6 (g) + 7O2(g) 4CO2 (g) + 6H2O + 750 kcal or
3135 kja.Is the reaction exothermic or endothermic?
Exothermic rxn. (heat is given off)
A + B C + D + kj. (heat)
A + B C + D
H = - kcal or kj
Endothermic rxn. (heat is absorbed)
A + B + heat C + D
or A + B C + D
H = kcal or kj
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2C2H6 (g) + 7O2(g) 4CO2 (g) + 6H2O + 750 kcal or
3135 kj
a. Is the reaction exothermic or endothermic?
b. What is the Hrxn ?
Hrxn = -750 kcal or -3135 kj
c. What is the Hrxn for the reverse reaction?
Hrxn =750 kcal or 3135kj
d. What is the heat flow (Q) if the total equation isdivided by 2 ?
(Q) = -750/2 = - 375kcal
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Problem 5
Calculate the Hrxn:
H rxn = Hf products - Hf reactants
2 CH3OH (l) + 3O2(g) 2CO2 (g) + 4H2O (g)
Hf (kcal/mole) ( -57.0) (-94.1) (-57.8)
H rxn = Hf products - Hf reactants
Hrxn = 2 (Hf CO2) + 4(Hf H2O) 2n(HfCH3OH)
= 2 n (-94.1 ) + 4n (-68.3) 2n (-57.0)
= - 347.4 kcal
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Problem 6
Calculate the amount of heat produced from the
combustion of 10.0g C2H6 (w/c burns in O2)
10.0g C2H6 x 1mole C2H6 x 750kcal
30g C2H6 2 mole C2H6
=125 kcal or 522kj
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Problem 7