Top Banner
2.4 – Writing Linear Equations
34

2.4 – Writing Linear Equations. 2.4 – Writing Linear Equations Forms:

Dec 31, 2015

Download

Documents

Darcy Bruce
Welcome message from author
This document is posted to help you gain knowledge. Please leave a comment to let me know what you think about it! Share it to your friends and learn new things together.
Transcript
  • 2.4 Writing Linear Equations

  • 2.4 Writing Linear Equations

    Forms:

  • 2.4 Writing Linear Equations

    Forms: Standard Form

  • 2.4 Writing Linear Equations

    Forms: Standard Form Ax + By = C

  • 2.4 Writing Linear Equations

    Forms: Standard Form Ax + By = CSlope-Intercept Form

  • 2.4 Writing Linear Equations

    Forms: Standard Form Ax + By = CSlope-Intercept Form y = mx + b

  • 2.4 Writing Linear Equations

    Forms: Standard Form Ax + By = CSlope-Intercept Form y = mx + bPoint-Slope Form

  • 2.4 Writing Linear Equations

    Forms: Standard Form Ax + By = CSlope-Intercept Form y = mx + bPoint-Slope Form y y1 = m(x x1)

  • 2.4 Writing Linear Equations

    Forms: Standard Form Ax + By = CSlope-Intercept Form y = mx + bPoint-Slope Form y y1 = m(x x1)

    Example 1 - Write an Equation Given Slope & a Point

  • 2.4 Writing Linear Equations

    Forms: Standard Form Ax + By = CSlope-Intercept Form y = mx + bPoint-Slope Form y y1 = m(x x1)

    Example 1 - Write an Equation Given Slope & a PointWrite and equation in slope-intercept form for the line that has a slope of -3/2 and passes through (-4,1).

  • 2.4 Writing Linear Equations

    Forms: Standard Form Ax + By = CSlope-Intercept Form y = mx + bPoint-Slope Form y y1 = m(x x1)

    Example 1 - Write an Equation Given Slope & a PointWrite and equation in slope-intercept form for the line that has a slope of -3/2 and passes through (-4,1).Given:

  • 2.4 Writing Linear Equations

    Forms: Standard Form Ax + By = CSlope-Intercept Form y = mx + bPoint-Slope Form y y1 = m(x x1)

    Example 1 - Write an Equation Given Slope & a PointWrite and equation in slope-intercept form for the line that has a slope of -3/2 and passes through (-4,1).Given: m = -3/2

  • 2.4 Writing Linear Equations

    Forms: Standard Form Ax + By = CSlope-Intercept Form y = mx + bPoint-Slope Form y y1 = m(x x1)

    Example 1 - Write an Equation Given Slope & a PointWrite and equation in slope-intercept form for the line that has a slope of -3/2 and passes through (-4,1).Given: m = -3/2 (-4,1)

  • 2.4 Writing Linear Equations

    Forms: Standard Form Ax + By = CSlope-Intercept Form y = mx + bPoint-Slope Form y y1 = m(x x1)

    Example 1 - Write an Equation Given Slope & a PointWrite and equation in slope-intercept form for the line that has a slope of -3/2 and passes through (-4,1).Given: m = -3/2 (-4,1) Point-Slope

  • 2.4 Writing Linear Equations

    Forms: Standard Form Ax + By = CSlope-Intercept Form y = mx + bPoint-Slope Form y y1 = m(x x1)

    Example 1 - Write an Equation Given Slope & a PointWrite and equation in slope-intercept form for the line that has a slope of -3/2 and passes through (-4,1).Given: m = -3/2 (-4,1) Point-Slope y y1 = m(x x1)

  • 2.4 Writing Linear Equations

    Forms: Standard Form Ax + By = CSlope-Intercept Form y = mx + bPoint-Slope Form y y1 = m(x x1)

    Example 1 - Write an Equation Given Slope & a PointWrite and equation in slope-intercept form for the line that has a slope of -3/2 and passes through (-4,1).Given: m = -3/2 (-4,1) Point-Slope y y1 = m(x x1) y 1 = (-3/2)(x (-4))

  • 2.4 Writing Linear Equations

    Forms: Standard Form Ax + By = CSlope-Intercept Form y = mx + bPoint-Slope Form y y1 = m(x x1)

    Example 1 - Write an Equation Given Slope & a PointWrite and equation in slope-intercept form for the line that has a slope of -3/2 and passes through (-4,1).Given: m = -3/2 (-4,1) Point-Slope y y1 = m(x x1) y 1 = (-3/2)(x (-4)) y 1 = (-3/2)(x + 4)

  • 2.4 Writing Linear Equations

    Forms: Standard Form Ax + By = CSlope-Intercept Form y = mx + bPoint-Slope Form y y1 = m(x x1)

    Example 1 - Write an Equation Given Slope & a PointWrite and equation in slope-intercept form for the line that has a slope of -3/2 and passes through (-4,1).Given: m = -3/2 (-4,1) Point-Slope y y1 = m(x x1) y 1 = (-3/2)(x (-4)) y 1 = (-3/2)(x + 4) y 1 = (-3/2)x 6

  • 2.4 Writing Linear Equations

    Forms: Standard Form Ax + By = CSlope-Intercept Form y = mx + bPoint-Slope Form y y1 = m(x x1)

    Example 1 - Write an Equation Given Slope & a PointWrite and equation in slope-intercept form for the line that has a slope of -3/2 and passes through (-4,1).Given: m = -3/2 (-4,1) Point-Slope y y1 = m(x x1) y 1 = (-3/2)(x (-4)) y 1 = (-3/2)(x + 4) y 1 = (-3/2)x 6

  • 2.4 Writing Linear Equations

    Forms: Standard Form Ax + By = CSlope-Intercept Form y = mx + bPoint-Slope Form y y1 = m(x x1)

    Example 1 - Write an Equation Given Slope & a PointWrite and equation in slope-intercept form for the line that has a slope of -3/2 and passes through (-4,1).Given: m = -3/2 (-4,1) Point-Slope y y1 = m(x x1) y 1 = (-3/2)(x (-4)) y 1 = (-3/2)(x + 4) y 1 = (-3/2)x 6 + 1 + 1

  • 2.4 Writing Linear Equations

    Forms: Standard Form Ax + By = CSlope-Intercept Form y = mx + bPoint-Slope Form y y1 = m(x x1)

    Example 1 - Write an Equation Given Slope & a PointWrite and equation in slope-intercept form for the line that has a slope of -3/2 and passes through (-4,1).Given: m = -3/2 (-4,1) Point-Slope y y1 = m(x x1) y 1 = (-3/2)(x (-4)) y 1 = (-3/2)(x + 4) y 1 = (-3/2)x 6 + 1 + 1 y = (-3/2)x 5

  • Example 2 Write an Equation of a Perpendicular Line

  • Example 2 Write an Equation of a Perpendicular LineWrite an equation for the line that passes through (-4,3) and is perpendicular to the line whose equation is y = -4x 1.

  • Example 2 Write an Equation of a Perpendicular LineWrite an equation for the line that passes through (-4,3) and is perpendicular to the line whose equation is y = -4x 1. (-4,3)

  • Example 2 Write an Equation of a Perpendicular LineWrite an equation for the line that passes through (-4,3) and is perpendicular to the line whose equation is y = -4x 1. (-4,3) m1 = -4

  • Example 2 Write an Equation of a Perpendicular LineWrite an equation for the line that passes through (-4,3) and is perpendicular to the line whose equation is y = -4x 1. (-4,3) m1 = -4m2 =

  • Example 2 Write an Equation of a Perpendicular LineWrite an equation for the line that passes through (-4,3) and is perpendicular to the line whose equation is y = -4x 1. (-4,3) m1 = -4m2 = So, write eq. through (-4,3) w/m2 = .

  • Example 2 Write an Equation of a Perpendicular LineWrite an equation for the line that passes through (-4,3) and is perpendicular to the line whose equation is y = -4x 1. (-4,3) m1 = -4m2 = So, write eq. through (-4,3) w/m2 = .y y1 = m(x x1)

  • Example 2 Write an Equation of a Perpendicular LineWrite an equation for the line that passes through (-4,3) and is perpendicular to the line whose equation is y = -4x 1. (-4,3) m1 = -4m2 = So, write eq. through (-4,3) w/m2 = .y y1 = m(x x1)y 3 = (x (-4))

  • Example 2 Write an Equation of a Perpendicular LineWrite an equation for the line that passes through (-4,3) and is perpendicular to the line whose equation is y = -4x 1. (-4,3) m1 = -4m2 = So, write eq. through (-4,3) w/m2 = .y y1 = m(x x1)y 3 = (x (-4)) y 3 = (x + 4)

  • Example 2 Write an Equation of a Perpendicular LineWrite an equation for the line that passes through (-4,3) and is perpendicular to the line whose equation is y = -4x 1. (-4,3) m1 = -4m2 = So, write eq. through (-4,3) w/m2 = .y y1 = m(x x1)y 3 = (x (-4)) y 3 = (x + 4)y 3 = (x) + (4)

  • Example 2 Write an Equation of a Perpendicular LineWrite an equation for the line that passes through (-4,3) and is perpendicular to the line whose equation is y = -4x 1. (-4,3) m1 = -4m2 = So, write eq. through (-4,3) w/m2 = .y y1 = m(x x1)y 3 = (x (-4)) y 3 = (x + 4)y 3 = (x) + (4) y 3 = (x) + 1

  • Example 2 Write an Equation of a Perpendicular LineWrite an equation for the line that passes through (-4,3) and is perpendicular to the line whose equation is y = -4x 1. (-4,3) m1 = -4m2 = So, write eq. through (-4,3) w/m2 = .y y1 = m(x x1)y 3 = (x (-4)) y 3 = (x + 4)y 3 = (x) + (4) y 3 = (x) + 1 + 3+ 3

  • Example 2 Write an Equation of a Perpendicular LineWrite an equation for the line that passes through (-4,3) and is perpendicular to the line whose equation is y = -4x 1. (-4,3) m1 = -4m2 = So, write eq. through (-4,3) w/m2 = .y y1 = m(x x1)y 3 = (x (-4)) y 3 = (x + 4)y 3 = (x) + (4) y 3 = (x) + 1 + 3+ 3 y = (x) + 4