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Jul 16, 2015
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Classroom Rules:2. I talk, you listen
3. I don’t allow:A. Heads on deskB. Feet on deskC. Going to sleep in classD. MP3 players
4. Mobile phones are to be off, or on “silent” unless OK’d with me, and in you bag (not on desk)
5. Should they be OK’d, and you receive a call, you will answer it outside the classroom
6. No SMS-ing in class
7. Keith Butler’s number is: 0417 637 909
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Topics (from Learning Outcomes)
10. Three-phase synchronous machines • operating principles • construction feature • application
11. Three-phase synchronous machines • effects of load changes • effects of excitation change • load/current characteristics
12. Single phase synchronous machines • alternators • motors • applications
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Assessment
(a)All prac’s must be completed• A final written exam will be given on the
learning outcomes covered. Should a student fail, they will be allowed one further attempt during block. Should they fail this they will be allowed one further attempt within six weeks of completing the block. Should they fail this they will be in a “Show Cause” situation.
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6500 KW Genset / Generator Set, powered with a Cummins VTA28G1 Engine
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2 x 14MW Synchronous Motors…apparently, they use permanent magnets!
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3 phase Dunlite machine
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Synchronous machines are not just the big units, but they can
be small also.
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V
AC Supply R
VI
I
Current is in phasewith voltage.
Time->
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LAC supply
V
I V
I
Current lags theVoltage by 90o
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CAC Supply
But if an ammeter were placed in series it would most definitely read a current.
Current appears to pass through the capacitor.In reality, it is charging in one direction, and thendischarging and recharging in the other direction.
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V I
CAC Supply
V
I
Current leads theVoltage by 90o
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This opposition to current flow is called:Inductive reactance, in inductors. (XL)Capacitive reactance in capacitors. (XC)
Both Inductors and Capacitors oppose, or “resist” current flow when connected to AC supplies.
While it opposes current flow, it is NOT called resistance.
Current flow through resistance produces HEAT. Current flow in inductors and capacitors doesn’t!
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Generator / Transformer / Motor
S F
S
F
S
F S F
S F
S F
B
A
C
AC
B
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AC
B
Motor
Why isn’t a neutral run to a balanced three phase Star connected load?
A
BC
N?????
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AC
B
Motor
Because the Star point is at 0V
A
BC
0V0VN
And the neutral is at zero volts also.So if they were joined no current would flow.
0A
So why join it?
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AC
B
MotorA
BC
The neutral is not connected to a balanced three phase star connected load.
Only connected to unbalanced loads!!!
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Transformer
S FB
S FC
Generator / Transformer / Motor
AB C
F
S F
S
FS
S FA
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Transformer
SFB
SFC
Generator / Transformer / Motor
AB C
S
F S
F
SF
SFA
Swapped
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3-phase Transformer Secondary
S FB CS F
A S F
A B C
Note that all windings are connected in series, with the twoends joined together.
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If we did that with three batteries, there would be majorproblems!
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The voltmeter should read the sum of the three voltages?Right?
VA
VBVC
AC B
F
S F
S
FS
Transformer
V
The voltmeter reads the phasor sum of the voltages.
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The voltmeter reads, in effect, the distance between thebeginning of VA and the end of VC. ie. 0V
VA
VBVC
AC B
F
S F
S
FS
Transformer
V
We can connect the two ends together because the phasor sum adds up to zero!
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Transformer
VA
VBVC
AC B
F
S F
S
FS
The voltmeter reads, in effect, the distance between thebeginning of VA and the end of VC. ie. 0V
We can connect the two ends together because the phasor sum adds up to zero!
No Arc!
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Generator Load
STARVL = 3 VPH
IL = IPH
DELTAIL = 3 IPH
VL = VPH
P = 3 x VPH x IPH x Cos = 3 x VL/3 x IL x Cos = 3/3 x VL x IL x Cos = 3 VL x IL x Cos
P = 3 x VPH x IPH x Cos = 3 x VLx IL/3 x Cos = 3/3 x VL x IL x Cos = 3 VL x IL x Cos
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P = 3 VL x IL x Cos
NOT:P = 415 x I x pf.
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Three Single Phase Power Equations:
True Power = Watts = V x I x Cos
Apparent Power = VA = V x I
Reactive Power = VAR’s = V x I x Sin
Power Factor = Cos where Cos = Cosine of the angle
between Voltage and Current
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VA
Watts
Var’s
Phase angle between current and volts
This can be put as a triangle:
VA2 = Watts2 + Var’s2
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V=240V
Alternators, where the windings are limited by the current through them, are rated in VA.
To rate them in watts, (ie. watts delivered to the load) would give no idea of the current through them.
Load 3 = 14.14A at 45º
Load 1 = 10A
Load 2 = 20A at 60º
P = V x I x Cos 45º = 240 x 14.14 x 0.707 = 2.4kW
P = V x I x Cos 0º = 240 x 10 x 1 = 2.4kW
P = V x I x Cos 60º = 240 x 20 x 0.5 = 2.4kW
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Q What dictates the phase angle of the current supplied by a single alternator supplying a single load?
V=240V
Load 3 = 14.14A at 45º
Load 1 = 10A
Load 2 = 20A at 60º
P = V x I x Cos 45º = 240 x 14.14 x 0.707 = 2.4kW
P = V x I x Cos 0º = 240 x 10 x 1 = 2.4kW
P = V x I x Cos 60º = 240 x 20 x 0.5 = 2.4kW
A The load
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V
Al currents here take the same power
Constant power line
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V
Al currents here take the same power
Higher power
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V
Al currents here take the same power
Constant power line
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V
Al currents here take the same power
Lower power
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Alternator
Mechanical Energy Electrical Energy
Losses
AlternatorPrime Mover
- Diesel Engine- Steam Turbine- Small petrol engine
Alternator: PoutEff% = x 100 Pin
Alternator:Pin = Pout + Losses
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Losses
Synchronous Motor
Mechanical Energy MSBElectrical Energy
Motor: PoutEff% = x 100 Pin
MotorPin = Pout + Losses
Motor Load
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Synchronous Machine
Stator- Identically wound to an induction motor.- Connected to supply.
Rotor- Constant DC field- Connected to supply via sliprings.
ElectricalPower
DCSupply
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• The stator produces a rotating magnetic field exactly the same as an induction motor.
• The rotor is a magnet and locks in to the RMF• Rotor travels at SYNCHRONOUS SPEED.
SYNCHRONOUSMOTOR
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Synchronous Machine
If a synchronous motor is OVER driven by the load (eg electric train going down a hill), then it will generate power, still at synchronous speed.
If an alternator coupled to the grid is UNDER driven by the prime mover (eg steam stops), then it will motor, and drive the turbine at synchronous speed.
ElectricalPower
DCSupply
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Synchronous Machine
In other words, the two machines are identical in construction.
ElectricalPower
DCSupply
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3000RPM 1500RPM 1000RPM 750RPM
185kw 310A, .88pf 315A, .86pf 343A, .80pf 348A, .78pf
220kw 362A, .89pf 375A, .86pf 408A, .78pf 412A, .78pf
150kw 242A, .90pf 265A, .87pf 279A, .80pf 278A, .77pf
Lower the RPM, • Larger value IS
• More lagging IS
Characteristic of WEG® Induction Motors.
110kw 182A, .90pf 200A, .84pf 205A, .80pf 203A, .81pf
22kw 39A, .87pf 41A, .83pf 42A, .80pf 47A, .74pf
4kw 7.8A, .87pf 8.2A, .82pf 9A, .74pf 11A, .63pf
What is thetendency as RPM gets lower?
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So why use a Synchronous Motor?Uses:– Low Speed Drives. Low speed induction motors
draw very large currents at poor power factors. This cannot be altered or corrected. In synchronous motors, the p.f. can be altered to cause the motor to draw minimum current. (The alternative is to use a high speed induction motor through a gearbox.)
– Power Factor Correction– Constant Speed drives
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Salient Pole Rotor Cylindrical Rotor
2 basic types:Cylindrical rotorSalient Pole
-Low speed-Diesel Prime Mover-Hydro systems
-High speed-Steam Turbine
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Small salient pole synchronous machine rotor
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Losses
Synchronous Motor
Mechanical Energy MSBElectrical Energy
Motor: PoutEff% = x 100 Pin
MotorPin = Pout + Losses
Motor Load
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Same as an induction motor.
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A1
A2
2-Pole Machineie. 3000RPM
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A1
A2
B1B2
C1
C2
2-Pole Machineie. 3000RPM
In reality, the coilsspan more slots in a 2-pole motor.
N
S
Notice that for a two pole stator we have a 2-pole rotor
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N N
S
S
A
A
AA
B
B
B
B
C
C
C
C
4-pole machine
A four pole stator must have a four
pole rotor
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Flux+
-Time->
1
Resultant flux = 1.5 x flux of one phase
N
S
N
S
S
N
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Flux+
-Time->
2
Resultant flux = 1.5 x flux of one phase
N
S
N
S
N
S
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Flux+
-Time->
3 4 5 6
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Flux+
-Time->
3 4 5 61 2
So the flux rotates one full rev in one cycle, for our two pole machine.
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Flux+
-Time->
3 4 5 61 2
Because the flux is a constant value, it gives: 1. Very quiet operation 2. Constant torque as the rotor rotates.
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Flux+
-Time->
3 4 5 61 2
This rotating magnetic field rotates at:3000RPM for a 2-pole motor1500RPM for a 4-pole motor
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Flux+
-Time->
3 4 5 61 2
To reverse the direction of rotation:reverse any two phases to the motor.
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where N = RPM f = frequency P = Number of poles (per phase).
N = 120f/P
So the speed of the rotating magnetic field isaffected by:
Frequency, andNumber of poles.
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As the rotating magnetic field rotates, the rotor is locked in synchronism with it and is dragged along for the ride.
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N
S
As the rotating magnetic field rotates, the rotor is locked in synchronism with it and is dragged along for the ride.
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What will happen as a load is put on the shaft?
N
S
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N
S
What will happen as a load is put on the shaft?
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The load tries to slow it down.But it must do synchronous speed!So it stretches the lines of flux.
N
S
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N
S
C/L of RMF
C/L of Rotor Field
Torque Angle
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If the lines stretch to breaking point (ie too much load), then the rotor stalls
This is referred to as “Pull Out Torque”.
N
S
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What would the Torque Curve look like?
RPMNs0
Torque Curve for an induction motor
Torque
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What would the Torque Curve look like?
Torque
RPMNs0
Torque “Curve” for a Synchronous Motor
Pull outTorque
Zero Torque below synchronous speed
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1. Amortisseur winding
Starting a Synchronous Motor?
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Rotor Construction
Squirrel Cage
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Starting a Synchronous Motor?
1. Amortisseur windingThis gets the motor up to speed as an induction motor. When it is close to synchronous speed it will lock in.
2. Shorting the rotor DC winding and starting it as a wound rotor motor. When it is close to synchronous speed, the short is removed and DC is applied to the rotor. It will (hopefully) lock in.
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3. Using a pony motor to get the synchronous motor up to speed, then applying AC to the stator and DC to the rotor.(Not applicable if there is a high starting torque load connected)
Note that these starting methods will only work if the load on the motor at start can be reduced or eliminated.
Starting a Synchronous Motor?
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• Amortisseur windings also reduce hunting.
• Hunting is rhythmic fluctuations of the RPM around an average value.
• If not subdued, hunting can cause the rotor to swing out of synchronism.
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Revs
Time
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N
S
N
S
N
S
N
S
N
S
And all this while it is whizzing around at synchronous speed!
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And all this while it is whizzing around at synchronous speed!
N
S
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VsupplyVinduced
Induced in the stator from the rotor
Phasor Diagram of Synchronous Motor
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Vsupply
Vinduced
Torque angle
Isupply
VR
Phasor Diagram of Synchronous Motor
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Phasor diagram for increased load:(Excitation current held constant)
Vsupply
Vinduced
Isupply
VR
Increased load = Increased Torque Angle
Vinduced
Increasing the load increases the power taken from supply
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Vsupply
Vinduced
Vinduced
Phasor diagram for increased excitation:(Constant Load)
Constant load = Constant Power line
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Phasor diagram for increased excitation:(Constant Load)
Vsupply
Vinduced
Constant load = Constant Power line
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Vsupply
Phasor diagram for increased excitation:(Constant Load)
Vinduced VRIsupply
So to force the supply current leading, we INCREASE excitation
Constant load = Constant Power line
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Vsupply
Vinduced
Isupply
VR
Phasor diagram for decreased excitation:(Constant Load)
Constant load = Constant Power line
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Vsupply
Isupply
VR
Phasor diagram for decreased excitation:(Constant Load)
Vinduced
So to force the supply current lagging, we DECREASE excitation
Constant load = Constant Power line
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Vsupply
Vinduced
IsupplyVR
Vsupply
Isupply
VRVinduced
Vinduced
Isupply
VR
Constant load = Constant Power line
Vsupply
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Vsupply
With a constant load, changing excitation changesthe phase angle and value of supply current.
Isupply
By increasing the DC excitation current to the rotor,the synchronous motor can act as a capacitorIt can be used for power factor correction.
Constant load = Constant Power line
120Excitation Current
Stat
or C
urre
nt
50% lo
ad
Unity pf
Lag Lead
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Deductions From Vee Curves
• At any particular load there is a certain value of rotor current which gives a minimum value of stator current and unity pf.
• If the rotor current is altered either way, the stator current will increase, and pf will decrease away from 1.
• For any given load there is a certain value of rotor current below which the rotor will fall out of synchronism.
• For any given load there are two values of rotor current that will give identical values of stator current. The lower value gives a lagging pf, and the higher value gives a leading pf.
122Excitation Current
Stat
or C
urre
nt
50% lo
ad
LagLead
75% lo
adStabilitylimit pf=1
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0.8 pf lag Unity 0.8 pf leadPer unitPower output
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Points:
• At a set load there is a value of excitation that will give minimum line current.
• Reducing OR increasing excitation from this value will only increase line current.
• At any other value of line current, there are two values of excitation current that can produce this.
• If a synchronous motor is heavily loaded, supply current may not be able to be driven highly leading.
• If a synchronous motor is lightly loaded, supply current can be driven highly leading.
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Single Phase Synchronous Motors• Used when constant speed is critical, with low
torque requirements. They have low efficiency, hence made in small sizes.
• Application:• clocks• record players• timers• recorders• communications• servo installations
• Two main types:• Reluctance motor• Hysteresis motor
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Reluctance Motor
Stator• Stator same as a single phase, split
phase motor.• Centrifugal Switch operates at
75% synchronous speed to open circuit the start winding.
Rotor• Assembled from laminated sheets
with defined teeth cut away. This forms salient poles.
• Windings are of the squirrel-cage type.
• Number of rotor poles equals the number of stator poles.
Two pole, 3000 RPM rotor
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Reluctance Motor• Operation
– Starts as an induction motor, with slip.– A single phase stator has a “Start” and “Run” winding. At
75% centrifugal the centrifugal switch operates.– As the load is light there is small slip– The salient poles become permanently magnetised by the
stator field– The salient poles will then lock to the stator field.– Once locked into synchronism the motor will continue to
operate at synchronous speed.– Not as much power output as a similar physical size 1-phase
motor.
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Hysteresis MotorRotor• Constructed from hardened steel rings, instead of thin,
magnetically soft, silicon steel laminations.• “Hysteresis” opposes any change once the flux is created, so
the rotor will lock into the RMF like a permanent magnet.Stator• Often a shaded pole stator principle is used.• If the shaded pole principle is used then the motor is self
starting.• Magnetic poles are established in the rotor.• These poles lock to the stator poles.• The rotor runs at synchronous speed determined by the
poles and frequency.
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Why generate AC?… Why not DC?
DC cant be “transformed” through a transformer. AC can go through a transformer.
Large brushless DC generators are not possibleLarge brushless AC alternators are!
Why do we want to transform it?It is easier to transmit to distant placesat higher voltages as the current will be lower. (P=V x I)
Induction motors are simpler and cheaper thanDC motors
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NS
V
Generating an AC Voltage
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N S
Generating an AC Voltage
Volts
+
-
Time->
136
NS
Generating an AC Voltage
Volts
+
-
Time->
137
NS
Generating an AC Voltage
Volts
+
-
Time->
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NS
Generating an AC Voltage
Volts
+
-
Time->
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N S
Generating an AC Voltage
Volts
+
-
Time->
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NS
Generating an AC Voltage
Volts
+
-
Time->
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NS
V
Generating a AC Voltage3-Phase
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N S
Volts
+
-
Time->
Generating a AC Voltage3-Phase
Require:Three sets of coils physically displaced from each other by120º electrical.
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VA
VC
VB
Generating a AC Voltage3-Phase
N S
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Generating a AC Voltage3-Phase
A1
A2
N S
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Generating a AC Voltage3-Phase
N S
A1
A2
B1B2
C1
C2
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N N
S
S
A
A
AA
B
B
B
B
C
C
C
C
4-pole machine
A four pole stator must have a four
pole rotor
Generating a AC Voltage3-Phase
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Alternator• Reasons for having the three phase winding on the
stator rather than the rotor:– More space on the stator for the three phase
winding.– Only one, low voltage winding on the rotor.
• Easier to insulate.• Less problems with centrifugal force.
– Only two sliprings required rather than four (3-ph + N)
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Alternator
Stator- Connected to load.
Rotor- Constant DC field- Connected to its own DC supply via sliprings.
ElectricalPower
MechanicalPower
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eld
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Alternator
Q: What keeps an alternator producing 50Hz under all load conditions?
A: The governor on the prime mover. It detects any drop in speed, and tries to speed the unit up.
AlternatorPetrolEngine
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151
IFIELD
VOUT
Alternator Excitation Curve
(No Load)
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Alt
LoadR
XLInternal
Impedance
Alternator
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VOUTILOADVR
VZ VL
VGEN
VZ = Internal Impedance of the alternator
VR = Internal Resistance of the alternatorVL = Internal Reactance of the alternator
Resistive Load
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Resistive Load
VOUTILOADVR
VZ VL
VGEN
Notice that terminal volts DROP as load increases Load current and p.f. are dictated by the LOAD!
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Inductive Load
VOUT
ILOAD
VR
VZ
VL
VGEN
Parallel
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Inductive Load
VOUT
ILOAD
VR
VZ
VL
VGEN
Now there is a greater voltage drop under load
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Capacitive Load
VOUT
ILOAD
V R
V Z
V L
VGEN
Now there is a voltage RISE under load
Parallel
Because of the voltage rise under load, it is not desirable to run alternators at a
leading power factor.
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Leading pf
Unity pf
Lagging pf
Load Current
OutputVoltage
Effect of Power Factor on Output Voltage
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Voltage Regulation
(VNL – VFL)%Voltage Regulation = x 100 VFL
eg An alternator output falls from 240V to 200Vwith constant excitation. Calculate the % voltage regulation.
(Ans: 20%)
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Summary:When an alternator is standing by itself with a single load:
Output voltage is affected by excitation currentOutput frequency is affected by input power to the
alternator.
Alternators - stand alone
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When an alternator is tied to the grid, you cannot change:Grid voltageGrid frequency
So the output voltage of the alternator will not change, andthe output frequency of the alternator will not change.
Notice that, for a stand alone alternator with stand alone load, these are the two things that changed when:
(a) the excitation was altered, and(b) the power input to the alternator was increased
(ie. Put the foot down on the prime mover)
Alternators tied to the Grid
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Alternators tied to the Grid
VOUT VR
VZ VL
VGEN
If excitation is increased, and VOUT cannot alter, VGEN
will increase and push the triangle over.
ILOAD
1. Altering Excitation.
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VOUTILOAD
VR
VZ
VL
VGEN
If excitation is increased, and VOUT cannot alter, VGEN
will increase and push the triangle over.
Alternators tied to the Grid1. Altering Excitation.
Note that input power to the alternator is not changing,so output power does not change either.
Constant Power Line(Output power of the alternator has notChanged)
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VOUTILOAD
VR
VZ
VL
If excitation is reduced, and VOUT cannot alter, VGEN
will reduce and pull the triangle back.
Alternators tied to the Grid1. Altering Excitation.
VGEN
This drives the load current lagging
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VOUT
ILOAD
V R
V Z
V L
VGEN
If excitation is reduced, and VOUT cannot alter, VGEN
will reduce and pull the triangle back.
Alternators tied to the Grid1. Altering Excitation.
This will drive the load current leading
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If input power is reduced, and frequency and VOUT cannot alter, output power will reduce.
Alternators tied to the Grid2. Altering input power to the alternator.
VOUT VR
VZ VL
VGEN
ILOAD
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If input power is reduced, and frequency and VOUT cannot alter, output power will reduce.
Alternators tied to the Grid2. Altering input power to the alternator.
VOUT VR
VZ VL
VGEN
ILOAD
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If input power is reduced, and frequency and VOUT cannot alter, output power will reduce.
Alternators tied to the Grid2. Altering input power to the alternator.
VOUT VR
VZ VL
VGEN
ILOAD
Size of trianglereduces
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If input power is reduced, and frequency and VOUT cannot alter, output power will reduce.
Alternators tied to the Grid2. Altering input power to the alternator.
VOUTV
RV
Z VL
VGEN
ILOAD
Size of trianglereduces
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If input power is increased, and frequency and VOUT cannot alter, output power will increase.
Alternators tied to the Grid2. Altering input power to the alternator.
VOUT VR
VZ VL
VGEN
ILOAD
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If input power is increased, and frequency and VOUT cannot alter, output power will increase.
Alternators tied to the Grid2. Altering input power to the alternator.
VOUT VR
VZ VL
VGEN
ILOAD
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If input power is increased, and frequency and VOUT cannot alter, output power will increase.
Alternators tied to the Grid2. Altering input power to the alternator.
VOUT VR
VZ VL
VGEN
ILOAD
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If input power is increased, and frequency and VOUT cannot alter, output power will increase.
Alternators tied to the Grid2. Altering input power to the alternator.
VOUTVR
VZ
VL
VGEN
ILOAD
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Alternators - tied to the GridSummary:
Changing excitation changes the pf of output current.Changing input power changes output power
• Increasing excitation drives load current lagging• Reducing excitation drives load current leading• Increasing input power increases output power• Reducing input power reduces output power
• Output frequency and voltage do not change.
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Alternators – stand aloneSummary:• Changing excitation changes output voltage.• Changing input power changes RPM, which changes
output frequency.
• Here, output frequency and voltage do change
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Paralleling Alternators
To parallel alternators (or parallel one onto the grid), the following criteria must be met:
• Output voltage must be the same• Output frequency must be the same• Phase rotation must be the same • Supply voltage must be in phase
It is understood that they must both produce the same waveform – a sine wave!
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Alternator Rating
Alternators are rated according to:FrequencyVoltageCurrentkVA
The frequency dictates the RPM (3000, 1500, etc).Voltage and Current give the kVA rating.
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Efficiency
Losses:• By far the main loss in an alternator is HEAT loss.• If an alternator can be kept cool, more power can
be obtained from it. ie. Instead of a 300MW machine, it will become a 500MW machine.
• More power must be put into it to get this increased output power.
• Cooling large alternators is a big deal! They are often cooled using hydrogen.
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Efficiency
Losses:• Copper Losses:
I2R losses in the stator windingI2R losses in the rotor winding
• Iron Losses:Hysteresis loss in statorEddy current Loss in stator
• Friction and windage
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Single Phase Alternators
ElectricalPower
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Mag
neti
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Regulator
Stat
or
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Single Phase Alternators
• These are usually low rated units for portable use.• Prime mover is usually a small petrol or diesel engine.• The engine speed is kept constant by a governor.• This speed will usually be either 3000RPM or 1500RPM• Output voltage is kept constant using an automatic voltage
regulator. This senses the output voltage and adjusts the rotor excitation current automatically.
• They are usually self exciting, so if the load is left on at start, they may not build up output voltage.
• Many small alternators are brushless.• Usually, neither side is earthed. This is called a FLOATING
system.
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Rotor
Brushless Alternators
AC issampled
Regulator DC
Field P.S.
Note: Self Excited
3-phaseout
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Brushless AlternatorsRotor
Regulator
3-phaseout
Prime Mover3-phase
out
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Small Alternators-Factors when choosing:
•Voltage: 240V / 415V (1-phase or 3-phase)•kVA rating•RPM (3000RPM or 1500RPM)•Petrol or Diesel•Brushless or brushes•Ability to start loads such as motors•Extras: Soundproofing, starting, power outlets,
mounting holes, 12VDC / welding output
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199