Q2. a) m w =m M −m B V M = m w ρ w + m B ρ B V M = m M −m B ρ w + m B ρ B V M = ( m M −m B ) ρ B +m B ρ w ρ B ρ w m B = m M ρ B −V M ρ B ρ w ρ B −ρ w m M =V M ρ M m B = V M ρ M ρ B −V M ρ B ρ w ρ B −ρ w = V M ρ B ( ρ M −ρ w ) ρ B − ρ w = 32 × 4200 ( 1600−1000) 4200−1000 ¿ 25,200 Kg V w = V M − m B ρ B =32− 25,200 4,200 ¿ 26 m 3 c)
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La Luna
Barinas
Q2. a)
mw=mM−mB
V M=mw
ρw+mB
ρB
V M=mM−mB
ρw+mB
ρB
V M=(mM−mB ) ρB+mB ρw
ρB ρw
mB=mM ρB−V M ρB ρw
ρB−ρw
mM=VM ρM
mB=V M ρM ρB−V M ρB ρw
ρB− ρw=V M ρB (ρM−ρw )
ρB− ρw=
32×4200 (1600−1000 )4200−1000
¿25,200Kg
V w=VM−mB
ρB=32−25,200
4,200 ¿26m3
c)
10 ; 40 ; 59 ; 922.4 ; 2.7 ; 2.87
2 ; 4
(i) La Luna
V sh=GR sh−GR zone
GRsh−GRsand
=92−5992−10
=0.4
Barinas
V sh=GR sh−GR zone
GRsh−GRsand
=9 2−4092−10
=0.6
(ii) La Luna
∅=ρma−ρbρma− ρf
=2.87−2.72.87−1
=0.09
Barinas
∅=ρma−ρbρma− ρf
=2.87−2.42.87−1
=0.25
(iii)
For La Luna: from the graph at ρ = 2.7 and PET = 4;
Ø = 5%
For Barinas: from the graph at ρ = 2.4 and PET = 2;
Ø = 18%
(iv)
For La Luna: from the graph at ρ = 2.7 and PET = 4;
Lithology: Limestone/Dolomite
For Barinas: from the graph at ρ = 2.4 and PET = 2;
Lithology: Sandstone
Q3. c)(i)
∅=ρma−ρbρma− ρf
=2670−23102670−1000
=0.216
∅=∆ t log−∆ tma∆ t f−∆ tma
=2.76×10−4− 1
54721
1642−
15472
=0.219
(ii)
Sw=1.65√ a×Rw
∅m×R t
=1.65√ 1.37×0.04
0.2161.8×27=0.124
Q4. a) W air=L×W Nom=30×19.5¿585 lb
W=585×1.103¿645.3 lb
b) From the table at density of 1438 kgm-3: buoyancy factor = 0.8172